需求确定条件下的逆向物流库存控制模型.pdf

河北大学 硕士学位论文 需求确定条件下的逆向物流库存控制模型 姓名：张铭锐 申请学位级别：硕士 专业：管理科学与工程 指导教师：李松 2011-05 ? i ? ? ? !?“#$%?:?“#abcd. ef?g?hijk,ef?glmno?pqrs?tlumef?g?v wxyz?_ab?cd?efgh7ij.ef?gklmnoxy, qrsvktef?gu?vwj?xyd?.“#?z|ghwj?k ,qr?7?sv?“#y?“#?.a?“#ab? ?7ghwj?k,t?qr? “fi ?fl g?3? 3“#rl ?”7?, .?”? ?l? economic order quantity,eoq?n“#?e?i?q?l? ?g? ?”?ef?gqr?.? ?ef?gqr?klq?3?7ef?gqr?klq?, ?7?y? .“#?ab?)7?vw? ,p p ?gsvqr?ef?geoq abstract ii abstract the rapid development of economy makes peoples life great wealthy and also it makes the competition among enterprises very fierce. the brutal competition and unprecedented challenges make more and more enterprises begin to establish their own reverse logistics system.the research of reverse logistics in foreign countries has considerabley developed, but in own country its development is still in the initial stages, therefore further research is very necessary. as a vital part in the reverse logistics, inventory management plays a very important role. effective management of inventory can not only reduce costs, increase profits, but also can set their own good image, increase customer satisfaction. but the past inventory model is often based on two assumptions, one assumption is a fixed rate of return, the other is that the goods price after repair is the same of the new products price. this assumption does not match the actual situation. for this article established three models which are based on the model of eoq. finally, take some typical examples to verify the model. the results show that the model has more practical significance. keywordslogistics management inventory control reverse logisticseoq ? 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f.w.harris l 1915 ?gt%?k?,? ? ?s?,v?%?kv*?,?“ ? %.?th d?qrl %c? d ?u fi ?qr?t$?f =kl?p?qrk$? sp? q?kn?u, 3.1.1./0?123 1?.?tf?o x 24? 3?4?4? 4)?5djk“y, 5 3-1 eoq 86?5 ? 3 ?“#?$“#()?*+ 19 ?“?l?u? 3-1 5?,5d“?fi ?v? ?,2v?pz?5i? ?jk? ?kl,?f=”?4jd?a?4? 5?2qr?p 0 ?5d?“?p?, 3.1.2./?45 1?7?5?j_r?m ?7?5?m?5i?7y?j?7u?5?_r?m? ?h?tkl?, 5i?7y?j?$ue?7?5?_r? m,? 3-2 ?q$u5?7?qr, ? 3-2 u? q ?qr5?j?,?u?fi ?qqr? !?q?,?a?.?tf?o?5? 3-2 u ?t?fi ,etqr?p 0 ?%?57?5?qr4?a 0 ? ”, k? 3-2 ?=?aqr?ll?e?qr?;?%t q?f? ?qrt 0 ?”,5?qra?n$%,?h?qrtqr?# ,#qrtq/2 , ?7y?t#qr3?75?m 1 c ?2,?qr?7y? 1( / 2)c q, 5 3-2 ?9:5 2?y? ?y?a“?m3$u“?2, “?th? a/x q?y?t 2( /)cx q , ? 20 3?qr?y? ?qry?1?y?3?7y?p,? 12 (/ 2)(/)cc qcx q=+3-1 ?y?l?u? 3-3 5?,?”?y?3 ?f$?,?a?7y?y?q? ?e?y?t?fi ?d, 5 3-3 ;?5? 12 (/ 2)(/)cc qcx q=+3-5 2 21 (/)(/ 2) c c x qc q = + 3-6 2 21 0(/)(/ 2)c xqc= +3-7 21 2/ opt qc x c=3-8 ? 3 ?“#?$“#()?*+ 21 ?5.?y?t?y?,5? min12 (/)(/ 2) optopt cc xqc q=+3-9 3.1.3? ?m?d7 i-75 ?o? ?rq.r7?o ?lv$?o?,?r7?d?o?vu?c ?o?, ?o?f ?qr ?y?“?o?$u?ht 10000 ?7?o?m t 0.75 ?“?j_r?mt 150 ?,?lu(?g? ?g$n?9rkl?v$u?“?u,l? 7? 1 0.75c =? 2 150c =? 10000x =? ?v?t? 21 2/(2 150)/0.752000 opt qc x c=? ?p?d?qr?y?t? min21 (/)(/ 2)150 (10000/ 2000)0.75 (2000/ 2)1500 optopt ccxqc q=+=+=? ?d$u?“?t?/10000/ 20005 opt xq=“ ?$uqu(?u?g?g?g(?# 311 9? ?d?ut? 311 311/562.2 / opt x q =#( k?=p?a?3-4u?7y?y? ?t”?l?uvt?f?o ?e?f? ?!t?, 5?l?2u? ?q?d ?fi ?vkt?l?,h”?fi ?7i ? 22 ju? !?|”?“n?y?4l=? ?1zul ,?=?l?qr y? 7?!;a, 3.2? ? ?qr?l eoq ?n“#?fl g? ei?y, 3.2.1? 1?*?.vu? 2?4fi qr 34?2qrt 0 ?%p? 4 ?.?f? ? 1 x th ?“k5?_3cth? ?kt4c %?7?mt a 5? x th? 6uc?t q 7?t s 8fl g?jk?%y?fl g?fi 3?7“? 9? % t ?kl“fl g? %?7y?tb fl g? kuv“?y?0m th?fl g?vy?t1m 10?y?y?7y?fl g?7y?vy? ?y?hy, ? ?ef?gqr?t?r? ”?#?y? ?o$!?y?”? q ? %? % t, ? 3-4 ?qqr?f7”?a?j?fi ?7?qr?f7”? a?j?fi ?fl g?qr?f7”, ? 3 ? 23 ? 3-4 ? 3.2.2? a?“? 1?“?t x n q =3-10 2?7qr?t 1( ) s k tqx t n =+3-11 ?qr#?t 11 00 111 ()( )() 2 tt ss e kk t dtqx t dtqx t ttnn =+=+ 3-12 3fl g?#qrt 2 s n 3-13 %? %c?y?d?hy? ?y?=?7y?+y?+fl g?7y?+fl g?vy? 1%? % t c?y? 34cc q+3-14 2?7?#?7y? ? 24 ?d3-7? 1 1 2 s aqx t n +3-15 3)?7fl g?5?m? ?d3-12? 2 s b n 3-16 4)%? % t cvfl g?5?y? 01( ) s mm n +3-17 ?%? % t c?y?t? 01 23 1 () ()1 ( , ) 22 s mm cc qss n tc q taqx tb tnnt + + =+ +3-18 ?a4?2qrt 0 ?%p?5?5?3 ?$?( )0k t =? 10 s qx t n +=3-19 .ad3-17 ?j?( , )tc q t?p? q ?u t, ?3-18d?p 1 ()q xs t x x + =3-20 ?3-1?3-19?n3-18? 01 341 11 () () ( ) ()() 22 sq mm cc qsqx tbsq x tc qaq sx qsx q xx x xx x + + =+ + 3-21 ?3-20?p?t? q ? 41341 2 ( )()()()() () 22 dtc qc x xq sxsxcc q x xa sxbs dqsx qxx + =+ + 1101 2 ()()() 0 () sq m sx sx qx x mmsx x sx q + = + 3-22 ? 3 ? 25 ? 1032() * ()() x mc qx sxsx abs + = + 3-23 ?3-18d? 03 1 2()() * () sxmc t xsx abs + = + 3-24 ?-?*,*q t?ty?”?u, 3.2.3? tq.?5i?7?330u?fl g? ?qr?p31u?ukl.?.31u? ?kl?, ?m?o?.r7?d?o? vu?c? ?o?,?w?o? q?“?o?$u? ?ht 10000 ?t 80 ?o?o?k? 50 ?7 ?o?mt 0.75 ? ?“?j_r?mt 150 ?, o? fl ?#t 120 ?t?100 ?120 ?140 ? fl ?%? %?7fl g?m? 0.1 ?fl g?_t 50 ?fl g?m? 0.5 ?, l?7? 0.75a =4c =503150c =s =120b =0.1 0 m =50 1 m =0.510000x = 1 x =80 1?“?t 10000x n qq =3-25 2?7qr? 1( ) s k tqx t n =+3-26 ?qr#?t 11 00 111 ()( )() 2 tt ss e kk t dtqx t dtqx t ttnn =+=+ ? 26 = 12011201 8080 2100002 q qtqt n +=+3-27 3fl g?#qrt 12060 22 1000010000 sqq n = 3-28 %? %c?y?d?hy? ?y?=?7y?+y?+fl g?7y?+fl g?vy? 1%? % t c?y? 3415050cc qq+=+3-29 2?7?#?7y? ? e(k)? 1 11201 0.75 80 2100002 sq aqx tqt n +=+3-30 3?7fl g?5?m? ?#qr? 60 0.1 210000 sq b n =3-31 4%? % t cvfl g?5?y? 01 120 ( )500.5 10000 sq mm n +=+3-32 ?%? % t c?y?t? 120 500.510000 ( , )0.75 800.1 10000210000 q qqq tc q tqt tt + + =+ 3-33 ?d?p? (10000 120) 80 10000 q t + = 3-34 ? tc(q)?d? (15050 ) 800000331000000 120 ( )0.75 40 1012025005000253 qqqq tc qqt q + =+3-35 . tc(q)?a q ?#?p? *203.5q =? ? 3 ? 27 2t 203.5 ? ?f ?5?p?y?t 4141.806? 10u?y?t 4863.396?y?j$?a? ?y?ef?l?y?7?7?, 3.3? eoq ? 5i?g? ?j? ?v?;? p?,? eoq ?u“?%?57?g? p?pg? ? eoq ?,? eoq ?“?e?qr l?pfi ? !lll,?”?l“#?n?qr?n? ”,?“#tqx,?an?d,?”z?;?l“#ab? ? ?$?”?n5?”,? 3-5 tg? ? ? eoq ?, ? 3-5 ? eoq ? l? eoq ?u?y?3?“?$?3qr“#?7 ?, ?a#qr? g? ? eoq ?u?7y?a? eoq ?u?7y?,g? ? eoq ?a? eoq ?avqr“# l?pfi ? !lll?e?v?qr?p q ? q ?eoq?u?j?,?.?y? ?aq,l ?#? ?fi ?p?a0 ?jd?fl ? ?“#,?fl ?p?“#?t 1 2 1 2 () l opt l c x cc q cc + =4-2 1 1 () optopt l c lq cc = + 4-3 4.2? 4.2.1 ? 1 “?aqrf?6;?s?$fi ?f?57 ?mr?s 2utt ? 4 ? 35 3uc?t0s 4uc?t q 5uc?a2qr?pfi ?p?s?ef? ?qr“#?7?p q?0qs 6? x th? 7?#t s 8?y?tlc 9t?7?mt1c?“?j_?mt2c? 10“?“k5?_3cth?kt4c fl g? %?7y?tb fl g?kuv“?y?0m th?fl g?vy? t1m, ?t?y?”? q ?“#0s, ? 4-1 ?qqr?rs”?a“#fi ?fi ?qr? %?r?f7”, 4.2.2? 1?“?t x n q =4-4 2?y?t 2 0() 2 l s s n c q 4-5 3?7?y?t 2 0 1 () 2 s qs n c q 4-6 4?y?t 2n c4-7 ? 36 5fl g?usmt b s4-8 6fl g?mt 01mm s+4-9 ef?qr?y?t 2 2 00 01201 ()() ( ,) 22 l ss qss nn tc q scn ccb smm s qq =+ +4-10 ?4-1d?np4-7d? 2 2 00 01201 ()() ( ,) 22 l sqsq qss x xx tc q scccb smm s qqq =+ +4-11 ?qr?y?0,q s?s?d 22 2 1 01020 2222 (1) ( ,) 0 2222 ll s c tc q sc sc xc sc s x qqqqx + =+= 4-12 0100 1 0 ( ,) (1)0 lltc q sc ssc sc s c sqxqx =+= 4-13 ?4-9d34-10d?de? 2 12 22 1 () 2 * ()(1) l ll x ccxc q c cxsscs s + = + 4-14 2 12 0 22 1 () 2 * ()(1) l ll c xsc sxc s c c xssc ss + = + 4-15 ?-?0*,*qs?t? ?“#, 4.2.3? .a4-? “?o?o?o? y?t2?utt?uc?t0s,“?o ?$u?ht10000?o?7?o?mt1?“ ? 4 ? 37 ?j_r?mt 150 ?,o?fl ?#t 120 ? ?t?100 ?120 ?140 ?fl ?%? %? 7fl g?m? 0.1 ? fl g?_t 50 ?fl g?m? 0.5 ?,?o? q ? 0s,?7? 1c =12150c =s =1200.1b = 0 50m = 1 0.5m =10000x =2lc = ?d?7?n?k?o? ?t 222 10000(12) 2 10000 150 *5196 1 2(10000120120)2 (1 120)120 q + = + (?) 2 0 22 1 (10000 120)2 120 2 10000 150 *1269 2 1(10000120120)2120 (1 120) s + = + ? ?a?”? eoq ?kk?ef? 1l?7 eoq ?ef?gqr?qfl g?7m?m? ?fl g?fl gr;.qrklfi , 2?q? ?g? ?”?ef?gqr?1?q ?7?, 3?q?”?ef?gqr?1?q?7?, 5.2? ef?glum?z+a|lcd,?n?.vxy?mn? vvwi?4f?()