土力学答案第三版东南大学浙江大学湖南大学苏州科技学院合编

=a a a Ba ac9 5s =c aBr“ M DN =9 H HX Hr 1 k pr“ A a c a # d#1 1 pr M1 Uim M1 Sl p b 3 /84.1 7.21 54.3249.72 cmg V m = = %39 54.3228.61 28.6149.72 = = S W m m w 3 /32.1 7.21 54.3228.61 cmg V m S d = = 069.1 49.10 21.11 = S V V V e a r“ HDN c r M k pr“ ar r 5w T p b V Vm WVs sat + = WS mmm +=Q S W m m w = ! 1= S m w V + = 1 WS S S V m d =Q WSWS S S dd m V = = 1 () () () () () () 3 W S S W S S W W sat cm/87g.11 71.20.341 171.285.1 d1 1d 1 1 d 1 1 1 d 1 1 11 1 =+ + =+ + = + + = + + = + + + = w w w w w w d w WS ( ) 3 /87.0187.1 cmg V VV V VVVm V Vm Wsat WVS sat WVWVWSSWSS = + = + = = 3 /7.81087.0 cmkNg = 3 3 /7.8107.18 /7.181087.1 cmkN cmkNg Wsat satsat = = a rr“ HDN c r M Kl d#1 Kv d#1 k p d#1FM L%Si r L 1 b ! 1= S V () e dw e mmw e mm V m WSSSWS + + = + + = + + = 1 1 11 T () () 656.01 77.1 167.2098.01 1 1 = + = + = WS dw e 595.0 461.0943.0 656.0943.0 minmax max = = = ee ee D r a B *r k“c r M AK K k p d#1a i A sY*rs b 819.073.230.0 = = S WS WSS WS WV dw V Vdw V V e 3 /50.1 819.01 173.2 1 cmg e d V m WSS d = + = + = ( ) ( ) 3 /95.1 819.01 173.23.01 1 1 1 cmg e dw e dwd V Vm WSWSWSWVs sat = + + = + + = + + = + = V xTr 161733 = PLp wwI 81.0 16 1730 = = = p p L I ww I V c 3-8a 1i k m 3-23 Ub 1i“ 1i“ “ A=200cm scmk /102 1 1 = scmk /101 1 2 = 2 k 1 s B555 | 6 $ 2 2 ) 1 qv$ 1 A L h kA L h k 2 2 2 1 2 1 60 = 2221 )60( hkhk = cm kk k h 40 101102 1026060 11 1 21 1 2 = + = + = 5 | 6 60-40=20cm 2 scmA L h kAikq /20200 40 40 101 31 2 2 2222 = = 3-9a h 1i kX 1iN D=75mm L=200mm 1 o h h=83mm 60s HW = 1 Q=71.6cm 3 pr 1i“ b scm thA QL k /105.6 603.85.7 4 206.71 2 2 = = = 3-10a ! SM h 1i k*r k“ 30cm 2 4cm 1iN%j 5 = 0.4cm k 7 S H 145cm H 7s25 4 100cm k H 2 k p k“ 1i“ b scm h h ttA aL k /104.1 100 145 ln 44530 44.0 4 ln )( 5 2 2 1 12 = = = am B u i r bXi r N 1i“ u rV / N - m Ub k psmmk /103 4 = m U BaCaDaEaF d# 1 b kPaU Wa 00 = kPaU Wb 2.880.9 = kPaU Wc 2.137 8 19 418 = = kPaU Wd 8.90.1 = kPaU We 00 = () smAikq /1012918 8 103 377 = 29 c 4-8a y s ( BAr 1.5m =x*r 4m 3 /17 mkN= 3 /19 mkN= 73.2= s G %31= / / 2m ) C*r 8m 3 /2.18 mkN= 74.2= s G %41= xr 3m 3 /5.19 mkN= 72.2= s G %27= G,b k9 ) _1 c i c s mb 1 p 3 ()()( ) ( ) () + = + = + = = = 1 11 Gs G GG G WW G W VW V VW S WSWS SW WS WWSWSSWSS T 3 2 /19.9 mkN= 3 3 /20.8 mkN= 3 4 /71.9 mkN= 2 p1 s kPah c 5.25175.1 111 = kPah c 0.355.0195.25h 211 =+=+= m ( ) kPa c 17.675.319.90.35h4 2c2 =+=+= n kPa c 132.7788.2067.17h 33c23 =+=+= n kPa c 90.161371.9132.77h 44c34 =+=+= n ()kPa9.3063.08.03.5 Wc44 =+= i 4-9a $ m 4-30 U !9 S)T 680kN 1.31m $ 2m j 4N2mb k p ( pHKv p max i Z_ smb 1 e 4 () 31.1=+ FeGF () me 891.0 20224680 68031.1 = + = 2 + = l e A GF p 6 1 min max y (337.11 4 891.06 1 6 1 = = l e ) C # T ()() kPa e l b GF p 301 891.0 2 4 23 20246802 2 3 2 max = + = + = 3 ( kPa A GF 125 8 1000 = + kPa be lA GF 3.150 209.13 1000 2 3 1000 = = = + kPa p 5.150 2 301 2 max = L= 4-10a $ j 4N2.4m !9 / 1.2m ? 0.2m !9 1200kNS)rF ( 18kN/m 3 b k p 1# 2/ 3.6m M 1 # M 2 )F Z b 1 kPa A GF p 149202.14.241300 =+= + = 2F kPadpp m 131118149 0 = 3F M 1 svlM v 8.1 2 6.3 2.1,2,4.2 = = b z b l mbml V 108.0= C 5 kPa Mz 31.28131108.02 1 = M 2 TLs 2v va 2l v v v 8.1 2 6.3 3,2,6 = = b z b l mbml V 143.0= C l v 8.1 2 6.3 8.1,2,6.3 = = b z b l mbml V 129.0= C 5 ( ) kPapp cccMMz 7.3131129.0143.02(22 0022 = lv 4-11a H$ z 2m0sH F /H p 0 max =200kPa p 0 min =100kPa k p z/H / 3m# 6m ) Z b kPap 150 2 100200 0 = + = ( / 3m) 5.10,3,0 = b z b x mzmx V 396.0= c kPa z 4.59150396.0 = 6m) 30,6,0 = b z b x mzmx V 208.0= c 5 kPa z 2.31150208.0 = H0sH AT F 3m) sH 1.5 2 3 b z 5.0 x = b V 343.0= c 4kPa.33100334.0 z = sH 1.5 2 3 b z 10 l = b V 938.0,734.0 21 = tt kPa34.7100*0734.0 1 = z 38kPa.9100*9380.0 2 = z HP z kPa z 74.4034.74.33 1 =+= kPa z 78.4238.94.33 2 =+= 6m) sH 3 2 6 b z 5.0 x = b V 198.0= c kPa8.19100981.0 z = sH 3 2 6 b z 10 l = b V 0511.0,0476.0 21 = tt kPa76.4100*0476.0 1 = z kPa11.5100*5110.0 2 = z HP z kPa z 56.2476.48.19 1 =+= kPa z 91.2411.58.19 2 =+= Bc 6-11a $ j 4NN? /$ N !9 ? N9 nm wL 5 b kr _ sm 9 L/N L1B (Bl isYs9E_ T ?S T9 $ ak fp 75.0 0 = 6m ) kPa C 48.154.772.02.0 = kPa z 48.150.11s= Vb V 1 s9E_ T9 1 F 1 ( F ( 1 +F wL - e 1i e 2i 0 0.0 25.2 94.8 1 1.0 34.4 81.5 29.8 88.2 118.0 0.821 0.761 33 2 2.0 43.6 53.1 39.0 67.3 106.3 0.818 0.769 27 3 3.0 52.8 33.4 48.2 43.3 91.5 r“ 41 0.808 0.774 19 4 4.0 61.0 22.0 56.9 27.7 84.6 0.800 0.782 10 5 5.0 69.2 15.2 65.1 18.6 83.7 0.796 0.783 7 6 6.0 77.4 11.0 73.3 13.1 86.4 r“ 42 0.791 0.781 6 8$K / mmss n i i 1026710192733 1 =+= = 2a?S T9 s | 1m 8 19 0 p s9EB“ kPapp C 8.942.25120 00 = 3s 9 1 ( F ( 1 +F wL - e 1i e 2i 0.0 1.0 29.8 88.2 118.0 0.821 0.761 2.68 2.0 39.0 67.3 106.3 0.818 0.769 2.50 3.0 48.2 43.3 91.5 r“ 41 0.808 0.774 2.30 4.0 56.9 27.7 84.6 0.800 0.782 2.77 5.0 65.1 18.6 83.7 0.796 0.783 2.57 6.0 73.3 13.1 86.4 r“ 42 0.791 0.781 2.35 39 _ (F “ z=0 H z =0 9 z=1m H s l ( ) 4*25.125.24 = 6.125.1/2/ =bl V 6-5 8.025.1/1/ =bz 2395.0= / 1mS = 958.02395.0*4 = Wn/Vb Z(m) l/b z/b z (z ) i -( z ) i-1 Esi is is 1 1.6 0.8 0.958 0.958 0.958 2.68 34 34 2 1.6 1.6 0.8316 1.6632 0.705 2.50 27 61 3 1.6 2.4 0.7028 2.1084 0.445 2.30 18 79 4 1.6 3.2 0.5988 2.3952 0.287 2.77 10 89 5 1.6 4.0 0.5176 2.588 0.193 2.57 7 96 6 1.6 4.8 0.4544 2.7264 0.138 2.35 6 102 4 9 M #$M9 V/ e T9 ()( ) mbbz n 3.55.2ln4.05.25.2ln4.05.2 = 5 s 9 S = n z 9 MPa p p E zzp E zzp E zp zp EAAE sn n n n n ss n n si n i n is 55.2 35.2 1384.0 57.2 1928.0 77.2 2868.0 3.2 4452.0 5.2 7052.0 68.2 958.0 7264.2 0 0 / 0 0 1 10 2 1 1 2 20 1 01 10 0 0 11 = + = + + = = L V H ak fp 75.0 0 1.1= s 29 K mmsss i n i ss 1121021.1 1 = = ay. B *r 30s _F F sY i nmr ( b k p rK rK HW r NN HW T*r /i 5r NN HWb kPakPa zz 160240 = m 82MPa.4E39MPa.0a88.0e./2.0 S 1 = Mcmk pK mmH e a s z 166400 2 160240 88.01 1039.0 1 3 = + + = + = %50= s s U t t s m 2.0= V T () () M/964.0 101039.0 1088.012.01 2 3 2 m a ek c W v = + = + = 2 H tc T v v = )(83.0 964.0 2 4 2.0 2 M= = v V c HT t H120mms t = %72= s s U t t m 42.0= V T 10 )(74.1 964.0 2 4 42.0 2 2 M= = v V c HT t /i H120mms t = 1 M M74.1 4 = t M96.6474.1. =t c 7-8a r “g k E_ 100a200a300a400kPa H Fg f Is Y 52a83a115a145kPa k p a T mE r“ Fg S c b T r B TE_ 260kPag 92 kPa g M $ I $ 20 L1B Fg E_ L1B aTmEr“ Fg S c=20kPa 0 18= b kPatgctg f 5.1042018260 0 =+=+= f kPa = 92 b 7-9a *rK F k Fg kPac u 70= TBr“ % k F kPa150 3 = kr“|v_ T/? 3 $ u c= + 2 31 kPac u 2901507022 31 =+=+= 7-10a *r k“ N% k H d# kq kT f u kq kPaukPakPa f 140,350,200 13 = 11 kq kPaukPakPa f 280,700,400 13 = k p aTmE *r k“ b kq E_r g cg M H d# “ Ab , cc cucu L1B 60 0 420210 120 400350 200 L1B E_ 700 Fg aTmE *r k“ 00 34,016,0 = cc cucu kPa f 12.186 2 34 452cos 2 120420 2 120420 2cos 22 0 3 1 3 1 = + + + = + + = kPa f 36.124)622sin( 2 120420 2sin 2 0 3 1 = = = c% k 0 3 =u () 311 = Auu ()()() 93.0 200400350700 140280 31 = = = u A 7-11a *r N% k T kq s 0 28,0 = c kPa200 1 = kPa150 3 = T d# kPau 100= kq $ I $ () 49kPa.138 2 28 45tg100150 0 02 1 = += m K 100kPa100200 1 = m L= n K m L= 11 b 7-12a %*r k“% k kPac uu 20,0 = “r 12 % k r Fg S T k“ Hq/ k pg M Hrv l b 0 30,0 = c L1BE_ L 1B Fg 40 2 30 45 3 1 0 02 3 1 = += tg kPakPa 20,60 3 1 = 7-13a 7-125*r T B E_ l 9F 200kPaE_ 9 F H Fg $ HW Fg $ kPa200 H WM Hq H Fg (0 = kPac u 20= H M Hq t kPa200 = f A kPatgtg f 47.11530200 0 = 7-14a *r k“% kr Fg S T k q 0 22,24 = kPac kPa200 3 = /% k k p Hv 1 b kPatgtg tgctg 76.510 2 22 45242 2 22 45200 2 452 2 45 0 0 0 02 0 02 31 = + += + += c 8-5a r : 5m : a ;a :Ar Ar k 1r :s 2r vlT b 3 /19 mkN= 0 30= kPac 10= :)r r 13 kPa cH a 12.20 2 30 45tan102 2 30 45tan519 2 45tan2 2 45tan 0 0 0 02 002 = = = r () () ( ) ( ) mkN c cHHE a /3297.31 19 102 2 30 45tan5102 2 30 45tan519 2 1 2 2 45tan2 2 45tan 2 1 2 0 0 0 022 2 0022 = += + = “ () mKcz a 82.1 2 30 45tan19/102/2 0 0 0 = = r E a T : ()( ) mzH 06.13/82.153/ 0 = 8-6a r : 4m : | Ar Ar Ar : m8-25 U k o p 1 r vlaTZ_ 2r :sb 0 20= 0 10= 3 /20 mkN= 0 30= 0=c 0 15= a a a 0 15= 0 20= 0 10= 0 30= V 560.0= a K mkNKHE aa /6.892/560.04202/ 22 = r T : m H 33.1 3 4 3 = ) r : s :) kPazK aa 8.44560.0420 = 8-7a r : 6m : a;a :Ar Ars B r =Tr r S m 8-26 U k p r i 14 r :smb 15 9 B A r r 0 2 45tan 1 02 10 = = z a ( ) kPah a 12 2 30 45tan218 2 45tan 0