D值法例题详解

1、37KN74KNS0 7kN图，用D 值法计算内力并绘制弯矩图DdHsLJFLjj-CGLQf or5-riT3BFJ-lg7LJr3AE1L2.7mne.in-值87已知：框架计算简剪 力求 各 柱 的CDGHLM第层p 1.5 + 1.7 厂*2x0.7歹1一5十0.8十1/7十ID2x06M.165p 0.8 + 10磴一-1 0002x0.92-1.079 "12A沁x 0?x2 + 2.28612()_n的钏xD- 4-166x 0 6 x2+416612f _n 4ns>l xD-x O P x2+1. am12()-0.3000x3.3x33-12 、33x3 3

2、(W 、33x3.3'3.3x3.3' 3.3x3,33Jx3.3V=37 夕=12.801.079kN0 4054V-37x =13 90 kN1.079V=10.29kN第层-L7十曲“K2加2x07p 2.4 +1.2 -i-l 7 + 1 0 32心=3.500p10 + 12K-1J222x0.92D=1 330< 12 )3Jx3JL 2929 D淇 0.7 x2 + 2.9291'()=0.4160 x3 3x33(12 J33x3.33.500n D= x Q.p x2 + 3.500 I；()-0 5737 x(12 )33x3.3D+O 341

3、 諏 (12 ) 3.3x33V=0.41(50 x 37+74 -1 33072kN27+74V-0.5727XM7.S01.330V=28.48kN解)12 4JT- " M.OODCl. 602,4十1.2疋一=4.50008r-1 2-l.5oo0.30.5+1.000D= x Id x2 + 4QQ012()冗Ox3 9x3.9(12 )0 5 + 4 500D= x O.S x2+4咒012()=0.6154 x3 9k3.9(12 、39x3.9D-0.4570x< 12 >3.5x3.?亦57-F 74+ 80.7V=0.4500 x=1.522杠门引“3

4、7+7 + 30.7V-0.6154X=1.52271.51UNV=57/kN层1.522x122 ）求出各柱的反弯点高度yh3）求各柱的柱端弯矩?第三层?Mcd =:kN - m?Mdc=: kN - m =kNm?Mgh=kN m =kNm?Mhg=kN m =kNm?Mlm=: kN - m =kNm?Mml= : kN - m =kNm?第二层?Mbc=:岚 x kN m =:kNm?Mfg=x x kN - m =:kNm?Mcb=:kN m?Mgh=:kN m?Mjl=汽汎kN m =kNm?Mml =:kN - m =kNm第一层M AB= ；：kN - m = kNmMef=:

5、kN m = kNmM BA= ；：；kN - m = kNmMfe：=-:kN m = kNmM IJ=:X XkN - m = kNmMji=：二kN - m = kNm4）求各横梁梁端的弯矩 第三层?Mdh= M dc= kN mkN -m = kN0.8kN -m = kN?Mhm= 1?Mmh= M ml= kN m?第二层?Mcg= M cd+ Mcb = kN m + kN m = kN m17?Mgc= 1 ' -(+) kN -m = kN m1 QMgc= - : (+) kN -m = kN mMlg= M lm + M lj = kN m + kN m = kN m 第一层Mbf= M bc+ M ba = kN m + kN m = kN m2VMfb= - -: -(+) kN - m = kN m1.2Mfj= l l -