路面设计标准轴载累计作用次数程序设计

1、附录 程序设计标准轴载累计作用次数程序设计基于毕业设计需求，为了简化水泥路面计算过程，同时也完成了毕业设计中程序编 写的任务，整理用C 语言编写了标准轴载累计作用次数程序设计进行设计年限 内标准轴载累计作用次数的计算。本程序采用JTG D40-2011水泥路面设计规范，各参数取值满足规范要求。运行时，请按提示输入指定的内容后按Enter，直至出现运行结果，到End表示程序运行结束。1 程序设计：#include<math.h> main()doubleNs,Ne,Pq=11.5,16.5,28.7,25.75,28.7,23.7,49,50.2,60, Ph=23,23,68.2,

2、59.5,69.2,69.2,101.6,104.3,100,d, pro, sum, a, c, gr;int lane, i, t,N;char b;sum=0; d=1;printf("Please put in someparameters.n");printf("Volume of traffic: n"); printf("minivan:n"); scanf("%d",&N0); printf("microbus(SH130):n"); scanf("%d&quo

3、t;,&N1);printf("big bus(CA50):n"); scanf("%d",&N2); printf("small truck(BJ130):n"); scanf("%d",&N3);printf("medium truck(CA50):n"); scanf("%d",&N4); printf("medium truck(EQ140):n"); scanf("%d",&N5);pr

4、intf("big truck(JN150):n"); scanf("%d",&N6); printf("large truck(KB222):n");scanf("%d",&N7);printf("trailer:n"); scanf("%d",&N8);printf("please put in growth rate, like 0.085:n");scanf("%f",&gr);printf(&q

5、uot;Please put in number of that how many traffic lane the highwayhave:n"); scanf("%d",&lane);if(lane>=4)printf("Please choose a number between 0.5-0.75. n"); scanf("%f",&a);elseswith(lane)case'1': a=1.0;case'2': printf("Please choos

6、e a number between 0.8-1.0. n"); scanf("%f",&a);break;case'3': printf("Please choose a number between 0.6-0.8. n"); scanf("%f",&a);break; default: printf("errorn");break;printf("Please choose your highway classificatian as A, B or C:

7、n") printf("A: expressway, senior road, fee sation n")printf("B: junior road(lane width more than 7m)n:)printf("C: junior road(lane width amount to 7 or less than 7m)n:) b=getchar();swith(b)case'A': printf("Please choose a number between 0.17-0.22. n"); sca

8、nf("%f",&c);t=30;break;case'B': printf("Please choose a number between 0.34-0.39. n"); scanf("%f",&c);t=20;break;case'C': printf("Please choose a number between 0.54-0.62. n"); scanf("%f",&c);t=20;break;default: printf(&qu

9、ot;errorn");break;for(i=0;i<=8;i+) d=2.22*pow10(3)*pow(Pqi,-0.43);proi=d*Ni*pow(Pqi/100),16);sum=sum+proi;if(i=8) d=2.24* pow10(-8)*pow(Phi,-0.22); proi=d*Ni*pow(Phi/100),16); sum=sum+proi; else d=1,proi=d*Ni*pow(Phi/100),16); sum=sum+proi;Ns=0.5*a*sum; Ne=Ns*(pow(1+gr),t)-1)*365*c/gr printf

10、("Ne=%fn",Ne)if(Ne>2*pow107)printf("It is super heavy traffic volume.n"); if(pow10(6)<=Ne<=2*pow10(7)printf("It is heavy traffic volume.n"); if(3*pow10(4)<=Ne<=pow10(6)printf("It is medium traffic volume.n"); if(Ne<3*pow10(4)printf("It i

11、s light traffic volume.n");printf("End.n");2 程序运行结果按提示输入数据，然后得到运行结果。（注：表示Enter，前为输入的内容）Please put in some parameters.Volume of traffic:minivan:3100microbus(SH130):980big bus(CA50):218small truck(BJ130):2300medium truck(CA50):1079medium truck(EQ140):1370big truck(JN150):890heavy truck(KB222):550trailer:450please put in growth rate, like 0.07:0.09Please put in number of that how many traffic lane the highway have:2 Please choose a number between 0.7-0.85.0.8Please choose your highway classificatian as A, B or C:A: expressway, senior roa