电子科大C语言实验10.doc

#include#include#includetypedef structdouble * mat;int row;int col;Matrix;Matrix max;int main()void InitialMatrix(Matrix *T, int row,int col);/只分配空间不初始化；void InitialMatrixZero(Matrix *T,int row, int col);/初始化为0void InitialMatrixRand(Matrix *T,int row, int col);/初始化为50以内随机正整数void InputMatrix(Matrix *T);/键盘输入矩阵void DestroyMatrix(Matrix *T);/ 释放矩阵空间void PrintfMatrix(Matrix *T);/矩阵输出int AddMatrix(Matrix *A,Matrix *B,Matrix *C); / 矩阵加int MinusMatrix(Matrix *A,Matrix *B,Matrix *C); / 矩阵减int MultiMatrix(Matrix *A,Matrix *B,Matrix *C); /矩阵乘法double MeanMatrix(Matrix *T); /矩阵元素均值int SubMatrix(Matrix *T1,Matrix *T2,int BeginRow,int BeginCol,int EndRow,int EndCol); /求T1的子矩阵T2;srand(unsigned) time(NULL);/用时间做种int n;printf( 矩阵函数测试，请选择功能，输入对应的数字：n);printf(*n);printf( 1：输入一个矩阵，求矩阵均值；n);printf( 2：产生一个随机数矩阵，求矩阵均值；n);printf( 3：输入两个个矩阵，求矩阵和；n);printf( 4：输入两个个矩阵，求矩阵差；n);printf( 5：输入两个个矩阵，求矩阵积；n);printf( 6：产生两个个随机数矩阵，求矩阵和；n);printf( 7：产生两个个随机数矩阵，求矩阵差；n);printf( 8：产生两个个随机数矩阵，求矩阵积；n);printf( 9：求矩阵的子阵，如矩阵的2-4行，1-3列的子阵；n);printf( 0：结束!n);scanf(%d,&n);if(n=0)exit(0);Matrix m,p,q;printf(输入矩阵的行数n);scanf(%d,&m.row);printf(输入矩阵的列数n);scanf(%d,&m.col);InitialMatrix(&m,m.row,m.col);/分配内存空间InitialMatrixZero(&m,m.row,m.col);/初始化为0if(n2&nmat=(double*)malloc(row*col)*sizeof(double*);/为指针数组分配内存for(i=0;irow;i+)T-mati=(double*)malloc(T-col*sizeof(double);/为数组中的数分配内存void InitialMatrixZero(Matrix *T,int row, int col)/初始化为0int i,j;for(i=0;irow;i+)for(j=0;jmatij=0;void InitialMatrixRand(Matrix *T,int row, int col)/初始化为50以内随机正整数int i,j;for(i=0;irow;i+)for(j=0;jmatij=rand()%51;/调用rand函数的随机数printf(%7.2f,T-matij);printf(n);void InputMatrix(Matrix *T)/键盘输入矩阵int i,j;for(i=0;irow;i+)for(j=0;jcol;j+)scanf(%lf,&T-matij);void DestroyMatrix(Matrix *T)/ 释放矩阵空间int i;for(i=0;irow;i+)free(T-mati);free(T-mat);void PrintfMatrix(Matrix *T)/矩阵输出int i,j;for(i=0;irow;i+)for(j=0;jcol;j+)printf(%7.2f ,T-matij);printf(n);/输出完一行之后换行int AddMatrix(Matrix *A,Matrix *B,Matrix *C)/ 矩阵加法int i,j;for(i=0;irow;i+)for(j=0;jcol;j+)C-matij=A-matij+B-matij;return 0;int MinusMatrix(Matrix *A,Matrix *B,Matrix *C) / 矩阵减法int i,j;for(i=0;irow;i+)for(j=0;jcol;j+)C-matij=(A-matij)-(B-matij);return 0;int MultiMatrix(Matrix *A,Matrix *B,Matrix *C) /矩阵乘法int i,j,k;for(i=0;irow;i+)for(j=0;jcol;j+)for(k=0;kcol;k+)C-matij=(C-matij)+(A-matik)*(B-matkj);return 0;double MeanMatrix(Matrix *T) /矩阵元素均值int i,j;double sum=0.0,ave;for(i=0;irow;i+)for(j=0;jcol;j+)sum=sum+T-matij;ave=sum/(T-row*T-col);return ave;int SubMatrix(Matrix *T1,Matrix *T2,int BeginRow,int BeginC