六西格玛黑带考试试题库共147题(含答案)

D第一阶段:阶段(20第一阶段:阶段(20界定阶段×1)1．6SIGMAA.GEB.摩托罗拉C.三星A.韩国3．6SIGMAB.减少缺陷降低成本C.A+BB.6SIGMA味着百万机会中缺陷数为3.4C.6SIGMA味着公差界限内能容纳6个D.6SIGMA于CP=2,CPK=1.55．KANOB.一元质量6．下列内容中哪一个不是6SIGMA组织结构A)ChampionB)MBBC)GBD)BBE)CFO7．6SIGMA论是：A.DMAICB.PDCAC.PSPD.SPC8.6SIGMAA.企业D.企业9.收集了个关于比萨饼配送的数据,发现有25迟到,10太冷,7损失,8错500误的成分,请计算DPMOA.5%B0.1C.100000D.25000A.1)+2)B.1)+2)+3)C.1)+2)+3)+4)1)流程范围2)组织范围3)工作场所范围4)产品范围A.1)+3)B.2)+3)C.1)+4)D.2)+4)A.流程分析B.因果分析C.项目相关方分析B.P是产品C.O是输出D.C是顾客920145.15A80%B60%C61.4%A都不满足BA不满足CA．60.94%B.7.75%C.78.06%D.27.85%Variance(ofVariance)RepeatabilityB.可行但需要改进C完全不可行Reproducibility5.6676Part-to-PartTotalVariationB.测量仪器C.零部件73.0981100.00RepeatabilityReproducibility2.38068Part-to-PartTotalVariationStudyVar%StudyVar(5.15*SD)(%SV)t121417192123252729l121416182123252729A.SummaryforPulse195%ConfidenceIntervalsA.FileB.DataC.StatD.GraphA.FileB.DataC.StatD.GraphA.1-tB.2-tC.1-ZD.1-PTestofmu=0.13vsnot=0.13Theassumedstandarddeviation=0.015100.1360000.004743(0.126703,0.145297)1.260.206A.生产正常B.生产不正常C.无法否认生产正常1030.91042.01046.01035.01056.81050.01035.31037.61046.01046.4，试问在显著性水平0.05A.1-tB.2-tC.1-ZD.1-PTestforEqualVariancesforPulse1TestStatisticTestStatistic95%BonferroniConfidenceIntervalsforStDevsPulse1A.1-tB.2-tC.1-PD.2-PBoxplotofHeightvsSexth68iA.散点图B.茎页图A.提出原因B.找到关键YC.提出改进方案D.确认关键原因改进阶段(20×1)回归分析、方差分析、DOEAAa．f=1b．f=3AAc．f=6=5d．fAATa．f=4=9b．fTTc．f=19=25d．fTTea．f=16=6b．feec．f=1=4d．fee165o6%8%10%1928353.32107.184.853.6389.395.756.0MINITABOne-One-wayANOVA:6%,8%,10%SourceDFSSMSFPFactor22943.41471.731.220.001Error6282.947.1Total83226.3S=6.866R-Sq=91.23%R-Sq(adj)=88.31%Individual95%CIsForPooledStDevLevelNMeanStDev--+---------+---------6%396.139.598%387.836.87(10%354.301.48(-----*-----)--+---------+---------48648B．6%与Scatterplotofyvsx5856545250y48464442400.050.10x0.150.20Worksheet:Worksheet1;2004-11-8;shippingcenterefficiencyPearsoncorrelationofxandy=0.950Theregressionequationisy=35.45+92.64xS=1.85366R-Sq=90.3%R-Sq(adj)=89.1%AnalysisofVarianceRegression1255.412255.41274.330.000827.4889282.900A.线性关系是显著的B线性关系是不显著的C无法判断线性关系Theregressionequationisy=40.64-30.48x+550.5x**2S=0.969896R-Sq=97.7%R-Sq(adj)=97.0%AnalysisofVarianceRegression2276.315138.158146.870.0009282.900SequentialAnalysisofVariance1255.41274.330.000Quadratic120.90422.220.002A.FactorialB.ResponseSurfaceC.MixtureA.FactorialB.ResponseSurfaceC.MixtureA.1B.2C.3D.4GeneralLinearModel:结果versusA,B,CSourceDFSeqSSAdjSSAdjMSFP21421.61421.6710.812.230.07625686.95686.92843.448.930.0202427.6427.6213.83.680.214Error2116.2116.258.1Total87652.2LeastSquaresMeansfor结果AMeanSEMean1185.04.4012198.04.4013167.34.4011161.74.4012218.74.4013170.04.4011185.04.4012174.34.4013191.014.4074.在=0.1下,哪些因子是显著的A.BB.A和BC.A、B和CD.A和CA.AB1CB.AB1C2C.AB2C3D.A2C1322MainEffectsPlot(fittedmeans)果for22020018016090011001300101112ofnea220M200180160708090Worksheet:Worksheet1;2004-11-10;shippingcenterefficiencyNormalProbabilityPlotoftheStandardizedEffects(response结果,Alpha=.05)99959080AEffectTypeNotSignificantSignificantFactorABCDNametnecer7060504030201051BC-5.0-2.50.02.5StandardizedEffect5.0Worksheet:Worksheet3;2004-11-10;shippingcenterefficiencyA.AB.BCC.DD.A+BA.多路传输B.SWOT分析D.TOC分析StDev(Within)3.09252m-1a-24.[1](多选)六西格玛管理方法:5.[1](多选)推进六西格玛管理的目的就是要6.[2]在质量功能展开(qualityfunctiondeployment,QFD)中,首要的工作是:D.关联图C.规范期1.项目目标4.项目团队成员D.1,2,3,和412.[3]在项目特许任务书(teamcharter)中,需要陈述"经营情况"(businessA.为什么要做该项目13.[3](多选)亲和图(affinitydiagram)可应用于以下场合:A.选择最优方案14.[4]有关质量成本的描述,正确的是:(35,45〕(45,55〕(55,65〕(65,75〕析后发现重复性(repeatability)标准差为3微米,再现性(reproducibility)标Cp=1.65,Cpk=0.92.这时,应该对生产过程作出下列判断:34.[6]回归方程^Y=30-X中,Y的误差的方差估计值9,拟合回归方程的数据点超A.(23,35)B.(24,36)C.(20,38)D.(21,39)35.[6](多选)在下列哪些情况中可以使用方差分析方法:Factorialfit:yversusA,B,C,DAnalysisofVariancefory(codedunits)Main