c#作业.docx

C#课程设计学校：华北水利水电学院院系：信息工程学院专业：计算机科学与技术专业班级：2010135班题目：设计一个window窗体计算机程序，可以实现优先级和括号的计算。一、程序代码：using System;using System.Collections.Generic;using System.ComponentModel;using System.Data;using System.Drawing;using System.Linq;using System.Text;using System.Windows.Forms;namespace 计算器1 public partial class Form1 : Form Button btn; public Form1() InitializeComponent(); private void button11_Click(object sender, EventArgs e) btn = (Button)sender; richTextBox1.Text = richTextBox1.Text + btn.Text; private void button16_Click(object sender, EventArgs e) btn = (Button)sender; string s = richTextBox1.Text.Trim(); string 数据 = s.Split(new char +, -, *, /, (, ) , StringSplitOptions.RemoveEmptyEntries); char yun=s.ToCharArray(); int k = 0; for (int i = 0; i yun.Length; i+) if (yuni = + | yuni = - | yuni = * | yuni = / | yuni = ( | yuni = ) k+; char 运算符=new chark; int j = 0; for (int i = 0; i yun.Length; i+) if (yuni = + | yuni = - | yuni = * | yuni = / | yuni = ( | yuni = ) 运算符j = yuni; j+; double 整型数据 = convert(数据); int 运算符号 = 转化运算符(运算符); double 结果 = 计算结果(整型数据, 运算符号); richTextBox1.Text += =; richTextBox1.Text += 结果.ToString(); private double convert (string 数) double result = new double数.Length; for (int i = 0; i 数.Length; i+) try resulti = double.Parse(数i); catch (Exception) MessageBox.Show(数i + 无法转化成功！); return result; private int 转化运算符(char 运算符) int yunsuan = new int运算符.Length; for (int i = 0; i 运算符.Length; i+) if (运算符i = +) yunsuani = 1; if (运算符i = -) yunsuani = 2; if (运算符i = *) yunsuani = 4; if (运算符i = /) yunsuani = 5; if (运算符i = () yunsuani = 7; if (运算符i = ) yunsuani = 8; return yunsuan; private double 计算结果(double 数, int 符) double 结果 = 0.0; if (符.Length = 1) switch (符0) case 1: 结果 = 数0 + 数1; break; case 2: 结果 = 数0 - 数1; break; case 4: 结果 = 数0 * 数1; break; case 5: if (数1 != 0)结果 = 数0 / 数1; else MessageBox.Show(除数不能为零！); break; return 结果; else int key=0; for (int i = 0; i 符.Length; i+) if (符i = 7) key = 1; break; /运算符中有括号 if (key = 1) int j = new int2; int x = 0;double a = 0.0; for (int i = 0; i 符.Length; i+) if (符i = 7) j0 = i; if (符i = 8) j1 = i; break; x = j1 + 1; double c = new doublej1 - j0; int d = new intj1 - j0-1; for (int i = 0; i c.Length; i+) if (i = 0) ci = 数j0; else ci = 数j0 + i; for (int i = 0; i d.Length; i+) di = 符j0 + i+1; a = 计算结果(c, d); double e = new double数.Length - j1 + j0+1; int f = new int符.Length - j1+j0-1; for (int i = 0; i e.Length; i+) if (i j0) ei = 数i; else if (i = j0) ei = a; else ei = 数j1; j1 = j1 + 1; if (e.Length = 1) return e0; else for (int i = 0; i f.Length; i+) if (i j0) fi = 符i; else fi = 符x; x = x + 1; 结果 = 计算结果(e, f); return 结果; /运算符中无括号 else double a = 0; if (符0 + 1 符1) switch (符1) case 4: a = 数1 * 数2; break; case 5: a = 数1 / 数2; break; double c = new double数.Length - 1; int d = new int符.Length - 1; for (int i = 0; i c.Length; i+) if (i = 1) ci = a; else if (i = 2) ci = 数+i; else ci = 数i; for (int i = 0; i d.Length; i+) if (i = 1) di = 符+i; else di = 符i; 结果 = 计算结果(c, d); return 结果; else switch (符0) case 1: a = 数0 + 数1; break; case 2: a = 数0 - 数1; break; case 4: a = 数0 * 数1; break; case 5: a = 数0 / 数1; break; double c = new double数.Length - 1; int d = new int符.Length - 1; for (int i = 0; i c.Length; i+) /MessageBox.Show(a.ToString(); if (i = 0) ci = a; else ci = 数i+1; /MessageBox.Show(c1.ToString(); /MessageBox.Show(数i.ToString(); for (int i = 0; i d.Length; i+) di = 符i+1; 结果 = 计算结果(c, d); return 结果; private void button19_Click(object sender, EventArgs e) MessageBox.Show(欢迎使用我的计算器！); private void button20_Click(object sender, EventArgs e) this.richTextBox1.Text = ; private void 退出ToolStripMenuItem_Click(object sender, EventArgs e) Close(); private void 关于aboutToolStripMenuItem_Click(object sender, EventArgs e) Form2 frm = new Form2(); frm.ShowDialog(); private void 复制ctToolStripMenuItem_Click(object sender, EventArgs e) richTextBox1.Copy(); private void 粘贴CtrlvToolStripMenuItem_Click(object sender, EventArgs e) richTextBox1.Paste(); 二、程序运行截图：（1）程序欢迎界面：在打开计算器使用前的提示界面（2）程序运行结果界面（3）除数为零：（4）其他：三、思考与总结：其实这对于我来说并不是一个简单的程序，总的下来不知道自己用了多长时间，但最后结果还是有点不太理想，感觉现在我写的这个程序有点浪费系统的存储空间，建立了很多的数组，其实我想用栈来解决问题会更好一些，但是经过写这个程序我还是有一些收获的，我的程序的总体思路是先将输入的表达式存在一个string字符串中然后经过一定的分割将数据与运算符分隔开在不同