C++程序设计.doc

hawk 计算十个同学的平均成绩： #includevoid main()int i,j,a10;float max,min,sum=0,ave;cout请输入十个学生的成绩:endl; for(i=0;i=9;i+)cout请输入i+1ai;max=a0;if(maxai)max=ai;min=a0;if(minai)min=ai;sum=sum+ai;ave=sum/10.0;cout高:maxendl; cout低:minendl; cout均:aveendl;插入字符：#include#includevoid main()char str20,*a;int i=0,n;couta;coutn;for(a=str+strlen(str)+1;i(strlen(str)-n+1);i+,a-)*a=*(a-1);cout*a;cout则这个新字符串是：strendl;兑换硬币：#includevoid main()int a,b,c,i=0;for(a=0;a=10;a+)for(b=0;b=20;b+)for(c=0;c=100;c+)if(10*a+5*b+c=100)i+;couta b c endl;cout一共有i种方法！endl;二维数组的矩阵输出：#include#includevoid main()int i,j,a34;cout请输入12个整数：;for(i=0;i=2;i+)for(j=0;jaij;for(i=0;i=2;i+)for(j=0;j=3;j+)coutsetw(3)aij; coutendl; 泰勒级数累加的项数：#includevoid main()int i,j,f;float e=1;i=0;dof=1; for(j=1;j1e-5);cout总共累加了j项endl;构造函数：#includevoid main()struct studentint num;char name15;char sex10;float score2;float ave;struct student stu;int i,j;float sum1=0,sum2=0;cout请按照下列的要求输入相关信息endl;for(i=0;i3;i+)coutstu.num;;coutstu.sex;coutstu.score0stu.score1;sum1=stu.score0+stu.score1;stu.ave=sum1/2;的两门课平均分是:stu.aveendl;coutendl;1!+2!+3!+.+10!=#includevoid main()long int t=1,s=0;int i;for(i=1;i=10;i+)t=t*i; s=s+t;cout1!+2!+3!+.+10!=sendl;1+1 2！+1 3！+1n!=#includeint fact(int n)int f=1,i;for(i=1;i=n;i+)f=f*i;return(f);float sum(int n)float s=0;int i;for(i=1;i=n;i+)s=s+1.0/fact(i);return(s);main()int n;float s;coutn;s=sum(n);couts=1+1/2!+1/3!+1/4!+.+1/n!=sendl;和、积、平方和及和的平方:#include void main()int s1=0,s2=1,s3=0,s4,i,x;for (i=1;i=10;i+)cout请输入第ix; s1=s1+x; s2=s2*x; s3=s3+x*x; s4=s1*s1; i+;couts1=s1endls2=s2endls3=s3endls4=s4endl;位数的逆序输出和判断位数：#includevoid main()int i,x,t;coutx;i=1;t=x%10;cout这个数的逆序是：;coutt;while(x/10!=0)i+; x=x/10; t=x%10; coutt;coutendl这个数是i位数!endl;1到100之和是： #includeint sum(int n)int a=0,i,b=0;for(i=1;i=100;i+)a+=i;b=a;return(b);main()int a,b;b=sum(a);cout1至100的和是：bendl;解一元二次方程组：#include#includemain()float a,b,c,t,x1,x2,x,p,q;coutabc;t=b*b-4*a*c;p=(float)(-b)/(2*a);if(t0)x1=(-b)+sqrt(t)/(2*a); x2=(-b)-sqrt(t)/(2*a); coutx1=x1endlx2=x2endl;elseif(t=0)x=(float)(-b)/(2*a);coutx=xendl;elseq=sqrt(-t)/(2*a); coutx1=p+qiendl; coutx2=p-qiendl;所有的水仙花数是：#includevoid main()int i,j,k,n;