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供电设计报告工作面:入井乙线1. 负荷统计与变压器选择1.1负荷统计计算变压器负荷统计表设备名称电机台数电机型号额定功率(KW)额定电压(V)额定电流(A)额定功率因数cose启动功率因数cosq额定效率e启动电流倍数M1(水泵)1YB315L-4185.00660208.600.850.420.954.0M2(YBT52-2风机)1YBT52-211.0066012.600.880.450.897.0M3(YBT52-2风机)1YBT52-211.0066012.600.880.450.897.0M4(7.5KW对旋风机)1BDFJNo5-1515.0066017.250.880.450.896.0M5(7.5KW对旋风机)1BDFJNo5-1515.0066017.250.880.450.896.0M6(7.5KW对旋风机)1BDFJNo5-1515.0066017.250.880.450.896.0M7(7.5KW对旋风机)1BDFJNo5-1515.0066017.250.880.450.896.0功率Pe(KW)267.00平均功率因数cospj0.86总计功率(KW)267.001.2 变压器的选择根据供电系统的拟订原则,变压器的选择原理如下:1.2.1 变压器 T1: Kx = 0.550 cospj=(Picosei)/Pi = (185.000.85+11.000.88+11.000.88+15.000.88+15.000.88+15.000.88+15.000.88)/(185.00+11.00+11.00+15.00+15.00+15.00+15.00) = 0.8592,取0.7 将Kx值和cospj值代入得 Sb = KxPe / cospj = 0.550267.00 / 0.70 = 209.79 KVA 选用KSGB-400/6/0.69 型号符合要求。2. 设备选择2.1 高压电缆选择和校验:名称 型 号额定电压(V)长度(m)根数允许载流量(A)负荷电流(A)功率和(KW)电压损失(%)C1MYJV22-356000500114826.342670.21C2MYJV22-3560005114826.342670.00C3MYJV22-3560005114826.342670.002.2 低压电缆选择和校验:名称 型 号额定电压(V)长度(m)根数允许载流量(A)负荷电流(A)功率和(KW)电压损失(V)C15MY-3*166601518512.29110.39C6MY-3*7066051215200.411850C7MY-3*7066051215200.411850.62C4MY-3*7066010121550.37820.30C8MY-3*706605121550.37820.15C12MY-3*506605117341.16670.16C13MY-3*506605117312.29110.05C9MY-3*50660300117316.75153.91C10MY-3*506605117316.75150.07C11MY-3*106601016416.75150.52C5MY-3*70660201215200.411850C26MY-3*3566067113834.40562.40C25MY-3*106601016412.29110.38C16MY-3*10660516412.29110.19C17MY-3*3566018113827.64450.52C18MY-3*256601111333.51300.05C19MY-3*256601111316.75150.02C20MY-3*106601016416.75150.52C21MY-3*106601016416.75150.52C22MY-3*2566058111316.75151.35C23MY-3*106601016416.75150.52C24MY-3*35660300113812.29113.84C14MY-3*50660270117334.40567.232.3 高压配电箱的选择:名称 型 号额定电压(V)额定电流(A)额定热稳定电流(KA)热稳定时间(s)额定断流容量(MVA)D1PBG-100600010012.52100D2PBG-100600010012.52100 D1(PBG-100): 长时负荷电流:Ig = (PeKx10) / (3Uecospjpj) = (2670.8210) /(3 60000.860.93) =27 (A) D2(PBG-100): 长时负荷电流:Ig = (PeKx10) / (3Uecospjpj) = (2670.8210) /(3 60000.860.93) =27 (A)3. 短路电流计算3.1 高压短路电流的计算短路点电缆型号每公里电阻()每公里电抗()长度(m)根数电阻()电抗()d2C1(MYJV22-35)0.64200.105050010.32100.0525d2C3(MYJV22-35)0.64200.1050510.00320.0005d2C2(MYJV22-35)0.64200.1050510.00320.0005总阻抗()0.6345Id3(A)5732.13Id2(A)4964.17短路容量(MVA)62.553.2 低压短路电流的计算短路点变压器编号电缆型号每公里电阻()每公里电抗()长度(m)根数电阻()电抗()d3T1总阻抗()0.0585Id3(A)6810.32Id2(A)5897.91d4T1总阻抗()0.0585Id3(A)6810.32Id2(A)5897.91d1T1C5(MY-3*70)0.36400.07802010.00730.0016d1T1C6(MY-3*70)0.36400.0780510.00180.0004d1T1C7(MY-3*70)0.36400.0780510.00180.0004总阻抗()0.0654Id3(A)6088.46Id2(A)5272.76d5T1C11(MY-3*10)2.18000.09201010.02180.0009d5T1C9(MY-3*50)0.49100.081030010.14730.0243d5T1C8(MY-3*70)0.36400.0780510.00180.0004d5T1C4(MY-3*70)0.36400.07801010.00360.0008d5T1C10(MY-3*50)0.49100.0810510.00250.0004总阻抗()0.2149Id3(A)1853.85Id2(A)1605.48d6T1C12(MY-3*50)0.49100.0810510.00250.0004d6T1C22(MY-3*25)0.93700.08805810.05430.0051d6T1C17(MY-3*35)0.68300.08401810.01230.0015d6T1C26(MY-3*35)0.68300.08406710.04580.0056d6T1C4(MY-3*70)0.36400.07801010.00360.0008d6T1C14(MY-3*50)0.49100.081027010.13260.0219d6T1C23(MY-3*10)2.18000.09201010.02180.0009d6T1C8(MY-3*70)0.36400.0780510.00180.0004总阻抗()0.3103Id3(A)1283.84Id2(A)1111.84d7T1C8(MY-3*70)0.36400.0780510.00180.0004d7T1C4(MY-3*70)0.36400.07801010.00360.0008d7T1C13(MY-3*50)0.49100.0810510.00250.0004d7T1C24(MY-3*35)0.68300.084030010.20490.0252d7T1C25(MY-3*10)2.18000.09201010.02180.0009d7T1C12(MY-3*50)0.49100.0810510.00250.0004总阻抗()0.2719Id3(A)1465.39Id2(A)1269.074. 启动电压计算:(电机)名称 型 号额定电压(V)额定电流(A)额定功率(KW)启动电流(A)启动阻抗()启动电压(V)M1YB315L-4660208.6185777.100.46614.68M1/185KW水泵启动电压计算 水泵M1的启动电压计算T1:KSGB-400/6/0.69变压器输出电流:I=U2n /(3*Z)=690/(1.732*0.469338)=848.794843(A)M1启动时变压器输出端相电压:U=I*Z=848.794843*0.424327=360.166372(V)F2处电流:I=U/Z=360.166372/0.463473=777.103502(A)F2处电压:U=I*Z=777.103502*0.458923=356.630803(V)S1处电流:I=U/Z=356.630803/0.458923=777.103502(A)S1处电压:U=I*Z=777.103502*0.457798=355.756122(V)M1启动电流:I=U/Z=355.756122/0.457798=777.103502(A)M1启动电压:U=(3)*I*Z=1.732*777.103502*0.456677=614.679166(V)水泵M1的启动电压=614.679166(V) = Ue*75%=495(V) 满足要求。5. 整定保护5.1 高压配电箱整定保护名称 型 号额定电压(V)额定电流(A)过载保护值(A)速断保护值(A)二相短路电流(A)灵敏系数D1PBG-10060001003165272.7616.4D2PBG-10060001003185320.520 D1( PBG-100) 过载保护电流: Ig.zd = Krel(Ie1+Ie2+.)/Ki = (1.0538.49)/20 = 2.02 (A),取3 (A) 速断保护电流: Is.zd = (KI1eq+I1e)/Ki = (838.49+0)/20 = 15.4 (A),取16 (A) 过载时限:60S 灵敏系数:Kr = Id(2) / (KiIs.zd) = 5272.76/(2016) = 16.4 因为Kr 1.5, 满足要求 D2( PBG-100) 过载保护电流: Ig.zd =(KrelI1e)/Ki = (1.0538.49)/20 = 2.02 (A),取3 (A) 速断保护电流: Is.zd = (KI1e)/Ki = 838.49)/20 = 15.4 (A),取18 (A) 过载时限:60S 灵敏系数:Kr = Id(2) / (KiIs.zd) = 5320.52/(2018) = 14.7 因为Kr 1.5, 满足要求5.2 馈电开关整定保护名称 型 号过载保护值(A)速断保护(A)二相短路电流(A)灵敏系数F2KBZ9-40024012005272.764.39F1KBZ1-4001204001605.484.01F3KBZ1-4001204001605.484.01F6KBZ1-4001204001605.484.01F4KBZ1-4001204001111.842.78F7KBZ1-4001204001111.842.78F5KBZ1-4001204001269.073.17 F2( KBZ9-400) 需用系数: Kx = 0.4 + 0.6 Pmax / Pe = 0.4 + 0.6185/185 = 1 过载保护电流: Ig.zd = IeKx = 208.61 = 208.6 (A),取240 (A) 速断保护电流: Is.zd = Ieq+IeKx = 834.4+01 = 834.4 (A),取1200 (A) 灵敏系数:Kr = Id(2) / Is.zd = 5272.76/1200 = 4.39 因为Kr 1.5,所以满足要求。 F1( KBZ1-400) 需用系数: Kx = 0.4 + 0.6 Pmax / Pe = 0.4 + 0.615/82 = 0.51 过载保护电流: Ig.zd = IeKx = 94.20.51 = 48.04 (A),取120 (A) 速断保护电流: Is.zd = Ieq+IeKx = 103.5+76.950.51 = 142.74 (A),取400 (A) 灵敏系数:Kr = Id(2) / Is.zd = 1605.48/400 = 4.01 因为Kr 1.5,所以满足要求。 F3( KBZ1-400) 需用系数: Kx = 0.4 + 0.6 Pmax / Pe = 0.4 + 0.615/15 = 1 过载保护电流: Ig.zd = IeKx = 17.251 = 17.25 (A),取120 (A) 速断保护电流: Is.zd = Ieq+IeKx = 103.5+01 = 103.5 (A),取400 (A) 灵敏系数:Kr = Id(2) / Is.zd = 1605.48/400 = 4.01 因为Kr 1.5,所以满足要求。 F6( KBZ1-400) 需用系数: Kx = 0.4 + 0.6 Pmax / Pe = 0.4 + 0.615/15 = 1 过载保护电流: Ig.zd = IeKx = 17.251 = 17.25 (A),取120 (A) 速断保护电流: Is.zd = Ieq+IeKx = 103.5+01 = 103.5 (A),取400 (A) 灵敏系数:Kr = Id(2) / Is.zd = 1605.48/400 = 4.01 因为Kr 1.5,所以满足要求。 F4( KBZ1-400) 需用系数: Kx = 0.4 + 0.6 Pmax / Pe = 0.4 + 0.615/56 = 0.56 过载保护电流: Ig.zd = IeKx = 64.350.56 = 36.04 (A),取120 (A) 速断保护电流: Is.zd = Ieq+IeKx = 103.5+47.10.56 = 129.88 (A),取400 (A) 灵敏系数:Kr = Id(2) / Is.zd = 1111.84/400 = 2.78 因为Kr 1.5,所以满足要求。 F7( KBZ1-400) 需用系数: Kx = 0.4 + 0.6 Pmax / Pe = 0.4 + 0.615/56 = 0.56 过载保护电流: Ig.zd = IeKx = 64.350.56 = 36.04 (A),取120 (A) 速断保护电流: Is.zd = Ieq+IeKx = 103.5+47.10.56 = 129.88 (A),取400 (A) 灵敏系数:Kr = Id(2) / Is.zd = 1111.84/400 = 2.78 因为Kr 1.5,所以满足要求。 F5( KBZ1-400) 需用系数: Kx = 0.4 + 0.6 Pmax / Pe = 0.4 + 0.611/11 = 1 过载保护电流: Ig.z

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