



全文预览已结束
下载本文档
版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领
文档简介
GB 4789.22010National food safety standardFood microbiological examination:Aerobic plate countAerobic plate count Food test sample is treated under certain conditions after (e.g. medium, culture temperature and culture time) culture, resulting per g (mL)The total number of microbial colonies formed seized samples1 Equipment and MaterialsIn addition to the microbiology laboratory and training routine sterilization equipment, other equipment and materials as follows:1.1 incubator: 36 1 , 30 1 .1.2 Refrigerator: 2 5 .1.3 thermostatic water bath: 46 1 1.4 Balance: a sense of the amount of 0.1 g.1.5 homogenizer.1.6 oscillators.1.7 Sterile pipette: 1 mL (0.01 mL with scale), 10 mL (0.1 mL with scale) or pipette and tip.1.8 sterile conical flask: capacity 250 mL, 500 mL.1.9 sterile Petri dish: diameter 90 mm.1.10 pH meter or pH colorimetric tubes or precision pH test paper.1.11 magnifier and / or colony counter.2 media and reagents2.1 plate count agar medium: See Appendix A, A.1.2.2 phosphate buffer: See Appendix A A.2.2.3 Sterile saline: See Appendix A A.33 Inspection ProgramThe total number of colonies inspection program in Figure 1Test sample25 g (mL) sample +225 mL diluent, homogeneousReportCalculate the total number of colonies10-fold serial dilutionsChoose two or three suitable dilution liquid sample uniform,From each 1 mL of sterile Petri dishes were added withinEach dish was added 15 mL 20 mLPlate count agar medium, mixCulture Count the number of colonies on each plateFigure1. The total number of colonies inspection procedures4 procedure4.1 dilution of samples4.1.1 solid and semi-solid samples: Weigh 25 g sample set containing 225 mL of phosphate buffered saline solution or sterile homogeneous within the cup, 8000 r / min 10000 r / min homogenized 1 min 2 min or placed filled with 225 mL of sterile diluent bag homogeneous, with slap-type homogenizer beat 1 min 2 min, a sample was evenly 1:10.4.1.2 Liquid samples: 25 mL sterile pipette sample set containing 225 mL of phosphate buffered saline solution or sterile Erlenmeyer flask (flask preset appropriate number of sterile glass beads), the full mix the sample was made uniform 1:10.4.1.3 with 1 mL sterile pipette or pipette to draw samples 1:10 uniform liquid 1 mL, along the wall slowly inject in a sterile tube containing 9 mL dilution (note pipette tip or not to tip touch diluted liquid), shake the tube or replaced with a sterile pipette repeated pipetting to mix evenly into 1: 100 of the liquid sample uniform.4.1.4 4.1.3 Procedure according to prepare 10-fold serial dilution of the sample was absorbed. Each incremental dilution once and replace it with a second 1 mL sterile pipette or tip.4.1.5 Based on the condition of sample contamination estimates, select the sample absorbed liquid 2 3 suitable dilution (liquid sample may include stock solution), during the 10-fold dilution increments, absorb 1 mL sample was homogenized in a sterile petri dish inside, do the two plates each dilution. Meanwhile, Pipette 1 mL dilution was added as blank blank in two sterile petri dish.4.1.6 promptly flat 15 mL 20 mL cooled to 46 count agar (can be placed at 46 1 water bath tank insulation) pour plate and turn the dish to mix evenly.4.2 Training5.2.1 until the agar solidified, the plates were inverted, 36 1 cultured 48 h 2 h. Aquatic 30 1 cultured 72 h 3 h.5.2.2 If the sample may contain the agar surface diffuse colonies grown, covering the agar surface in a thin layer of solidified agar medium (about 4 mL), after solidification flip tablet, according to 6.2.1 conditions bring up.4.3 colony countsNaked eye observation, if necessary, with a magnifying glass or a colony counter, recording the corresponding dilution factor and the number of colonies. Colony count in colony-forming units (colony-forming units, CFU), said.5 Results and reports5.1 Calculation of the total number of colonies5.1.1 If only a dilution of the number of colonies on the plate count in the appropriate range, calculate the average number of colonies of the two plates, and then flatMean multiplied by the corresponding dilution factor, as per g (mL) sample of the total number of colonies results.5.1.2 If two successive dilution plate count when the count in the appropriate range, according to the formula (1):N- colonies in the sample;C- tablet (tablet containing the appropriate range of the number of colonies) and the number of colonies;n1- first dilution (lower dilution) plate number;n2- second dilution (higher dilution factor) the number plate;d- dilution factor (first dilution).For example:Dilution1:100(first Dilution)1:1000(second Dilution)CFU232,24433,35Refer to 5.2.2, above data by rounding figures, expressed as 25,000 or 2.5 1045.1.3 If the number of colonies on the plate all dilutions were greater than 300 CFU, the highest degree of dilution plates were counted, other tablet canRecorded as uncountable, the result is multiplied by the average number of colonies highest dilution calculations.5.1.4 If the plate count all dilutions were less than 30 CFU, the dilution should be the lowest average number of colonies counted multiplied by the dilution factorCount.5.1.5 If all dilutions (including liquid sample liquid) tablet no colony growth, places less than a dilution factor is calculated by multiplying the minimum.6.1.6 If the plate count not at all dilutions between 30 CFU 300 CFU, some of which less than 30 CFU or greater than 300CFU, the places closest to 30 CFU or 300 CFU average dilution factor is calculated by multiplying the number of colonies.5.2 The report of total number colonies5.2.1 the number of colonies less than 100 CFU, press the rounding the principle of rounding to integer report.5.2.2 colony number greater than or equal to 100 CFU, the first three digits after the use of rounding the principle of rounding off, take the first two numbers, afterFace with a 0 instead of the median; 10 can also be used to represent the exponential form, press the rounding off after rounding principle, the use of two significant figures.5.2.3 If it is unable to counter the spread of colonies on all flat, the report colonies spread.5.2.4 If the colony growth on the control, then the test results invalid.5.2.5 Weighing sampled to CFU / g reported in units of volume sampled to CFU / mL reported in units ofAppendix A(Standard Appendix)Media and reagentsA.1 plate count agar,PCAA.1.1 CompositionTryptone 5.0 gYeast Extract 2.5 gGlucose 1.0 gAgar 15.0 gDistilled water 1000 mLPH 7.00.2A.1.2 MethodThe above ingredients were added to distilled
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 嵌入式GUI课件教学课件
- 中石油加油站可行性研究报告
- 激光焊接基础知识培训
- 二零二五年度XX企业厂长任期绩效考核与薪酬调整合同
- 2025版夫妻财产分割与子女抚养责任协议
- 二零二五年工业固废处理环保验收合同
- 二零二五年度农业贷款延期还款服务协议
- 二零二五年度住宅工程中介居间代理服务合同范本
- 二零二五年度仓储服务外包合同范本及仓储服务补充协议
- 2025版环境卫生治理与固体废弃物资源化利用合同
- 2025至2030年中国奶牛养殖行业竞争格局分析及投资战略咨询报告
- 光伏施工基本知识培训课件
- 创伤性血气胸的急救与护理
- 2025关于医疗平台与医疗机构合作合同模板
- 福州工会考试试题及答案
- 学校后勤工作管理培训
- 胰腺炎的营养治疗与护理
- 教师校园安全培训课件
- 头皮健康与头发生长关系的研究
- 财务结账相关管理制度
- 叉车维修方案(3篇)
评论
0/150
提交评论