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发信人: xiaoLee ($oftware Engineer), 信区: Job 标 题: Intel笔试题目2 发信站: 武汉白云黄鹤站 (2002年11月19日10:45:41 星期二), 站内信件 发信人: huidog (要多酸,就多酸), 信区: JobAndWork 标 题: 合集INTEL考题1 发信站: 南京大学小百合站 (Thu Nov 14 00:18:59 2002), 站内信件 Promenader (Promenader) 于Sun Nov 10 21:58:04 2002) 提到: 1。下面的程序是否正确,如正确,给出结果,否则,说明理由。 #include struct A int i; char j; char * ptr; long Array100;char b2; char * c; ; #define PRINT_ME (char *)&(struct A *)0)-c) void main() printf(%dn, PRINT_ME); amanofsky (枫丹白露) 于Sun Nov 10 22:01:55 2002) 提到: offset 应该是4+1+4+100*4+2*1 【 在 Promenader 的大作中提到: 】 : : 1。下面的程序是否正确,如正确,给出结果,否则,说明理由。 : #include : struct A : int i; : char j; : char * ptr; : long Array100; : char b2; : char * c; : ; : #define PRINT_ME (char *)&(struct A *)0)-c) : void main() : : printf(%dn, PRINT_ME); : seaboy (haha) 于Sun Nov 10 22:10:39 2002提到: 正确,答案是416 【 在 amanofsky (枫丹白露) 的大作中提到: 】 : offset : 应该是4+1+4+100*4+2*1 : : 【 在 Promenader 的大作中提到: 】 : (以下引言省略 . .) missllor (忆乐者) 于Sun Nov 10 22:13:30 2002) 提到: 32位机器,int和指针都占4个字节。 【 在 Promenader 的大作中提到: 】 : : 1。下面的程序是否正确,如正确,给出结果,否则,说明理由。 : #include : struct A : int i; : char j; : char * ptr; : long Array100; : char b2; : char * c; : ; : #define PRINT_ME (char *)&(struct A *)0)-c) : void main() : : printf(%dn, PRINT_ME); : Promenader (Promenader) 于Sun Nov 10 22:14:52 2002) 提到: 正确答案是416 因为机器字长32,四个字节,按4字节对齐, int占4字节,指针ptr占4个字节,所以“char j”也不得不占4字节了。 以此类推。 结构的大小为4+4+4+4*100+4+4=420 【 在 amanofsky 的大作中提到: 】 : offset : 应该是4+1+4+100*4+2*1 : : 【 在 Promenader 的大作中提到: 】 swayonline (在线飘零) 于Sun Nov 10 22:15:45 2002提到: 但是我试了一下,可以编译通过,但是运行出错,“dereference of null pointer” 【 在 seaboy (haha) 的大作中提到: 】 : 正确,答案是416 : 【 在 amanofsky (枫丹白露) 的大作中提到: 】 amanofsky (枫丹白露) 于Sun Nov 10 22:18:47 2002) 提到: /nod 应该4字节对其。 【 在 Promenader 的大作中提到: 】 : 正确答案是416 : 因为机器字长32,四个字节,按4字节对齐, : int占4字节,指针ptr占4个字节,所以“char j”也不得不占4字节了。 : 以此类推。 : 结构的大小为4+4+4+4*100+4+4=420 : : 【 在 amanofsky 的大作中提到: 】 lzf (一飞) 于Sun Nov 10 22:19:31 2002) 提到: 416? 【 在 Promenader 的大作中提到: 】 : : 1。下面的程序是否正确,如正确,给出结果,否则,说明理由。 : #include : struct A : int i; : char j; : char * ptr; : long Array100; : char b2; : char * c; : ; : #define PRINT_ME (char *)&(struct A *)0)-c) : void main() : : printf(%dn, PRINT_ME); : PlugPlay (饲养员何去何从?) 于Sun Nov 10 22:19:53 2002提到: c是一个指针呀,里面的初值什么时候定义了? 我觉得值是随机的。 【 在 Promenader (Promenader) 的大作中提到: 】 : : 1。下面的程序是否正确,如正确,给出结果,否则,说明理由。 : #include : struct A : int i; : char j; : char * ptr; : long Array100; : char b2; : char * c; : ; : #define PRINT_ME (char *)&(struct A *)0)-c) : void main() : : printf(%dn, PRINT_ME); : amaranth (恒星) 于Sun Nov 10 22:23:08 2002) 提到: 一般是字边界对齐(双字节),字符所占的空间只有两个字节 4+2+4+100*4+2,可以用sizeof验证一下(我没有验证过) 【 在 Promenader 的大作中提到: 】 : : 1。下面的程序是否正确,如正确,给出结果,否则,说明理由。 : #include : struct A : int i; : char j; : char * ptr; : long Array100; : char b2; : char * c; : ; : #define PRINT_ME (char *)&(struct A *)0)-c) : void main() : : printf(%dn, PRINT_ME); : xiling (水水) 于Sun Nov 10 22:23:31 2002提到: 前面不是有一个&吗?是地址的值。 【 在 PlugPlay (饲养员何去何从?) 的大作中提到: 】 : c是一个指针呀,里面的初值什么时候定义了? : 我觉得值是随机的。 : 【 在 Promenader (Promenader) 的大作中提到: 】 ADang (阿当) 于Sun Nov 10 22:24:27 2002提到: 改成单字节对齐,就是411 【 在 Promenader (Promenader) 的大作中提到: 】 : 正确答案是416 : 因为机器字长32,四个字节,按4字节对齐, : int占4字节,指针ptr占4个字节,所以“char j”也不得不占4字节了。 : 以此类推。 : 结构的大小为4+4+4+4*100+4+4=420 : : 【 在 amanofsky 的大作中提到: 】 PlugPlay (饲养员何去何从?) 于Sun Nov 10 22:25:33 2002提到: 学电子的考这个有点吃亏了 【 在 ADang (阿当) 的大作中提到: 】 : 改成单字节对齐,就是411 : 【 在 Promenader (Promenader) 的大作中提到: 】 sculptor (雕塑家) 于Sun Nov 10 22:26:11 2002) 提到: 407用TC2.0编译运行的答案 【 在 amanofsky 的大作中提到: 】 : offset : 应该是4+1+4+100*4+2*1 : : 【 在 Promenader 的大作中提到: 】 amanofsky (枫丹白露) 于Sun Nov 10 22:28:15 2002) 提到: tc里面int难道是2字节? 【 在 sculptor 的大作中提到: 】 : 407用TC2.0编译运行的答案 : 【 在 amanofsky 的大作中提到: 】 asusmb (华硕) 于Sun Nov 10 22:31:41 2002) 提到: 其中的0是什么意思 PlugPlay (饲养员何去何从?) 于Sun Nov 10 22:33:34 2002提到: 0变成地址 【 在 asusmb (华硕) 的大作中提到: 】 : 其中的0是什么意思 darming (原来时间让一切继续) 于Sun Nov 10 22:34:42 2002提到: VC+6.0编译的结果是416 【 在 Promenader (Promenader) 的大作中提到: 】 : : 1。下面的程序是否正确,如正确,给出结果,否则,说明理由。 : #include : struct A : int i; : char j; : char * ptr; : long Array100; : char b2; : char * c; : ; : #define PRINT_ME (char *)&(struct A *)0)-c) : void main() : : printf(%dn, PRINT_ME); : seaboy (haha) 于Sun Nov 10 22:48:45 2002提到: 这种题目没什么意思!对齐方式是可以改变的,况且不是每一种编译器都有完全一致的 解释 【 在 ADang (阿当) 的大作中提到: 】 : 改成单字节对齐,就是411 : 【 在 Promenader (Promenader) 的大作中提到: 】 php1 (php) 于Mon Nov 11 10:22:49 2002提到: 32位字节中int占4个字节。结构中字节的存储是按依次的顺序来的,先前i占4字节,接 着是j占一个字节,如果j后定义的变量和j 的类型相同就接着j的地址存储,不同就跳过 未用字符,从下一个存储单位即4字节开始放下面的变量。所以此题为 4+4+4+4*100+4=416, 【 在 Promenader (Promenader) 的大作中提到: 】 : : 1。下面的程序是否正确,如正确,给出结果,否则,说明理由。 : #include : struct A : int i; : char j; : char * ptr; : long Array100; : char b2; : char * c; : ; : #define PRINT_ME (char *)&(struct A *)0)-c) : void main() : : printf(%dn, PRINT_ME); : amanofsky (枫丹白露) 于Mon Nov 11 10:31:20 2002) 提到: it depends! Compiler defines how many bytes a INT type is,and byte alang in most of systems,its 4 bytes. 【 在 php1 的大作中提到: 】 : 32位字节中int占4个字节。结构中字节的存储是按依次的顺序来的,先前i占4字节,. . : 着是j占一个字节,如果j后定义的变量和j 的类型相同就接着j的地址存储,不同就?. : 未用字符,从下一个存储单位即4字节开始放下面的变量。所以此题为 : 4+4+4+4*100+4=416, : 【 在 Promenader (Promenader) 的大作中提到: 】 : (以下引言省略.) - 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