广东省2020年中考数学模拟卷(新题型,含解析)

54465446广东省2020年中考数学模拟（新题型）90分120:级______________________一选题共10小题，分分每题3分A

B

C2020202020185500055000A5.5×10

B

C

D5.5×10AaB

Ca|bD0”

“”A13B1313C131413.5eq\o\ac(△,)∠CsinBsinA

B

C

DO34°∠ABCD66°1

226632222266322222222A2aaaCxx

B27D+ba+b45xA

B

C

DBDEaE90°PA

Ba

C

D010++a①++b4ac0②2a0③ax+0ax++④+A①②③

B①④

C②③④

D①③④二填题共7小，满28分，小分12P3x

13+a14y

kkk154n2

20201620°

17yaxax+yAMPOPAMBMABa三解题共8小，满62分）18+|1|+1920eq\o\ac(△,)∠

+b0∠O⊙O21⊙O21eq\o\ac(△,)CCD∥ABDEABG1AFCD3

2GB3BC6AB22201923“12“”32”2320//x/yx/

……

……123.5215024ABCABOBCAC4

E⊥AC1DH⊙O2H310C25++x1By3D12yPeq\o\ac(△,)PBCP3MABN2MMeq\o\ac(△,)MNB5

5446n45446n4参考答与试题解析一选题共10小题，分分每题3分A

B

C20202020C20185500055000A5.5×10

B

C

D5.5×10×1010na10n1n550005.5×10CAaB

Ca|bD0B0cCD0c0bB∵1∴B6

222222Ca|CD∵0c∴0D”

“”A13B1313C131413.541313

13eq\o\ac(△,)∠CsinBsinA

B

C

D∵eq\o\ac(△,)ABC∠90°∴∠A∠B90°∴sinAsinA∵sinB∴sinA

⊙OCD⊙O34°∠BAD7

22662266322226422ABCD66°⊙O∠90°∠ACD∠∵AB⊙O∴∠ADB90°∵∠34°∴∠ABD34°∴∠BAD90°∠CA2aaaCxx

B27D+ba+baaBaCxxD+45xA

B

C

Dx+68

30BDEaE90°PA

Ba

C

D0Ex∠ABC∠AEBE∠EAP∠PaBPbPEE90°x∵ABCD∴∠ABC90°∴∠90°BE∠EAP∠45°∵Pa∴BP∵∠90°∴∠∠BEP∴△≌ASA∴APb∴PbD

9

22222222222222222222222222222210++a①++b4ac0②2a0③ax+0ax++④+A①②③

B①④

C②③④

D①③④①xa++0②x1+0③

+4b

+c0eq\o\ac(△,)eq\o\ac(△,)0④+eq\o\ac(△,)①x1b+0∴△≥0②x1+x4a+2b+02216c2+0③

+eq\o\ac(△,)ac0∴bac0ax+0b40∴④++aca+c∵a∴4+0②③④10

2222二填题共7小，满28分，小分x+3x+3312P3xP23P3x2313+a

1++0m的23+m∴114yky∵y∴k0k1k1

kkk1k154n11

84Pn

16BAC20°

DAC35°AB∠90°DBC∵AB∴∠C90°∵∠BAC20°∴∠B90°∠

∵

∴∠∠17yaxax+yAMPOPAMBMABa212

2020AMP∵y2+y∴0x1∴1aM∵MAB∴B4OPyk∴y三解题共8小，满62分）18π

1|+

2×19

+b013

+a220eq\o\ac(△,)∠

∠O⊙O21⊙OOOBO22OODD∵CO∠∴OBODdr∴⊙OAC21eq\o\ac(△,)CCD∥ABDEABG1AFCD14

2GB3BC6ABACAB∥CD∠∠”eq\o\ac(△,)AEF△CEDCDAB∥2eq\o\ac(△,)GBFGCD

AFBF∴AE∵ABCD∴∠AFE∠CDEAEFeq\o\ac(△,)∵

∴△AEF≌△AAS∴AFCDAB∥CD∥∴AFCD2∵∥CD∴△GBF∴

CD∵AFCD15

∴AFCD∴ABAF+22201923“12“”32”2360°3404016

2“”3

108°∵∴2320//x/yx/

……

……123.52150yx23.52×xy+kx17

1212∴y2+80x23.5y2332x+80x∵≤x∴x251502524eq\o\ac(△,)ABCABABOBCACE⊥AC1DH⊙O2H310CODADADB90°BDCDODeq\o\ac(△,)OD∥ACDHOD⊥DH⊙O2DE∠DEC∠B∠∠CCHEH3eq\o\ac(△,)ADCAC

eq\o\ac(△,)CDHCH

DHOODAD∵AB18

∴∠ADB90°AD⊥∵AB∴AOBO∴∴OD∵⊥∴ODDH∴O2DE∵⊙O∴∠∠∵AB∴∠B∠C∴∠∠C∵⊥∴CHEHHCE3eq\o\ac(△,)CDBC5∵∴

eq\o\ac(△,)∵cos∴CH

∴CH2∴AECE

2

3

25++x1B19

222212222212y3D12yPeq\o\ac(△,)PBCP3MABN2MMeq\o\ac(△,)MNBA1C2BCeq\o\ac(△,)PBC①CB②BP③PBPCAMtDN2t2BMeq\o\ac(△,S)eq\o\ac(△,)2t×2ttMN2yx+