数字电子技术基础第一章习题答案.doc

第一章 习题解答题1.1【解】 (1) ()=(97)=(151) (2)() = =(109)(3)( 0. )=(0.5F)=(0.)(4)(11. 001) =(3. 2) =（3.125）题1. 2将下列十六进制数化为等值的二进制数和等值的十进制数。【解】(1) (8C) =()=(140)(2) (3DBE)= (.)=(61. )(3)(8FFF)=(.) =( 143.)(4)(10.00)=(10000.)= (16. )题1. 3解(17)=(10001)=(11) (127)=()=(7F)(0.39)=(0.0110)=(0.6) (25.7)=(11001.1011)=(19.B)题1. 4 解(1) (+1011)的原码和补码都是01011(最高位的0是符号位)。(2) (+00110)的原码和补码都是(最高位的0是符号位)。(3) (-1101)的原码是11101(最高位的1是符号位)，补码是10011(4) (-)的原码是(最高位的1是符号位)，补码是 题1. 5 解 (1)首先找出真值表中所有使函数值等于1的那些输人变量组合。然后写出一组变量组合对应的一个乘积项，取值为1的在乘积项中写为原变量，取值为0的在乘积项中写为反变量。最后，将这些乘积项相加，就得到所求的逻辑函数式。 (2)将输人变量取值的所有状态组合逐一代入逻辑函数式，求出相应的函数值。然后把输入变量取值与函数值对应地列成表，就得到了函数的真值表。 (3)将逻辑图中每个逻辑图形符号所代表的逻辑运算式按信号传输方向逐级写出，即可得到所求的逻辑函数式。 (4)用逻辑图形符号代替函数式中的所有逻辑运算符号，就可得到由逻辑图形符号连接成的逻辑图了。题1. 6 解表Pl. 6( a)对应的逻辑函数式为表P1.6(b)对应的逻辑函数式为题1. 7 解 题1.8 解答如下：题1.9 解答如下题1.10 解答如下(5)(6)先将Y化简为题1.11 解答如下题1.12 解答如下题1.13 解答如下 校长为学校学生道路交通安全工作第一责任人，负责校（园）内的道路交通安全管理工作和学生出行的道路交通安全教育，以及学生春(秋)游和其他教育教学活动的道路交通安全管理工作center pin checks and anchoring the inner cylinder. According to While coupling alignment should keep oil out of cavity and locate the rotor axis neck raised are within the prescribed limits, there should be no gaps, Horn, Horn and Horn 0.05mm feeler gauges fit into. Center coupling, condenser water filling and water-filled according to factory requirement. For coupling three supported rotor Center, the mouth under the coupling between the value should be as stipulated in the manufacturer, usually 0.150.25mm. In the case of coupling connection, if possible, lifting only one bearing end of the support bearing of the rotor, remove the bearing, fitted with special tiles and special lifting tools, disc rotors, check the journal flutter tile, should generally be less than 0.10MM. When the couplings and rotor comes when there is a conflict, the coupling Centre shall prevail. 6.4.5.2.2 shaft looking for: . 6.4.5.3. Provisional bolt confirmed the positioning of the rotor size, as well as the coupling between the adjustment shim thickness accuracy, drawings to meet the technical requirements. Plane, cylindrical and clean the coupling bolt holes should be clean and without burrs, scrap iron and grease-free, relative position of the coupling according to the drawing requirements are. Coupling top screws, round distance apart, indicators to monitor movement of the aircraft, its value is allowed to pass the value axis moving, mounted adjustment pads, note pads installation direction guide pin coupling with process end closed. The back wheels slowly tightened, when 2mm or so, with standard white bars where two back wheel bolt hole measurement above and below, confirm two back wheel bolt hole concentricity. Then, the symmetrical horizontal mount two temporary bolts tightened, attention to monitor dial indicator, then install the symmetrical temporary bolts, this time sites slowly moving rotor, in the measured circumference of 8 equal parts back wheel rim rock, each measuring relative changes in value should be less than 0.02mm. 6.4.5.4 coupling reamed and paired bolt reaming die reamer, adjustable reamers, boring mill, in several ways. 6.4.5.4.1 General requirements before reaming or boring, 题1.14 解答如下(5)用卡诺图化简。填写卡诺图时在大反号下各乘积项对应的位置上填0，其余位置填i。卡诺图中以双线为轴左右对称位置上的最小项也是相邻的。化简后得到 它的卡诺图如右下： 题1.15 解答如下（4）用卡诺图证明。画出表示左式的卡诺图。将图中的0合并后求反，应与右式相等。将0合并后求反得到，故成立。（5)用卡诺图证明。画出左式的卡诺图，化简后得到卡诺图如下：题1.16 解答如下 题1.17 解答如下 题1.18 参见教材第1. 8. 1节。 题1.19 解答如下根据题意可知，m到m均为约束项，而约束项的值恒为0，故同理，由题意可知m9m15,m34m31也都是约束项，故得到，余类推。题1.20 解答如下 题1.21 解