连连求java小游戏源代码

1、求java小游戏源代码I 悬赏分：100 -解决时间：2007-11-30 12:37要做课程设计，想找几个小游戏的代码做参考，请各位高手帮忙！ ！ ！小弟不胜感激！ ！ ！提问者：S2005035 -二 级最佳答案连连看java源代码import javax.swing.*;import java.awt.*;import java.awt.event.*;public class lianliankan implements ActionListener JFrame mainFrame; 主面板Container thisContainer;JPanel centerPanel,sout

2、hPanel,northPanel; /子面板JButton diamondsButton口口 = new JButton65;/游戏按钮数组JButton exitButton,resetButton,newlyButton;/退出，重歹U,重新开始按钮JLabel fractionLable=new JLabel("0"); 分数标签JButton firstButton,secondButton; /分别记录两次被选中的按钮int grid叩=new int87;/储存游戏按钮位置static boolean pressInformation=false; /判断是否

3、有按钮被选中int x0=0,y0=0,x=0,y=0,fristMsg=0,secondMsg=0,validateLV; /游戏按钮的位置坐标int i,j,k,n;消除方法控制public void init()mainFrame=new JFrame("JKJ 连连看");thisContainer = mainFrame.getContentPane();thisContainer.setLayout(new BorderLayout();centerPanel=new JPanel();southPanel=new JPanel();northPanel=new

4、 JPanel();thisContainer.add(centerPanel,"Center");thisContainer.add(southPanel,"South");thisContainer.add(northPanel,"North");centerPanel.setLayout(new GridLayout(6,5);for(int cols = 0;cols < 6;cols+)for(int rows = 0;rows < 5;rows+ )diamondsButtoncolsrows=new JBut

5、ton(String.valueOf(gridcols+1rows+1);diamondsButtoncolsrows.addActionListener(this);centerPanel.add(diamondsButtoncolsrows);exitButton=new JButton(" 退出");exitButton.addActionListener(this);resetButton=new JButton("重歹 U");resetButton.addActionListener(this);newlyButton=new JButton

6、("再来一局");newlyButton.addActionListener(this);southPanel.add(exitButton);southPanel.add(resetButton);southPanel.add(newlyButton);fractionLable.setText(String.valueOf(Integer.parseInt(fractionLable.getText();northPanel.add(fractionLable);mainFrame.setBounds(280,100,500,450);mainFrame.setVisi

7、ble(true);public void randomBuild() int randoms,cols,rows;for(int twins=1;twins<=15;twins+) randoms=(int)(Math.random()*25+1);for(int alike=1;alike<=2;alike+) cols=(int)(Math.random()*6+1);rows=(int)(Math.random()*5+1);while(gridcolsrows!=0) cols=(int)(Math.random()*6+1);rows=(int)(Math.random

8、()*5+1);this.gridcolsrows=randoms;public void fraction()fractionLable.setText(String.valueOf(Integer.parseInt(fractionLable.getText()+100);public void reload() int save口 = new int30;int n=0,cols,rows;int grid= new int87;for(int i=0;i<=6;i+) for(int j=0;j<=5;j+) if(this.gridij!=0) saven=this.gr

9、idij;n+;n=n-1;this.grid=grid;while(n>=0) cols=(int)(Math.random()*6+1);rows=(int)(Math.random()*5+1);while(gridcolsrows!=0) cols=(int)(Math.random()*6+1);rows=(int)(Math.random()*5+1);this.gridcolsrows=saven;n-；mainFrame.setVisible(false);pressInformation=false; /这里一定要将按钮点击信息归为初始init()；for(int i

10、= 0;i < 6;i+)for(int j = 0;j < 5;j+ )if(gridi+1j+1=0)diamondsButtonij.setVisible(false);public void estimateEven(int placeX,int placeY,JButton bz) if(pressInformation=false) x=placeX;y=placeY;secondMsg=gridxy;secondButton=bz;pressInformation=true;else x0=x;y0=y;fristMsg=secondMsg;firstButton=s

11、econdButton;x=placeX;y=placeY;secondMsg=gridxy;secondButton=bz;if(fristMsg=secondMsg && secondButton!=firstButton)xiao();public void xiao() 相同的情况下能不能消去。仔细分析，不一条条注释if(x0=x &&(y0=y+1|y0=y-1) | (x0=x+1|x0=x-1)&&(y0=y) /判断是否相邻remove();elsefor (j=0；j<7；j+ ) if (gridx0j=0) /判断第一

12、个按钮同行哪个按钮为空if (y>j) /如果第二个按钮的 Y坐标大于空按钮的Y坐标说明第一按钮在第二按钮左边for (i=y-1;i>=j;i- ) /判断第二按钮左侧直到第一按钮中间有没有按钮if (gridxi!=0) k=0;break;else k=1; /K=1说明通过了第一次验证if (k=1) linePassOne();if (y<j) /如果第二个按钮的Y坐标小于空按钮的Y坐标说明第一按钮在第二按钮右边for (i=y+1;i<=j ;i+儿 判断第二按钮左侧直到第一按钮中间有没有按钮if (gridxi!=0)k=0;break;else k=1;

13、 if (k=1) linePassOne();if (y=j ) linePassOne();if (k=2) if (x0=x) remove();if (x0<x) for (n=x0;n<=x-1;n+ ) if (gridnj!=0) k=0;break;if(gridnj=0 && n=x-1) remove();if (x0>x) for (n=x0;n>=x+1 ;n- ) if (gridnj!=0) k=0;break;if(gridnj=0 && n=x+1) remove();for (i=0;i<8;i+

14、) / 列if (grid皿y0=0) if (x>i) for (j=x-1;j>=i 卜)if (grid皿y!=0) k=0;break;else k=1; if (k=1) rowPassOne();if (x<i) for (j=x+1;j<=i;j+ ) if (grid皿y!=0) k=0;break;else k=1; if (k=1) rowPassOne();if (x=i) rowPassOne();if (k=2)if (y0=y) remove();if (y0<y) for (n=y0;n<=y-1 ;n+ ) if (grid皿

15、n!=0) k=0;break;if(gridin=0 && n=y-1) remove();if (y0>y) for (n=y0;n>=y+1 ;n-) if (grid皿n!=0) k=0;break;if(gridin=0 && n=y+1) remove();public void linePassOne()if (y0>j)/第一按钮同行空按钮在左边for (i=y0-1;i>=j ;i-儿判断第一按钮同左侧空按钮之间有没按钮if (gridx0i!=0) k=0;break;else k=2; /K=2说明通过了第二次验证i

16、f (y0<j) /第一按钮同行空按钮在与第二按钮之间for (i=y0+1;i<=j ;i+)if (gridx0i!=0) k=0;break;else k=2; public void rowPassOne()if (x0>i) for (j=x0-1;j>=i 卜)if (grid皿y0!=0) k=0;break;else k=2; if (x0<i) for (j=x0+1;j<=i ;j+ ) if (grid皿y0!=0) k=0;break;else k=2; public void remove()firstButton.setVisib

17、le(false);secondButton.setVisible(false);fraction。；pressInformation=false;k=0;gridx0y0=0;gridxy=0;public void actionPerformed(ActionEvent e) if(e.getSource()=newlyButton)int grid叩=new int87;this.grid = grid;randomBuild();mainFrame.setVisible(false);pressInformation=false;init();if(e.getSource()=exitButton)System.exit(0);if(e.getSource()=resetButton)reload();for(int cols = 0;cols <