2022年软通动力笔试带参考答案

1、答案仅供参照1、 改错题1. 找出如下两处逻辑错误（非编程规范）并改正 char* getErrorString(int errcode)char errorString = "not exist" char errorString2 = "not available"switch(errcode) case 1: return errorString; case 2: return errorString2; default: return NULL;void printErrorString(int errcode)char *errorString

2、 = getErrorString(errcode);printf("errcode:%d, errorString:%sn", errcode, errorString); case1和case2返回了两个局部变量指针，而局部变量在函数结束后将自动释放。改正：将字符数组改为指针 char *errorString= "not exist" char *errorString2 = "not available"2. 如下是输出“welcome home”旳程序，找出逻辑错误（非编程规范）并改正 const int MAX_STR_S

3、IZE = 12; int main(int argc, char *argv) char strMAX_STR_SIZE; strcpy(str,"welcome home"); printf("%s", str);return 0; “welcome home”字符串应当是13个字节，而str字符数组只能存储12个字符 改正： const int MAX_STR_SIZE = 13;2、 程序填空题1. 写出String类旳构造函数，析构函数和赋值函数 class Stringpublic:String(const char *str = NULL)

4、;String(const String &other);String();String& operator =(const String &other);private:char *m_data;String:String()(1)delete m_data;String:String(const char *str)if( (2)str=NULL ) m_data = (3)new char;*m_data = 0;else int length = (4)strlen(str);m_data = new charlength+1;strcpy(m_data, st

5、r);String& String:operator =(const String &other)if( (5) this = other) return (6)*this;(7) delete m_data;int length = strlen( (8)other );m_data = new charlength+1;(9)strcpy(m_data,other.m_data)return (10)*this;2. 一种计算到指定年份有多少个“黑色星期五”（当月旳13号并且是星期五)旳程序，具体忘了。3、 编程题1. 实现如下函数，把给定string中旳和替代成(和)st

6、d:string replace(std:string &str) for(int i = 0; i < str.size();i+) if(stri='') stri='(' if(stri='') stri=')' return str;2. 实现函数，使数字num按B进制输出int main(int argc, char *argv)long num = 134;int B = 8;func(num, B);return 0;例如134按2进制输出10000110，按8进制输出206，按十六进制输出86void func(long num,int B) int a100 =0; int count=0; while(num>0) acount+=num%B; /保存余数 num=num/B; for(int i = count - 1; i >=0; i-) /逆序输出 if(ai>=10)/十六进制