土力学与基础工程_第三版_赵明华_课后答案.pdf

1 2 2 2.2 1 1 sw d d e = + (2) 1 rws w s erd r e + = + (3) (1) S r wdn s n = 1 s v = v s v e v = v ve=1 sv vvve=+= + s s s m d v = 1 w p ssswsw md vd= w s m w m =100% wssw mwmwd= (1) swsw mmmdw=+=+ 1 s d m v = 1 sw d d e = + 2 w r v v s v =100% s r wd s e = sr wds e= (1)(1) 11 swsw dwdw rm rggg vee + = +1 sws w d wrd r e + = +1 rws w s erd r e + = + 3 v v n v =100% 11 en ne en = + w r v v s v =100%= s wd e = (1) s vdn n 2.31 s v = s d =2.70=32.2%=1.91 3 /g cm 3 1.0/ w g cm= 2.506 r s r 1 s v = ,2.70 s d =, w=32.2%,=1.91g/ 3 cm, 3 1.0/ w g cm= svsv vv vveve= =+ + w w s m m m m 1 10 00%0% ( (1)1) swsw ( (1)1)dwdw( (1)1)1) sw =+=+dwdw( (1)1) veve= +ve1d w w m mw wm=wm 100%0%s s 3 (1)2.70(1 0.322)1.0 110.87 1.91 sw dw e + = = = 1 3 v v0.87ecm= 20.322 ws vwd=*2.70=0.87 3 cm 311 0.871.87ve= += += 3 cm 42.70 ssw md=*1.0=2.70g 50.322 wsw mwd=*2.70*1.00.87g= 63.57 sw mmmg=+= 7 s r wd s e = w v v v * 0.87 100% 0.87 =*100%=100% 8 12.7 1 110.87 s w d rgg e = + *10 3 9.1/kN m= 2.472 3 cm129.5g121.5g 2.7we r sr sat r r d r , 3 72vcm=m=129.5g121.5 s mg=2.7 s d = 3 129.5 1.799/ 72 m g cm v = (1) w m w ms =*100%= s s mm m *100% 129.5 121.5 121.5 =*100%=6.6% 7070g g 2222* *2 2. .7070* *1.0 w gggg w 0. .8787g g= 0. .8787 100%0% 0 = = 1 1 s s d ds s gggggggg s gggg s gggggggggg +e e 4 s s sw m d v = 121.5 2.7 s s s m v d =45=724527 vs vvv= 2 27 45 v s v e v =0.60 129.5 121.5 8 1 w w w m v = 3 8 27 w r v v s v =*100%=29.6 41.799rg=*10=18.0kN/ 3 m 5 svw sat mv rg v + = 121.527 72 + =*10=20.6kN/ 3 m 6 121.545 72 ssw mv rgg v =*1010.6Kn/ 3 m 121.5 72 s dd m rgg v =*10=16.9kN/ 3 m sat rr d r r 2.52.6832.0% er 100% r s =2.68 s d =32.0%w= w r v v s v =*100%=100% wv vv= w s m w m =*100%= ww s v m = vw s v m vw s v m w = s s sw m d v = sssw md v= vw ssw v d v w = vss vd v w= vss s ss vd v w ed w vv =Q=2.68*0.32=0.86 (1)2.68 11 0.86 s w dw rg e + = + 1+0.32 *10=19kN/ 3 m 2.61.77g/ 3 cm,9.8%2.67 0.4610.943e r D 3 1.77/g cm=w=9.8%2.67 s d = min 0.461e= max 0.943e= (1) 1 sw dw e + = = 2.67 (10.098) 1 1.77 + =0.656 2 3232.0%0%w= = wvwv vvvv wvwv vvvvvv 68 w w s m m m = =* *1 10000%= sw vwvw v v w vw s s d wd w s =2 2 68 5 max maxmin 0.9430.656 0.595 0.9430.461 r ee D ee = Q0.67 r D 0.33 2.7=1.66g/ 3 cm, s d =2.69 40%w? 3 1.66/ d g cm=2.69 s d =40% r s = 2.69 1 110.620 1.66 sw d d e = = = 0.40 0.62 w 2.69 r s s e d =*100%=9.2% 2.8w=28.5%,r=19kN/ 3 m,2.68 s d =, mm 220.50.50.25 0.20.0751.3 k k 2 21 1.6 60 0k kN/mN/m 2 5 5+ + m m kN 3 /m 7 7) 5 5 2 22 .7 5 5 =1. .6 615 m m 26 6- 66- 7 6- 75 3 /0 .22mkN k = 6- 7 2 2 2 )cos()cos( )sin()sin( 1)cos( )( cos cos + + + = ka = 2 2 2 )cos()cos( )sin()sin( 1)cos( )( 15201520 15351535 152020cos 2035cos oooo oooo ooo oo + + + =0.526 Ea=kh a 2 2 1 =0.5186 2 0.526=170.44 m kN (2) G=0.5(0.8+2.98)622=249.48kN 48.249 1 0 = x 0.560.422+0.56(2.98- 0.8)22 3 1 (2.98- 0.8)+0.8=1.05 m 3 2 1) ) ( ( c cosos s( s( ( + +1) ) co os( s( in( ) )s( ) )s s) )s s 202020 c co os( s( c c o 0 o 0 27 zE xEx k f f t a a G x z + = 0 = 2cos424.170 3 )8 . 098. 2(2 8 . 0sin424.17005. 148.249 35 35 + o o =1.73 GE EG k tat ann s + = )( = 35 35 cos424.170 sin55. 0424.17055. 048.249 o o + =1.37 6- 8b=3md=12m 3 / 5 . 18mkN= kPac15= o 20= cr p 4/1 p 6- 81 d cd Pcr 0 0 2 cot )cot.( + + + =2 . 15 .18 2180 20 cot )cot152 . 15 .18( 20 20 + + + o o o =152.68kPa 2 d d cd P 0 0 4 1 2 cot ) 4 cot.( + + + = =2 . 15 .18 2180 20 cot ) 4 3 5 .18cot152 . 15 .18( 20 20 + + + o o o =181.23kPa 6.9b=1.5md=2.0m 3 /2 .18mkN=kPac0 .30= o 22= 4/1 p 3 6.91= 0 P4 1=0 . 22 .18 2180 22 cot ) 4 5 . 1 2 .18cot0 .300 . 22 .18( 22 22 + + + o o o =322.61kPa 2 180180 2020 o1515 c c 2020 + + 1515 o d d 0 ) ) 4 4 + + 2 . 15 .1815 . 2 +5 .18 5 . 180 2020 18cot ot 2020 2020 + +18cot ot20 20 o o o 28 =22 o )tanexp() 2 (45 tan 2 += o Nq =)tanexp() 2 ( 22 22 45tan 2o o o + =7.8 Nc=16.9N =6.9 NNNP dqc qcu 4 . 02 . 1+= =1.230.016.9+18.22.07.8+0.418.21.56.9=967.668kPa 3 P P u =322.6kPa 3 Nc=16.9Nq=7.8N =4.1 1= iiiqc 02. 1= sc 375. 1= sq 6 . 0= s 0=0=1= =bbb ggg qc qc 333. 1 5 . 1 0 . 2 = b d dc=1+0.4arctan1.333=1.37 29. 1333. 1arctan)sin1 (tan21 2