建模工作选择问题

1、精品文档2、工作的选择方案挑选合适的工作。经双方恳谈， 已有三个单位表示愿意录用某毕业生。该生根据已有信息建立了一个层次结构模型，如下图所示。A B1B2B3B4B5B6B1111411/2B2112411/2B311/21531/2B41/41/41/511/31/3B5111/3311B6222331（方案层）B1C1 C2C 3B2C1C2C3C111/41/2C111/41/5C 2413C2411/2C 321/31C3521B3C1C2 C3B4C1C 2C 3C1 131/3C111/35随意编辑精品文档C 21/317C 2317C 331/71C 31/51/71B5C1C

2、2C3B6C1 C2C 3C1117C1179C 2117C 21/711C31/71/71C 31/911帮助该毕业生挑选出合适的工作，并给出选择的依据。clca=1,1,1,4,1,1/21,1,2,4,1,1/21,1/2,1,5,3,1/21/4,1/4,1/5,1,1/3,1/31,1,1/3,3,1,12,2,2,3,3,1;x,y=eig(a);eigenvalue=diag(y);lamda=eigenvalue(1);ci1=(lamda-6)/5;crl=ci1/1.24w1=x(:,1)/sum(x(:,1)b1=1,1/4,1/2;4,1,3;2,1/3,1;x,y=e

3、ig(b1);eigenvalue=diag(y);lamda=eigenvalue(1);ci21=(lamda-3)/2;cr21=ci21/0.58随意编辑精品文档w21=x(:,1)/sum(x(:,1)b2=1,1/4,1/5;4,1,1/2;5,2,1x,y=eig(b2);eigenvalue=diag(y);lamda=eigenvalue(1);ci22=(lamda-3)/2;cr22=ci22/0.58w22=x(:,1)/sum(x(:,1)b3=1,3,1/3;1/3,1,7;3,1/7,1x,y=eig(b3);eigenvalue=diag(y);lamda=ei

4、genvalue(1);ci23=(lamda-3)/2;cr23=ci23/0.58w23=x(:,1)/sum(x(:,1)b4=1,1/3,5;3,1,7;1/5,1/7,1x,y=eig(b4);eigenvalue=diag(y);lamda=eigenvalue(1);ci24=(lamda-3)/2;cr24=ci24/0.58w24=x(:,1)/sum(x(:,1)b5=1,1,7;1,1,7;1/7,1/7,1x,y=eig(b5);eigenvalue=diag(y);lamda=eigenvalue(1);ci25=(lamda-3)/2;cr25=ci25/0.58w

5、25=x(:,1)/sum(x(:,1)b6=1,7,9;1/7,1,1;1/9,1,1x,y=eig(b6);eigenvalue=diag(y);lamda=eigenvalue(1);ci26=(lamda-3)/2;cr26=ci26/0.58w26=x(:,1)/sum(x(:,1)w_sum=w21,w22,w23,w24,w25,w26*w1随意编辑精品文档ci=ci21,ci22,ci23,ci24,ci25,ci26;cr=ci*w1/sum(0.58*w1)结果crl =0.0996w1 =0.15070.17920.18860.04720.14640.2879cr21 =

6、0.0158w21 =0.1365随意编辑精品文档0.62500.2385b2 =1.00000.25000.20004.00001.00000.50005.00002.00001.0000cr22 =0.0212w22 =0.09740.33310.5695b3 =1.00003.00000.33330.33331.00000.14293.00007.00001.0000随意编辑精品文档cr23 =0.0061w23 =0.24260.08790.6694b4 =1.00000.33335.00003.00001.00007.00000.20000.14291.0000cr24 =0.055

7、9w24 =0.27900.6491随意编辑0.0719b5 =1.00001.00001.00001.00000.14290.1429cr25 =-1.1485e-015w25 =0.46670.46670.0667b6 =1.00007.00000.14291.00000.11111.0000精品文档7.00007.00001.00009.00001.00001.0000随意编辑精品文档cr26 =0.0061w26 =0.79860.10490.0965w_sum =0.39520.29960.3052cr =0.0117crl一致性比率CR=cr1=0.0996<0.1,通过一致

8、性检验cr21=0.0158<0.1cr22=0.0212<0.1随意编辑精品文档cr23=0.0061<0.1cr24=0.0559<0.1cr25=-1.1485e-015<0.1cr26=0.0061<0.1通过一致性检验准则研究发展待遇同事地理单位总排序课题前途情况位置名气权值准则层权值0.15070.17920.18860.04720.14640.2879方案层工作 10.13650.09740.54820.27900.46670.79860.3952单排序工作 20.62500.33310.72710.64910.46670.10490.2996