C++与数据结构基础简明教程课后习题答案

1、精选优质文档-倾情为你奉上C+与数据结构基础简明教程课后习题答案 1-7-1/输出一个数的10倍#include <iostream>using namespace std;int main()         cout<<"Please input an interger:n"         int a;      &#

2、160;  cin>>a;         cout<<"result="<<a*10<<endl;         return 0;1-7-2/输出两个数中的较小的#include <iostream>using namespace std;int main()       

3、  double x,y,min;         cout<<"please input two numbers"<<endl;         cin>>x>>y;         min=(x>y?y:x);     &

4、#160;   cout<<"the smaller is"<<' '<<min<<endl;         return 0;1-7-3/输入半径计算周长和面积#include <iostream>using namespace std;int main()         cout<<"请输入半

5、径n"         double rad;         cin>>rad;         double c,s;         c=2*3.14*rad;       

6、0; s=3.14*rad*rad;         cout<<"周长是"<<c<<endl;         cout<<"面积是"<<s<<endl;         return 0;1-7-4/将10000秒化成小时分钟秒#include

7、 <iostream>using namespace std;int main()         int hour,min,second;         hour=10000/3600;         min=(10000%3600)/60;         s

8、econd=10000-hour*3600-60*min;         cout<<hour<<"hours"<<min<<"minutes"<<second<<"seconds"<<endl;         return 0;1-7-5/将一个三位数倒叙输出#include <io

9、stream>using namespace std;int main()int num,num_bai,num_shi,num_ge;cout<<"请输入一个三位数"cin>>num;num_bai=num/100;num_shi=(num-num_bai*100)/10;num_ge=num-num_bai*100-num_shi*10;cout<<num_ge<<endl;cout<<num_shi<<endl;cout<<num_bai<<endl;return 0

10、;2-3/简单的输入输出#include <iostream>using namespace std;int main()         double y,n;         cout<<"please input a numbern"         cin>>n;  

11、0;      if (n>0) y=n+1;         if (n<0) y=n*n;         if (n=0) y=0;         cout<<"the result is:"<<' '<<y;

12、0;        return 0;2-4/输出学生学号和对应的成绩等级#include <iostream>using namespace std;int main()         double fenshu;         int xuehao;         c

13、har dengji;         int i;         for (i=1;i<=10;i+)                            onerro

14、r:cout<<"please input student scoren"                   cin>>fenshu;                   if (fenshu&

15、gt;=90&&fenshu<=100) dengji='A'                   if (fenshu>=80&&fenshu<90) dengji='B'             

16、0;     if (fenshu>=600&&fenshu<80) dengji='C'                   if (fenshu>=0&&fenshu<60) dengji='D'       

17、0;           if (fenshu<0)                                     

18、0;         cout<<"error"                            goto onerror;       &#

19、160;                              if (fenshu>100)                  

20、                             cout<<"error"                  

21、;          goto onerror;                                      cout<<&

22、quot;the id is"<<i<<endl;                   cout<<"the score is"<<dengji<<endl;               &

23、#160;  return 0;2-5/判断输入字符类别#include <iostream>using namespace std;int main()char zifu;int ascii;cout<<"please input a characteristicn"cin>>zifu;ascii=zifu;if (ascii>=48&&ascii<=57)             

24、;     cout<<"数字n"         goto end;         if (ascii>=97&&ascii<=122)                  co

25、ut<<"小写字母n"         goto end;         if (ascii>=65&&ascii<=90)                  cout<<"大写字母n"

26、         goto end;         cout<<"其他字符"cout<<endl;end:return 0;2-6/求圆周率的近似值#include <iostream>#include <iomanip>using namespace std;int main()int xishu=-1;double danshu=1.0;int i=1;doubl

27、e sifenzhipi=0;do         xishu=xishu*(-1);         danshu=1.0/(2*i-1);         sifenzhipi=sifenzhipi+xishu*danshu;         i+;while(danshu&

28、gt;=0.);cout<<setprecision(15)<<sifenzhipi*4<<endl;return 0;2-7/输出斐波那契数列前40个数，以8*5的格式输出#include <iostream>#include <iomanip>using namespace std;int main()           int b=2;        

29、; int feibo1=0;         int feibo2=1;         cout<<setw(9)<<'0'<<setw(9)<<'1'         for(int i=1;i<=38;i+)     

30、;                       int a=feibo2;                   feibo2=feibo1+feibo2;    

31、0;              feibo1=a;                   cout<<setw(9)<<feibo2;           &

32、#160;       b=b+1;                   if(b%8=0) cout<<endl;                  return 0;2-8/统计输入的

33、元音字母个数#include <iostream>using namespace std;int main()         char zimu;         int a,e,i,o,u;         a=e=u=i=o=0;         begin:c

34、in>>zimu;         switch(zimu)                  case 'a' :a+;break;         case 'e' :e+;break;    

35、;     case 'i' :i+;break;         case 'o' :o+;break;         case 'u' :u+;break;         case '#' :goto end;   &

36、#160;              goto begin;end:cout<<a<<endl<<e<<endl<<i<<endl<<o<<endl<<u<<endl<<a+e+i+o+u;         return 0;2-10/计算5!+6!+7!#inclu

37、de <iostream>using namespace std;int main()         int i,j;         int sum=0;         for (i=5;i<=7;i+)            

38、;      int jiecheng=1;         for (j=1;j<=i;j+) jiecheng=jiecheng*j;         sum=sum+jiecheng;                 

39、 cout<<sum;         return 0;2-11/从2开始100个素数#include <iostream>using namespace std;int main()         int num=1;         int sushu=0;      

40、;   start:;         num+;         for (int i=2;i<=num;i+)                          

41、;  if(num%i=0) break;                  if (i=num)                            cout<

42、<num<<endl;                   sushu+=1;                  if(sushu!=100) goto start;      &#

43、160;  return 0;2-12/百钱买百鸡问题#include <iostream>using namespace std;int main()         int x,y,z;         for(x=0;x<=100;x+)               

44、;             for(y=0;y<=100;y+)                                   

45、            for(z=0;z<=100;z+)                                   &#

46、160; if (x+y+z=100&&5*x+3*y+z/3=100&&z%3=0) cout<<x<<'t'<<y<<'t'<<z<<endl;                           

47、return 0;2-13#include <iostream>using namespace std;int main()                 int a,b,c,d,e;         c=0;         cin>>a; 

48、        cout<<"输入"<<a<<endl<<"该数的三次方是"<<a<<"个连续奇数"         b=1;         e=a*a*a;      

49、60;  while (c!=e)                            d=b;                   c=0;

50、60;        for (int i=1;i<=a;i+)                                       &

51、#160;      c=c+d;                   d=d+2;                  b=b+2;      

52、60;           /cout<<b-2;         int f=b-4;         for (int j=1;j<=a;j+)                &

53、#160;           f=f+2;                   cout<<f<<' '               &#

54、160;  cout<<"的和n"         return 0;2-14/输出四方*形状#include <iostream>using namespace std;int main()         int i,j;         for (i=1;i<=9;i+)  

55、;                          j=1;                   for(j=1;j<=9;j+)   

56、60;                                           if(i+j>=6&&i+j<=14&&j-i<

57、=4&&i-j<=4) cout<<'*'                            else cout<<' '          

58、60;                 cout<<endl;                  return 0;3-1-1/向数组a中输入10个整数，求其中的最大值，最小值和10个数的算术平均值#include <iostream>using namespace

59、 std;int main()         int a10;         for(int i=0;i<=9;i+)                   cin>>ai;     

60、60;   int max=a0,min=a0,sum=a0;         for(int j=0;j<=9;j+)                            sum=sum+aj;   

61、                max=(max>aj?max:aj);                   min=(min<aj?min:aj);          

62、;        double ave=sum/10.00;         cout<<max<<endl<<min<<endl<<ave<<endl;         return 0; 3-1-2#include <iostream>using namespace st

63、d;int main()         int score10;         int sum=0,a=0,b=0;         for(int i=0;i<=9;i+)               

64、60;            cin>>scorei;                   sum=sum+scorei;               

65、60;  double ave=sum/10.0;         for(int j=0;j<=9;j+)                            if(scorej>ave) a+;   &

66、#160;               if(scorej<60) b+;                  cout<<"成绩大于平均值的人数是"<<a<<endl<<"成绩小于60的人数"<<

67、;b<<endl;         return 0;3-3-1#include <iostream>using namespace std;int main()         int a10,sum=0,min,max;         double ave;      

68、   int *ptoa=a;         for (int i=0;i<=9;i+)                            cin>>*(a+i);    &#

69、160;              sum+=*(a+i);                  min=*(a);         max=*(a);      

70、0;  for (int j=1;j<=9;j+)                            min=(min<*(a+j)?min:*(a+j);             &

71、#160;     max=(max>*(a+j)?max:*(a+j);                  cout<<max<<endl<<min<<endl;         ave=sum/10.0;     

72、;    cout<<ave<<endl;         return 0;3-3-2#include <iostream>using namespace std;int main()         int a10,sum=0,j=0,c=0;          

73、60;             /定义数组a，sum是各学生成绩之和，j是小于60的个数，c是大于平均值的个数         double ave=0;                     /定

74、义平均值         int *ptoa=a;                         /使用指针         for (int i=0;i<=9;i+)  

75、                   /输入并算和 ，统计小于60的                            cin>>*(ptoa+

76、i);                   sum+=*(ptoa+i);                   if (*(ptoa+i)<60)       &#

77、160;                                       j+;           

78、60;                         ave=sum/10.0;                     /计算平均值   

79、0;     /cout<<ave<<endl;                     /可以输出平均值         for (int k=0;k<=9;k+)       

80、            /计算大于平均值的                            if (*(ptoa+k)>ave)       

81、60;                                       c+;           

82、0;                         cout<<c<<endl<<j;         return 0;3-3-3#include <iostream>using namespace std;int main() 

83、0;       char string100;         cin>>string;         int i=0,an=0,in=0;         cout<<"您输入的字符串"     &#

84、160;   while (stringi!='0')                            if(stringi='a') an+;           

85、60;       if(stringi='i') in+;                   cout<<stringi;                 &

86、#160; i+;                  cout<<endl<<an<<endl<<in<<endl;         return 0;3-3-3a#include <iostream>using namespace std;int main()  &

87、#160;      char a100;                 /定义存放字符串的数组         char *ptoa=a;              

88、                  /使用指针         int i=0,an=0,in=0;                     

89、;    /an，in分别为a，i的个数         cin>>a;         while (*(ptoa+i)!='0')                    

90、0;     /a【i】                            cout<<*(ptoa+i);              

91、0;    switch (*(ptoa+i)                        /判断                     

92、;                          case 'a' : an+;break;                    

93、;        case 'i' : in+;break;                                      i+; 

94、                 cout<<endl<<an<<endl<<in;         return 0;3-3-4#include <iostream>using namespace std;int main()       

95、;  int a33;          for (int i=0;i<=2;i+)                            for(int j=0;j<=2;j+)    

96、                                           cin>>*(*(a+i)+j);     

97、;                                cout<<*(*(a+0)+0)+*(*(a+1)+1)+*(*(a+2)+2)<<endl;         cout<<*

98、(*(a+0)+2)+*(*(a+1)+1)+*(*(a+2)+0)<<endl;         return 0;3-3-5v1#include <iostream>using namespace std;int main()         int a11=2,4,5,8,12,14,16,18,20,30,0,b,i,m,j;      

99、0;  cin>>b;         a10=b;         if (b<2)                            m=0;&

100、#160;                  goto end;                  if (b>30)             

101、               goto end2;                  for(i=0;i<=9;i+)               

102、60;            if (ai+1>b)                                     

103、;          m=i+1;                            goto end;           

104、                 end:;         for (j=10;j>=m+1;j-)                      

105、0;     aj=aj-1;                  am=b;end2:;         for (int k=0;k<=10;k+)             

106、0;     cout<<ak<<endl;         return 0;3-3-5v2#include <iostream>using namespace std;int main()         int i,j,temp;         int a11=2,4,5,8

107、,12,14,16,18,20,30;         cin>>a10;         for (i=0;i<=10;i+)         for(j=0;j<=10-i-1;j+)            &#

108、160;                                  if(aj>aj+1)              

109、0;                                                  temp=aj+

110、1;                                     aj+1=aj;            &

111、#160;                        aj=temp;                        

112、0;                                               for (int k=0;k<=10;k+) cout<&l

113、t;ak<<' '         cout<<'n'         return 0;3-3-5v3#include <iostream>using namespace std;int main()         int a11=2,4,5,8,12,14,16,18,20,30,nu

114、m,i,j;         cout<<"请输入一个整数"         cin>>num;         if (num>a9)               &#

115、160;             a10=num;                  else                   

116、0;        for (i=0;i<=11;i+)                                        

117、;       if(ai>num)                                          &#

118、160;                      for(j=9;j>=i;j-)                         

119、                                                   

120、;        aj+1=aj;                                          &

121、#160;                               ai=num;                  

122、;                   break;                               

123、60;                                 for (i=0;i<=10;i+)                &#

124、160;           cout<<ai<<' '                  return 0;3-3-5final#include<iostream.h>void main()        

125、 int a11=2,4,5,8,12,14,16,18,20,30,b,i=0,j=10;         cin>>b;         while(ai<b&&i<=9)i+;         while(j>i)        

126、;           aj=aj-1;                   j-;                  ai=b;  

127、60;      cout<<"输入插入后的结果："         for(i=0;i<11;i+)cout<<ai<<" "         cout<<endl;3-3-6#include <iostream>using namespace std;int main()

128、0;        int a53,s5=0,0,0,0,0,temp;         for (int i=0;i<=4;i+)                           

129、; cout<<"请输入第"<<i+1<<"行的数据"<<endl;                   for (int j=0;j<=2;j+)               

130、;                                cin>>*(*(a+i)+j);               

131、0;            *(s+i)+=*(*(a+i)+j);                                     /*&#

132、160;        /注释掉的部分可以输出每行数据之和         for (int k=0;k<=4;k+)                            

133、       cout<<*(s+k)<<endl;                  */         for (int m=0;m<=4;m+)         for (int n

134、=0;n<=4-m-1;n+)                            if (*(s+n)>*(s+n+1)                &

135、#160;                   temp=*(s+n+1);                             

136、60;       *(s+n+1)=*(s+n);                                     *(s+n)=temp;  

137、60;                                                  &#

138、160;          for (int l=0;l<=4;l+)                            cout<<endl<<*(s+l);     

139、60;             cout<<endl;         system("pause");         return 0;4-3#include <iostream>using namespace std;int fun1(int x,int y);int fun2(

140、int x,int y);int fun3(int x,int y);int fun4(int x,int y);  int main()         int a,b;         cout<<"输入两个数"         cin>>a>>b;  

141、60;      cout<<"两个数的和的平方是"<<fun1(a,b)<<endl;         cout<<"两个数的平方和是"<<fun2(a,b)<<endl;         cout<<"两个数的差的平方是"<<fu

142、n3(a,b)<<endl;         cout<<"两个数平方的差是"<<fun4(a,b)<<endl;         return 0;   int fun1(int x,int y)         int z=(x+y)*(x+y); 

143、;        return z;  int fun2(int x,int y)         int z=x*x+y*y;         return z; int fun3(int x,int y)         int z=(x-y)*(x-y)

144、;         return z; int fun4(int x,int y)         int z=x*x-y*y;         return z;4-4#include <iostream>using namespace std;double jc(int x);int sm(int x);  &#

145、160;int main()         int m,n,s2;         double s1;         cin>>m>>n;         s1=jc(m)/(jc(n)*jc(m-n);    

146、;     s2=sm(m)-sm(n);         cout<<s1<<endl<<s2;         return 0;  double jc(int x)         double s=1;    

147、60;    for (int i=1;i<=x;i+) s*=i;         return s; int sm(int x)         int s=0;         for (int i=1;i<=x;i+) s+=i;      

148、;   return s;4-6#include <iostream>#include <cmath>using namespace std;double jxf(int n);double txf(int n);double f(double x);/const pi=3.;int main()         int n;         double y1,y2;  

149、       cin>>n;         y1=jxf(n);         y2=txf(n);         cout<<y1<<endl<<y2;       

150、0; return 0;  double jxf(int n)         double sum=0,s;         for (int i=0;i<=n-1;i+)                     

151、;       s=(i*3.14)/n;                   sum+=(3.14/n)*f(s);                  return sum;  

152、double txf(int n)         double sum=0,s1,s2;         for (int i=0;i<=n-1;i+)                        &

153、#160;   s1=i*3.14/n;                   s2=(i+1)*3.14/n;                   sum+=3.14/n*(f(s1)+f(s2);  

154、;                sum/=2.0;         return sum;  double f(double x)         double y;         y=sin(x

155、)+cos(x);         return y;4-6v1#include <iostream>#include <cmath>using namespace std;double jxf(int n);double txf(int n);double f(double x);const pi=3.;int main()         int n;     

156、;    double y1,y2;         cin>>n;         y1=jxf(n);         y2=txf(n);         if (abs(y1-2)>abs(y2-2) cout<<

157、;"矩形法"         else cout<<"梯形法"         return 0;  double jxf(int n)         double sum=0;         for (

158、int i=0;i<=n-1;i+) sum+=pi/n*f(i*pi/n);         return sum;  double txf(int n)         double sum=0;         for (int i=0;i<=n-1;i+) sum+=pi/n*(f(i*pi/n)+f(i+1)*pi/n);         sum/=2;         return sum;  double f(double x)    &#