C语言程序设计入门源代码代码集合

1、时间：2021.03.02创作：欧阳数#include vstdio .h pHn*nN)；廿Cvoid print_star(void)void print_welcome(void)print:fCC IanguageAelcomelXn); void main()print_star(); print_welcome();print_star(); getchar();#include stdio .hint sum(int i,int j)return(i + j);max = z;return max;#inelude int sl(int n)intj,s;s=0;for(j =

2、l;j = n ;j + +) s二 s+j;return s;int sum(int n) int irS=O;for(i = l;i = n;i + +) s=s+sl(i);return s;void main()int n; printf(n: H); scan f( % ： &n);printf( ,s=%dnn/sum(n);#inelude void func(int n) int i;for(i 二 ;i = l;i-)n = n + i; printf(,n=%dnn/n);void main()int n; printf(lnput n: H); scanf(H%dnz&n

3、); func( n);printf(n=%dn n/n); #inelude void swap(int a,int b) int temp; temp=a;a = b;b=temp; printf(swap : a=%d/b=%dn/a/b); void main()int a,b;a = 3;b=10;swap(a,b);pri ntf(a=%d /b=%dn/a/b);#inelude int func(int azint b) int c;c=a + b;return c;void main()int x=6iy=7/z=8r; r=func(x-zy+ +/x+y)/z-); pr

4、in tf(n%dnnzr);#include max(float x,float y) return xy? x:y; void main()printf( %n ; max(235);#inelude int sum(int n)int i,s=0;for(i=0;i = n ;i + +)s=s+i;return s;void main()int mzsn;scanf( %d; &m);sn 二 sum(m);printf( Hthe sum is %dn ； sn);#inelude void swap(int x,int y); int main() int azb;n；) scan

5、fC%d,%cr,&a,&b); printf(input number is:a=%d zb=%d nnzazb); swap(a,b); printf(input 2 numbers is:a=%d,b=%dn,a fb); return 0;void swap(int x,int y)int temp;temp = x;x = y;y = temp;print:f( swap number is%: xdzy= %d n；x,y);include nstdio.hn#define K 3#define N 5 long f2(int nJnt k) long power = n; int

6、 i;for(i=l;ik;i + +) power return power; long fl(int n,int k)long sum = 0 ;int i;for(i = l;i = n;i + +)sum = sum + f2(i,k);return sum;int main (void)printf(sum of %d power of integer from 1 to %d =KN);printf( ,%ldn,/fl(N/K)； return 0;#inelude int min(int ajnt b);int main (void)in t jzk,mininum; prin

7、tf(input 2 integers:);sea nfC%d,%d,8A&k); mininum = minAk);and %cZtheprintfC、n of the two values %d n j,k,mininum); return 0;int min(int ajnt b)if(ab) return a;elsereturn b;#ineludeint fune(int a,int b)int m=0zi=2;inti + = m + l;funem = i+a + b;(intreturn m;a,int演*#inelude vstdio .hint max(int x,int

8、 y)int乙z=xy?x:y;return 乙void main()extern int A,B; 声明外部变量pri ntf( dn/max(AzB);intA=13; B=-8;定义外部变量#inelude int fl(i nt xb)extern int xa;return (xa*xb);int main (void)extern int xb;int xa = 5;printf( ,xa=%d,xb=%dresult=%d/xa/xb/fl(xa);return 0;int xa = 3zxb = 4;#inelude vstdi o. h void num()extern in

9、t xzy;int a=15zb=10; x=a-b;y=a + b;int x,y;void main() int a=7zb=5; x=a + b;y=a? b; num();printf(%cL%dn ； x,y);#inelude void main()void swap();extern int a,b;a = 3;b=10;sw 叩()；pri ntf(a=%d /b=%dn/a/b);int a,b;void swap()int temp;temp=a;a = b;b=temp;#inelude void auto_static(void)int var_auto = 0;sta

10、tic int var_static = 0;printf(var_auto=%dvar_static=%dnzvar_auto+,var_static+);void main()int i;for (i=0;i3;i + +)auto_static();#inelude void swap(int x,int y) int t;t=x;x=y;y=t;int azb; scanf( %d：%cT: &a&b); swap(a,b);printf( %,drTab);#inelude int xzy;void swap(int , ,int)int t;t=x;x=y;y=t;void mai

11、n()scanfC%ct%cr &x,&y);swap(xzy);printf( %,dn; x,y);#inelude int Xzy;void swap(int x,int y)int t;t=x;x=y;y=t;void main()scanfC%d,%cT &x,&y);swap(xy); printfC%d,%dn; x,y);演示20#inelude int fac(int n) static int f=l;f=f*n;return f;void main()int i;for(i = l;iint func(int a,int b);void main()int k=4im =

12、 l/p; p=func(k/m);printf(%d /,/p); p=func(k/m);printf(%dn /p); int func(int ant b)static int m=0,i=2;i + = m + l;m = i+a + b;return m;演示23#inelude f(int n)int c;if (n =6)c=l;elsec=(f(n + l) + l)*2; return c;void main()printf( n%dn,/f(l);#inelude long power(int n)long f;if(nl) f=power(elsef=l;return

13、f;main()int n;long x;n ); scarf%d&n);x=power( n);printf( d!=%ldnfn,x);getchar(); #inelude vstdio.h int fact()static int i = 5;if(i = =O) return 1;elsei-;return (i + l)*fact();void main()prin tf( ,fact=%dnn/fact();#include int fun(i nt k);int w=3;void mainOint w=10;printfC %drifun(5)*w);int fun(i nt k)if(k=O) return w; return(fu n(k- l)*k);#in elude vstdio .h int fac(i nt n) register int i ff=l;for(i = l;i = n;i + +)仁 f*i; return f;mai n()in ti;for(i = l;i = 5;i + +) printfC %d!=%dnJ,fac(i);#in clude age(i nt n) int c;if(n= = l)c=10;elsec=age (n-1)+2;return c;voi