面向对象上机考试题

1、面向对象上机考试题（1）关于宠物进笼Anne的宠物小屋有12个笼子,每个笼子可以放不同的动物,但只能放1只或0只,包括 猫Cat,狗Dog,蛇Snake. 1,实现一个简单的管理系统,可增加、删除笼子中的宠物,查询每个笼子中存放的 宠物类型,(包括笼子为空的情况),统计笼中宠物的种类和数量. 2,定义描述宠物小屋的类shelves,其中有12笼子用于存放各种宠物. 3,定义虚拟基类Animal,包括纯虚函数ShowMe,显示每个宠物的情况,包括类型、颜色、 体重和喜爱的食物。 4，定义派生类Cat,Dog,Snake,具体实现上述纯虚函数。 5，重载输入*作符，使得可能通过cin直接读入宠物颜

2、色、体重和喜爱的 食物。 6，编写main函数，测试上述要求和各种功能。 */ #include iostream.h #include string.h enum NONE=0, CAT=1, DOG=2, SNAKE=3; class Animal protected: char color20; char food20; double weight; public: virtual void ShowMe()=0; ; class Cat:public Animal public: friend istream& operator(istream &is, Cat &cat); void

3、 ShowMe() cout猫的颜色、喜欢的食物、体重分别为:; coutcolor”,”food”,”weight(istream &is, Cat &cat) coutcat.color; coutcat.food; coutcat.weight; return is; class Dog:public Animal public: friend istream& operator(istream &is, Dog &Dog); void ShowMe() cout狗的颜色、喜欢的食物、体重分别为:; coutcolor”,”food”,”weight(istream &is, Dog &

4、dog) coutdog.color; coutdog.food; coutdog.weight; return is; class Snake:public Animal public: friend istream& operator(istream &is, Snake &snake); void ShowMe() cout蛇的颜色、喜爱的食物、体重分别为：; coutcolor”,”food”,”weight(istream &is, Snake &snake) coutsnake.color; coutsnake.food; coutsnake.weight; return is;

5、class Shelves int cage12; /每个笼子里动物的数量int sum3; 每种动物的数量Cat cats12; Dog dogs12; Snake snakes12; public: Shelves () for (int i=0; i12; i+) cagei=NONE; for (i=0; i3; i+) sumi=0; int push_cat(Cat &cat, int n) catsn = cat; if (cagen!=NONE) return 0; else sum0+; return cagen=CAT; int push_dog(Dog &dog, int

6、 n) dogsn=dog; if (cagen!=NONE) return 0; else sum1+; return cagen=DOG; int push_snake(Snake &snake, int n) snakesn=snake; if (cagen!=NONE) return 0; else sum2+; return cagen=SNAKE; void del(int n) if (cagen=CAT) sum0-; if (cagen=DOG) sum1-; if (cagen=SNAKE) sum2-; if (cagen=NONE) cout笼子里没有动物;else c

7、agen=NONE; cout已删除笼子里的动物; cout void seek(int n) if (cagen=NONE) cout第N个笼子里没有动物;if (cagen=CAT) cout第N个笼子里的动物为猫,; catsn.ShowMe(); if (cagen=DOG) cout第N个笼子里的动物为狗,; dogsn.ShowMe(); if (cagen=SNAKE) cout第N个笼子里的动物为蛇,; snakesn.ShowMe(); cout void count() cout笼子里的猫总共有：SUM0只endl;cout笼子里的狗总共有：SUM1只endl;cout笼子

8、里的蛇总共有：SUM2只endl; ; void main() Cat cat; Dog dog; Snake snake; Shelves shelves; int i=1,j; cout这是关于往笼子里放动物的问题: endl;cout 1: 往笼子里放猫；endl;cout 2: 往笼子里放狗；endl;cout 3: 往笼子里放蛇；endl;cout 4: 查询笼子里的动物；endl;cout 5: 删除笼子里的动物；endl;cout 6：统计笼子里的动物种类及数量；cout 7: 退出程序;endl;cout-endl;while(i) couti; switch(i) case

9、1: coutj; cincat; while (shelves.push_cat(cat, j)=0) coutj; break; case 2: coutj; cindog; while (shelves.push_dog(dog, j)=0) coutj; break; case 3: coutj; cinsnake; while (shelves.push_snake(snake, j)=0) coutj; break; case 4: coutj; shelves.seek(j); break; case 5: coutj; shelves.del(j); break; case 6

10、: shelves.count(); break; default: i=0; break; cout”*作符，使得可以通过cin直接读入上述整数类和字符串类的对象值。 (5) 编写main函数，测试上述所要求的各种功能，即可以根据菜单命令增加栈元素、删除栈元素、显示栈顶元素，其中的元素可以 是整数和/或字符串。 提示：虚拟基类Element的定义至少包括以下纯虚函数ShowMe， class Element / public: virtual void ShowMe () = 0; / ; */ #include stdafx.h #include iostream.h #include s

11、tring.h const max=1000; #define NULL 0 class Element public: virtual void ShowMe () = 0; ; class MyInteger:public Element int a; public: MyInteger()a=0; friend istream &operator(istream &is, MyInteger &MyI); int Get() return a; void ShowMe() cout 整数：A(istream &is, MyInteger &MyI) isMyI.a; return is;

12、 class MyString:public Element char s100; public: friend istream &operator(istream &is, MyString &MyS); void ShowMe() cout 字符串：S(istream &is, MyString &MyS) isMyS.s; return is; class stack MyString MySmax; MyInteger MyImax; int top; public: stack() top=-1; void push(MyInteger &My) MyI+top=My; void p

13、ush(MyString &My) MyS+top=My; void Top() if (empty() cout栈为空else MyItop.ShowMe(); void Tops() if (empty() cout栈为空else MyStop.ShowMe(); void pop() MyItop-.ShowMe(); void pops() MyStop-.ShowMe(); bool empty() return (bool)(top=-1); bool full() return (bool)(top=max-1); ; int main(int argc, char* argv)

14、 MyInteger My1; MyString My2; stack st1, st2; int i, j; coutj; cout请输入J个整数My1; st1.push(My1); cout栈顶元素为：; st1.Top(); coutj; cout依次出栈元素为：for (i=0; ist1.pop(); cout出栈后栈顶元素为：; st1.Top(); coutj; cout请输入J个字符串My2; st2.push(My2); cout栈顶元素为：; st2.Tops(); coutj; cout依次出栈元素为：for (i=0; ist2.pops(); cout”*作符，使得

15、可以通过cin直接读入上述整数类和字符串类的对象值。 (5) 编写main函数，测试上述所要求的各种功能，即可以根据菜单命令增加队列元素、删除 队列元素、显示队列头部元素和队列尾部元素，其中的元素可以是整数和/或字符串。 提示： 虚拟基类Element的定义至少包括以下纯虚函数ShowMe， 这是我24号的考题！ class Element / public: virtual void ShowMe () = 0; / ; */ #include stdafx.h #include iostream.h #include string.h const max=1000; #define NUL

16、L 0 class Element public: virtual void ShowMe () = 0; ; class MyInteger:public Element int a; public: MyInteger()a=0; friend istream &operator(istream &is, MyInteger &MyI); int Get() return a; void ShowMe() cout整数：A(istream &is, MyInteger &MyI) coutMyI.a; return is; class MyString:public Element cha

17、r s100; public: friend istream &operator(istream &is, MyString &MyS); void ShowMe() cout字符串：S(istream &is, MyString &MyS) coutMyS.s; return is; class Queue int size; Element *Elmmax; MyInteger MyImax; MyString MySmax; public: Queue() for (int i=0; iElmi=NULL; size=-1; void add(MyInteger &My) if (ful

18、l() cout队列已满else MyI+size=My; Elmsize=new MyInteger; Elmsize=&MyIsize; void add(MyString &My) if (full() cout队列已满else MyS+size=My; Elmsize=new MyString; Elmsize=&MySsize; void tail() if(empty() cout队列为空else coutShowMe(); void head() if(empty() cout队列为空else coutShowMe(); void del() if(empty() cout队列为

19、空else coutShowMe(); bool empty() return (bool)(size=-1); bool full() return (bool)(size=max-1); ; void main() MyInteger my1; MyString my2; Queue queue; int s=1; while(s) coutPlease select 1-6 cout 1: 整数进队列;cout 2: 字符串进队列;cout 3: 显示队列头元素;cout 4: 显示队列尾元素cout 5: 出队列;cout 6: 退出程序cout-couts; switch(s) ca

20、se 1: cinmy1; queue.add(my1); break; case 2: cinmy2; queue.add(my2); break; case 3: queue.head(); break; case 4: queue.tail(); break; case 5: queue.del(); break; default: s=0; break; 面向对象上机考试题（3）关于堆栈（续）/建立一个栈类，能够存放图形元素（矩形或圆形），有入栈，出栈， /取栈顶的功能。建立元素类，里面至少一个纯虚函数，矩形和圆形类 /来实现里面的函数SHOWME，实现他的显示图形信息的功能。重载，

21、/能够输入图形信息。测试以上类的功能。 #include stdafx.h #include iostream.h #include string.h const n=50; class shape protected: double width, length; public: shape() virtual void ShowMe()=0; ; class rectangle:public shape public: rectangle():shape() friend istream &operator(istream &is, rectangle &rec) coutrec.lengt

22、h; coutrec.width; return is; void ShowMe() cout长方形的长宽分别为：(,WIDTH)(istream &is, circle &cir) coutcir.width; iscir.length; coutcir.r; return is; void ShowMe() cout圆的圆心坐标为：(WIDTH,LENGTH) 半径为：R ; class stack shape *spn; rectangle recn; circle cirn; int size; public: stack() for (int i=0; ispi=NULL; size

23、=-1; bool empty()return size=-1; bool full()return size=n-1; void push(rectangle &rect) rec+size=rect; spsize=new rectangle; spsize=&recsize; void push(circle &circ) cir+size=circ; spsize=new circle; spsize=&cirsize; void top() if (empty() cout栈为空else cout栈顶元素为:ShowMe(); void pop() if (empty() cout栈

24、为空else cout出栈元素为:ShowMe(); ; void main() stack Stack; rectangle rec; circle cir; int s=1; while (s) coutcout请选择1-5号键*作cout 1: 矩形进栈;cout 2: 圆进栈;cout 3: 显示栈顶元素;cout 4: 出栈;cout 5: 退出程序;s; switch(s) case 1: cinrec; Stack.push(rec); break; case 2: cincir; Stack.push(cir); break; case 3: Stack.top(); brea

25、k; case 4: Stack.pop(); break; case 5: s=0; break; /default: cout请重新输入”操作符。 3.编写main函数，测试以上所要求的各种功能，即可以根据菜单命令增加、删除和查询商品，以及商品销售和商品上架的操作。 1、Annie的宠物小屋里有12个笼子,每个笼子可以放不同的动物,包括猫,狗和蛇,但同一时刻一个笼子只能放0只或1只宠物,本题要求完成:(1)实现一个简单的管理系统,可以增加,删除指定笼子中的宠物,查询每个笼子中存放宠物的情况,统计宠物的种类和数量.(2)定义描述宠物小屋的类Shelves,其中包括12个笼子用于存放各种宠物;

26、(3)定义虚拟基类Animal,至少包含纯虚函数Showme;(4)定义派生类Cat,Dog,Snake,具体实现上述纯虚函数showme,显示该宠物的种类,名称,着色,体重和喜欢的食物.(5)重载输入操作符,使得可以通过cin直接读入宠物的着色,体重,和喜欢的食物;(6)编写main函数,测上述所要求的各种功能;Main.cpp#include#includeanimal.husing std:cout;using std:cin;using std:endl;int main()Shelves * shelves=new Shelves;Cat *cat;Dog *dog;Snake *s

27、nake;int n;int i=0;char ch;while(i!=5)cout please chiose(1-5):endl;cout 1:add an animalendl;cout2:delete an animalendl;cout 3:queryendl;cout4:statendl;cout5:exiti;switch(i)case 1:coutn;coutc:cat d:dog s:snakeendl;coutch;switch(ch)casec:cat=new Cat;cin*cat;if(!shelves -add(n,cat)cat-deleteme();break;

28、cased:dog=new Dog;cin*dog;if(!shelves-add(n,dog)dog-deleteme();break;cases:snake=new Snake;cin*snake;if(!shelves-add(n,snake)snake-deleteme();break;default:cout your choise is wrongendl;break;break;case 3:coutn;shelves-query(n);break;case 2:coutn;shelves-Delete(n);break;case 4:shelves-stat();break;c

29、ase 5:break;return 0;Animal.h#ifndef ANIMAL_H#define ANIMAL_H#includeclass Animalpublic:virtual void showme()=0;virtual void deleteme()=0;Animal()protected:char *name ;char *color;float weight;char *food;int type;class Cat:public Animalpublic:Cat();void showme();static int number();friend std:istrea

30、m & operator (std:istream & is,Cat &cat);void deleteme();Cat();private:static int Catnum;class Dog:public Animalpublic:Dog();void showme();static int number();friend std:istream & operator(std:istream & is,Dog &dog);void deleteme();Dog();private:static int Dognum;class Snake:public Animalpublic:Snak

31、e();void showme();static int number();friend std:istream & operator(std:istream & is ,Snake &snake);void deleteme();Snake();private:static int Snakenum;class Shelvespublic:Shelves();int add(int n,Animal *animal);void Delete(int n);void query(int n);void stat();private:Animal * shelves12;#endifAnimal

32、.cpp#include#includeanimal.husing std:cout;using std:cin;using std:endl;int Cat:Catnum=0;Cat:Cat()type=0;weight=0;name=new char20;color =new char 20;food=new char 20;Catnum+;void Cat:showme()coutI am a Cat.endl;cout My name is nameendl;cout My color is colorendl;coutMy weight is weightendl;cout My f

33、avorite foood is food (std:istream & is ,Cat &cat);coutendlcat.color;coutendlcat.weight;coutendlcat.food;return is;void Cat:deleteme()Catnum-;Cat:Cat()int Dog:Dognum=0;Dog:Dog()type=1;name=new char 20;color =new char 20;food=new char 20;weight=0;Dognum+;void Dog:showme()coutendlI am a Do

34、gendl;coutMy name is nameendl;cout My color is colorendl;coutMy weight is weightendl;coutMy favorite food is food(std:istream &is ,Dog &dog);coutendldog.color;coutendldog.weight;coutendldog.food;return is;void Dog:deleteme()Dognum-;Dog:Dog()int Snake:Snakenum=0;Snake:Snake()type=2;name=n

35、ew char 20;color=new char 20;food=new char 20;Snakenum+;void Snake:showme()coutendlI am a Snakeendl;coutMy name is nameendl;cout My color is colorendl;coutMy weight is weightendl;coutMy favorite food is food(std:istream &is ,Snake &snake);coutendlsnake.color;coutendlsnake.weight;couten

36、dlsnake.food;return is;void Snake:deleteme()Snakenum-;Snake:Snake()Shelves:Shelves()for(int i=0;i12;i+)shelvesi=NULL;int Shelves:add(int n,Animal * animal)int successful=1;if(shelvesn!=NULL)coutthe n the shelve is fullendl;successful=0;return successful;shelvesn=animal;cout successful!endl;return su

37、ccessful;void Shelves:query(int n)if(shelvesn=NULL)coutthe n the shelve is empty!showme();return ;void Shelves:Delete(int n)if(shelvesn=NULL)coutthe n shelves is emptydeleteme();shelvesn=NULL;coutsuccessful!endl;return ;void Shelves:stat()coutthere ar Cat:number()catsDog:number()dog,andSnake:number(

38、)snake.endl;return ;2、请实现一个简单的银行储蓄系统,承担活期用户的存款和取款业务,要求如下:(1) 实现描述银行的类Bank,记录系统中现有哪些储户,(可用数组实现但注意越界),定义了生成储户的函数append,按照账户删除储户的函数Delete,按账号查询储户的函数query,并显示结果.(2)定义储户类Account,具有属性账号,存款人姓名和余额,操作saving withdraw和showme.函数saving 存储业务,函数withdraw处理取款业务,(余额不足时不予以取并给提示信息),showme函数显示储户所有信息.(3)编写main函数,测试上述所要求的

39、各种功能,即可以根据菜单命令增加,删除,和查询储户,以及储户存款和取款操作.Main.cpp#include#includebank.husing std:cout;using std:cin;using std:endl;int main()Bank bank;int choice=0;cout welcome to bank system endl;while(choice!=4)cout 1: add an account endl;cout2: delete an account endl;cout 3: query an account endl;cout 4: exit endl;coutchoice;switch(choice)case 1:bank.append();break;case 2:bank.deletes();break;case 3:bank.query