单片机指令合集.docx

已知A=34H，R6=29H 把R6的前4位和后4位交换MOV R6,#29HXCH A R6SWAP AXCH A R6把29H赋值给R6R6和A交换A的前后4位交换R6和A交换22H单元开始有一无符号数，长度存在20H单元，求出数块的最大值，并存21H单元。LP:NEXT:NEXT1:CLR AMOV R2,20HMOV R1,#22HCLR CSUBB A,R1JNC NEXTMOV A,R1SJMP NEXT1ADD A,R1INC R1DJNE R2 LPMOV 21H,ARET寄存器清0把20H（地址）赋值给R2把22H赋值给R1进位位清零A- R1没有进位跳转NEXT把R1里面的数赋值给A强制跳转到NEXT1把R1里面的数赋值给AR1+1R2减一不为0跳转到LP把A赋值给21H执行计算 1234H+0FE7H 程序 高4位存41H 低4位存40HMOV A,#34HADD A,#0E7HMOV 40H,AMOV A,#12HADDC A,#0FHMOV 41H,A把A赋值34H把0E7H赋值给A把A赋值给40H把A赋值12HA加上0FH把A赋值给41H把8位2进制（0255）转换成3位BCD码 百位存储在21H 十位个位存储在22H中MOV B,#64HDIV A BMOV 21H,AMOV A,#0AHXCH A BDIV A BSWAP AADD A BMOV 21H,A,把B赋值64HA除以B把A（商）赋值给21H把0AH赋值给AA（10）B（余数）交换A除以BA的高四位和低四位交换（余数是两位数高4位是0000）A加B（余数）把A赋值给21H单字节BCD码减法 21H里放被减数 11H里放减数MOV R1,#21HMOV R0,#11HCLR CMOV A,#9AHSUBB A R0ADD A R1DA AMOV 12H AR1赋值21HR0赋值11H进位位清零把9AH赋值给AA-R0 （求补码）A加上R110进制调正把A赋值给12H有十个无符号的数 由小到大排序（沉底）ROL:LP0:LP1:MOV R0,#10HMOV R2,#0AHMOV A,R0MOV R1,AMOV A,R2MOV R5,ACLR 00HDEC R5MOV A,R1MOV R3,AINC R1CLR CMOV A,R1SUBB A,R3JNC LP1SETB 00HMOV A,R3XCH A,R1DEC R1XCH A,R1INC R1MOV A,R1DJNZ R5,LP0JB 00H,ROL把10H赋值给R0把0AH赋值给R2把R0赋值给A把A赋值给R1把R2赋值给A把A赋值给R500H位清零R5减一把R1赋值给A把A赋值给R3R1加1进位位清零把R1赋值给AA减去R2没有进位位跳转LP1设定00H为1把R3赋值给AA 与 R1交换R1减去1A 与 R1交换R1加1把R1赋值给A没有借位跳转到R500H为1跳转ROL用P1口连续8次数据并作和后平均LP0:LP1:LP3:MOV R0,#00HMOV R1,#00HMOV R2,#08HMOV P1,#0FFHMOV A,P1ADD A,R1JNC LP1INC R0MOV R1,ADJNE R2 LP2MOV R2,#03HMOV A,R0RRC AMOV R0,AMOV A,R1RRC AMOV R1,ADJNZ R2 LP3把00H赋值给R0把00H赋值给R1把08H赋值给R2把0FFH赋值给P1把P1赋值给A把R1赋值给A没有进位跳转到LP1R0加1把A赋值给R1R2-1不为0跳转LP2把03H赋值给R2把R0赋值给A向右移动1位把A赋值给R0把R1赋值给A向右移动1位把A赋值给R1R2减1不为0跳转到LP3设片外RAM2000H开始存有100个有符号的数。试统计这一个百符号数的正数负数0的数量LOOP:NO_ZERO:NO_NEGA:DOWNCLR AMOV R5,AMOV R6,AMOV R7,AMOV R2,#64HMOV DPTR,#2000HMOVX A,DPTRJNE NO_ZEROINC R5SJMP DOWNJNB A NO_NEGAINC R6SJMP DOWNINC R7INC DPTR DJNZ R2 LOOPRET寄存器清零把A赋值给R5把A赋值给R6把A赋值给R7把64H赋值给R2把2000H赋值给DPTR把DPTR赋值给A不等于0跳转NO_ZEROR5加1强制跳转DOWN首位为0跳转NO_NEGAR6加1强制跳转DOWNR7加1DPTR加1R2减一不为0跳转LOOP执行CD码变二进制BCDBML10TAFAMOV R7,#03HMOV R0,#43HMOV R3,#00HMOV A,R0MOV R2,AMOV A,R2MOV B,#0AHMUL A BMOV R2,AMOV A,BXCH A,R3MOV B,#0AHMUL A BADD,A,R2MOV R3,ADEC R0MOV A,R0ADD A,R2MOV R2,AMOV A,R3ADDC A,#00HMOV R3,ADJNZ R7,ML10R7赋值03HR0赋值43HR3赋值00H把43H里面的数赋值给A把A赋值给R2把R2赋值给A把10赋值给BAXB把A赋值给R2（低4位给R2）把B赋值给A（高4位给A）把R3和A调换（A为00H、R3为高4位）把0AH（10BCD）赋值给B AXB（10X0）A（低4位）加上R2（第一个乘法的低4位）把A+R2和赋值给R3R0减1把42H里面的数赋值给A把A加上R2把A赋值给R2把R3赋值给AA+CY把A赋值给R3R7减1不为0跳转ML10将R0中的ASCLL码转换为十六进制SB2MOV A,R0CLR CSUBB A,#30HMOV R0,ASUBB A,#0AHJC SB2XCH A,R0SUBB A,#07HMOV R0,ARET把R0里面的数赋值给A进进位清零A减30H把A赋值给R0A减0AH有借位跳转到SB2R0与A交换A减去07H把A赋值给R0执行AF的ASCLL码是41H47H09的ASCLL码是31H39H十六进制变ASCLL码LOOP1NEXTMOV A,R0CJNE A,#0AH,LOOP1JC,NEXTADD A,#07HADD A,#30HMOV R0,ARET把R0赋值给AA不等于10跳转到LOOP1有借位跳转到NEXT（A小于10）A加上07HA加上30H把A赋值给R0执行40H0541H0142H0643H0344H0016进制转换成10进制R30EHR21FH10000=2710H1000=03E8H100=0064H10=000AHBBCD:BBC1：BBC2:BBC3:MOV R0,#44HMOV R7,#0AHMOV DPTR,PWTAMOV R6,#00HMOV A,R6MOVC A,A+DPTRMOV R4,AINC R6MOV A,R6MOVC A,A+DPTRMOV R5,AINC R6MOV R0,#00HCLR CMOV A,R2SUBB A,R4MOV R2,AMOV A,R3SUBB A,R5MOV R3,AJC BBC3INC R0SJMP BBC2MOV A,R2ADD A,R4MOV R2,AMOV A,R3ADDC A,R5MOV R3,ADEC R6DJNZ R7,BBC1MOV A,R2MOV R0,ARET把R0赋值44H把R7赋值0AH把PWTA赋值给DPTR把00H赋值给R6把R6赋值给A把A+DPTR的数赋值给A把A赋值给R4R6加1把R6赋值给A把A+DPTR的数赋值给A把A赋值给R5R6加1把00H赋值给R0进位位清零把R2赋值给AA减去R4把A赋值给R2把R3赋值给A把A减R5把A赋值给R3有进位跳转到BBC3R0加1强制跳转到BBC2把R2赋值给AA加上R4把A赋值给R2把R3赋值给AA加上R5把A赋值给R3R6减1R7减一不为0 跳转到BBC1把R2赋值给A把A赋值给R0执行PWTA DB 10H 27H 0E8H 03HDB 64H 10H 0AH 00H BBC1为查表 BBC2为减法 BBC3为恢复试编程把以2040H为首地址的连续50个单位中的无符号数按降序排列，存放到以3000H为首地址的存储区LP:LP1:LP2:L1:NO_CH:MOV R2,#32HMOV R3,#20HMOV R4,#40HMOV R5,#30HMOV R6,#00HMOV DPH,R3MOV DPL,R4MOVX A,DPTRINC DPTRMOV R3,DPHMOV R4,DPLMOV DPH,R5MOV DPL,R6MOVX DPTR,AINC DPTRMOV R5,DPHMOV R6,DPLDJNZ R2,LPMOV R2,#31HMOV DPTR,#3000HMOV R3,#31HMOVX A,DPTRMOV B,AINC DPTRMOVX A,DPTRJC NO_CHMOV 30H,ACLR CMOV A,DPLSUBB A,#01HMOV DPL,AMOV A,30HINC DPTRMOV A,BMOVX DPTR,ADJNZ R3,LP2DJNZ R2,LP1RET把R2赋值#32H（50BCD）把R3赋值#20H把R4赋值#40H把R5赋值#30H把R6赋值#00H把R3赋值给DPH（DPTR的高8位）把R4赋值给DPL（DPTR的低8位）把DPTR里面的数赋值给A把DPTR加1把DPH赋值给R3把DPL赋值给R4把R5赋值给DPH把R6赋值给DPL把A赋值到DPTR里面DPTR加1把DPH赋值给R5把DPL赋值给R6R2减1不为0跳转到LP把R2赋值31H把DPTR赋值3000H把R3赋值31H把DPTR里面的数赋值给A把A赋值给BDPTR加1把DPTE里面的数赋值给A有进位跳转NO_CH把A赋值给30H进位位清零把DPL赋值给AA加01H把A赋值给DPL把30H赋值给ADPTR加1把B赋值给A把A赋值给DPTRR3减1不为0跳转到LP2R2减1不为0跳转到LP1执行在以2000H为首地址的存储区中，存放着20个用ASKII码表示的09之间的数，是编程将它们转换成BCD码，并LP:MOV R2,#10MOV R3,#20HMOV R4,#00HMOV R5,#30HMOV R6,#00HMOV DPH,R3MOV DPL,R4MOVX A,DPTRANL A,#0FHSWAP AXCH A BINC DPTRMOVX A,DPTRANL A,#0FHORL A,BINC DPTRMOV R3,DPHMOV R4,DPLMOV DPH,R5MOV DPL,R6MOV DPTR,AINC DPTRMOV R5,DPHMOV R6,DPLDJNZ R2,LP把10赋值给R2把20H赋值给R3把00H赋值给R4把30H赋值给R5把00H赋值给R6把R3赋值给DPH把R4赋值给DPL把DPTR赋值给AA与#0FH做与门把A的高低4位交换把A与B交换DPTR加1把DPTR赋值给A把A与#0FH做与门把A与B 做或门DPTR加1把DPH赋值给R3把DPL赋值给R4把R5赋值给DPH把R5赋值给DPL把A赋值给DPTRDPTR加1把DPH赋值给R5把DPL赋值给R6R2减1不为0-跳转LP以压缩BCD码（即一个单位存放2位BCD码）的形式存放在3000H3009H单元中。把内存单元40H60H中的数逐个存入对应的片外2540H2560H单元中L1:MOV DPTR,#2540HMOV R2,#20HMOV R0,#40HMOV A,R0INC R0MOVX DPTR,AINC DPTRDJNZ R2 L1把#2540H赋值给DPTR把#20H赋值给R2把#40H赋值给R0把R0赋值给AR0