《C Programming》TEST PAPER试卷.docx

提醒：考试失败你将仍有机会；警告：考试作弊你将失去学位。C ProgrammingTEST PAPERTime: 8:30-10:30 am. Jan 15, 2004Important note: your answers must be written on the answer sheetSection 1: Single Choice（2 mark for each item, total 20 marks）1. The declaration _ declares the variable which can hold the largest positive number.Aint a;Bchar b;Cfloat c;Ddouble d;2. The _ operator cannot be used as a unary-operator.A+B-C*D/3. _ is wrong if it is used as a character constant.A”1” B1 C1Dn4. If c is a character variable, its value is 1 or 0 after evaluating the expression _。Ac=getchar()!=EOFB(c=getchar()!=EOFCc = 0Dc = c c5. According to the declaration: int a10, *p=&a1; the last element of the array a is _.Aa10Bp8Cp9Dp106. The precedence of operator _ is the highest one.A+=B C? :D+7. The following code fragment prints out _.char s =student;printf(“%s%d”, s+3, sizeof(s); Astudent7Bdent7Cdent8Dstudent88. According to the following declaration, _ is valid.struct node char s10;int k; p5;Ap.k=2Bp0-k=2 C(p-s)0=aDp0.s=“a”9. According to the declaration: int (*p)10, p is a_.ApointerBarrayCfunctionDelement of a array10. Assume that the user of a program is asked to enter a day number (1-7) into an integer variable called day. In the following while loops, _ can be used to validate the day entered.A. while (day = 1 | day = 1 & day = 7) printf(ERROR 1 - 7 only, enter again: ); scanf(”%d”, &day); C. while (day 7) printf(ERROR 1 - 7 only, enter again: ); scanf(”%d”, &day); D. while (day = 7) printf(ERROR 1 - 7 only, enter again: ); scanf(”%d”, &day); Section 2: Fill in the blanks（2 mark for each item, total 30 marks）1. Write a conditional expression _ to calculate the maximum of x and y. 2. The value of expression 7 * 7 / 9 * 4 % 3 is _.3. The value of expression 10=10=10 is _.4. The value of expression 255 & 128 is_.5. The following code fragment prints out _.int a = 3, b;if ( a 5 ) b = 7;else if ( a 2 ) b = 6;else b = 5;printf(%d, b);6. The following code fragment prints out _.int a = 13;int b = 3;float x;x = a / b;printf (%.1f, x);7. The following code fragment prints out _.int j = 1, k = 2;printf (%d, %d#, j+, +k);printf (%d, %d, -j, k-);8. The following code fragment prints out _.int x, y;x = y = 3;switch (y) case 1: x = 0; break;case 2: x = 17; break;case 4: x = 9; break;printf (“%d”, x);9. The following code fragment prints out _.int array = 2, 8, 6, 11, 13, 2, 8, 2;int k; int total = 0;for ( k = 0; k 8; k+ ) if ( array k % 2) break;total += array k;printf ( “%d”, total );10. The output of the following statements is _. #define MM(x,y) (x)*(y)printf(%d, MM(4, 2+3)-8);11. The output of the program given below is _.#include int main (void)int k = 1; int a_function ( int j ); k = a_function ( k );printf ( %d , k );int a_function ( int j ) if ( j 3 ) j+;j = a_function ( j );printf ( %d# , j );return ( j );12. The following code fragment prints out _.int a = 1; int b = 2;int *x, *y;x = &a;y = &b;*x = *x + 1;x = y;*x = *x + 1;printf(%d, %d, a, b);13. To execute the command: prog at my home, the value of *(+argv)1 is_.14. The program given below prints out _.void melon (int g, int * h);int main (void) int a = 1, b = 2; melon ( a, &b ); printf ( a = %d, b = %d, a, b );void melon (int b, int * c) b+; *c = *c + b;15. Write a while loop that is equivalent to the for loop given below.for ( k = 0; k 10; k+ ) sum = sum + k;Section 3: Read each of the following programs and answer questions (6 marks for each item, total marks: 30)1. The output of the following program is _.#include stdio.hvoid main() int j, k; for (j=0; j3; j+) for (k=0; k3; k+) printf(%2d,(k+j+1)% 3 ? (k+j+1)%3 : 3 ); printf(#); 2. The output of the following program is _.#include void main() int i, k,m; int a8=60,75,63,92,87,64,79,21, s10; for(k=0; k10; k+) sk=0; for(i=0; i8; i+) k=ai/10; sk+; m=s0; k=1; while (km) m=sk; k+; printf(%d, m);3. The output of the following program is _.#include #includeint prime(int n) int i,m; if(n=1) return 0; m=sqrt(n); for(i=2;im;void main() int num,i; num=20; for(i=2;i=num;i+) while(prime(i)&(num%i=0) printf(%d ,i); num/=i; 4. The output of the following program is _.#include void main( ) int j, k; char c, s180=” a-b-e8-9”, s280; j=k=0;while(c=s1j+)!=0)if(s1j=-&s1j+1=c)j+;while(cs1j)s2k+=c+;elses2k+=c;s2k=0; printf(“%s”, s2);5. If the following data are stored in text file a.txtOne23Two45The output of the following program is _.# include # include void main() char ch; FILE *fp; if (fp = fopen(a.txt,r) = NULL)printf(Cant open file : %sn, a.txt); exit(0);while (!feof(fp) ch=fgetc(fp); if(ch=0 & ch=9) putchar(ch-0+A); fclose(fp);Section 4: According to the specification, complete each program (2 mark for each blank, total: 20 marks)1The program written below prints out the numbers between 1 and 1000, which equal the sum of the cubes of the digits. For example, one of the numbers printed out could be 153, because 153=1*1*1+5*5*5+3*3*3.#include void main( ) int digit, k, m, s;for (k=1; k=1000; k+) (1) ; m=k; while(m!=0) digit=m%10;s=s+digit*digit*digit; (2) ; if( (3) ) printf(%d , s); 2The function written below is a binary search one which decides if a particular value x occurs in the sorted array v. The elements of v are in increasing order. The function returns the position(a number between 0 and n-1) if x occurs in v, and 1 if not. int binasearch(int x, int v, int n) int low, high, mid; low=0;high=n-1;while( (4) ) mid=(low+high)/2; if( (5) ) high=mid-1; else if( (6) ) low=mid+1; else return mid; (7) ;3The de