计算方法之分线性方法求根

1、00111 axaxaxannnn0104)(23 xxxf310109*10000976562. 0 abcxeEPSababNNN 296. 92log31021103 NN)()(kkkkkkbfafxbax )()()()(kkkkkkkbabfafafax xxkkkk limlim1352 xx, 2 , 1 , 0,5231 kxxkk5 . 2)32(210 x,.2 , 1 , 0,2352231 kxxxkkk253 xx, 2 , 1 , 0,2531 kxxkky=xy=(x); 1151959082. 0)52(32)(,52)(32131 xx; 10)23()52

2、(6)(,2352)(2232232 xxx1580718866. 623)(),5(21)(2333 xx0sin21)( xxxfxxsin21 xxxxcos)( ,sin21)( kkxxsin211 222g 222kxgxkk limkkxx 21xx 2)( 121221)( xx kkxx 21y=xy= 1(x)y=xy= 2(x)cxxxxkkk *1*lim)(,)()()(*1*之之间间与与在在xxxxxxxxkkkkkk 1)()(limlim*1* cxxxxxkkkkk cxxxxkkk *1*lim1*2*1* kkkkxxxxxxxxkkkkkkxxxxxxx

3、 1221*2)()()1(1kkxx 预预估估)()1(1)2(1 kkxx 校校正正)2(1)1(12)1(1)2(112)( kkkkkkkxxxxxxx改改进进)( )(000 xxxfxfy y=f(x)(x0,y0)(x1,y1)(x2,y2)( )(0001xfxfxx )( )(1112xfxfxx )( )(1kkkkxfxfxx ; 0)( )(00 xfxf0)()( bfaf0)( xf0)( , 0)( xfxf0)( )(00 xfxf)( )()()(0000 xffxfxf 00, 0 xx;, 0)( )(010001xxxfxfxx 0)( )()()( )

4、( )( )()( )( )( )(0000000000001 xffxxxffxfxxfxfxxfxfxx 104320102)( )(2231 kkkkkkkkkkxxxxxxxfxfxx3x 302)(, 02)( , 0)2()1( xfxxfff)3(21)( )(1kkkkkkxxxfxfxx 0)()(00 xfxf,)(! 2)()()()(2kkkkkkkxxxxfxxxfxfxf 2*12*)()(2)()()(2)()()(kkkkkkkkkkxxxffxxxxffxfxfxx )(2)()()()(2)(2*1*2*1*kkkkkkkkxffxxxxxxxffxx cx

5、fxfxffxxxxkkkkkk )(2)()(2)(lim)(lim*2*1*)()()()(101011xxxxxfxfxfy )()()(0101112xfxfxxxfxx )()()(0202223xfxfxxxfxx )()()(001xfxfxxxfxxkkkkk )()()(111 kkkkkkkxfxfxxxfxx 0),(0),(21yxfyxf yxu0),(),()(21 yxfyxfuF *yxu0)(* uF 0)(),()(),(),(0)(),()(),(),(222111kkkkkkkkkkkkkkkkyyyyxfxxxyxfyxfyyyyxfxxxyxfyxf

6、 yyxfxyxfyyxfxyxfuFkkkkkkkkk),(),(),(),()(22110)()( kkkuuuFuF)()(1kkkkuFuFuu )()(11kkkkuFuFuu kkkuuu 1)()(1kkkuFuFu )(kuF )()(kkkuFuuF ,10kuuu ,1kuu ),max(kkyx 01),(04),(2221yeyxfyxyxfx 7 . 11000yxu 122)(2211xeyxyfxfyfxfuF 171828. 24 . 32)(0uF 01828. 011. 0),(),()(0020010yxfyxfuF)()(000uFuuF 01828. 011. 017