2026届南通六年级数学小升初分班考试独家解析包第141套强证据校准版(教师版+学生版含答案详解与评分标准)_第1页
2026届南通六年级数学小升初分班考试独家解析包第141套强证据校准版(教师版+学生版含答案详解与评分标准)_第2页
2026届南通六年级数学小升初分班考试独家解析包第141套强证据校准版(教师版+学生版含答案详解与评分标准)_第3页
2026届南通六年级数学小升初分班考试独家解析包第141套强证据校准版(教师版+学生版含答案详解与评分标准)_第4页
2026届南通六年级数学小升初分班考试独家解析包第141套强证据校准版(教师版+学生版含答案详解与评分标准)_第5页
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南通六年级数学小升初分班考试第141套学生版试题与教师版答案解析2026届南通六年级数学小升初分班考试独家解析包第141套强证据校准版(教师版+学生版,含答案详解与评分标准)考试名称:2026届南通六年级数学小升初分班考试数学试卷(第141套)考试时间:90分钟满分:120分试卷形态:Word文本版,可打印可作答,参考答案另起新页学校班级姓名考号注意事项:1.全卷共18题,题号1—18,满分120分;请在规定时间内独立完成,作图和计算过程要清楚。2.选择题每题只有一个正确选项;填空题直接写最终结果,单位、百分号、分数形式需规范。3.解答题必须写出主要步骤、关键公式和必要说明;只写答案而无过程的题目将按评分标准扣分。4.本卷可直接打印作答;参考答案与解析在试题结束后单独分页呈现,教师讲评时可按采分点核分。一、选择题(共8题,每题5分,共40分)每小题给出的四个选项中,只有一项符合题意。请把正确选项填入下方答题卡。1.把2.5∶0.75化成最简整数比,结果是()。A.5∶3B.10∶3C.25∶75D.3∶102.计算36×(7/12+5/18)-36×1/9,正确结果是()。A.23B.25C.27D.313.下面四组量中,y与x成反比例关系的是()。A.正方形周长y与边长xB.长方形面积固定为48,长x与宽yC.每本练习册单价固定,总价y与本数xD.圆的周长y与半径x4.下列四组线段长度中,能围成三角形的是()。A.4cm、5cm、10cmB.5cm、5cm、9cmC.3cm、6cm、9cmD.2cm、4cm、7cm5.一种文具先提价20%,再在提价后的基础上降价20%。与原价相比,现在的价格是原价的()。A.80%B.96%C.100%D.104%6.一组数据为7、8、8、9、10、10、10,这组数据的中位数和众数分别是()。A.8和9B.9和10C.10和9D.9和87.一个圆柱形水桶内底面半径10cm,高30cm,装满水后全部倒入长50cm、宽40cm的长方体水槽中。若不考虑损耗,水槽中的水深约为()。(π取3.14)A.3.14cmB.4.71cmC.6.28cmD.9.42cm8.甲、乙两数的和是48,甲数是乙数的5/7。甲数是()。A.18B.20C.28D.30选择题答题卡:12345678二、填空题(共4题,每题5分,共20分)请把答案写在横线上。结果需要带单位时必须写清单位;能化简的分数应化成最简分数。9.用同样长的小棒按规律摆一排正方形:摆1个正方形用4根,摆2个正方形用7根,摆3个正方形用10根。照这样摆20个正方形,需要小棒________根。10.不等式3(x-4)+5≤2x+11的最大整数解是________。11.一个袋子里有5个红球、3个黄球、2个蓝球,除颜色外完全相同。任意摸出1个球,摸到的球不是蓝球的概率是________。12.一个圆环的外半径是5cm,内半径是3cm,这个圆环的面积是________cm²。(π取3.14)三、解答题(共6题,每题10分,共60分)解答时要写出必要的运算过程、数量关系或推理依据。需要画图分析的题目可在空白处画示意图。13.计算与方程。(10分)(1)计算:7.2÷(0.9×4)-1.25。(2)解方程:3/4x-1/6=5/6。3/4x-1/6=5/6学生作答区:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________14.行程应用题。(10分)南通某校六年级学生进行骑行体验活动。甲、乙两名同学分别从A、B两地相向出发,A、B两地相距50km。甲每小时骑12km,乙每小时骑8km。甲先出发0.5小时后,乙再从B地出发。(1)乙出发后几小时两人相遇?(2)相遇地点距A地多少千米?6+(12+8)t=50学生作答区:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________15.百分数与利润问题。(10分)一家文具店购进一批同款练习本。按每本2.4元出售时,正好比进价提高20%。后来进行开学优惠活动,每本降价0.3元。已知活动价卖出120本后,整批练习本全部售完,共获得利润144元。(1)每本练习本的进价是多少元?(2)这批练习本一共有多少本?2.4÷(1+20%)=2学生作答区:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________16.圆柱体积与水位变化。(10分)一个圆柱形水箱的内直径是60cm,高80cm,原来水深50cm。把一个长30cm、宽20cm、高15cm的长方体石块完全浸没在水中,水没有溢出。(1)水面上升了多少厘米?(结果可保留两位小数,π取3.14)(2)若石块仍在水中,要使水深重新回到50cm,需要抽出多少升水?V=30×20×15S=πr^2学生作答区:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________17.统计与概率综合题。(10分)南通某小学六年级45名学生报名参加三类拓展活动,统计如下表。学校计划按相同比例把150个活动名额分配到三类活动中。活动类别数学探究科技创客阅读演讲报名人数181512(1)按报名人数比例分配150个名额,三类活动各应分配多少个?(2)从这45名报名学生中随机抽1名,抽到报名“数学探究”或“阅读演讲”的学生的概率是多少?(3)若其他两类报名人数不变,要使“科技创客”的报名人数占总报名人数的40%,还需要新增多少名科技创客报名学生?学生作答区:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________18.压轴题:图形规律与费用方案。(10分)用黑、白两色正方形地砖拼图案:第n个图案的中间是n行、n+1列的白砖长方形,外面恰好围一圈黑砖。黑砖与白砖的边长相同,图案四周没有缺口。(1)写出第n个图案中白砖块数和黑砖块数;(2)第6个图案中黑砖、白砖各有多少块?(3)如果某个图案中白砖比黑砖多102块,这是多少号图案?(4)若黑砖每块3元、白砖每块2元,制作第12个图案共需多少元?白砖=n(n+1)黑砖=(n+2)(n+3)-n(n+1)学生作答区:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________

解答题补充作答区(一)用于第13—15题继续书写过程。请按题号标明步骤,保持算式、单位和结论完整。________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________

解答题补充作答区(二)用于第16—18题继续书写过程。几何题先写公式再代入,应用题先写数量关系再计算。________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________

演算与检查草稿区检查顺序建议:先查题号是否漏答,再查单位、括号、百分数基准、概率分母和圆周率取值。草稿区内容不单独计分,但清晰演算有助于避免计算失误。________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________

参考答案与解析本答案区覆盖题号1—18。选择题、填空题给出结论与依据;解答题给出步骤、采分点和易错点,教师可按步骤核分。一、选择题答案与依据(1—8题,每题5分)题号答案解析依据评分与易错提醒1B2.5∶0.75=250∶75=10∶3,化为最简整数比。写成25∶7.5或未化简不得满分。2C把36看作公因数:36×7/12=21,36×5/18=10,36×1/9=4,21+10-4=27。先算括号或分配律均可,关键是1/9项要减去。3B长方形面积固定为48时,xy=48,x扩大,y按相同比例缩小,成反比例。A、C、D均为正比例关系。4B三角形两边之和大于第三边。5+5>9,能围成三角形。等于第三边时不能围成三角形。5B设原价为1,提价后为1.2,再降价20%为1.2×0.8=0.96。两次20%的基准不同,不能相互抵消。6B数据从小到大排列后第4个数是9,出现次数最多的是10。中位数看位置,众数看频数。7B水桶体积为3.14×10²×30=9420cm³,水槽底面积为50×40=2000cm²,水深9420÷2000=4.71cm。单位均为厘米,不能把半径当直径。8B甲∶乙=5∶7,48对应12份,1份为4,甲为5×4=20。也可列方程求解。选择题评分:每题5分,只选一个正确选项得5分;多选、错选或空选不得分。二、填空题答案与依据(9—12题,每题5分)题号答案解析依据采分点961一排正方形共用小棒数为3n+1。n=20时,3×20+1=61。列出规律2分,代入计算2分,结果1分。10183(x-4)+5≤2x+11,化简得3x-7≤2x+11,所以x≤18,最大整数解为18。注意题目问最大整数解,不是所有解。114/5不是蓝球共有5+3=8个,总数10个,概率为8/10=4/5。写0.8或80%也可得分。1250.24圆环面积=π(5²-3²)=3.14×16=50.24cm²。若写16π且未代入π=3.14,可给部分分。填空题评分:每题5分。结果正确且形式规范得满分;过程不要求写出,但答案含单位时必须写单位。三、解答题答案、详解与评分标准(13—18题,每题10分)13.计算与方程(1)7.2÷(0.9×4)-1.25=7.2÷3.6-1.25=2-1.25=0.75。(2)3/4x-1/6=5/6,移项得3/4x=1,所以x=4/3。步骤采分点分值计算题正确计算0.9×4=3.6,完成除法与减法,得0.75。5分方程题移项正确,得到3/4x=1,并求得x=4/3。5分易错点:把3/4x误解为3÷4÷x会导致方程错误;计算题中括号必须先算。14.行程应用题甲先出发0.5小时,先骑行12×0.5=6km;此时两人相距50-6=44km。乙出发后两人相向而行,速度和为12+8=20km/h。乙出发后相遇时间为44÷20=2.2小时。相遇地点距A地的距离为甲总路程:6+12×2.2=32.4km。步骤采分点分值先行路程算出甲先行6km,剩余44km。3分相遇时间用剩余距离除以速度和,得2.2小时。4分相遇位置计算距A地32.4km,单位正确。3分易错点:不能把50km直接除以20km/h,因为甲已经先行;相遇地点距A地应计算甲的总路程。15.百分数与利润问题(1)设每本进价为a元。按每本2.4元出售时比进价提高20%,所以a×(1+20%)=2.4,a=2元。活动价为2.4-0.3=2.1元,每本活动价利润为2.1-2=0.1元。活动价卖出120本,利润为120×0.1=12元。按原价卖出的每本利润为2.4-2=0.4元。整批总利润144元,原价销售部分利润为144-12=132元,原价销售本数为132÷0.4=330本。因此总本数为330+120=450本。步骤采分点分值进价由售价是进价的120%求出进价2元。3分活动利润求出活动价2.1元,活动价每本利润0.1元,120本利润12元。3分总数量求出原价销售330本,总数450本。4分易错点:提高20%是以进价为单位1;降价0.3元后仍然盈利,不能把0.3元当作利润。16.圆柱体积与水位变化水箱内半径为60÷2=30cm,底面积为3.14×30²=2826cm²。石块体积为3

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