《高等数学》单元自测题

经典word整理文档，仅参考，双击此处可删除页眉页脚。本资料属于网络整理，如有侵权，请联系删除，谢谢！《高等数学》单元自测题第七章空间解析几何自测题专业班级姓名学号a与ba，babab，=。yzk0y2z0与k=。x3y1z3x1与z2y5Ak2。2kk153(B(C(6,2,D2，，，AD。41x2y2z2。yzx222。jjki22a(ab)ab2aaa,a,abb,b,b}ba。xyzxyzb,ab,abababab0axxyyzzxxyyzzabaabbbababDayxzzxyzxyzxya,,cabcabbcca=。x+=。xacos。asinyzb{{zzzxacosz0yacosz0{xacos{xya222bzbbsinyaz0b1a,,c0abc32abbcca。7aba7a2b，aa与b23xy2z0yzx2x1y12z9:，平面:x3y5z20L133）））3xyz1abc：1111若。dd2a2b2c22y2z303x4《高等数学》单元自测题第八章多元函数微分学专业班级姓名学号一、填空题：zx3xy,则设z1(x,y)设f则'fyx2y2zx1z是x,y则2zzysine则设xy1xy)dz设z22则2f(x,y)dz2xydxaxydyaz函数z3223xxyy43在点处沿从点A到方向的方向导数等于xyyzzxuu二．选择题：,yyx22(x,y)(.)设f则fxy(x2y2x22;;;.z2(2),（设zee则.xyx2(0,0))zxF(xy,yz,zx)0zx,y是(F''F'2'3F'2'2F''F''F''F''F'';;;;111331FFFFFFFF2323235xyxyzdz(．2(ydy)(xy)22(xdx)(xy)2）；））；2(xdy)(xy)22(ydx)(xy)2）；3xxyxylz32x;t,yt,ztx2yz023(.;;.3;(x,y)x2xyy4y2(f232xyz2.;;三．计算题：;(D).zzln(xxy)设z22求,.xyyxarctan求z.6z2yz4z0x,y,求x是z.222x2xyzr0时设r222rrr2222.xyzr222yz2zf(xy,)f设z,求,.xxxy7(x,y)xy3x3y9xf.3322yz14).x222Vm38《高等数学》单元自测题第九章重积分专业班级姓名学号一、填空题:0xa,0yb(xy)dDDy1xy2x0x1Dx，，及f(x,y)dxdyD22y(,)fxydxdy0y2:axyb(0ab)f(x,y)dxdyD2222D22y(0)dxaaa将积分dyx2y2化为极坐标形式的二次积分为00:0xyz1(x2y3z)dv已知区域，则三重积分y2xx2,yzza(a围成，则将三重积分已知区域由(x,y,z)dvfxyz2xy2z22与2二、选择题y1x与ydxdy1.DxD(11）;2;.4x,x1xf(x,y)d（Dy和Ddxfxydy;11dxfxydy;(,)11(,)000xdyfxydx.1dxfxydy;(,)x1y(,))00009f(x,y)dy(elnxdx10dyf(x,y)dxyedyf(x,y)dx；elnye1010dy1e(,)fxydx1efxydx(,)dyy0e0lnyf(xy)dD:xy1I(I22．22D）rfr1()21()）rfr2dr；2dr；001()21frdr.()）fr2dr；D）200:xy4ed（D22x2y2D(e2(e；）4；）42(e）；）e4．422f(x,y,z)dv2化zx2(y2及zxx22y2(,,)dxdy1x22x2fxyzdz;(,,)1x2dxdyfxyzdz;10x22y2102x2221x22x2fxyzdz;(,,)1x22(,,)fxyz.xydxdy1x2x22y21x22x2yazz2axy已知积分区域由x22及22围成，则将三重积分yf(,z)(x2a2ar,)2a2ar,)dfz;dfz;r2r20000aar2r22az;,)2a,)fz.dfdaa002ar002ar14f(xyz)dv：x2y2z2222(22()fr2sin2frdr;()dd2dr;dd2001001sind2dsin2()fr22()frd2rdr;d2r2dr00100110三、计算下列二重积分2x1D,yxx4.dyy3xDxy)221xy4D.22x2y2D2xy1y，及edxdyDyyD11四、计算下列三重积分xdxdydz2xy4.z22z五、求由平面xyxy1所围成的柱体被平面0及抛物面zz6x2y2所截得的立体的体积12《高等数学》单元自测题第十章曲线积分、曲面积分专业班级姓名学号一、计算下列曲线积分：1.e.设L求x2y2LL,y.xydsxL1x,ecost,yesint,ze01.tttx2y2z213(xydx(yx)dyL为Lx(4,2)y;2(4,2);2)(4,2)到.(2xyxdx(xy)dyyx2及yx.22,L2Lx22y22ye)dx(xedy1(Aa到求LxxabLB(a.14(xydx(xy)dyLxydxxydy.(2,3)()()二、计算下列曲面积分(xydSzxy12z.222(xyyzzxdSzxyy2ax2x2,22.15xzdxdyxydydzyzdzdxxyz1x0.y,及z0.xdydzydzdxzdxdyyza,x22.33322zxyzRxy2,是设2222求xdydzydzdxzdxdy.16《高等数学》单元自测题第十一章无穷级数专业班级姓名学号一、选择题：ulimu，()nnnn1DA、B、C、（）11111(；B、(()；C、(；、()。DA、n1n1nnnn1nnn1n1n1n1、）(nn1((nnn1D、。。。A、(；B、；C、；n1nlnn3n2n2n2n1n2）1(nnnD；、A、；B、；C、(nn)n)2n12n1n1n1n1n1）2(n1nn1D；、(n1((A、B、；C、n1n321nn3nn1n1n1n1u）nn1A、limu0；B、unnnn1D、(uu)C、ku(kn2n12nn1n1(1)(n1n)（）n1n1D）A、BC2x1ax在xnnn117A、BCD(x)xe2(,)xf在）2xx2n1xn2x2(n1)x2nA、(n；B、；C、；D、。(2n1)!n!n!n!n1n1n1n1二、填空题：1。。1x2xn(n1在(nn1(x3)n。nnn1(x)2[,)f0x0f(x)k(k0),则f(x)x0x。三、1n1．2nn12n32．nn3n1nn3．n1n1n1n4．2nn118四、出详