物理 欧姆定律 培优练习(含答案)及详细答案

经典word整理文档，仅参考，双击此处可删除页眉页脚。本资料属于网络整理，如有侵权，请联系删除，谢谢！一、初中物理欧姆定律问题R．．．．CR与AR与BR与UUIRRIRCCDRD．RLRL”A．RRabR122PU）RΩ1RΩ26VWCP0.8WI10.4A1U2V1P2U0.5W5VI20.1A2U电源RU1电源RU1电源10Ω1、UAC电源5V2R50Ω0.5W2当RΩB206V2U2P3.6WR10Ω1D。L）CL2UPRPIUAUI2.5V0.5ARΩLIIImaxLRUUU4.5V2.5V2V总LUI2VRΩ0.5A10ΩRmaxU4.5VΩ10ΩI0.3A总RRLUΩmaxmax3VC。R0()．．．QRBRIUU电UUIR电IU-IRU电I和U与AIU电IRU电URR电I01IURR电0RBPIRIRP22RR00是PI2R1RRRQRPR0I200Q与RCRRABUUI-RRRR0B0AUUUR-RRRRRAB0A0BUU-IRRRR10B0AUUURR-R0RRRRAB0A0B即1IUR0△I△UDR1）PBR1UIR100Ω500Ω故APUI3V0.005A0.015W故BPRC1R为D1。RRx0SSISS12121IR）2xIIIRR＝210R＝20xIxI21IR2I1IIR＝0R＝RIxIx01221CSSR与R120xISSR与RR1210x0IRIII2xx12IR2IRRR＝0I20xxI12。EARa端bCF与Lg取PaP在bR0R0R0CaRI，0a由R，a00bR与RI，0bb0000RA0R，a0RB0aR0PR），22a0在bR0PR），22b0RC0R==，总R，0总，，由=D．．．．．CABCDRVVCVVIIR两12UU12RUUUUUUII，122112RRRUU(II)R0.04A10Ω0.4V，2112R．．S（）RR21RR21CR2AR1BR2CRR12RD1。(0）Cm=VU==IUR1R。003R5P()ACRRRURIBImaxU4.5V0.6AR总7.5Ω，ImaxRRR7.5ΩΩ2.5Ω，滑min总UIR0.6A2.5Ω1.5V；minmax滑minUmaxRUUU4.5V3V1.5V，RmaxUImin，RRΩ3VUIR10Ωmax，0.3A滑maxminCRSV表22S1）VA12RR13RR和RVR和RVR和R123112223SVU21VA1AR和RAR和R中123212R2UI==2RΩ2R3I=I−I32故DR3UR==Ω3I3Ω20ΩURR==23UU1U由=IR1RUIR=11=Ω故CA和RR212UI=′+=I+=I212RΩ1故BRRR12）S1S3SSS123SS13SR12SR与RR31SSSR与R1232R2SSR与RRR1312SR12A正SR与RR31PRR1UU1RUUR11RIIBSSSR与R1232RP向2UIRCSSR与RRR1312URPIR2D。二、初中物理欧姆定律的实际应用问题RLRLCRLRRDCRP从a0到b（）R0PbCPaIRR100PbUR滑==20滑I2UUR滑00U2PR可R0a。知RRRR1234）与ARR与ARR12121312与ARR与ARR24233423②B③④④①AAR211A与A①A与A1213URR和RRR②1212IUIA与AR24'RRRR1R2RR12R'RR34即RR1RR2RR3412RR1RR-R2R3412RR1RRR1RR-RR--RR-RRR0222RRRRR23242424121212③R2R3④中RA与A234UIRRRR234RR④23。P从A）VAAA112VAVA11CR与RA测RA测R011021AP从ARA01VARA01URIR1AB2VAVA11VACD1。RQ）UUUUAURUAC，．bR，R，12﹣IR，RR121R）2ARRR122过RRRRR11212。RP）R0AARB0CPUID。）SVVA112的SVA31不变SVV212量SSR131SR和VVRRV1111232RVA32