扑克牌生成与洗牌程序.doc

扑克牌生成与洗牌程序 使用JAVA编写以下程序： 1、请定义一个名为Card的扑克牌类，该类有两个private访问权限的字符串变量face和suit；分别描述一张牌的牌面值（如：A、K、Q、J、10、9、3、2等）和花色（如：“黑桃”、“红桃”、“梅花”、“方块”）；定义Card类中的public访问权限的构造方法，为类中的变量赋值；定义protected访问权限的方法getFace()，得到扑克牌的牌面值；定义protected访问权限的方法getSuit()，得到扑克牌的花色；定义方法toString()，返回表示扑克牌的花色和牌面值字符串（如“红桃A”、“梅花10”等）。 2、若应用程序的main方法中，定义字符串数组f和s；分别表示扑克牌的牌面值和花色；定义52个元素的Card类型数组deck，用来存放4个花色的52张牌。如下所示。 String f =A,2,3,4,5,6,7,8,9,10,J,Q,K; String s = 黑桃,红桃,梅花,方块; Card deck = new Card52； （1）使用Card类的构造方法给deck数组的52张牌赋值，要求数组中先存放黑桃花色的A、2、3、K；然后是红桃花色的A、2、3、K；梅花花色的A、2、3、K；方块花色的A、2、3、K。请写出实现上述功能的程序段。 （2）请编写模拟洗牌的完整程序，即把数组deck中的扑克牌随机打乱存放顺序。 原题如下： 引用内容 private String face; / A, K, Q, J, 10, . 2 private String suit; / Spade, Heart, Club, Diamond public Card(String suit, String face) this.face = face; this.suit = suit; protected String getFace() return face; protected String getSuit() return suit; public String toString() return suit + + face; 解题，完成程序解： 程序代码package poker; public class Card private String face; / A, K, Q, J, 10, . 2 private String suit; / Spade, Heart, Club, Diamond public Card(String suit, String face) this.face = face; this.suit = suit; protected String getFace() return face; protected String getSuit() return suit; public String toString() return suit + + face; public static void shuffle(Card deck, int startIndex, int size, int splitIndex) /shuffle洗牌 System.out.println(startIndex: + startIndex); if (splitIndex * 2 size) /if rand is 30 Card.swap(deck, startIndex, splitIndex, size - splitIndex); /52、0、30、22 shuffle(deck, size - splitIndex, splitIndex, size - splitIndex); /52、22、30、22 else if (splitIndex * 2 size) /if rnd is 10 Card.swap(deck, startIndex, size - splitIndex, splitIndex); /52、0、42、10 shuffle(deck, startIndex, size - splitIndex, splitIndex); /52、0、42、10 else Card.swap(deck, startIndex, splitIndex, splitIndex); public static void swap(Card deck, int srcIndex, int dstIndex, int size) /交换 /SRC是在本位置显示：source的缩写，源的意思 HREF是点击后连接的目标：HyperlinkReference，超链接引用 String face = ; String suit = ; for (int i = 0; i size; i+) face = decksrcIndex + i.face; suit = decksrcIndex + i.suit; decksrcIndex + i.face = deckdstIndex + i.face; decksrcIndex + i.suit = deckdstIndex + i.suit; deckdstIndex + i.face = face; deckdstIndex + i.suit = suit; /* * param args */ public static void main(String args) /第一问解答 Card deck = new Card52; String f = A, 2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K; String s = Spade, Heart, Club, Diamond; for (int i = 0; i s.length; i+) for (int j = 0; j f.length; j+) decki * 13 + j = new Card(si, fj); /依次存入数组之中，每13张一回合 /第二问解答 int rnd = 0; int numOfShuffle = 10; for (int i = 0; i numOfShuffle; i+) rnd = (int) Math.abs(Math.random() * 52); /Math.random()返回大于或等于 0.0 但小于 1.0 的伪随机 double 值。 Card.shuffle(deck, 0, deck.length, rnd); / Test /* for (int i=0; ideck.length; i+) System.out.println(decki); */PS：函数shuffle是模拟洗牌的过程，这里的算法比较粗燥，随机产生一个52以内数字n，把牌分为两份，1.n-1,和n-52,然后把两份牌交换一下顺序，这里做了十次切牌。 shuffle是一个递归函数，startIndex 表示切牌的开始序号，splitIndex表示切牌的序号，即上面的n getXXX是用来得到牌的花色和数字，第二问用不到本文来自CSDN博客，转载请标明出处：/weishaofei/archive/2009/07/28/4386710.aspxpublic class DeckOfCards extends Applet private Card deck; private int currentCard; private Button dealButton, shuffleButton; private TextField displayCard; public void init() String faces = Ace, Deuce, Three, Four, Five, Six, Seven, Eight, Nine, Ten, Jack, Queen, King ; String suits = Hearts, Diamonds, Clubs, Spades ; deck = new Card 52 ; currentCard = -1; for( int i = 0; i deck.length; i+ ) deck i = new Card( faces i % 13 , suits i / 13 ); dealButton = new Button( Deal card ); shuffleButton = new Button( shuffle cards ); displayCard = new TextField( 20 ); displayCard.setEditable( false ); add( dealButton ); add( shuffleButton ); add( displayCard ); public boolean action( Event event, Object object ) if( event.target = dealButton ) Card dealt = dealCard(); if( dealt != null ) displayCard.setText( dealt.toString() ); showStatus( Card #: + currentCard ); else displayCard.setText( NO MORE CARDS TO DEAL! ); showStatus( Shuffle cards to continue! ); else if( event.target = shuffleButton ) displayCard.setText( SHUFFLE CARDS. ); showStatus( ); shuffle(); displayCard.setText( DECK IS SHUFFLED! ); return true; public void shuffle() currentCard = -1; for( int i = 0; i deck.length; i+ ) int j = ( int )( Math.random() * 52 ); Card temp = deck i ; deck i = deck j ; deck j = temp; dealButton.enable(); public Card dealCard() if( +currentCard deck.length ) return deck currentCard ; else dealButton.disable(); return null; class Card private String face; private String suit; public Card( String f, String s ) face = f; suit = s; public String toString() return face + of + suit ; 两种洗牌发牌程序 收藏 用指针实现，这种比较低效#include #include void shuffle(int 13);void deal(int 13, char *, char *);int main(void) char *suit4 = hearts, diamonds, clubs, spades; char *face13 = one, two, three, four, five, six, seven, eight,nine, ten, eleven, twelve, thrteen; srand(time(NULL); int deck413 = 0; shuffle(deck); deal(deck, face, suit); return 0;void shuffle(int deck13) int card, row, column; for (card = 1; card = 52; card+) row = rand() % 4; column = rand() % 13; while (deckrowcolumn != 0) row = rand() % 4; column = rand() % 13; deckrowcolumn = card; void deal(int deck13, char *face, char *suit) int card, row, column; for (card = 1; card = 52; card+) for (row = 0; row = 3; row+) for (column = 0; column = 12; column+) if (deckrowcolumn = card) printf(%s of %sn, facecolumn, suitrow); 第二种是直接用结构体实现，比较高效#include #include struct card char *suit; char *face;typedef struct card Card;void fillDeck(Card *, char *, char *);void shuffle(Card *);void deal(Card *);int main(void) Card card52; char *suit4 = hearts, diamonds, clubs, spades; char *face13 = one, two, three, four, five, six, seven, eight,nine, ten, eleven, twelve, thrteen; srand(time(NULL); fillDeck(card, face, suit); shuffle(card); deal(card); return 0;/*void shuffle(int deck13) int card, row, column; for (card = 1; card = 52; card+) row = rand() % 4; column = rand() % 13; while (deckrowcolumn != 0) row = rand() % 4; column = rand() % 13; deckrowcolumn = card; void deal(int deck13, char *face, char *suit) int card, row, column; for (card = 1; card = 52; card+) for (row = 0; row = 3; row+) for (column = 0; column = 12; column+) if (deckrowcolumn = card) printf(%s of %sn, facecolumn, suitrow); */void fillDeck(Card *deck, char *face, char *suit) int i; for (i = 0; i 52; i+) decki.face = facei % 13; decki.suit = suiti / 13; void shuffle(Card *deck) int i, j; Card temp; for (i = 0; i 52; i+) j = rand() % 52; temp = decki; decki = deckj; deckj = temp; void deal(Card *deck) int i; for (i = 0; i 52; i+) printf(%s of %sn, decki.face, decki.suit); 用C+写的扑克牌洗牌、发牌和检测牌质量的程序代码(2010-12-12 23:00:09) 转载标签： c、扑克牌it用C+写的扑克牌洗牌、发牌和检测牌质量的程序代码编译器我用的是VS2008 。执行结果如图：源文件：有三个文件，一个是主函数文件 扑克牌游戏.cpp,一个是类函数成员的实现文件dapai.cpp，还有一个是系统生成的stdafx.app。头文件：有两个，一个是dapai.h,另一个是系统生成的stdafx.h。可以实现的简单功能：可以从一副扑克牌（不带王牌）发出n手牌（n4）,每手牌发m张牌（n*m 52）。每次执行都是随机发牌，发的牌没有重复出现，可以检测每一手牌的质量，比如有多少对牌出现、是否有同花出现、是否有连对出现、是否有顺子出现。我只是凭着我的思路写下的。里面没有复杂的算法，只是一些简单的语句，也有比较详细的注释。虽然写得不专业，但是我还会继续努力学习下去的。下面是源码：/dapai.h文件#pragma onceclass dapaipublic:int m;/要发几手牌int n;/要发牌的张数int count0;/是否有连续的五张牌出现标记int count2;/成对牌出现的对数int count3;/三张同号牌出现的个数int count4;/四张同号牌一起出现的标记int count222;void xipai();/洗牌void fapai(int,int);/发牌int a413;/ 发牌时统计同号牌出现的次数int b44;/ 发牌时统计每中花色出现的次数dapai(void);dapai(void);private:int puke413;const char *color 4 ;/ 花色char *face 13 ;/ 牌面;/ stdafx.h : 标准系统包含文件的包含文件，这个是系统生成的stdafx.h/ 或是经常使用但不常更改的/ 特定于项目的包含文件/#pragma once#define WIN32_LEAN_AND_MEAN/ 从 Windows 头中排除极少使用的资料#include #include / TODO: 在此处引用程序需要的其他头文件/ 扑克牌游戏.cpp : 定义控制台应用程序的入口点。/主函数文件#include stdafx.h#includeiostream#include dapai.husing namespace std;void compare( int ( *p1) 13 , int (*p2) 4 )/检测哪手牌比较好int max=*p2;int row1 = 0;for ( int i = 0; i 4; i+ )for ( int j =0; j max )max = *(*(p2 + i)+j);row1 = i;if ( max =5 )cout第 row1+1 手牌比较好！endl;int _tmain(int argc, _TCHAR* argv)dapai A;docout你要发几手牌？A.m;cout你要发多少张牌?A.n;if ( A.m*A.n 52 )cout 4)cout输入非法，只允许发4手牌以内！ 52 | A.m 4 );A.xipai();A.fapai(A.m,A.n);compare(A.a, A.b);/dapai.cpp文件#include StdAfx.h#include dapai.h#include cstdlib#include ctime#include iomanip#include iostreamusing namespace std;/构造函数开始dapai:dapai(void)for ( int i = 0; i 4; i+ )for( int j = 0; j 13; j+ )aij=0;for (int i = 0; i 4; i+ )for(int j = 0; j 4; j+ )bij=0;color 0 = 黑桃;color 1 = 梅花;color 2 = 方块;color 3 = 红桃;face 0 =A;face 1 = 2;face 2 = 3;face 3 = 4;face 4 = 5;face 5 =6;face 6 = 7;face 7 = 8;face 8 = 9;face 9 =10;face 10 = J;face 11 = Q;face 12 = K;for ( int row = 0; row 4; row +)for ( int column = 0; column 13; column +)puke row column =0;srand( time( 0 ) );/获得当前的时间作为随机数的种子/构造函数结束/洗牌void dapai:xipai()int row;int column;for ( int pai = 1; pai = 52; pai +)dorow = rand () % 4;column = rand() % 13; while ( puke row column !=0 );puke row column = pai;/洗牌结束/开始发牌,m手牌，每手牌n张void dapai:fapai( int m, int n)int pai = 1;int k = n;for( int j = 0; j m; j+ )cout第j+1手牌为：endl;for ( ; pai = n; pai + )for ( int row = 0; row 4; row + )for ( int column = 0; column 13; column + )if ( puke row column = pai )coutsetw( 8 )rightcolor row face column endl;ajcolumn +;bjrow +;n = n+k;count0 = 0;/是否有连续的五张牌出现标记count2 = 0;/成对牌出现的对数count3 = 0;/三张同号牌出现的个数count4 = 0;/四张同号牌一起出现的标记count222 = 0;/连对标记for (int i = 0; i 13; i + )if ( aji = 2 )/一对牌count2+;/cout有一对facei在里面endl;if ( aji = 3)/三张一样的牌count3+;/cout有三张同号牌facei在里面endl;if ( aji = 4 )/四张一样的牌count4+;/cout有四张同号牌facei在里面endl;/检测是否有顺子牌（五张连续的牌）for (int i = 0; i 12; i+ )if ( aji = 0 )count0 =0;elsecount0+;if ( count0 = 5)break;/顺子牌检测结束for ( int i = 0; i 12; i+ )if ( a j i 2 )count222 = 0;elsecount222+;if ( count222 =3 )break;/判断对牌并输出if ( count2 != 0 )cout tt很好！里面有count2对牌endl;/对牌输出结束if ( count3 !=0 )cout tt里面有三张同号牌endl;if ( count4 != 0 )cout tt里面有四张同号牌endl;if ( count0 = 5 )couttt非常棒！注意看，里面有顺子牌（五张连续的牌）喔endl;if ( count222 = 3 )couttt 不错，里面有连对喔!endl;/判断输出是否有五张同花的牌for (int i = 0; i 4; i + )if ( bji = 5 )couttt手气不错！有5张color i 在里面喔endl;/同花判断结束/发牌结束dapai:dapai(void)/ stdafx.cpp