多属性决策分析案例 结果.doc

多属性决策分析案例(分析过程文件见文件夹“分析过程”)第一步：利用MATLAB求综合属性值M-FILE源文件见“multiattribute.m”代码：%first import the data for A!%首先输入数组 A（即文件“多属性决策”）! 源数据顺序经过了调整，把逆指标放在前23列，正指标放在后八列R=zeros(60,31);R1=zeros(60,31);E=zeros(1,31);W=zeros(1,31);Z=zeros(60,1);B=ones(1,31);%把B变成全为1的数组k=1:23;B(1,k)=1./max(A(:,k)-min(A(:,k); %确定MAX(a(i,j)-MIN(a(i,j)数组for j=1:23 R(:,j)=(max(A(:,j)-A(:,j).*B(1,j);%先把前23个逆指标规范化 endB=ones(1,31);%再次把B变成全为1的数组k=24:31;B(1,k)=1./max(A(:,k)-min(A(:,k); for j=24:31 R(:,j)=(A(:,j)-min(A(:,j).*B(1,j)%再把后八个正指标规范化for j=1:31 R1(:,j)=R(:,j)./(sum(R(:,j);%将矩阵R列归一化ende=0;for j=1:1:31 for i=1:1:60 if R1(i,j)=0 s=0; else s=R1(i,j)*log(R1(i,j); end e=s+e; end E(j)=(-1/log(60)*e;%得出信息熵endsK=sum(1-E(1,:);for j=1:31 W(j)=(1-E(j)./sK;%得出权重endfor i=1:60;z=0; for j=1:31 z=z+R(i,j)*W(j); end Z(i)=z;%得出综合属性值Zendend综合属性值Z的具体数值见文件EXCLE “综合属性Z的数值“第二步：用SPSS进行聚类分析分析结果聚类成员案例号VAR00002聚类距离1 1.001.0132 2.005.0023 3.004.0144 4.004.0015 5.004.0316 6.004.0187 7.005.0248 8.005.0179 9.005.02210 10.004.01211 11.002.01812 12.003.00613 13.005.01614 14.004.00015 15.004.01416 16.0057.511E-617 17.002.00118 18.002.01019 19.002.02220 20.001.01921 21.004.03722 22.003.00223 23.001.00624 24.004.03625 25.002.00226 26.004.01627 27.004.01928 28.003.00129 29.004.01030 30.002.03031 31.002.01432 32.005.00233 33.003.00934 34.004.02435 35.004.02336 36.002.01737 37.005.01038 38.004.00239 39.002.01640 40.005.00741 41.002.00242 42.004.00543 43.002.00744 44.004.00345 45.002.03246 46.004.02147 47.004.02448 48.002.02349 49.002.00650 50.002.01251 51.002.01752 52.002.01753 53.005.02454 54.005.00755 55.001.01256 56.005.02057 57.005.00758 58.005.01359 59.004.02160 60.002.018最终聚类中心