心形图案代码.docx

.1# include # include # define U 0.06# define V 0.025# define M 1.1# define N 1.2int main(void)float x, y;float m, n;for ( y=2; y=-2; y-=U )for ( x=-1.2; x=1.2; x+=V)if ( ( ( (x*x + y*y - 1)*(x*x + y*y - 1)*(x*x + y*y - 1) - x*x*y*y*y ) = 0 ) )printf(*);elseprintf( );printf(n);getchar();return 0;2#include#include# include # include # define U 0.06# define V 0.025# define M 1.1# define N 1.2void gotoxy(int x,int y);int main(void)system(mode con cols=100 lines=60);float x, y;float m, n;for ( y=2; y=-2; y-=U )for ( x=-1.2; x=1.2; x+=V)if ( ( ( (x*x + y*y - 1)*(x*x + y*y - 1)*(x*x + y*y - 1) - x*x*y*y*y ) = 0 ) )printf(*);elseprintf( );printf(n);gotoxy(0,0);getchar();return 0;void gotoxy(int x,int y)COORD Pos;Pos.X=x;Pos.Y=y;SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE),Pos);3. #includeint main(void)int a1,a2,a3,b,n,x,y,z,b1;int x1,x2,x3;printf(nnn 请先将窗口最大化！);printf(nnn 请输入一个3-10的数字，然后就将见证奇迹！nn);printf(nnnnnnnnnnnnnnnn);printf( made by 江陈苗n);scanf(%d,&z);printf(nnnnnnnnnnnnnnn);printf(nnnnnnnnnnn 送给最亲爱的XXX:nn);if (z6)printf(nn);for (x1=1;x1x1-3;x2-)printf( );for (x2=z;x22*z+3*x1-3;x2+)printf(8);for (x2=0;x24*(z-x1)-2;x2+)printf( );for (x2=z;x22*z+3*x1-3;x2+)printf(8);printf(n);elsefor (x1=2;x1x1-3;x2-)printf( );for (x2=z;x22*z+3*x1-3;x2+)printf(8);for (x2=0;x24*(z-x1)-2;x2+)printf( );for (x2=z;x22*z+3*x1-3;x2+)printf(8);printf(n);for (a1=0;a1z;a1+)if (a1!=1)printf( );for (b=0;b=a1;b+)printf( );for (x=0;x2*(4*z-a1)-8;x+)printf(8);printf(n);else printf( );for (b=0;b=a1;b+)printf( );for (b=1;b4*z-10;b+)printf(8);printf( I love you );for (b=1;b4*z-10;b+)printf(8);printf(n);if (z5)for (a1=z,b1=0;a13*z;a1+,b1+=2)printf( );for (b=z;b=a1;b+)printf( );for (b=0;b=a1;b+)printf( );for (x=2;x2*(4*z-a1)-8-b1;x+)printf(8);printf(n);printf( 来自爱你的江陈苗nnn);else if (z7)for (a1=z,b1=0;a13*z-5;a1+,b1+=2)printf( );for (b=z;b=a1;b+)printf( );for (b=0;b=a1;b+)printf( );for (x=2;x2*(4*z-a1)-8-b1;x+)printf(8);printf(n);printf( 来自爱你的江陈苗n);elsefor (a1=z,b1=0;a13*z-5;a1+,b1+=2)printf( );for (b=z;b=a1;b+)printf( );for (b=0;b=a1;b+)p