基本路径测试法和单元测试工具JUnit的使用

1、精选优质文档-倾情为你奉上实验报告实验序号：02实验项目名称：基本路径测试法和单元测试工具JUnit的使用学号姓名曹锋专业、班09软件工程一班实验地点1#316指导教师崔建峰实验时间2012/3/5一、实验目的l 掌握基本路径测试方法；l 了解在Eclipse环境下JUnit单元测试工具的安装和使用方法；l 针对一个实际问题，在JUnit环境下设计并执行测试用例。二、实验要求l 开发环境：Eclipse v3.7及以上版本；JUnit v4.10及以上版本；文本编辑软件。 l 硬件要求：CPU PIV 以上，256M 内存，1G 硬盘空间。l 系统要求：Windows98/Me/XP/NT/2

2、000，IE 5 以上。三、实验内容与步骤1. 下载并安装JDK+Eclipse，学习Eclipse安装与使用方法。2. 下载并安装JUnit，学习JUnit安装与使用方法。3. 通读自动售货机程序，并将其在Eclipse环境下运行。问题描述，程序流程图和程序源代码见附录。4. 按照如下格式，采用基本路径测试法编写测试用例（要有程序流程控制图，基本路径）。编号输入值Type输入值money状态预输出实际情况1Beer5C各资源剩余Input Information Type: Beer; Money: 5 Cents; Change: 0Current StateBeer: 5Orange J

3、uice: 65 Cents: 71 Dollar: 6与预期相同2OrangeJuice5C各资源剩余Input Information Type: OrangeJuice; Money: 5 Cents; Change: 0Current StateBeer: 6Orange Juice: 55 Cents: 71 Dollar: 6与预期相同3Beer5C没有啤酒Filure InformationBeer Shortage与预期相同4OrangeJuice5C没有橙汁Failure InformationOrangeJuice Shortage与预期不同5Cola5C各资源剩余Fail

4、ure InformationType Error与预期相同6Beer1D没啤酒Failure InformationBeer Shortage与预期不同7Beer1D各资源剩余Input Information Type: Beer; Money: 1 Dollar; Change:5 CentsCurrent StateBeer: 5Orange Juice: 65 Cents: 51 Dollar: 7与预期不同8OrangeJuice1D各资源剩余Input Information Type: OrangeJuice; Money: 1 Dollar; Change: 5 CentsC

5、urrent StateBeer: 6Orange Juice: 55 Cents:51 Dollar: 7与预期不同9OrangeJuice1D没有橙汁Failure InformationOrangeJuice Shortage与预期不同10Cola1D各资源剩余Failure InformationType Error与预期相同11Beer1D没有5角Failure InformationChange Shortage与预期不同12OrangeJuice4C各资源剩余Failure InformationMoney Error与预期相同5. 编写并执行基于JUnit的测试用例。6. 提交

6、测试用例程序和该程序运行结果最终画面。7. 总结本次试验，并撰写实验报告。程序流程图如图一所示：（流程图可复制粘贴到画图查看大图。）图一实验截图：编写完测试用例，运行程序，源程序有六个错误，如图二所示：图二根据相应错误修改代码后测试通过，如图三所示：图三四、分析与讨论 通过此次实验，我初步学会了测试工具Junit的使用方法，发现使用测试工具可以给程序测试带来很大的方便，使我们更容易找到程序的错误。五、教师评语签名：日期：成绩程序源代码：修改后的代码：package first;public class SaleMachine private int countOfBeer, countOfOr

7、angeJuice, countOfFiveCents, countOfOneDollar;private String typeOfGoods = Beer, OrangeJuice;private String resultOfDeal;public SaleMachine()initial();public void initial()countOfBeer = 6;countOfOrangeJuice = 6;countOfFiveCents = 6;countOfOneDollar = 6;public SaleMachine(int fiveCents, int oneDollar

8、, int numOfBeer, int numOfOrange)/便于测试的初始化函数countOfFiveCents = fiveCents;countOfOneDollar = oneDollar;countOfBeer = numOfBeer;countOfOrangeJuice = numOfOrange;public String currentState()String state = Current Staten + Beer: + countOfBeer + n + Orange Juice: + countOfOrangeJuice + n + 5 Cents: + cou

9、ntOfFiveCents + n + 1 Dollar: + countOfOneDollar;return state;public String operation(String type, String money)/type是用户选择的产品，money是用户投币种类if(money.equalsIgnoreCase(5C) /如果用户投入5角钱if(type.equals(typeOfGoods0) /如果用户选择啤酒if(countOfBeer0) /如果还有啤酒countOfBeer-;countOfFiveCents+;resultOfDeal = Input Informat

10、ion n + Type: Beer; Money: 5 Cents; Change: 0nn + currentState();return resultOfDeal;elseresultOfDeal = Failure Information n + Beer Shortage;return resultOfDeal;else if (type.equals(typeOfGoods1) /用户选择橙汁if(countOfOrangeJuice 0)countOfOrangeJuice-;countOfFiveCents+;resultOfDeal = Input Information n

11、 + Type: OrangeJuice; Money: 5 Cents; Change: 0nn + currentState();return resultOfDeal;elseresultOfDeal = Failure Information n + OrangeJuice Shortage;return resultOfDeal;elseresultOfDeal = Failure Information n + Type Error;return resultOfDeal;else if(money.equalsIgnoreCase(1D) /如果用户投入一元钱/if(countO

12、fFiveCents0) /如果用户投入一元钱/if(countOfFiveCents 0) /如果用户有零钱if(type.equals(typeOfGoods0)&countOfBeer0)/如果用户选择啤酒而且还有啤酒countOfBeer-;countOfFiveCents-;countOfOneDollar+;resultOfDeal = Input Information n + Type: Beer; Money: 1 Dollar; Change: 5 Centsnn + currentState();return resultOfDeal;else if (type.equa

13、ls(typeOfGoods1)&countOfOrangeJuice0)/如果用户选择橙汁而且还有橙汁countOfOrangeJuice -;countOfFiveCents -;countOfOneDollar +;resultOfDeal = Input Information n + Type: OrangeJuice; Money: 1 Dollar; Change: 5 Centsnn + currentState();return resultOfDeal;elseif(type.equals(typeOfGoods0)&countOfBeer=0)resultOfDeal =

14、 Failure Information n + Beer Shortage;return resultOfDeal;else if(type.equals(typeOfGoods1)&countOfOrangeJuice=0)resultOfDeal = Failure Information n + OrangeJuice Shortage;return resultOfDeal;elseresultOfDeal = Failure Information n + Type Error;return resultOfDeal;elseresultOfDeal = Failure Infor

15、mation n + Change Shortage;return resultOfDeal;/else/resultOfDeal = Failure Information n + Money Error;/return resultOfDeal;/resultOfDeal = Failure Information n + Money Error;return resultOfDeal;测试用例代码：package first;import junit.framework.TestCase;public class TestSaleMachine extends TestCase publ

16、ic void testOperation1() /售货机各资源均有剩余，用户投币5角，选择啤酒SaleMachine saleMachine1 = new SaleMachine();String expectedResult = Input Information n +Type: Beer; Money: 5 Cents; Change: 0nn +Current Staten +Beer: 5n +Orange Juice: 6n +5 Cents: 7n +1 Dollar: 6;assertEquals(expectedResult, saleMachine1.operation(

17、Beer, 5C);public void testOperation2()/售货机没有啤酒剩余，用户投币5角，选择啤酒SaleMachine saleMachine2 = new SaleMachine(6,6,0,6);String expectedResult = Failure Information n + Beer Shortage;assertEquals(expectedResult,saleMachine2.operation(Beer, 5C);public void testOperation3() /售货机各资源均有剩余，用户投币5角，选择橙汁SaleMachine s

18、aleMachine3 = new SaleMachine();String expectedResult = Input Information n +Type: OrangeJuice; Money: 5 Cents; Change: 0nn +Current Staten +Beer: 6n +Orange Juice: 5n +5 Cents: 7n +1 Dollar: 6;assertEquals(expectedResult, saleMachine3.operation(OrangeJuice, 5C);public void testOperation4()/售货机没有橙汁，

19、用户投币5角，选择橙汁SaleMachine saleMachine4 = new SaleMachine(6,6,6,0);String expectedResult = Failure Information n + OrangeJuice Shortage;assertEquals(expectedResult,saleMachine4.operation(OrangeJuice, 5C);public void testOperation5()/用户投入5角，选择非啤酒非橙汁SaleMachine saleMachine5 = new SaleMachine(6,6,6,6);Stri

20、ng expectedResult = Failure Information n + Type Error;assertEquals(expectedResult,saleMachine5.operation(Cola, 5C);public void testOperation6()/售货机有啤酒且有5角币，用户投币1元，选择啤酒SaleMachine saleMachine6 = new SaleMachine(6,6,6,6);String expectedResult = Input Information n +Type: Beer; Money: 1 Dollar; Change

21、: 5 Centsnn +Current Staten +Beer: 5n +Orange Juice: 6n +5 Cents: 5n +1 Dollar: 7;assertEquals(expectedResult,saleMachine6.operation(Beer, 1D);public void testOperation7() /售货机没有啤酒有5角，用户投币1元，选择啤酒SaleMachine saleMachine7 = new SaleMachine(6,6,0,6);String expectedResult = Failure Information n + Beer

22、Shortage;assertEquals(expectedResult, saleMachine7.operation(Beer, 1D);public void testOperation8()/售货机有橙汁且有5角币，用户投币1元，选择橙汁SaleMachine saleMachine8 = new SaleMachine(6,6,6,6);String expectedResult = Input Information n +Type: OrangeJuice; Money: 1 Dollar; Change: 5 Centsnn +Current Staten +Beer: 6n +Orange Juice: 5n +5 Cents: 5n +1 Dollar: 7;assertEquals(expectedResult,saleMachine8.operation(OrangeJuice, 1D);public void testOperation9()/售货机有5角没有橙汁，用户投币1元，选择橙汁SaleMachine saleMachine9 = new SaleMachine(6,6,6,0);String expectedResult = Failure Information n + OrangeJu