软件类笔试题目参考

1、软件类笔试题目参考 软件类笔试题目参考下面的代码输出是什么，为什么？ void foo(void) unsigned int a = 6; int b = -20; (a+b6)?puts(6):puts(6就是考察隐式转换int型变量转化成unsigned int,b成了正数2. b)运行下面的函数会有什么结果？为什么？ void foo(void) char string10,str110; int i; for(i=0;i10;i+) str1i = a; strcpy(string, str1); printf(%s,string); 首先搞清strcpy函数的实现方法，char *

2、strcpy(char * strdest,const char * strsrc)if (strdest=null)|(strsrc=null) throw invalid argument(s);char * strdestcopy=strdest;while (*strdest+=*strsrc+)!=0); return strdestcopy;由于str1末尾没有0结束标志，所以strcpy不知道拷贝到何时结束printf函数，对于输出char* 类型，顺序打印字符串中的字符直到遇到空字符（）或已打印了由精度指定的字符数为止下面是微软的两道笔试题.3. implement a str

3、ing class in c+ with basic functionality like comparison, concatenation, input and output. please also provide some test cases and using scenarios (sample code of using this class).please do not use mfc, stl and other libraries in your implementation.我的实现方案如下,这道题真地对c+的主要特性都进行了较好地考察.string.h:#ifndef

4、string_h#define string_h#include using namespace std;class string public: string(); string(int n,char c); string(const char* source); string(const string& s); /string& operator=(char* s); string& operator=(const string& s); string(); char& operator(int i)return ai; const char& operator(int i) const

5、return ai;/对常量的索引. string& operator+=(const string& s); int length(); friend istream& operator(istream& is, string& s);/搞清为什么将设置为友元函数的原因. /friend bool operator (const string& left, const string& right);/下面三个运算符都没必要设成友元函数,这里是为了简单. friend bool operator= (const string& left, const string& right); frien

6、d bool operator!= (const string& left, const string& right); private: char* a; int size;#endifstring.cpp:#include string.h#include #include string:string() a = new char1; a0 = 0; size = 0;string:string(int n,char c)a = new charn + 1;memset(a,c,n);an = 0;size = n;string:string(const char* source)if(s

7、ource = null) a = new char1; a0 = 0; size = 0;else size = strlen(source); a = new charsize + 1; strcpy(a,source);string:string(const string& s)size = strlen(s.a);/可以访问私有变量.a = new charsize + 1;/if(a = null)strcpy(a,s.a);string& string:operator=(const string& s)if(this = &s) return *this;else delete

8、a; size = strlen(s.a); a = new charsize + 1; strcpy(a,s.a); return *this;string:string()delete a;/ string& string:operator+=(const string& s) int j = strlen(a); int size = j + strlen(s.a); char* tmp = new charsize+1; strcpy(tmp,a); strcpy(tmp+j,s.a);delete a;a = tmp;return *this;int string:length()r

9、eturn strlen(a);main.cpp:#include #include string.husing namespace std;bool operator=(const string& left, const string& right)int a = strcmp(left.a,right.a); if(a = 0) return true;else return false;bool operator!=(const string& left, const string& right)return !(left = right);ostream& operator(ostre

10、am& os,string& s)int length = s.length();for(int i = 0;i length;i+) /os s.ai;这么不行,私有变量. os si;return os;string operator+(const string& a,const string& b)string temp;temp = a;temp += b;return temp;bool operator(const string& left,const string& right)int j = 0;while(leftj != 0) & (rightj != 0) if(left

11、j (const string& left, const string& right) int a = strcmp(left.a,right.a); if(a 0) return true;else return false;istream& operator(istream& is, string& s)delete s.a;s.a = new char20;int m = 20; char c;int i = 0;while (is.get(c) & isspace(c); if (is) do s.ai = c; i+; /*if(i = 20) cout input too much characters! f;/需要输入.string g;g = a + b;/abcdwwwif(a b) cout a b endl;else cout = b endl;if(e = a) cout e = a endl;else cout e != a endl;b += a;cout a endl;cout b endl; cout c endl;cout d endl;cout e endl;cout f endl;cout g endl;cout g0 endl;return 0;4. implement a single-direction linked