matlab实验8答案详解.doc

实验八 数据处理与多项式计算一、 实验目的二、 实验内容1、程序：A=rand(1,30000);b=mean(A)std(A,0,2)max(A)min(A)n=0;for i=1:30000 if A(i)0.5 n=n+1; endendp=n/30000结果：（1）b = 0.4982ans = 0.2889(2) ans = 1.0000ans = 4.8158e-005(3) p =0.49882.程序：A=45+51*rand(100,5);Y,U=max(A)a,b=min(A)m=mean(A)s=std(A)sum(A,2)Y,U=max(ans)a,b=min(ans)zcj,xsxh=sort(ans)结果:(1) Y = 95.6266 95.6995 95.8595 95.6439 95.6975U = 27 9 32 93 57a = 45.7076 45.3834 45.1919 45.3302 45.6031b = 57 89 36 10 44(2) m = 71.3417 72.4539 71.5630 71.4631 71.8984s = 14.1910 15.4451 14.7521 15.0758 14.3209(3) Y = 428.5552U = 98a = 294.8629b =41(4) zcj = 294.8629 304.3951 306.0462 307.0155 307.4650 311.0144 311.5203 315.5695 316.4493 316.5579 317.6092 318.0252 321.1504 324.3965 324.5386 325.0759 325.6970 325.7350 326.6637 327.0061 327.4769 328.3794 328.6685 328.8510 328.8944 330.8695 331.3033 332.4179 332.4514 333.2143 334.0262 335.0851 335.5684 337.9851 339.1718 339.4149 339.9892 340.1515 343.3999 343.4614 343.7944 344.8591 345.9703 348.5857 348.6997 350.2581 350.9037 351.6776 353.9651 356.3746 357.0423 357.2647 361.1787 361.9877 362.4313 364.7428 365.6088 366.6697 367.1449 368.1284 370.1263 371.1219 371.1449 372.7182 373.5121 373.7641 374.0658 374.0876 378.0501 378.0549 379.0053 382.9812 383.0496 383.4662 383.8982 384.2101 386.0883 387.1944 387.4844 387.6648 388.1824 392.6041 393.4056 396.0833 396.9413 401.8044 401.9607 402.6185 403.3431 404.1411 405.1662 408.9670 410.0667 413.3917 415.9679 416.2074 420.0281 423.0012 423.0274 428.5552xsxh = 41 66 14 89 73 6 42 28 13 85 68 44 27 31 26 76 21 65 39 77 19 94 18 11 51 92 22 55 63 10 50 82 59 4 54 62 69 23 3 25 96 2 7 12 36 49 60 24 78 37 48 97 45 34 33 91 1 35 8 17 74 99 15 38 52 88 81 47 90 80 75 53 79 87 46 61 70 95 32 93 16 40 71 72 5 9 86 83 58 29 43 20 30 67 56 57 64 100 84983.程序：h=6:2:18;x=6.5:2:18.5;t1=18,20,22,25,30,28,24;t2=15,19,24,28,34,32,30;T1=spline(h,t1,x)T2=spline(h,t2,x)结果：T1 = 18.5020 20.4986 22.5193 26.3775 30.2051 26.8178 23.7966T2 = 15.6553 20.3355 24.9089 29.6383 34.2568 30.9594 31.12184.程序：x=1:0.1:101; y1=log10(x); p=polyfit(x,y1,5) y2=polyval(p,x); plot(x,y1,:,x,y2,-)结果：p =0.0000 -0.0000 0.0001 -0.0040 0.1139 0.16415.程序：p1=1,2,4,0,5; p2=1,2; p3=1,2,3; p=p1+0,conv(p2,p3) %为使两向量大小相同，所以补0 A=roots(p) A=-1,1.2,-1.4;0.75,2,3.5;0,5,2.5; polyval(p,A) polyvalm(p,A)结果：（1）p = 1 3 8 7 11（2）A = -1.3840 + 1.8317i -1.3840 - 1.8317i -0.1160 + 1.4400i -0.1160 - 1.4400i（3）ans = 1.0e+003 * 0.0100 0.0382 0.012