姚斌机电控制技术考试试卷及答案解析

1、Mechatronic Control SystemsSpring 2013Dr. Bin YaoFINAL EXAM April 30, 2013ProblemPoint ValuePoints Gained120220340420Total100INSTRUCTIONS: 1. This is a Closed book exam. You are allowed one help sheet of hand-written summary.2. Your exams must be stapled.3. Circle your final answers.4. Be neat and c

2、lear. PROBLEM 1 (20Points)Consider the following feedback system: Y(s)-ControllerPlantwhere.You are required to design a controller to meet the following performance specifications: (P1). Zero steady-state error for ramp type reference input and constant disturbance (P2). The resulting closed-loop s

3、ystem should not have excessive transient responses for step reference input , i.e., your design should avoid either excessive large overshoot or large undershoot in the step responses. To solve this problem, you are required to follow the following procedure:a) Determine the correct controller stru

4、cture that is needed to meet the performance requirement P1. To receive full credit, you need to justify your answer as well.b) Determine the suitable desired pole locations of the closed-loop system so that the performance requirement P2 can be satisfied. Again, to receive full credit, you need to

5、justify your answer as well.c) Determine the unknown controller parameters to meet the above performance requirements. Solutions:由上面两条定理可以得到结论：1、a). As the plant has an integrator, to satisfy (P1), the controller only needs one integrator, i.e., (1)With the controller (1), the closed-loop output is

6、given by (2)Thus, for ramp type reference input (i.e., ) and constant disturbance (i.e., ), the system output tracking error is (3)So as long as the CL system is stable (i.e., the denominator in (3) has all roots in LHP), the condition for applying FVT is satisfied. By FVT, you can easily show that

7、the steady-state error in (3) is zero.PROBLEM 1 (conts)b). As the plant has an unstable pole at 1, to avoid excessive overshoot due to this unstable pole, the CL bandwidth should be higher than the break frequency of this unstable pole, which can be roughly met by imposing the following conditions o

8、n dominant CL poles:(4)As the plant has a stable zero at -3 which tends to increase the overshoot significantly when it is slower comparing to the CL bandwidth, to avoid excessive overshoot, the following condition on dominant CL poles should be imposed normally:(5)Thus we can place the dominant CL

9、poles around 2 to make a compromise between the conflicting requirements of (4) and (5). Note that as this zero is stable, you can also cancel this zero in the controller design (by placing one CL pole at -3) to remove its effect on the CL response with respect to the reference input as well. In tha

10、t case, its effect still appears in the CLTF from the disturbance input to the output.c). With a second-order controller of the form (1), (6)we have four controller parameters free to choose and the resulting CL system has four poles. Thus we can arbitrarily place all four CL poles with the controll

11、er form of (6). For simplicity, let all CL poles at -2, which leads to the following desired CL characteristic polynomial (CLCP): (7)From (2), the actual CLCP with the controller (6) is (8)Comparing (7) and (8), we obtain (9)Thus, (10)PROBLEM 2 (20 Points)Consider the following two-DOF feedback syst

12、em: SensorReference ValueNoises-ControllerPlantwhere and the system has the following characteristics: (C1) The input disturbance has significant energy in the frequency band 0, 1 rad/s.(C2) The measurement noise has significant energy in the frequency band 5, 100rad/s.(C3) The reference signal has

13、significant energy in the frequency band 0, 10 rad/s.You are required to synthesize proper controller transfer functions and to meet the following specific design goals while taking into account the above system characteristics: (P1) Zero steady-state errors for ramp type output disturbances (P2) Th

14、e response of the closed-loop system for step reference input has no oscillations.(P3) The closed-loop system should follow the reference signal well in the frequency band specified in (C3). To solve this problem, you may want to follow the following procedure:a) Determine the correct structure of f

15、eedback controller that is needed to meet the steady-state performance requirement P1. b) Determine the suitable desired pole locations of the closed-loop system that take into account the system characteristics (C1)-(C3). To receive full credit, you need to justify your answer as well.c) Determine

16、the parameters of the feedback controller to place the closed-loop poles at the desired locations.d) Determine a suitable filter transfer function so that (P2) and (P3) are satisfied. Solutions:a). As the plant has an integrator, to satisfy (P1), the controller only needs one integrator, i.e., (1)b)

17、. (C1) demands that the CL bandwidth should be at least higher than 1 rad/s to have certain attenuation to the input disturbance in the frequency band of 0, 1 rad/s. (C2) implies that the CL bandwidth should not be set too high to amplify the effect of noise in the frequency band of 5, 100 rad/s. Th

18、us a good compromise for the CL bandwidth to meet both requirements should be around 2 to 3 rad/s. So assume that we would like to place dominant CL poles at -3 in the following. c). With a first-order controller of the form (C1) (2)there will be two controller parameters free to choose and the resu

19、lting CL system will be of order 2. Thus we can arbitrarily place the two CL poles. With , the desired CLCP is(3)The actual CLCP with the controller (2) is (4)Comparing (3) and (4), we obtain (5)d). With the controller (5), the CLTF from to is (6)Thus, to be able to track reference signal in the fre

20、quency band of 0, 10 rad/s, a feedforward TF is needed so that the resulting CLTF from to has a bandwidth far more than 10 rad/s. As such, we needs to cancel the slow CL poles at -3 in (6). Furthermore, to avoid overshoot, the stable zero in (6) should be cancelled as well. With all these in mind, w

21、e can choose (7)where is the small time constant of the additional filter needed to make proper.Problem 3 (40 Points)Consider the control of an inertia load such as the rigid ECP emulator introduced in the lectures and the homework. In the presence of disturbance forces such as the Coulomb friction

22、force, the inertia load dynamics can be described by: where represents the disturbance force. Assume that the disturbance force is constant but unknown (i.e., =unknown constant), and only the output is measured. a) Design a minimum-order observer to estimate the unmeasured state (i.e., the velocity)

23、 and the unknown constant disturbance force. The observer gain should be chosen to place all observer poles at -5.b) Consider the following output feedback control law with disturbance estimate:where and represent the plant state and disturbance estimates from part a), and represents the filtered re

24、ference input. Determine the feedback gain so that all un-cancelled poles of the closed-loop transfer function from the filtered reference input to the output, i.e., , are at -1.c) Draw the equivalent block diagram of the closed-loop system with the above controller and estimator using transfer func

25、tions. To receive full credit, you need to obtain the explicit expressions of all relevant transfer functions.d) Obtain the closed-loop transfer function from the filter reference input to the output, and verify that all its un-cancelled poles are at -1 as required.e) Obtain the closed-loop transfer

26、 function from the disturbance input to the output, . Use this transfer function to show that constant disturbances will not cause any steady-state error in the output as expected. Solutions:a) . 降阶观测器极点配置的方法For constant disturbance , the augmented system model is (1)which is in the standard form fo

27、r designing minimum-order observer with and (2)The observer gain matrix can then be determined by placing the eigenvalues of (3)at -5, i.e., (4)(5)The minimum-order observer is thus given by(6)b). 状态反馈极点配置的求法 ：根据独立性原则，状态观测器和状态反馈互不影响，也就是K和L互不影响The closed-loop poles due to the state feedback gain are

28、determined by (7)Thus, to have the un-cancelled CL poles at -1, (8)c). With the minimum-order observer (6), the control law is given by (9)Substituting (9) into (6), (10)Thus,(11)and the control law (9) in s-domain is given by (12)The equivalent block diagram of the above CL system can then be drawn

29、 below：图中从u+d到Y的输出是由原系统中的A、B、C矩阵求出来的！orFig.1d). From Fig.1, the CLTF from to is (13)which has all uncancelled poles at -1.e). From Fig.1, the CLTF from to is (14)which has a in the numerator. As such, , indicating that the constant disturbances will not cause steady-state error.Problem 4 (20 Points)

30、Consider the same second-order system as in Problem 3 but with an input disturbance, i.e.,where represents the disturbance force. Assume that the disturbance force is constant but unknown (i.e., =unknown constant), and only the output is measured. Design an output feedback controller using the techn

31、ique of state-estimator with disturbance estimation and compensation (i.e., ) to achieve the following performance requirement:a) Stable closed-loop system.b) Zero state-steady error for any constant input disturbance .c) All the un-cancelled poles of the closed-loop transfer function from the filte

32、red reference input to the output, i.e., , are at -2.d) All other assignable closed-loop poles should be placed at -10. Solutions 1:As shown in Problem 3, the given system is not observable but detectable, and is not controllable but stabilizable. By introducing the coordinate transformation of (a1)

33、The system matrices in the new coordinate are (a2)which isolates the uncontrollable and unobservable mode represented by the coordinate . Though this mode cannot be moved with any state feedback and observable design, it is stable and does not contribute to the overall TF from the input to the outpu

34、t. Thus we can ignore this mode and only consider the controllable and the observable mode in synthesizing the output feedback controller. Thus the given system is reduced to(a3)For constant disturbance , the augmented system model is (a4)A full-order observer can then used to estimate the augmented

35、 states in (a4). The observer gain matrix should be chosen such that the eigenvalues of (a5)are at -10, -10, i.e., (a6)(a7)With the above observer gain, a full-order observer can be constructed as (a8)To have the CL poles by the state feedback at -2, from (a3), the state feedback gain for should be chosen as （忽略Z1，因为不可观） (a9)With the observer (a8) and the above gain in (a9), the following stabilizing output feedback control law can be used: (a10)Solutions 2:For constant disturbance , the augmented system model is (1)As shown in Problem 3, the above system is not observable but detectabl