【连连看】小游戏初始源代码.doc

_【连连看】简单小游戏初始源代码使用说明：进入Java开发工具eclipse中，在左面建立一个任意名的java project,然后在工程下建立一个名字为Lianliankan的package，最后建立一个名字为lianliankan的class类。将以下程序代码复制入class内容面板中，点击运行。package Lianliankan;import javax.swing.*; import java.awt.*; import java.awt.event.*; public class lianliankan implements ActionListener JFrame mainFrame; /主面板 Container thisContainer; JPanel centerPanel,southPanel,northPanel; /子面板 JButton diamondsButton = new JButton65;/游戏按钮数组 JButton exitButton,resetButton,newlyButton; /退出，重列，重新开始按钮 JLabel fractionLable=new JLabel(0); /分数标签 JButton firstButton,secondButton; /分别记录两次被选中的按钮 int grid = new int87;/储存游戏按钮位置 static boolean pressInformation=false; /判断是否有按钮被选中 int x0=0,y0=0,x=0,y=0,fristMsg=0,secondMsg=0,validateLV; /游戏按钮的位置坐标 int i,j,k,n;/消除方法控制 public void init() mainFrame=new JFrame(JKJ连连看); thisContainer = mainFrame.getContentPane(); thisContainer.setLayout(new BorderLayout(); centerPanel=new JPanel(); southPanel=new JPanel(); northPanel=new JPanel(); thisContainer.add(centerPanel,Center); thisContainer.add(southPanel,South); thisContainer.add(northPanel,North); centerPanel.setLayout(new GridLayout(6,5); for(int cols = 0;cols 6;cols+) for(int rows = 0;rows 5;rows+ ) diamondsButtoncolsrows=new JButton(String.valueOf(gridcols+1rows+1); diamondsButtoncolsrows.addActionListener(this); centerPanel.add(diamondsButtoncolsrows); exitButton=new JButton(退出); exitButton.addActionListener(this); resetButton=new JButton(重列); resetButton.addActionListener(this); newlyButton=new JButton(再来一局); newlyButton.addActionListener(this); southPanel.add(exitButton); southPanel.add(resetButton); southPanel.add(newlyButton); fractionLable.setText(String.valueOf(Integer.parseInt(fractionLable.getText(); northPanel.add(fractionLable); mainFrame.setBounds(280,100,500,450); mainFrame.setVisible(true); public void randomBuild() int randoms,cols,rows; for(int twins=1;twins=15;twins+) randoms=(int)(Math.random()*25+1); for(int alike=1;alike=2;alike+) cols=(int)(Math.random()*6+1); rows=(int)(Math.random()*5+1); while(gridcolsrows!=0) cols=(int)(Math.random()*6+1); rows=(int)(Math.random()*5+1); this.gridcolsrows=randoms; public void fraction() fractionLable.setText(String.valueOf(Integer.parseInt(fractionLable.getText()+100); public void reload() int save = new int30; int n=0,cols,rows; int grid= new int87; for(int i=0;i=6;i+) for(int j=0;j=0) cols=(int)(Math.random()*6+1); rows=(int)(Math.random()*5+1); while(gridcolsrows!=0) cols=(int)(Math.random()*6+1); rows=(int)(Math.random()*5+1); this.gridcolsrows=saven; n-; mainFrame.setVisible(false); pressInformation=false; /这里一定要将按钮点击信息归为初始 init(); for(int i = 0;i 6;i+) for(int j = 0;j 5;j+ ) if(gridi+1j+1=0) diamondsButtonij.setVisible(false); public void estimateEven(int placeX,int placeY,JButton bz) if(pressInformation=false) x=placeX; y=placeY; secondMsg=gridxy; secondButton=bz; pressInformation=true; else x0=x; y0=y; fristMsg=secondMsg; firstButton=secondButton; x=placeX; y=placeY; secondMsg=gridxy; secondButton=bz; if(fristMsg=secondMsg & secondButton!=firstButton) xiao(); public void xiao() /相同的情况下能不能消去。仔细分析，不一条条注释 if(x0=x &(y0=y+1|y0=y-1) | (x0=x+1|x0=x-1)&(y0=y) /判断是否相邻 remove(); else for (j=0;jj) /如果第二个按钮的Y坐标大于空按钮的Y坐标说明第一按钮在第二按钮左边 for (i=y-1;i=j;i- ) /判断第二按钮左侧直到第一按钮中间有没有按钮 if (gridxi!=0) k=0; break; else k=1; /K=1说明通过了第一次验证 if (k=1) linePassOne(); if (yj) /如果第二个按钮的Y坐标小于空按钮的Y坐标说明第一按钮在第二按钮右边 for (i=y+1;i=j ;i+ ) /判断第二按钮左侧直到第一按钮中间有没有按钮 if (gridxi!=0) k=0; break; else k=1; if (k=1) linePassOne(); if (y=j ) linePassOne(); if (k=2) if (x0=x) remove(); if (x0x) for (n=x0;nx) for (n=x0;n=x+1 ;n- ) if (gridnj!=0) k=0; break; if(gridnj=0 & n=x+1) remove(); for (i=0;ii) for (j=x-1;j=i ;j- ) if (gridjy!=0) k=0; break; else k=1; if (k=1) rowPassOne(); if (xi) for (j=x+1;j=i;j+ ) if (gridjy!=0) k=0; break; else k=1; if (k=1) rowPassOne(); if (x=i) rowPassOne(); if (k=2) if (y0=y) remove(); if (y0y) for (n=y0;ny) for (n=y0;n=y+1 ;n-) if (gridin!=0) k=0; break; if(gridin=0 & n=y+1) remove(); public void linePassOne() if (y0j) /第一按钮同行空按钮在左边 for (i=y0-1;i=j ;i- ) /判断第一按钮同左侧空按钮之间有没按钮 if (gridx0i!=0) k=0; break; else k=2; /K=2说明通过了第二次验证 if (y0j) /第一按钮同行空按钮在与第二按钮之间 for (i=y0+1;ii) for (j=x0-1;j=i ;j- ) if (gridjy0!=0) k=0; break; else k=2; if (x0i) for (j=x0+1;j=i ;j+ ) if (gridjy0!=0) k=0; break; else k=2; public void remove() firstButton.setVisible(false); secondButton.setVisible(false); fraction(); pressInformation=false; k=0; gridx0y0=0; gridxy=0; public void actionPerformed(ActionEvent e) if(e.getSource()=newlyButton) int grid = new int87; this.grid = grid; randomBuild(); mainFrame.setVisible(false); pressInformation=false; init(); if(e.getSource()=exitButton) System.exit(0); if(e.getSource()=resetButton) reload(); for(int cols = 0;cols 6;cols+) for(int rows = 0;r