




已阅读5页,还剩23页未读, 继续免费阅读
版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领
文档简介
作业反映出来的几个问题 1. 记对作业题; 2. 按顺序做题; 3. 可以不用抄题,但要写清题号; 4. 答题应尽量体现解题思路和过程; 5. 按要求交作业,不要跨班; 6. 作业本写清班号学号。 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 第一章 数字逻辑基础 1.1.1 解:01011010 1.1.2(2)0111010 1.3.1(3)254.25 254.25D=11111110.01B=376.2O=FE.4H = 10 0101 0100.0010 0101)8421BCD (254.25)D=(11111110.01)B=(376.2)O=(FE.4)H =(10 0101 0100.0010 0101)8421BCD Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 1.3.2(2) 100010010011B=211+27+24+21+20=2195D 1000 1001 0011BCD=893D 1.3.3(2) 11.01101B=0011.0110 1000B=3.68H 1.3.4(4) 1002.45D=3EA.7333H 1.3.5 (1) 23F.45H=10 0011 1111.0100 0101B 1.3.6 (1) 103.2H=1x162+3x160+2x16-1=259.125D Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 第二章 逻辑门电路 2.4.1 逻辑0判断 VIL=0.8V (1)(2)(3)(4) 2.4.2 逻辑1判断 VIH=2V (1)(2)(3)(4) Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 2.4.3 解:(1) LSTTL驱动同类门 N=20 (2) LSTTL驱动基本TTL门 N=5 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 2.4.4 (1)IOH74LS00=0.4mA 2IIH7404+4IIH74Ls00=0.16mA IOL74LS00=8mA 2IIL7404+4IIL74Ls00=4.8mA (2)拉电流多余: (0.4-0.16)/0.02=17 (3) 灌电流多余: (8-4.8)/0.4=8 N=min(8,17)=8 2.4.5 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 2.4.6 RP计算 (1)拉电流时 VOH 7401 74LS00 (2)灌电流时 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 2.9.1 驱动: 负载: 拉电流: 灌电流: 扇出: 2.9.2 VOH VIH VOL IIH IOL IIL Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 第三章 组合逻辑电路分析与设计 3.1.3代数法化简 (a) (c ) (e ) 3.1.2证明(C) Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. (i ) (g ) (k ) Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. (m ) 3.1.4变换与或式 (b) Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 3.1.6 变换2输入与非 3.1.7与非(a) 3.1.8或非(a) 3.2.1展开最小项 (a) Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 3.2.2 (a) (c) 00011110 00 11 01 11 11 1111 10 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. (e) (g) Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 3.2.3 略 3.3.3 一位数值比较器 3.3.5: 输入端奇数个1,L=1,否则为0,即为奇偶校验器 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 3.4.200 01 11 10 00 1 01 1 11 11 10 111 (a)与或非 (b)与非 (c)或非 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 3.4.4CLi 0AI 1AI Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 第四章 组合逻辑器件 4.1.1 输输入输输出 I3 I2 I1 I0D7 D6 D5 D4 D3 D2 D1 D0 1 0 0 010 1 1 0 0 1 1 0 1 0 011 0 1 0 1 0 1 0 0 1 00 1 1 1 1 0 1 0 0 0 0 11 1 0 0 1 1 0 1 其它全0或全1 4.1.4 输出端增加一级非门 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 4.2.3 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 4.2.4 32个地址译码电路设计 分析:32个地址译码需要4片 74138,5位译码输入,高2位用 片选实现,低3位用原输入并联 。 E D 74138(1) 0 0 74138(2) 0 1 74138(3) 1 0 74138(4) 1 1 D E 00H-07H 80H-0FH10H-17H18H-1FH A B C Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 4.2.5 (1)逻辑门设计 (2)74138实现D=0 选中低位片1;D=1 选中高位片2 12 0 1 0 0 A B C D 0 1 2 3 45 6 7 8 9 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 4.2.9 7位数字译码显示电路 整数部分 小数部分 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 4.3.4 4选1数据选择器 ES3S2S1S0Y 10001I0 10010I1 10100I2 11000I3 0XXXX高 阻 最后一级与门使用三态与门 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 4.3.5 74151输出波形 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd.Copyright 2004-2011 Aspose Pty Ltd. 4.3.6(2) 74151输出波形 Evaluation only.Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile .Created with Aspose.Slides for .NET 3.5 Client Profile . Copyright 2004-2011 Aspose Pty Ltd
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 2024年滨州新能源集团有限责任公司及权属公司公开招聘工作人员递补笔试备考题库附答案详解(典型题)
- 2025年黑龙江省五常市辅警招聘考试试题题库及答案详解(易错题)
- 2024年湖南医师定期考核模拟试卷-临床医学1000题
- (福建高考卷自主命题6科)2023年福建省普通高中学业水平选择性考试高考物化生+政史地真题试卷及答案
- 2024年消防条令纲要知识考试题库及参考答案
- QCC质量工具培训
- Brand KPIs for online betting:Action Network in the United States-英文培训课件2025.5
- 低空经济在应急管理的典型应用与案例解析方案
- 四川西昌青山机场油库增容项目环评报告
- AI大模型赋能数字化未来工厂建设方案
- 煤矿重大危险源评估
- 艺术基金授课协议书
- 2025年入团考试时事热点及试题与答案
- 生物+昆一中2025届高三联考试卷及答案(九)
- 医务科工作制度
- 神奇校车 测试题及答案
- 人流综合征试题及答案
- 家政考试题及答案大全
- 《政策性金融工具》课件
- 重度贫血护理疑难病例讨论
- 武汉大学研究生毕业论文模板
评论
0/150
提交评论