Java实验测试题目(共10页)

1、精选优质文档-倾情为你奉上1 输入两个自然数，找出两个数的最大公因数import java.util.Scanner;public class zuida public static void main(String args) Scanner scanner = new Scanner(System.in);System.out.print("请输入第一个数字 ");int num1 = scanner.nextInt();System.out.print("请输入第2个数字 ");int num2 = scanner.nextInt();int te

2、mp = num1;num1 = num1 < num2? num1: num2;num2 = temp > num2? temp: num2;for(int num = num1; num >= 1; num-)if(num1 % num = 0 && num2 % num = 0)System.out.println("最大公因数为 : " + num);break;2 接受输入x，计算sinx的近似值（不使用Math类中的函数，自己实现）package Test;import java.util.Scanner;public clas

3、s sin static double stop = 0.001; public static void main(String args) sin s = new sin(); System.out.println("The value of sin(30')"); System.out.println(s.sin(Math.PI / 6.0, 100); double sin(double x, int n) double v = x; int postive = 1; for (int i = 1; i < 2 * n; i = i + 2) v = v

4、 + postive * (Math.pow(x, i) / factorial(i); postive = postive * -1; return v; private double factorial(double s) double r = 1; for (int i = 1; i <= s; i+) r = r * i; return r; 3 打印所有的水仙花数（一个三位数，各位的三次方之和等于它本身）public class zuida public static void main(String args) int count=0;/水仙花数个数计数器 for(int n

5、um=100;num<1000;num+) int g=num%10;/个位 int s=num/10%10;/十位 int b=num/100;/百位 if(g*g*g+s*s*s+b*b*b=num) count+; System.out.print(num+" "); if(count%5=4) System.out.println(); 4 输入年、月、日，判断这一天是星期几（年、月、日的输入有一定范围，数值合理）import java.io.BufferedReader;import java.io.IOException;import java.io.In

6、putStreamReader;import java.util.Calendar;public class zuida public static void main(String args) throws IOException System.out.println("请输入年月日,格式: yyyy-MM-dd"); BufferedReader br = new BufferedReader(new InputStreamReader(System.in); String s = br.readLine(); Calendar c = Calendar.getInst

7、ance(java.util.Locale.CHINA); String sp = s.split("-"); c.set(Calendar.YEAR,Integer.parseInt(sp0); c.set(Calendar.MONTH,Integer.parseInt(sp1)-1); c.set(Calendar.DATE,Integer.parseInt(sp2); int wd = c.get(Calendar.DAY_OF_WEEK); String x = "" switch(wd) case 1:x="星期日"brea

8、k; case 2:x="星期一"break; case 3:x="星期二"break; case 4:x="星期三"break; case 5:x="星期四"break; case 6:x="星期五"break; case 7:x="星期六"break; System.out.println(s+"是:"+x); 5 数组的简单排序方法（冒泡，选择，插入排序之一）import java.util.Scanner;public class zuida pu

9、blic static void main(String args) Scanner input = new Scanner(System.in); int Max=0; int score = new int5; /自定义数组长度 System.out.println("please input five numbers："); for(int i=0; i< score.length; i+) scorei = input.nextInt(); for(int j=0; j<score.length-1; j+) swap(score); /调用数组排序方法

10、 System.out.println("# the result: #"); for(int i=0; i<score.length; i+) System.out.print(scorei+"t"); public static void swap(int arr) /冒泡法排序 for(int i=0; i<arr.length-1; i+) if(arri>arri+1) int temp = arri; arri = arri+1; arri+1 = temp; 6 输入系数，求解一元二次方程import java.util.

11、Scanner;public class zuidapublic static void main(String args)Scanner sc = new Scanner(System.in);System.out.println("输入2次方的系数");int a = sc.nextInt();System.out.println("输入1次方的系数");int b = sc.nextInt();System.out.println("输入0次方的系数");int c = sc.nextInt();double x1 = (-b

12、+ Math.sqrt(b*b - 4*a*c)/2*a;double x2 = (-b - Math.sqrt(b*b - 4*a*c)/2*a;System.out.println("根分别是 " + x1 + "," + x2);7 统计一个输入的字符串中的数字（0-9）个数import java.util.Scanner;public class zuida public static void main(String args) int englishCount = 0;/ 英文字母个数 int spaceCount = 0;/ 空格个数 in

13、t numCount = 0;/ 数字个数 int otherCount = 0;/ 其他字符个数 Scanner sc = new Scanner(System.in); System.out.println("请您输入一行字符："); String str = sc.nextLine();/ 取得控制台输入的一行字符 char ch = str.toCharArray();/ 把取道的字符串变成一个char数组 for (int i = 0; i < ch.length; i+) if (Character.isDigit(chi) / 判断是否为数字 numCo

14、unt+; System.out.println("数字的个数：" + numCount); 8 给定字符串和一个子字符串，统计字符串中子串出现的次数public class zuida public static void main(String args) String string = "6456" String str = "123" int count = 0; while(true) int index = string.indexOf(str); if(index != -1) string = string.subst

15、ring(index+str.length(), string.length(); count+; else break; System.out.println(count); 9 计算斐波那契数列的前n项和public class zuida public static void main(String args) System.out.println(sum(10); public static long sum(int n) if(n < 1) return 0; if(n = 1) return 1; if(n = 2) return 2; long f1 = 1, f2 = 1; long sum = 2; for(int i=3; i<=n; i+) f2 = f1 + f2; f1 = f2 - f1; sum += f2; return sum; 10 输入一个数，输出该数字的因子分解结果import java.util.Scanner;public class zuida public static void