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2026届长沙市六年级数学小升初分班考试QS01黑白可打印标准付费预览仿真卷B1第0360套(含参考答案、逐题解析、评分细则、压轴题讲评与学生作答空间)考试时间:90分钟满分:120分适用场景:长沙市六年级数学小升初分班考试考前训练姓名:____________班级:____________考号:____________得分:____________资料形态QS01黑白可打印标准仿真卷;试题区与参考答案区分开,便于先练后评。作答提示选择题填涂或填写选项;填空题写出最终结果;解答题必须写出主要过程、单位和结论。检查要求先检查题号1至25是否完整,再按顺序作答;遇到难题可先做标记,回头处理。评分提示全卷120分,过程题按步骤给分;书写清楚、单位完整、结果核验可减少失分。整卷训练重点:本卷围绕长沙市六年级数学小升初分班考试常见能力要求设计,既考查计算基本功,也考查比例、百分数、几何、统计、行程、工程和规律探究等综合应用。做题时要把题意、数量关系、运算过程和单位检查结合起来。黑白可打印使用提示:试题区保留学生作答空间,参考答案区另页呈现,便于课堂限时训练、家庭自测和讲评订正。主观题书写时请按“列式—计算—答语”的顺序完成,遇到多问题要分小问作答。卷面规范提示:选择题不要空题;填空题要写最简结果;计算题要保留关键等式;应用题答语要带单位。若结果需要取近似值,应按题目要求保留相应位数。考点与时间分配参考:题号范围主要内容建议用时卷面提醒1~8计算、比例、几何、百分数、规律、可能性16分钟先排除明显错误选项,再核算关键数值9~16分数小数百分数、因数倍数、单位换算、统计量18分钟答案写在横线上,单位和百分号不要漏写17~20分数四则运算、方程、简算、旋转成圆锥26分钟关键步骤不能跳,公式代入要清楚21~25打印合作、折扣利润、统计、环形跑道、规律探究30分钟分小问作答,答语完整,压轴题先写观察再列式作答节奏提示:前两大题要稳中求快,计算题要把主要等式写完整,综合题要把题意转化成数量关系。若最后一题暂时没有完整思路,可先完成第(1)问和第(2)问,保住可得分,再回到第(3)问和理由表达。一、选择题(本大题共8小题,每小题3分,共24分。每题只有一个正确选项。)1.计算2.5×0.4+3/5÷0.75的结果是()。A.1.6B.1.8C.2D.2.42.已知a:b=3:5,b:c=10:7,则a:c=()。A.3:7B.6:7C.7:6D.10:213.一个圆柱的底面半径是3厘米,高是8厘米,它的体积是()立方厘米。A.24πB.48πC.72πD.144π4.某数先增加20%,再减少20%,最后得到的数是原数的()。A.80%B.96%C.100%D.104%5.按规律排列:3,8,15,24,()。A.30B.33C.35D.386.一件商品按七五折出售后比原价便宜45元,这件商品的原价是()元。A.120B.150C.180D.2257.一个长方形的周长是56厘米,长与宽的比是4:3,它的面积是()平方厘米。A.168B.180C.192D.2248.袋中有3个红球、2个蓝球、5个白球,任意摸出1个球,摸到不是白球的可能性是()。A.1/5B.2/5C.1/2D.3/5选择题答题栏:题号12345678答案二、填空题(本大题共8小题,每小题3分,共24分。请把答案写在横线上。)9.0.375化成最简分数是__________,化成百分数是__________。10.36和48的最大公因数是__________,最小公倍数是__________。11.一辆车平均每小时行72千米,行驶2小时15分钟,一共行驶__________千米。12.方程4x-1.5=2.5的解是x=__________。13.一幅地图的比例尺是1:50000,图上距离6厘米表示实际距离__________千米。14.一个圆锥的底面积是28.26平方厘米,高是5厘米,它的体积是__________立方厘米。15.一件文具的进价是160元,售价是200元,按进价计算的利润率是__________。16.一组成绩为85,90,88,92,95,这组数据的平均数是__________,中位数是__________。填空题演算区:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________三、计算与简答题(本大题共4小题,每小题8分,共32分。要求写出必要过程。)17.计算:7/12+(5/6-1/4)×3/5。________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________18.解方程:3(2x-5)/4-(x+1)/2=2。________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________19.用合理方法计算:125×32×25。________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________20.一个直角三角形的两条直角边分别为12厘米和16厘米。若绕较短直角边旋转一周形成圆锥,求这个圆锥的体积。(π取3.14)________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________
四、综合解答题(本大题共5小题,每小题8分,共40分。请写出思考过程、计算过程和答语。)21.为准备班级数学资料,甲、乙两个打印点合作打印700页QS01黑白可打印练习材料。甲每小时打印80页,乙每小时打印60页。甲先单独打印30分钟后,乙加入一起打印。问从甲开始打印到全部完成,一共用了多少时间?________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________22.长沙市某书店购进一批小升初数学训练册。每本定价48元,按八折销售仍可获得20%的利润。(1)每本训练册的进价是多少元?(2)若售出250本,一共获得利润多少元?________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________23.某六年级班进行一次数学分班自测,成绩分布如下表。请根据表中数据回答问题。分数段90~10080~8970~7960~6960分以下人数8161263(1)本班共有多少人参加自测?(2)及格率是多少?(百分号前保留一位小数)(3)80分及以上的学生占全班人数的百分之几?(百分号前保留一位小数)(4)若90分及以上学生每人获得一本单价9.5元的笔记本,需准备多少元?________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________24.甲、乙两名同学在400米环形跑道上从同一点出发。甲每秒跑6米,乙每秒跑4米。(1)若两人反向跑,多少秒后第一次相遇?(2)若两人同向跑,甲多少秒后第一次追上乙?(3)若两人反向跑100秒,在这100秒内两人一共相遇几次?________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________25.压轴题:用同样大小的小正方形拼成一组有规律的图案,前四个图案所用小正方形个数如下表。图案序号n1234小正方形个数4101828(1)第5个图案需要多少个小正方形?(2)用含n的式子表示第n个图案所需小正方形个数。(3)若某个图案用了238个小正方形,求这个图案的序号。(4)用一句话说明你得到式子的理由。__________________________________________________________________________________________________________________________________________________________________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参考答案、逐题解析、评分细则与压轴题讲评本区供教师讲评和学生订正使用。答案题号与试题题号一一对应,主观题按步骤给分。一、选择题参考答案12345678BBCBCCCC二、填空题参考答案93/8;37.5%1012;144111621211331447.11525%1690;90三、整卷评分细则1.选择题每小题3分,共24分。答案唯一,选项涂写或填写清楚即可得分;同一题出现两个及以上选项,按不得分处理。若答题栏与题旁答案不一致,以答题栏为准。2.填空题每小题3分,共24分。涉及分数、百分数、单位换算和统计量的答案,要求表达规范;等值答案可以给分,但题目要求最简分数或指定单位时,未按要求书写应扣相应分。3.计算与简答题每小题8分,共32分。能体现正确运算顺序、变形依据和关键等式,可按步骤给分;结果正确但过程过于跳跃,教师可结合卷面判断扣1至2分;过程正确但末步运算小失误,可保留主要步骤分。4.综合解答题每小题8分,共40分。列式、计算、单位、答语均属于采分内容。多小问题目按小问给分,前一问结果用于后一问时,若思路正确且后续计算承接一致,可酌情给后续步骤分。5.主观题卷面要求:等式左右要对齐,数量关系要写清,单位名称要完整;百分率结果要带百分号;时间结果可用小时、分钟或复合形式表示,但应与题目语境一致。6.订正要求:学生订正时应写出错因、正确方法和最终答案。教师讲评时可重点关注百分数基准、比例统一、环形跑道相对速度、圆锥体积三分之一和规律题表达式这五类高频失分点。7.过程得分提醒:分步题的每一步都要能让阅卷者看出数量关系。例如行程题要写出相对速度,工程题要写出已完成页数与剩余页数,几何题要写出对应的半径、高和体积公式,规律题要写出从前几项到一般式的过渡。8.卷面复查提醒:交卷前重点检查题号是否遗漏、单位是否一致、百分率是否带百分号、答语是否回应问题。9.教师给分时可先看结果,再回看过程;学生订正时应先找出错步,再重新书写完整解法。三、逐题解析与评分细则1.答案:B解析:先算2.5×0.4=1;0.75=3/4,3/5÷3/4=3/5×4/3=4/5=0.8;合计1.8。评分细则:选B得3分;若只写1.8但未选项,教师可按答题要求给3分。订正提示:混合运算中要先乘除后加减,分数除法要转化为乘倒数,再与小数结果统一比较。2.答案:B解析:由b:c=10:7,将a:b=3:5放大2倍,得a:b=6:10。此时b相同,所以a:c=6:7。评分细则:写出6:10与10:7的衔接得2分,最终比6:7得1分。订正提示:连比题的关键是把中间量b调整成同一个数,不能直接把3:5和10:7首尾相接。3.答案:C解析:圆柱体积=底面积×高=π×3²×8=72π立方厘米。评分细则:能写出πr²h得1分,代入正确得1分,选C得1分。订正提示:圆柱体积不是侧面积,半径平方后再乘高,含π的结果可保留π。4.答案:B解析:设原数为1,增加20%后为1.2,再减少20%得到1.2×0.8=0.96,即原数的96%。评分细则:会用单位“1”分析得1分,计算1.2×0.8得1分,结论96%得1分。订正提示:先增加再减少的百分数基准已经改变,因此不能把20%与20%直接抵消。5.答案:C解析:相邻两项的差依次为5,7,9,下一差为11,所以24+11=35。评分细则:找出差的规律得2分,结果35得1分。订正提示:数列题要先看相邻两项的差,再看差本身是否有规律。6.答案:C解析:七五折表示售价为原价的75%,便宜部分为25%。45÷25%=180元。评分细则:理解便宜比例为25%得1分,列式45÷0.25得1分,结果180得1分。订正提示:七五折表示售价占原价75%,便宜45元对应的是原价的25%。7.答案:C解析:长方形周长56厘米,长宽和为28厘米。长:宽=4:3,共7份,每份4厘米,长16厘米,宽12厘米,面积16×12=192平方厘米。评分细则:求长宽和得1分,求出长和宽得1分,面积192得1分。订正提示:周长先除以2得到长宽和,再按比例分配,不要把56直接按4:3分。8.答案:C解析:球的总数为3+2+5=10个,不是白球有3+2=5个,可能性为5/10=1/2。评分细则:求出总数和有利个数得2分,选C得1分。订正提示:不是白球包含红球和蓝球两类,要把有利结果数合并后再求可能性。9.答案:3/8;37.5%解析:0.375=375/1000,约成最简分数为3/8;把小数化成百分数,小数点向右移两位,得37.5%。评分细则:每空1.5分;分数未化最简扣0.5分。订正提示:小数化分数要先写成分母为1000的分数,再约分到最简;小数化百分数注意百分号。10.答案:12;144解析:36=2²×3²,48=2⁴×3。最大公因数取公共质因数的低次幂,得2²×3=12;最小公倍数取各质因数的高次幂,得2⁴×3²=144。评分细则:每空1.5分;只写一个正确结果得相应分。订正提示:最大公因数取公共部分,最小公倍数要覆盖两个数的全部质因数组成。11.答案:162解析:2小时15分钟=2.25小时,路程=速度×时间=72×2.25=162千米。评分细则:换算时间得1分,列式得1分,结果与单位得1分。订正提示:时间单位必须统一,15分钟是0.25小时,不是0.15小时。12.答案:1解析:4x-1.5=2.5,两边同时加1.5得4x=4,所以x=1。评分细则:移项或等式变形正确得2分,解得x=1得1分。订正提示:等式两边做同样变化,移项后要再除以未知数前的系数。13.答案:3解析:比例尺1:50000表示图上1厘米代表实际50000厘米。6厘米代表300000厘米,即3000米,也就是3千米。评分细则:求实际厘米数得1分,单位换算得1.5分,答案3千米得0.5分。订正提示:比例尺换算后要从厘
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