C语言ATM程序模拟

1、一、 课题要求1、 当输入给定的卡号和密码（初始卡号和密码为123456）时，系统能登录ATM柜员机系统。2、 查询余额：初始余额为10000元。3、 ATM取款：每次取款金额为100的倍数，总额不超过5000元，支取金额不允许透支。4、 ATM存款：不能出现负存款。5、 修改密码：新密码长度不小于6位，不允许出现6位完全相同的情况，只有旧密码正确，新密码符合要求，且两次输入相同的情况下才可以成功修改密码。二、 代码#include "stdafx.h"#include "stdio.h"#include "windows.h"#in

2、clude "stdlib.h"#include "conio.h"void gotoxy(int x,int y); /光标位置函数void enter_ATM(); /账号输入函数 void input_code(); /密码输入函数void caozuo(); /基本操作界面void qukuan(); /取款函数void success(); /操作成功函数void delay(); /延时函数void yu_e(); /余额查询函数void cunkuan(); /存款函数void panduan(long int z); /判断取款是否合法函

3、数void exit(); /退出界面函数void mima(); /密码修改void zhuangyi();long int CODE=123456,YU_E=10000;/=主函数=/main()enter_ATM();caozuo();/=/=柜台机账号输入函数=/void enter_ATM()system("cls");printf("*n");printf("* *n");printf("* 欢迎使用 ATM 柜台机 *n");printf("* 请输入卡号 *n");printf(

4、"* *n");printf("* 取消 确定 *n");printf("* *n");printf("*n");long int user;gotoxy(14,4);scanf("%d",&user);while(user!=123456) system("cls");printf("*n");printf("* *n");printf("* 账户不存在，请从新输入 *n");printf("*

5、*n");printf("* *n");printf("* 取消 确定 *n");printf("* *n");printf("*n");gotoxy(13,3);scanf("%d",&user);input_code();/=/=密码输入函数=/void input_code()long int code; int temp=3,time;system("cls");printf("*n");printf("* *n&quo

6、t;);printf("* 请输入密码 *n");printf("* *n");printf("* *n");printf("* 取消 确定 *n");printf("* *n");printf("*n"); gotoxy(14,3);scanf("%d",&code); while(code!=CODE)temp-;if(temp=0)for(time=5;time>0;time-)system("cls");print

7、f("*n");printf("* *n");printf("* 您已经 3 次输入密码 *n");printf("* 系统将退出操作 *n");printf("* *n");printf("* ");printf("%d",time);printf(" *n");printf("* *n");printf("*n");delay();enter_ATM();system("cls&qu

8、ot;);printf("*n");printf("* *n");printf("* 密码错误，请重新输入 *n");printf("* 您还有 ");printf("%d",temp);printf(" 次机会 *n");printf("* *n");printf("* 取消 确定 *n");printf("* *n");printf("*n");gotoxy(14,4);scanf("

9、;%d",&code);caozuo();/=/=主操作界面函数=/void caozuo()system("cls");printf("*n");printf("* 请选择一下业务 *n");printf("* 1.修改密码 *n");printf("* 2.查询余额 *n");printf("* 3.取款 *n");printf("* 4.实时存款 *n");printf("* 5.退出 *n");printf(&

10、quot;*n");switch(getch()case '1': mima(); break;case '2': yu_e(); break;case '3': qukuan(); break;case '4': cunkuan(); break;case '5': exit(); break;default:printf("errorn");/=/=密码修改函数=/void mima()long int mm1,mm2,mm3;char temp;system("cls&

11、quot;);printf("*n");printf("* *n");printf("* 旧密码: *n");printf("* *n");printf("* 新密码: *n");printf("* 确认新密码: *n");printf("* *n");printf("*n");gotoxy(15,2);scanf("%d",&mm1);gotoxy(15,4);scanf("%d",&a

12、mp;mm2);gotoxy(15,5);scanf("%d",&mm3);if(mm1!=CODE)system("cls");printf("*n");printf("* *n");printf("* 旧密码错误 *n");printf("* *n");printf("* 请重新输入！ *n");printf("* *n");printf("* *n");printf("*n");de

13、lay();delay();zhuangyi();if(mm2!=mm3)system("cls");printf("*n");printf("* *n");printf("* 确认密码不一致 *n");printf("* *n");printf("* 请重新输入！ *n");printf("* *n");printf("* *n");printf("*n");delay();delay();zhuangyi();i

14、f(mm2<100000)system("cls");printf("*n");printf("* *n");printf("* 密码必须大于或等于6位数 *n");printf("* *n");printf("* 请重新输入！ *n");printf("* *n");printf("* *n");printf("*n");delay();delay();zhuangyi();temp=mm2%111111;i

15、f(temp=0)system("cls");printf("*n");printf("* *n");printf("* 密码过于简单 *n");printf("* *n");printf("* 请重新输入！ *n");printf("* *n");printf("* *n");printf("*n");delay();delay();zhuangyi();CODE=mm2;system("cls"

16、;);printf("*n");printf("* *n");printf("* 操作成功 *n");printf("* *n");printf("* 1.返回 2.退出 *n");printf("* *n");printf("* *n");printf("*n");switch(getch()case '1': caozuo(); break;case '2': exit(); break;/=/=余额

17、查询函数=/void yu_e()system("cls");printf("*n");printf("* *n");printf("* *n");printf("* 系统正在查询 *n");printf("* 请稍候. *n");printf("* *n");printf("* *n");printf("*n");delay();delay();system("cls");printf(&quo

18、t;*n");printf("* *n");printf("* 您的余额为 *n");printf("* *n");printf(" ");printf("%d",YU_E);printf("n* *n");printf("* 1.返回 2.退出 *n");printf("*n");switch(getch()case '1': caozuo(); break;case '2': exit();

19、 break;/=/=取款函数=/void qukuan()long int temp;system("cls");printf("*n");printf("* 请选择您要取款的金额 *n");printf("* 1.100 2.200 *n");printf("* 3.500 4.800 *n");printf("* 5.1000 6.其它 *n");printf("* *n");printf("* 7.返回 8.退出 *n");pr

20、intf("*n");switch(getch()case '1': panduan(100); break;case '2': panduan(200); break;case '3': panduan(500); break;case '4': panduan(800); break;case '5': panduan(1000); break;case '6':system("cls");printf("*n");printf(&qu

21、ot;* *n"); printf("* 请输入您要取款的金额 *n");printf("* *n"); printf("* *n");printf("* *n");printf("* *n"); printf("*n");gotoxy(14,4);scanf("%d",&temp);panduan(temp); break;case '7':caozuo(); break;case '8':exit();

22、 break;/=/=判断取款是否合法函数=/void panduan(long int z)int beishu;if(z>YU_E)system("cls");printf("*n");printf("* *n");printf("* 余额不足！ *n");printf("* 请重新操作 *n");printf("* *n");printf("* 1.返回 2.退出 *n");printf("* *n");printf(&qu

23、ot;*n");switch(getch()case '1': qukuan();case '2': exit();beishu=z%100;if(beishu!=0)system("cls");delay();printf("*n");printf("* *n");printf("* 本ATM机只支持 100 的人民币 *n");printf("* 请重新操作 *n");printf("* *n");printf("* 1

24、.返回 2.退出 *n");printf("* *n");printf("*n");switch(getch()case '1': qukuan();case '2': exit();if(z=5000|z>5000)system("cls");printf("*n");printf("* *n");printf("* 每次取款不能超过 5000 元 *n");printf("* 请重新操作 *n");pri

25、ntf("* *n");printf("* 1.返回 2.退出 *n");printf("* *n");printf("*n");switch(getch()case '1': qukuan();case '2': exit();YU_E=YU_E-z;success();/=/=存款函数=/void cunkuan()long int temp;system("cls");printf("*n");printf("* *n"

26、;);printf("* 请放入人民币 *n");printf("* *n");printf("* 取消 确定 *n");printf("* *n");printf("* *n");printf("*n");gotoxy(14,3);scanf("%d",&temp);while(temp<0)system("cls");printf("*n");printf("* *n");pri

27、ntf("* 非法存款 *n");printf("* 请重新放入人民币 *n");printf("* *n");printf("* 取消 确定 *n");printf("* *n");printf("*n");gotoxy(14,4);scanf("%d",&temp);YU_E=YU_E+temp;success();/=/=光标位置函数=/void gotoxy(int x,int y) COORD coord; coord.X=x; coord.Y=y; SetConsoleCursorPosition( GetStdHandle( STD_OUTPUT_HANDLE ), coord );/=/=简答延时函数=/void delay()long int bl1; int bl2;for(bl1=655356;bl1>0;bl1-)for(bl2=410;bl2>0;bl2-);/=/