测试报告-1：ping和tracert.doc

Ping & Tracert 网络测试报告实训岗位：网管( 9 ) 复习：0/参考资料/Part1：网络命令讲义 并完成本报告注意： 文字大小均按五号字体设置！输入 命令 /? 可了解帮助信息注意：命令记录要求记录的是文本内容(不是截图！)文本复制方法如下图所示：提示：可以多开几个命令视窗同时进行多个测试，提高效率！第一部分：Ping命令测试分析 测试员签名：袁帅（1）分别 ping 和 8命令记录网管9 C:ping Pinging 04 with 32 bytes of data:Reply from 04: bytes=32 time=29ms TTL=54Reply from 04: bytes=32 time=9ms TTL=54Reply from 04: bytes=32 time=8ms TTL=54Reply from 04: bytes=32 time=10ms TTL=54Ping statistics for 04: Packets: Sent = 4, Received = 4, Lost = 0 (0% loss),Approximate round trip times in milli-seconds: Minimum = 8ms, Maximum = 29ms, Average = 14ms网管9 C:ping 8Pinging 8 with 32 bytes of data:Reply from 8: bytes=32 time=28ms TTL=244Reply from 8: bytes=32 time=24ms TTL=244Reply from 8: bytes=32 time=25ms TTL=244Reply from 8: bytes=32 time=29ms TTL=244Ping statistics for 8: Packets: Sent = 4, Received = 4, Lost = 0 (0% loss),Approximate round trip times in milli-seconds: Minimum = 24ms, Maximum = 29ms, Average = 26ms分析计算各自的网络距离，分析到哪个目标更近？结论计算过程及结论：（1）255-54=201,64-54=10,128-54=74,32-54=-22.网络距离范围0-30。所以为10。（2）255-244=11，64-244=-180，128-244=-116，32-244=-212。网络距离为11。所以更近。（2）按每个包1400字节大小连续 Ping 10 次命令记录网管9 C:ping -l 1400 -n 10Pinging 02 with 1400 bytes of data:Reply from 02: bytes=1400 time=15ms TTL=54Reply from 02: bytes=1400 time=13ms TTL=54Reply from 02: bytes=1400 time=11ms TTL=54Reply from 02: bytes=1400 time=13ms TTL=54Reply from 02: bytes=1400 time=11ms TTL=54Reply from 02: bytes=1400 time=13ms TTL=54Reply from 02: bytes=1400 time=11ms TTL=54Reply from 02: bytes=1400 time=12ms TTL=54Reply from 02: bytes=1400 time=11ms TTL=54Reply from 02: bytes=1400 time=11ms TTL=54Ping statistics for 02: Packets: Sent = 10, Received = 10, Lost = 0 (0% loss),Approximate round trip times in milli-seconds: Minimum = 11ms, Maximum = 15ms, Average = 12ms（3）通过ping 获知8的主机名命令记录Pinging 8 with 32 bytes of data:Reply from 8: bytes=32 time=20ms TTL=244Reply from 8: bytes=32 time=22ms TTL=244Reply from 8: bytes=32 time=25ms TTL=244Reply from 8: bytes=32 time=21ms TTL=244Ping statistics for 8: Packets: Sent = 4, Received = 4, Lost = 0 (0% loss),Approximate round trip times in milli-seconds: Minimum = 20ms, Maximum = 25ms, Average = 22ms结论主机名：（4）为了网络安全，网络路由通常对报文大小是有限制的；使用渐进法测试向 网路最大能发送多大字节的ping报文（注意：只记录 最终的两次 （通和不通的分界）命令记录网管9 C:ping -l 1473Pinging 02 with 1473 bytes of data:Request timed out.Request timed out.Request timed out.Request timed out.Ping statistics for 02: Packets: Sent = 4, Received = 0, Lost = 4 (100% loss),Approximate round trip times in milli-seconds: Minimum = 0ms, Maximum = 0ms, Average = 0ms网管9 C:ping -l 1472Pinging 02 with 1472 bytes of data:Reply from 02: bytes=1472 time=15ms TTL=54Reply from 02: bytes=1472 time=13ms TTL=54Reply from 02: bytes=1472 time=11ms TTL=54Reply from 02: bytes=1472 time=13ms TTL=54Ping statistics for 02: Packets: Sent = 4, Received = 4, Lost = 0 (0% loss),Approximate round trip times in milli-seconds: Minimum = 11ms, Maximum = 15ms, Average = 13ms结论（5）ping 命令记录网管9 C:ping Pinging with 32 bytes of data:Reply from 3: TTL expired in transit.Reply from 3: TTL expired in transit.Reply from 3: TTL expired in transit.Reply from 3: TTL expired in transit.Ping statistics for : Packets: Sent = 4, Received = 4, Lost = 0 (0% loss),Approximate round trip times in milli-seconds: Minimum = 0ms, Maximum = 0ms, Average = 0ms分析返回的ICMP差错报文表示什么问题？结论回答：expired in transit 表示TTL超过最大跳数30。不能到达。第二部分：路由分析命令 测试员签名：袁帅（1）tracert 分析远程路由命令记录网管9 C:tracert Tracing route to 06over a maximum of 30 hops: 1 2 ms 1 ms 1 ms 2 3 ms 2 ms 3 ms 3 2 ms 3 ms 11 ms 54 4 4 ms 6 ms 4 ms 2 5 5 ms 7 ms 6 ms 7 6 4 ms 7 ms 6 ms 5 7 7 ms 7 ms 80 ms 9 8 4 ms 7 ms 6 ms 8 9 5 ms 7 ms 6 ms 7 10 5 ms 7 ms 7 ms 3 11 4 ms 7 ms 7 ms 46 12 7 ms 7 ms 7 ms 2 13 5 ms 11 ms 6 ms 06Trace complete.分析从源到目的，中间经过多少个网络路由器？结论13个路由。（2）tracert 分析远程路由命令记录网管9 C:tracert Tracing route to over a maximum of 30 hops 1 1 ms 1 ms 1 ms 2 4 ms 5 ms 6 ms 3 3 ms 3 ms 2 ms 54 4 4 ms 7 ms 7 ms 2 5 5 ms 7 ms 4 ms 1 6 6 ms 6 ms 7 ms 5 7 6 ms 7 ms 6 ms 9 8 5 ms 6 ms 8 ms 42 9 7 ms * 6 ms 9 10 * * * Request timed out. 11 * * * Request timed out. 12 * * * Request timed out. 13 * * * Request timed out. 14 * * * Request timed out. 15 * * * Request timed out. 16 * * * Request timed out. 17 * * * Request timed out. 18 * * * Request timed out. 19 * * * Request timed out. 20 * * * Request timed out. 21 * * * Request timed out. 22 * * * Request timed out. 23 * * * Request timed out. 24 * * * Request timed out. 25 * * * Request timed out. 26 * * * Request timed out. 27 * * * Request timed out. 28 * * * Request timed out. 29 * * * Request timed out. 30 * * * Request timed out.Trace complete.分析该网络路由故障现象是？在何处发生了故障？结论回答1：网络连接断开。回答2：设备9。（3）tracert （注意：不要中断，让命令执行完成！个别节点显示*，忽略即可)）命令记录网管9 C:tracert Tracing route to over a maximum of 30 hops 1 1 ms 1 ms 1 ms 2 4 ms 2 ms 2 ms 3 4 ms 3 ms 3 ms 54 4 6 ms 7 ms 7 ms 2 5 5 ms 7 ms 7 ms 1 6 5 ms 7 ms 6 ms 5 7 6 ms 6 ms 5 ms 3 8 36 ms 37 ms 42 ms 57 9 36 ms * * 33 10 * * * Request timed out. 11 137 ms 135 ms 137 ms 9 12 163 ms 169 ms 165 ms 01 13 171 ms 172 ms 173 ms 57 14 168 ms 169 ms 169 ms 54 15 167 ms * * 6 16 171 ms 176 ms 172 ms 94 17 169 ms 172 ms 169 ms 4 18 195 ms 169 ms 173 ms 3 19 171 ms 173 ms 173 ms 4 20 181 ms 154 ms 157 ms 3 21 169 ms 169 ms 176 ms 4 22 171 ms 173 ms 173 ms 3 23 167 ms 173 ms 171 ms 4 24 170 ms 177 ms 176 ms 3 25 171 ms 173 ms 168 ms 4 26 174 ms 172 ms 169 ms 3 27 177 ms 169 ms 161 ms 4 28 206 ms 172 ms 172 ms 3 29 167 ms 170 ms 172 ms 4 30 171 ms 175 ms 176 ms 3Trace complete.分析故障现象是？ 故障从哪个节点开始发生？结论网络连接断开。设备10。(4)Pathping q 数值 选项可控制测试的报文数/点， 测试越多则统计越精确。请验证一下，Pathpingq 数值最大为多少？如果按最大数值量来测试 需多少时间？命令记录网管9 C:pathping -q 255 Tracing route to 03over a maximum of 30 hops: 0 3 1 2 3 54 4 2 5 1 6 1 7 7 8 10 9 7 10 46 11 46 12 6 13 6 14 03Computing statistics for 892 seconds. Source to Here This Node/LinkHop RTT Lost/Sent = Pct Lost/Sent = Pct Address 0 3 0/ 255 = 0% | 1 1ms 0/ 255 = 0% 0/ 255 = 0% 0/ 255 = 0% | 2 2ms 0/ 255 = 0% 0/ 255 = 0% 0/ 255 = 0% | 3 2ms 0/ 255 = 0% 0/ 255 = 0% 54 0/ 255 = 0% | 4 4ms 0/ 255 = 0% 0/ 255 = 0% 2 0/ 255 = 0% | 5 5ms 0/ 255 = 0% 0/ 255 = 0% 1 0/ 255 = 0% | 6 6ms 0/ 255 = 0% 0/ 255 = 0% 1 0/ 255 = 0% | 7 7ms 0/ 255 = 0% 0/ 255 = 0% 7 0/ 255 = 0% | 8 4ms 0/ 255 = 0% 0/ 255 = 0% 10 0/ 255 = 0% | 9 5ms 0/ 255 = 0% 0/ 255 = 0% 7 0/ 255 = 0% | 10 15ms 0/ 255 = 0% 0/ 255 = 0% 46 0/ 255 = 0% | 11 14ms 0/ 255 = 0% 0/ 255 = 0% 46 0/ 255 = 0% | 12 11ms 0/ 255 = 0% 0/ 255 = 0% 6 0/ 255 = 0% | 13 11ms 0/ 255 = 0% 0/ 255 = 0% 6 0/ 255 = 0% | 14 7ms 0/ 255 = 0% 0/ 255 = 0% 03Trace complete.网管9 C:pathping -q 256 Bad value for option -q.结论最大值为255。需要892秒(5)Pathping (注意:时间需要几分钟！请保持hold住，切勿中断！可偶尔按回车一下)命令记录网管9 C:Pathping cd0