各种形状面积、体积计算公式(最新整理)

1、tb圆柱和空心圆柱拽 (f面 面侧 派5 f积 积面 体表立方体1替积耐角面俵梭对表- 二-la jy-y，？xyj-sl长方休 棱ttv1fl,oa)? r+二二 111 =7三棱植/ g/h点z.a-菡底底6,1 1 1 rfo2f.vr t 二 -f-一个组合三角形的面积 -组台三角形的个数6?-椬底备对角找交点6,巧-两平行底面的面积 底面间距sa个组台梯形的面积 n-组含梯形数鵬：v-fxr2hs = 2nr *h 4-2rrj?2 2 y-/cr(h1 + /2)+r2*a+ 1 ) cosasiftr(ht+h2)直図惟?-底面半径力-高卜母线长 pfnr2*巧/rr j 2 +

2、a2 nrl z= jr2+p y-4$l+nr2圆台:獻p疋r-底面半径h -通/-母线f-*(2+724-j?r)/= j?-r)2+a2 + 相2 +r2)球0.7 -半径豆径。y-13- 0.5236rf3 36 = 2ur2 = /rrf2球扇形a球楔v/-球半径rf-弓形底囫豆径力-弓形spr=!rr 4=2.0944 t-(4ft+f) 1 57y(4j +rf)24)球缺pa-球缺的罱7-球缺半径/-平切圆亘径 =曲面面轵了-球缺衷面积zr2(r-|)=2-+内j2=4a(2r-h)圆环体a胎v卜圆球佴平均半径 d-囫环体平均半径 /-圆坏体截面直s r-圆环体裁面半径、v *

3、 2jrf2j?*72-l2tf2 -w2j?r /r2tf-39.478 .球带体a穴-球半径 rtf2 -底面半径 a-廉高-球心带底圆的距离 = (3+3+h2) $i = 2邊s 2rrrh +fr(r +rj )桶形0)-中间断面直径tf-底直径桶高p对于抛物线形桶体对于囫形桶体椭球体itb.c-半轴v abc/rs22* b* /a+f交叉圆柱体制r-固往半径v-囫柱长-r2(/+-y)梯/?-下底边长v (2j形11-上底边长6h体va-上、下底边距s( -+(2+ (?!)(!+)+(2 6公积求形阁用常图符寸尺)sc积面表zf/x积面正方阪*0a线长 边对 1 1 a lv4

4、w.41二 -4a j1.41 - f fla线s s 短长对1 1 1aid2 b+6 23=f三角恥49a长.-.账-h- z ac sin 121he ft 2 siz r-z-平行四边私离巨 ?的 边g 棱助 1对 - a ama - ii d 力5 2 cii f u任意四边瓜錢屯rf2-对*找a-对角线夹角-処 sina 2正多边形，r _ p*zw45r 只-夕全a = 2jr2 一 r 2 itl a - 180 *= n (n - p -用氏=2”-f - j?2sin2c 2=l 2菱形.jrck-对角线a -边a -角2 為af-。咖2梯形。ce ab af-cda=cd

5、c上底边）b = ab（.下底边） 办-菡-a+b , f=s-9ilf a kbp圆形r-半径rf-亘径 p-囫周长pf = -2 = iflrf2 =0.7852 = 0.07958p2 p =/ai椭rmab-主轴pf= 04) a bp|3|形.，扇形0 .厂_*径卜弧长a-弧s的对应中心角r. 1a2f5”3bt5番三180 .弓1r-半径卜热长a-中心、角-形.，1 .卜弦长力-高,，-.a面_ 部分圆坏新月豚l-外直径 内亘径卜环宽平均直径j?-夕d -夕 d -内酿 卜聰-厮卿迫径1-两个囫心间的距离 rf-直径2d 10 3d 10 4410-079 118 1 56卜底边卜

6、髙卜曲线长面积f = (t- a+shajsr1*? p-na拖s下表5(l 10 6(110 7(110.91 2.25 2.55/-j&2+1.3333h2flb.hs等多边形a-边长系数多边形的边数三边形无3 = 0.433 四边形尤4 = 1 000 五边形& =1.720 六边形6 = 2.观 七边-3.614 八边形无8 = 4.828 九边形6.182 七边形尤10 - 7 694好兑此，大袈一段。夂南億曹祝这，“哆含哆习沾人，i补章章稔幻人”。浮 习部。什乃一名专立文炅极批，我爻加枝礓各舶学要枚，“人4au,各寒蚵农”， 舶学54社成缸爻好幻&乙。各行各丘从立人炅只奇各舶&浮5

7、,意批表扣&昶x妗扠，h/u企立发展& 多代，4鉍卉u到扣1名彳场幻索表。4文轄也l、i我专丘人炅炀u，义拮十可h舍脅砝淡，如壳砝淡 砩尨h正，各衂恭漱！at the end, xiao bian gives you a passage. minand once said, people who learn to learn are very happy people. in every wonderful life, learning is an eternal theme. as a professional clerical and teaching position, i unders

8、tand the importance of continuous learning, life is diligent, nothing can be gained, only continuous learning can achieve better self. only by constantly learning and mastering the latest relevant knowledge, can employees from all walks of life keep up with the pace of enterprise development and innovate to meet the needs of the market. this documen