医学基础化学课件

大学化学（1）

医学基础化学

分组地点1组72022组72163组7217医学基础化学实验（1）山东大学学院总览化学院化工学院示范中心无机及分析化学实验网络资源(多种形式)基础化学实验操作内容简介（观看一、五、六、七）实验1内容：

实验基本操作、酸碱标准溶液的配制与标定（实验十六）网络教学：实验循环1

实验一粗食盐精制（7202）实验九

醋酸电离平衡常数的测定（7216）实验三、十七分析天平的使用硼砂含量测定（7217）基础化学实验操作内容简介观看（二、三、四、八、九）网络教学：进入方法：山东大学学院总览化学院化工学院示范中心无机及分析化学实验网络资源(多种形式)医学基础化学实验（1）考核方法

采取平时和期终两种考核相结合方法:

平时考核：出勤情况、实验预习、实验过程、实验操作、实验报告、实验安全卫生等。

2.期终考核：考核学生的基本操作技能或多种形式。（涵盖所有实验内容的相关技能操作）

平时成绩占70％、期终成绩占30％。CHAPTERONE

SOLUTION

1-1BasicTermsofSolution1-2Solubility

ofSolution1-3SolutionConcentration1-4ColligativePropertiesofSolutions问题：

生理盐水？等渗溶液？溶液浓度、稀溶液的依数性、渗透及渗透压概念有关（5%GS、50%GS）（0.9%NaCl）

肾脏衰竭的治疗方法——血液透析原理？为什么临床输液要注意所输入溶液的浓度和体积呢？生物膜与疾病1-1

BasicTermsofSolutionAsolutionisahomogeneousmixtureoftwoormoresubstancesevenlydistributedineachother.Whenoneofthesesubstancesisaliquidandtheothersareso1idsorgases,wetendtothinkoftheliquidasthesubstancethatdissolvesthesolidorgas.Theliquidisreferredtoasthesolvent

andthesolidsandgasesasthesolutes.Suchinteractionsbetweensoluteandsolventmoleculesisknownassolvation(溶剂化).Whenthesolventiswateritisknownas

hydration.（水合）

2.Molarity(c):

molessolute/Liter

solution

3.Molality*(mB)

：molessolute/Kgsolvent4.MoleFraction(x):waysofexpressingconcentration:1-3SolutionConcentration1.Amount-of-substanceConcentrationc（物质的量浓度）（体积摩尔浓度）（质量摩尔浓度）（摩尔分数）1.Amount-of-substanceConcentration——isaconcentrationunitequaltotheamount-of-substanceofsolutedissolvedinaliterofsolution

nB(mol)

or

cB=(mol/L)

V(L)eg:58.5gofNaClisdissolvedinenoughwatertogive1Lofsolution,whatistheAmount-of-substanceConcentrationofthesolution?

Answer:cNaCl=1mol/L2.Molarity(c):

_____molessolute/Litersolution

nB

cB=V

Molarity(c):

≈

Amount-of-substanceConcentrationEg:If0.435gofKMnO4isdissolvedinenoughwatertogive250.mLofsolution,whatisthemolarityofKMnO4?

Solve:thefirststepistoconvertthemassofmaterialtomoles.0.435gKMnO4•1molKMnO4=0.00275molKMnO4158.0gKMnO4MolarityKMnO4=

0.00275molKMnO4=0.0110mol/L 0.250Lsolution3.

Molality_____molessolute/kgsolventMolalityisaconcentrationunitequaltotheamount-of-substanceofsolutedissolvedinakilogramofsolvent.

amount-of-substanceofsolute(nB)Molality(mB)=massofsolvent(mA)

nB

or

mB=

mA

若将58.5gNaCl溶于1kg水，所得溶液的质量摩尔浓度是1mo1/kg4Molefraction

(Amount-of-substanceFraction)

MolesofA(Amount-of-substanceofA)MolefractionofA=Sumofmolesofallcomponents(组分)

ornA

xA=

nA+nB+…它表示某物质的物质的量与混合物的总物质的量之比，常以符号“x”表示，它没有单位。AlcoholsolutionnH2O=2molnalcohol=3mol

nH2OxH2O=nalcohol+nH2O

=2/(2+3)=0.4SolutionsBy“Parts”Partspermillionisthenumberofparticlesofsoluteperone-millionparticlesofsolution.1ppm=1mg/L(10-3)Partsperbillion（十亿）isthenumberofparticlesofsoluteperone-billionparticlesofsolution.1ppb=1µg/L(10-6)Partspertrillion（万亿）

isthenumberofparticlesofsoluteperone-trillionparticlesofsolution.1ppt=1ng/L(10-9)等物质的量的反应规则关于浓度，细读中文书p8-101-4ColligativePropertiesofSolutions

1VaporPressureLowering

2

BoilingPointElevation

3

FreezingPointDepression

4Osmosisand

OsmoticPressure5TheColligativePropertiesofElectrolyteSolution6Isotonic(等),

Hypotonic(低),Hypertonic(高)Thefirstdependsonthenatureofsolute

eg.Color、electricandthevolumechangeThesecond

notdependonthenatureofsoluteeg.vaporpressure、boilingpoint、freezingpointandosmoticpressure1-4ColligativePropertiesofSolutionsTwokindsofpropertiesofasolution:colligativeproperty:

——

Allthesepropertiesdependonthecollectiveeffectofthenumberofdissolvedparticlesratherthanonthenatureoftheparticlesinvolved依数性指溶液的某些性质与溶质的粒子数的多少有关，与溶质本性无关。通性(1)theloweringofthevaporpressureofthesolutionrelativetothatofthepuresolvent,(2)theelevationoftheboilingpoint,

(3)thedepressionofthefreezingpoint,(4)thephenomenonofosmoticpressure.colligativepropertynonvolatile,nonelectrolytedilutesolution依数性

难挥发性非电解质稀溶液Evaporation

istheprocessbywhichwaterisconvertedfromitsliquidformtoitsvaporform.1-4.1LoweringofVaporPressureEvaporationisasurfacephenomenon-somemoleculeshaveenoughkineticenergytoescape.蒸发的2个条件：质点的动能足够大；运动的方向指向液体表面Condensationisthechangeofwaterfromitsgaseousform(watervapor)intoliquidwater.Ifthecontainerisclosed,anequilibriumisreachedwhereanequalnumberofmoleculesreturnto

thesurface.

SaturatedVaporPressureEquilibrium:

ν

rateevaporation

=ν

ratecondensation.Atthispointthevaporissaidtobesaturated,andthepressureofthatvaporiscalledthesaturatedvaporpressure.Thepressureofthisequilibriumiscalledthevaporpressure.

LoweringofVaporPressure(a)vaporpressureofpuresolvent(b)vaporpressureofsolutionpopΔp=po-pAdilutesolution:Vaporpressure(p)ofisdirectlyproportionalto

molefractionofthesolvent.

p∝

xA

xAismoleofsolvent

Theconstantisthevaporpressureofpuresolventp°

p=p°xA……（经验公式）比例系数xA+xB=1p=po

xA

=po(1-xB)=po-poxB∴po-p=poxB

Δp=poxB

Raoult’slaw:

Vaporpressurelowing(Δp)ofadilutesolutionthatcontainingnonvolatile,nonelectrolyteisdirectlyproportionaltotheamount-of-substancefractionofthesoluteandhasnothingtodowiththenatureofsolute.Raoult’slaw在一定温度下，难挥发非电解质稀溶液蒸气压下降Δp与溶质的质量摩尔分数xB成正比，而与溶质的本性无关

Foradilutesolution

nA>>nB，(nA+nB≈nA)

Δp=K

bB(1-9)Suppose:solventis1000g

Δp=K

bBmBmB若以水为溶剂，1kgH2O中含有nB在数值上mB≈nB

Raoult’slaw:Vaporpressurelowingofadilutesolutionthatcontainingnonvolatile,nonelectrolyteisdirectlyproportionaltothemolalityofthesolutionandhasnothingtodowiththenatureofsolute.

Δp=KmBRaoult’slaw:在一定温度下，难挥发非电解质稀溶液蒸气压下降Δp与溶液的质量摩尔浓度mB成正比，而与溶质的本性无关。

Raoult’slaw:Δp=KmBT（温度）ppuresolventsolutionsolutionFigure1-1Thevaporpressureofsolution稀溶液的mB大，粒子数目越多，溶液的p越低，Δp

越大。VaporPressureLoweringDescribewhatishappeninginthepicturesbelow.Usetheconceptofvaporpressureloweringtoexplainthisphenomenon.1-4.2ElevationofBoilingPointWhy?anti-freeze（防冻剂）(orsalt)?汽车散热器中的溶液作用

保护发动机——冬季免于冰冻

——夏季免于高温increasingtheboilingpointNormalBoilingPoint:

H2OTb=1000C

boiling

PH2O=P外=101.3kPa

Aboutsolution

T=1000Cnoboiling

PH2O≠P外≠101.3kPa

Figure1-2ThevaporpressureofsolutionislowerAboutsolution

T=1000CPH2O≠P外≠101.3kPa

BoilingPointElevation

Δ

Tb=(Tb-Tb°)

Tb°_b.p.ofpuresolvent

Tb_b.p.solventinsolution

ΔTb=KbmBKb

isdifferentfordifferentsolvent大量的实验得出溶液的沸点升高与质量摩尔浓度有如下关系Kb为溶剂的摩尔沸点升高常数

Table1-1Boiling-PointelevationandFreezing-PaintDepressionConstants

SolventFormulaTb(℃)Kb

Tf(℃)Kf

AceticacidCH3COOH118.13.07173.9

BenzeneC6H680.12.535.54.9

CarbontetrachlorideCCl476.75.03-22.932

DiethyletherC4H10O34.72.02-116.21.8

EthanolC2H5OH78.41.22-114.7-

NaphthaleneC10H8--80.56.8

WaterH2O100.00.5120.01.86

萘二乙醚1-4.3DepressionofFreezingPointFreezingPoint:

-Temperatureatwhichaliquidcongeals(凝固)intothesolidstateatagivenpressure.

P液=P固凝固点是溶剂的固相与液相平衡共存的温度

Water

00CP固相=P液相（固-液两相共存）00C以上P固相〉P液相（冰溶化）00C以下P固相〈P液相（水转化为冰）Freezepiont：

H2OT=0℃P液=P固

|Aboutsolution

T=0℃P固

≠P液

0

solution：0℃

P溶液＜

P冰（冰吸收热量融化，使体系温度降低）

Figure1-2Thevaporpressureofsolutionislower0.610ab

ΔTf=KfmBKfisthemolalfreezingpointdepressionconstantofthesolvent.

Kfis

differentfordifferentsolvent

Δ

Tf=(Tf°-Tf)

Tf°_f.p.ofpuresolvent

Tf_f.p.solventinsolution

DepressionofFreezingPointΔ

Tf

Table1-1Boiling-PointelevationandFreezing-PaintDepressionConstants

SolventFormulaTb(℃)Kb

Tf(℃)Kf

AceticacidCH3COOH118.13.07173.9

BenzeneC6H680.12.535.54.9

CarbontetrachlorideCCl476.75.03-22.932

DiethyletherC4H10O34.72.02-116.21.8

EthanolC2H5OH78.41.22-114.7-

NaphthaleneC10H8--80.56.8

WaterH2O100.00.5120.01.86

萘二乙醚[例]取0.749g谷氨酸溶于50.0g水，测得凝固点为－0.188℃，试求谷氨酸的摩尔质量。解：利用公式，ΔTf

＝Kf·mB所以M＝148（g·mol－1）按谷氨酸的分子式[COOHCHNH2(CH2)2COOH]计算，其摩尔质量应为147g·mol－1。DeterminingMolecularWeight(p21)

[例1-9]乙二醇CH2(OH)CH2(OH)是一种常用的汽车防冻剂，它溶于水并完全是非挥发性的（b.p.197℃）。

计算在2505g水中溶解651g该物质的溶液的凝固点。夏天能否将它用于汽车散热器中？乙二醇的摩尔质量是62.01g/mol。解：溶液的质量摩尔浓度ΔTf

＝Kf·mB＝1.86×4.19＝7.79(K)因为纯水的凝固点是273K，该溶液凝固点Tf＝273-7.79＝265.21K沸点升高ΔTb＝0.52×4.19＝2.2（K）此溶液在375.2K沸腾，所以夏天它能用于汽车散热器中防止溶液沸腾。DeterminingMolecularWeight(p21)

Dissolves2.06gofanunknownsolidsubstancein164gofcyclohexane(C6H12环己烷)anddeterminesthatthefreezingpointofthissolutionis4.76℃.Thefreezingpointofpurecyclohexaneis6.47℃;theKf

is20.0Kkg/mol.Whatisthemolecularweightoftheunknownsolid,(Assumethatitisnonionizableandnonvolatile.)

Solution:Thefreezing-pointdepressionisΔTf=freezingpointofpuresolvent-freezingpointofsolution=6.47℃-4.76℃=1.71℃accordingtoΔTf

=KfmB

mB=ΔTf/

Kf

=1.71/20.0=0.0855(mol/kg)Amount-of-substanceofsolute(nB)=0.164kg×0.0855mol/kg=0.0140moln=m/MMolarmassunknown=2.06g/0.0140mol=147g/mol1-4.4OsmoticPressureOsmosis

——isthespontaneousmovement(自发运动)ofwateracrossasemi-permeablemembranefromanareaoflowsoluteconcentrationtoanareaofhighsoluteconcentration渗透达平衡：溶液与纯溶剂之间产生——压力差π

π

：由于溶剂渗透造成的，所以将其称为渗透压。

π

：维持渗透平衡所向溶液上方施加的最小压力。单位是Pa或kPa。

实验证明：在一定温度下，π与它的浓度成正比；在一定浓度时，π与绝对温度成正比。1886年荷兰物理化学家范托夫（van’tHoff）综合上述实验结果，指出稀溶液的渗透压与温度、浓度的关系同理想气态方程一致：

πV＝nRTπ＝

cRT

Foradilutesolution,公式的意义在于：一定温度下，溶液的渗透压与溶液的质量摩尔浓度成正比，也就是说:与溶液中所含溶质质点的数目成正比，而与溶质的本性无关。

π＝

cRT

π＝

mBRT

难挥发非电解质稀溶液依数性总结Δp=KmB

ΔTb=Kb

mBKb=0.512ΔTf=

Kf

mBKf=1.86Π=RTmB

Problem1.Whatwouldtheboilingpointofasolutionbeif18.0gofglucoseweredissolvedon1000gofH2O?freezingpoint?OsmoticPressure？2.Whatwouldtheboilingpointofasolutionbeif5.85gofNaClweredissolvedon1000gofH2O?解ΔTb=Kb

mB=0.52×0.10=0.052Tb

=100+0.052=100.0521-4.5TheColligativePropertiesof

ElectrolyteSolution

Δp=i

KmB

ΔTb=iKb

mB

ΔTf=iKf

mB

i-Van’tHofffactor

Π

=i

RT

mB

Forglucose

i=1;forKNO3

i=2;forMgCl2,i=31-

4.6

Isotonic,Hypotonic,HypertonicSolutionOsmosis—isimportantinmanybiologicalprocessesAcellmightbethoughtofasanaqueoussolutionsurroundedbyasemipermeablemembrane.Thesolutionssurroundingcellsmusthavethesameosmoticpressure.Otherwise,waterwilleitherleavethecell,

dehydrating（脱水）it,orenterthecell,causingittoburst（溶胀）——hemolysis（溶血）.OsmosisandBloodCells(a)Acellplacedinanisotonicsolution.Thenetmovementofwaterinandoutofthecelliszerobecausetheconcentrationofsolutesinsideandoutsidethecellisthesame.(5%C6H12O6)(b)Inahypertonicsolution,theconcentrationofsolutesoutsidethecellisgreaterthanthatinside.Thereisanetflowofwateroutofthecell,causingthecelltodehydrate,shrink,andperhapsdie.(50%C6H12O6)(c)Inahypotonicsolution,theconcentrationofsolutesoutsideofthecellislessthanthatinside.Thereisanetflowofwaterintothecell,causingthecelltoswellandperhapstoburst.(1%C6H12O6)1-4.7Osmolarity（渗透物质的量浓度）

Osmolaritycos

（mol/Lor

mmol/L).

isthemeasureofsoluteconcentration,definedasthenumberofosmoles(Osm)ofsoluteperliterofsolution渗量浓度cos

__指1L溶液中能产生渗透效应的各种溶质微粒（分子或离子）的总物质的量。例

计算医院补液用的50.0g·L-1葡萄糖溶液和9.00g·L-1NaCl溶液(生理盐水)的cos.解葡萄糖的摩尔质量M=180g·mol-1，50.0g·L-1C6H12O6

溶液的渗量浓度为：NaCl的摩尔质量M=58.5g·mol-1，9.00g·L-1NaCl溶液的渗量浓度为：Bodyfluids：280-320mmol/LBodyfluids：Π?Fordilutesolutions,osmolarityisexpressedinmilliosmolsperliter(mOsm/L).Whatistheosmolarityofa0.9%NaClsolution?

osmolarity=molarity×i1000=0.9%×-----------------

×2=0.308Osm/L

100×M(58.5)

(308mOsm/L)

Whatistheosmolarityofa5%glucosesolution?Solution:Glucoseisanonelectrolyte;

numberofparticlesosmolarity=molarity×-------------------------=molarity×i

moleculeofsolute1000=5%×-----------------

×1=0.277Osm/L

100×M(180)

=277mOsm/L

Edema（水肿）

occur1-4.8CrystalloidOsmoticPressureand

ColloidalOsmoticPressure

1-4.8CrystalloidOsmoticPressureand

ColloidalOsmoticPressure

CrystalloidOsmoticPressure(772KPa)byNaCl,NaHCO3,regulate（调节）balanceoffluidandelectrolyteonthetwosideofcellwall

ColloidalOsmoticPressure(2.93~4.00KPa)bylargemolecular(Protein）regulatebalanceoffluidandelectrolyteonthetwosideofbloodcapillarywall.

CrystalloidOsmoticPressurColloidalOsmoticPressure?Crystalloid

OsmoticPressure

Iflackofwaterinthebody,theoutsidefluidsofcellsbecomehypertonic,canleadtodehydratio

Ifwaterintakeistoomuch,theoutsidefluidsofcellsbecomehypotonic,canleadtohemolysis(溶血),

Iftheproteininplasmabecomelessbecausesomedisease,ColloidalOsmoticPressurebecomeless,smallmoleculesosmosistotheoutsideofbloodcapillarywall,sotheedema（水肿）occur.672-1StrongandWeakElectrolyteSolution

2-1.1TheoryofStrongElectrolyteSolutionIon-ionInteraction

TheoryFigure2-1Ionatmosphereofstrongelectrolytesolution68IonActivityandActivityCoefficientActivity(a):

Ionconcentration,whichcanplayarealactioninsolutionisioniceffectiveconcentration,iscalledionactivity.

actualconcentrationofion(c)multiplyacorrectionfactor-activitycoefficient(f).

a=f·c

(2-1)Generally,

a＜c,0＜f＜1

69Activitycoefficientareinfluencedby

ionconcentration

theelectric-chargenumberofion

hasnothingtodowiththenatureofion.70

IonicStrength(I)Where,Iisionicstrength;cistheamount-of-substanceconcentrationoftheioni;

ziisthechargenumberoftheioni.Notethattheactivityisforanion;theionstrengthisforasolution.71Table2-1Ionactivitycoefficientandion

strengthofsolution72Example2-1

25ml0.02mol/LHClmixedwith25ml0.18mol/LKCl,calculateactivityofH+?Solution:

(1)calculatetheionstrengthofthesolution:I=(0.01×12+0.01×12+0.09×12+0.09×12)/2=0.1(2)lookuptheactivitycoefficientofionhasonecharge:

whenI=0.1,Z=1,f=0.78(3)calculatetheactivityofH+(aH+)cH+=0.02/2=0.01mol/L,f=0.78So,aH+=f·c=0.78×0.01=0.0078(mol/L)732-1.2IonizationEquilibriumof

WeakElectrolyteSolution

ThelawofChemicalEquilibrium(EquilibriumConstant)aA+bB→cC+dD

[C]c[D]d

K=------------(2-3)[A]a[B]b

74

IonizationConstant(Ki)

HAc+H2OH3O++Ac-

orsimplyHAcH++Ac-Thecorrespondingequilibrium-constantexpressionis[H+][Ac-]

K

i=------------(2-4)[HAc]75

DegreeofIonization(α)1.Definition:

Numberofionizedmoleculesα=----------------------------×100%

totalnumberofsolutemolecules

Numberofionizedmolecules=-----------------------------------×100%ionizedmolecules+non-ionizedmolecules

concentrationofionizedweakelectrolyte

=----------------------------------×100%

initialconcentrationofweakelectrolyte

762.Thefactorofinfluencingdegreeof

ionization①thenatureofsolute:18℃，0.1mol/L,αHAc=1.33%,αH2S=0.07%,

αHCN=0.007%②theinitialconcentrationofsolute:(themoredilutethesolution,thegreaterthedegreeofionization).③temperature:77DilutionLaw

HAH++A-

cα

Initialc

c00Equilibrium

c–cα

cαcα

concentration

[H+][A-]cα·cαcα2

KHA=------------=----------=-------

[HA]c-cα

1-α

ForKaisverysmall,αisverysmall,1-α≈178

KHA=cα2

orPhysicalmeaning:Notethatabovedilutelawonlyisforsomegivenconditions:(1)theweakelectrolytemustbemonoprotic(2)α≤5%79TheCommonIonEffectandSaltEffect1.Commonioneffect

Theionizationofaweakelectrolyteismarkedlydecreasedbytheaddingtothesolutionanioniccompoundcontainingoneoftheionoftheweakelectrolyte,thiseffectiscalledthecommonioneffect.Forexample,HAcAc-+H+

NaAc→Ac–+Na+shifttheequilibriumfromrighttoleft,decreasingthe[H+].802.SalteffectTheionizationofaweakelectrolyteisincreasedbyaddingtothesolutionansolublestrongelectrolytewhichnotcontainsthecommonionwiththeweakelectrolyte.Thiseffectiscalledsalteffect.Forexample:0.1mol/L[HAc]α=1.33%,addingNaCl,[NaCl]=0.1mol/L,α=1.68%81Example:

Thereisasolutionofc(HAc)=0.1mol/L,ifweaddNaAc,whenc(NaAc)=0.1mol/L.CalculatetheαofHAc.Solution:HAcH++Ac-Initialc0.100Equilibriumc0.1-[H+][H+]0.1+[H+]≈0.1≈0.1[H+][Ac-][H+]×0.1Ka=-------------=------------=[H+]=1.8×10-5[HAc]0.1

α=[H+]/[HAc]=0.018%＜＜1.33%822-2.2Bronsted-LowryAcidsand

Bases

1.Definitionofacidandbase

Acid

-isasubstancecapableofdonatingaproton.

HCl,NH4+,HSO4-,H2OBase

-isasubstancecapableofacceptingaproton.

Cl-,NH3,HSO4-,OH-2-2TheoryofAcid-base83AHClbaseacidConjugateacid-basepairH++BH++Cl-H2CO3H++HCO3-HCO3-H++CO32-NH4+H++NH3H3O+H++H2OH2OH++OH-84Conclusion:Acidorbasemaybeamolecule,atom,orion.Somemoleculesorionsarecapableofdonatingaproton,andalsoacceptingaproton,whichnamedampholyte.Therearenoconceptsofsaltinacid-baseprotontheory.852.EssenceofAcidandBaseReactionEssence:protontransferreaction.Forexample:HCl(g)+NH3(g)H+conjugateNH4++Cl-A1+B2A2+B186(1)

ComparebyK

aorKb

HAc+H2OH3O++Ac-[H3O+][Ac-]

Ka=──────

[HAc]H+ThesmallerthevalueforK

a，theweakertheacid；

ThegreaterthevalueforK

a，thestrongertheacid.

3.RelativeStrengthofAcidsandBases87Ac-+H2OHAc+OH-[HAc][OH-]Kb=──────

[Ac-]

H+ThesmallerthevalueforKb，theweakerthebase；ThegreaterthevalueforKb，thestrongerthebase.88

TherelationshipbetweenKaandKb:

Ka×Kb=K

w(2)Therelationshipbetweenacid-basestrengthandsolventH2OweakacidNH3strongacidHNO3

H2OstrongacidHAcweakacidH2SO4basesubstanceHAc

894.TheLevelingEffectand

DifferentiatingEffectThelevelingeffect:

Theinabilityofasolventtodifferentiateamongtherelativestrengthsofallacidsstrongerthanthesolvent’sconjugateacidisknownasthelevelingeffect.Becausethesolventissaidtolevelthestrengthsoftheseacids,makingthemseenidentical.levelingsolvent:Strongacid

suchas

HClO4,HCl,HNO3,H2SO4willappeartobeofequalstrengthinaqueoussolution.90Strongacids--hydrochloricacid(HCl),nitricacid(HNO3),perchloricacid(HClO4),andsulfuricacid(H2SO4),forexample-areallstrongelectrolytes.Theymaybeassumedtobecompletelyionizedinwater.HCl(aq)+H2O(1)→H3O+(aq)+Cl-(aq)HNO3(aq)+H2O(1)→H3O+(aq)+NO3-(aq)HClO4(aq)+H2O(1)→H3O+(aq)+ClO4

-(aq)H2SO4(aq)+H2O(1)→H3O+(aq)+HSO4

-(aq)wecannotdeterminetheirstrength,becauseH3O+isthestrongestacidthatcanexistinaqueoussolution.

Forstro