C语言期末考试例题.docx

C语言期末考试试题例题1. 排序#includemain()int i,num10;void px(int num);printf(Input 10 numbers :n);for(i=0;i10;i+)scanf(%d,&numi);printf(n);px(num);for(i=1;i10;i+)printf(%5d,numi);void px (int num)int i,j,k;for(i=0;i9;i+)for(j=0;jnumj+1)k=numj;numj=numj+1;numj+1=k;2. 指针变量对数排序#includemain()int n1,n2,n3;int *p1,*p2,*p3;p1=&n1;p2=&n2;p3=&n3;void px(int *p1,int *p2);printf(Input three integrers :n1,n2,n3n);scanf(%d,%d,%d,p1,p2,p3);if(n1n2) px(p1,p2);if(n1n3) px(p1,p3);if(n2n3) px(p2,p3);printf(%3d,%3d,%3d,n1,n2,n3);void px(int *p1,int *p2)int p;p=*p1;*p1=*p2;*p2=p;3. 求方程的根#include#includeint main()int a,b,c;printf(please input a,b,c:);scanf(%d,%d,%d,&a,&b,&c);float s=b/(-2*a);float t=b*b-4*a*c;float r=(sqrt(t)/(2*a);float x1=s+r,x2=s-r;if(t0)printf(无实根！n);else if(t=0)x1=x2;printf(%d,x1);elseprintf(x1=%f,x2=%fn,x1,x2);4. 分段函数（以下函数为列）y=x x12x-1 1x103x-11 x10#includemain()float x,y;printf(please input x:n);scanf(%f,&x);if(x1)y=x;else if(x10)y=2*x-1;else y=3*x-11;printf(%f,y);5. 求和1. 求1！+2！+3！+20！#includevoid main()int i,j;long a,he=0;for(i=1;i21;i+)a=1;for(j=1;ji+1;j+)a=a*j;he=he+a;printf(%dn,he);2. 求2/1+3/2+5/3+8/5+ 前20项的和#includedouble sum(int n)int i;double j=0;for(i=1;i=n;i+)j=j+(1.0/i);return 2*n-j;main(void)printf(%f,sum(20);return 0;6. 求平均分7. 打印菱形#includevoid main()int a9=4,3,2,1,0,1,2,3,4,b9=1,3,5,7,9,7,5,3,1;int i,j;for(i=0;i9;i+)for(j=0;jai;j+)printf( );for(j=0;jbi;j+)printf(*);printf(n);8. 结构体#includestruct cj int sx;int yw;int yy;float pjcj;struct studentchar xh8;char *name;struct cj;void main()int i,j;struct student stu40;for(i=0;i40;i+)printf(输入第%d个学生信息,i);printf(输入格式：学号，姓名，数学成绩，语文成绩，英语成绩);scanf(%s,%s,%d,%d,%d,&stui.xh,,&stui.cj.sx,&stui.cj.yw,&stui.cj.yy);stui.cj.pjcj=(stui.cj.sx+stui.cj.yw+stui.cj.yy)/3void px(student stu,int n);px(stu,40);printf(学号t姓名t数学t语文t英语t平均分n);for(j=0;j40;j+)printf(%d,stuj.xh);printf(t%s,);printf(t%d,stui.cj.sx);printf(t%d,stui.cj.yw);printf(t%d,stui.cj.yy);printf(t%2f,stui.cj.pjcj);printf(n=*=*=*=*=*=*=*=*=*=*=*=*=*=*=*=*=*=*=*=*n);void px(student stu,int n)int i,j,max;student temp;for(i=0;in;i+)max=i;for(j=j