井下设备的整定计算

井下设备的整定计算过流整定细则说明〔含移变低压侧中过载长延时保护电流整定按实际负载电流值行状况，乘一需用系数。公式： I=K Iez式中： ——过载保护电流整定值，A；zIe A;K0.5~1。〔含移变低压侧中最大负载电机的起动电流，加其余电机的实际电流之和。公式： I=IQe+K Iez式中： I——短路保护电流整定值，A；zIQe——最大负载电机起动电流，A;Ie ，A;0.5~1。电磁起动器中电子保护器的过载电流Iz

整定以负载电机的额定电流为依据，依据掌握开关的整定方式取其近似值。当运行中电流超过Iz

时，即视为过8Iz

值时，即视为短路，保护器瞬间动作。1.5。公式：式中 相短路电流，A；I——馈电开关短路电流整定值，A；z1.5——牢靠系数。81.2。公式：式中 相短路电流，A；I——馈电开关短路电流整定值，A；z1.5——牢靠系数。高压配电装置，应依据其保护干线中移动高压侧过流整定值进展整定。似值。〔煤矿工业出版社〕第一章其次抑制定。综采工作面电气整定计算〔一〕.移变的整定计算500KVA〔10KV→690V,14.5〕二次侧过载整定电流：I/=K =0.75×1.15×577.4=498Azz e二次侧短路保护电流：I=I+K =6×1.15×180+0.75×1.15×zz Qe e397.4=1585A 〔取皮带机电机为干线最大负载〕折算至一次侧过载整定电流：I/=498÷14.5=34AZ折算至一次侧短路保护电流：I=1585÷14.5=109AZ1000KVA〔10KV→1200V,8.3〕二次侧过载整定电流：I/=K =0.75×0.67×1020=513Azz e二次侧短路保护电流：I=I+K =6×0.67×500+0.75×0.67×zz Qe e520=2271A 〔取采煤机为干线最大负载〕折算至一次侧过载整定电流：I/=513÷8.3=62AZ折算至一次侧短路保护电流：I=2271÷8.3=274AZ800KVA〔10KV→1200V,8.3〕二次侧过载整定电流：I/=K =0.75×0.67×730=367Azz e二次侧短路保护电流：I=I+K =6×0.67×160+0.75×0.67×zz Qe e570=929A 〔取后溜机头为干线最大负载〕折算至一次侧过载整定电流：I/=367÷8.3=44AZ折算至一次侧短路保护电流：I=929÷8.3=112AZ〔2〕.馈电开关的整定计算回风顺槽馈电的过载整定计算:I/=K回风顺槽馈电的短路保护计算:I=IK

=0.75×1.15×101.4=87Ae=6×1.15×75+0.75×1.15×Qe e26.4=540A 〔取无极绳电机为干线最大负载〕运输顺槽馈电的过载整定计算:I/=K运输顺槽馈电的短路保护计算:I=I+K

=0.75×1.15×265.5=230Ae=6×1.15×180+0.75×1.15×Qe e85.5=1316A 〔取皮带电机为干线最大负载〕名称型号电压〔V)用途负载〔KW)过载电流〔A)短路电流〔A)器QBZ-80660回风顺电机1113104器QBZ-80N660电机11.413104起动器QBZ-80N660液压张电机45.544器QBZ-120N660机7586688起动QJR-200660皮带机90×22071656器电机起动器QBZ-80N660张紧装置电机7.5972起动器QBZ-80660排水泵电机1315120起动器QBZ-80660排水泵电机1315120起动器QBZ-80660排水泵电机1517136起动器QBZ-80660回柱绞车18.521168起动器QBZ-80660回柱绞车18.521168组合QBZ-1600/1140(660)-61140采煤机5003352680开关1140乳化液1125846721140乳化液2125846721140裂开机110745921140转载机1601078561140备用软起组合QJR-4×400/1140(660)-41140后溜机头1601078561140后溜机尾1601078561140前溜机头1601078561140前溜机尾160107856起动器QBZ-801140喷雾泵4530240起动器QBZ-801140喷雾泵4530240(一〕.综掘队馈电的整定计算馈电过载整定电流：I/=K =0.75×1.15×180.5=156Azz e馈电短路保护电流：I=I+K =6×1.15×40+0.75×1.15×zz Qe e140.5=397A 〔取刮板机电机为干线最大负载〕〔二〕500KVA8.3〕二次侧过载整定电流：I/=K =0.67×135=90Azz e

=I+K

=8×90=720Azz Qe e折算至一次侧过载整定电流：I/=90÷8.3=11AZ折算至一次侧短路保护电流：I=720÷8.3=87AZ名称型号电压〔V)用途负载〔KW)过载电流〔A)短路电流〔A)馈电KBZ-4001140综掘机13590720馈电KJZ-200660综掘队馈电180.5156397起动器QBZ-80N660刮板机4046368起动器QBZ-80N660刮板机4046368起动器QBZ-80N660刮板机4046368起动器QBZ-80N660刮板机4046368起动器QBZ-80N660喷浆机5.56.552起动器QBZ-80N660水泵1517136切换QBZ-2×660局扇风2×1535280开关120SF开关120SF机四．机电机运队电气整定计算(一〕.主井装载硐室馈电的整定计算馈电过载整定电流：I/=K =0.75×1.15×41.5=36Azz e馈电短路保护电流：I=I+K =6×1.15×18.5+0.75×1.15×zz Qe e23=147A (二〕.副井二水平信号硐室馈电的整定计算馈电过载整定电流：I/=K =0.75×1.15×26=22Azz e馈电短路保护电流：I=I+K =6×1.15×18.5+0.75×1.15×zz Qe e7.5=134A 〕(三〕.轨道巷配电的整定计算D10馈电过载整定电流：I/=K =0.75×1.15×83=72Azz eD10馈电短路保护电流：I=I+K =6×1.15×45+0.75×1.15×zz Qe e38=343A (四〕.主皮带机头馈电的整定计算馈电过载整定电流：I/=K =0.75×1.15×111.5=96Azz e馈电短路保护电流：I=I+K =6×1.15×90+0.75×1.15×zz Qe e21.5=640A 〕(五〕.副井一水平信号硐室馈电的整定计算馈电过载整定电流：I/=K =0.75×1.15×40=35Azz e馈电短路保护电流：I=I+K =6×1.15×22+0.75×1.15×zz Qe e18.5=168A 〕(六〕.800KVA800KVA〔10KV→690V,14.5〕二次侧过载整定电流：I/=K =0.75×1.15×302=260Azz e二次侧短路保护电流：I

=I+K

=6×1.15×90+0.75×1.15×zz Qe e212=804A 〔取主皮带机电机为干线最大负载〕折算至一次侧过载整定电流：I/=260÷14.5=18AZ折算至一次侧短路保护电流：I=804÷14.5=55AZ名位置型号电压用途负载过载电短路电称〔V)〔KW)流〔A)流〔A)起动QBZ-80660液压站1517136器主油泵起液压站动QBZ-80660备用油1517136器泵起动QBZ-806601#闸门2.55.544器电机起动QBZ-806602#闸门2.55.544器起动主井底装载硐室QBZ-80660电机1#给煤5.56.552器机电机起动QBZ-806602#给煤5.56.552器机电机起动QBZ-806601#皮带18.521168器电机起QBZ-806602#皮带18.521168动电机器起主井底动QBZ-80660水泵电7.58.568器机起动副井二水平信号硐QBZ-80660主油泵18.521168器室电机起动QBZ-80660备用油18.521168器泵起轨道巷动QBZ-80660绞车电2528.5228器机起动轨道巷QBZ-806601#挡水4551408器墙水泵起动QBZ-806602#挡水1315120器墙水泵起动QBZ-80660液压站18.521168器主油泵起液压站副井一水动平信号硐器室起

QBZ-80 660 备用油泵副井井

18.5 21 168动 QBZ-80 660 22 26 208底水泵器起 QBZ-80 660

副井井

22 26 208变电所高爆整定表动变电所高爆整定表动底水泵器软主皮带QJR-400 660 90104832起 电机起张紧装动 QBZ-80 660 15 17 136置电机器主皮带机起头 皮带制动 QBZ-80 660 1 5.5 44动电机器起动QBZ-80660除铁器5.56.552器编名型号电压用途负载过载电流短路电流号称〔V)〔KW)〔A)〔A)G1高爆PJG-10-50010000Ⅰ回总高爆3561167664G2高爆PJG-10-100100003#变压器3021855G3高爆PJG-10-20010000主排水128021126G4高爆PJG-10-20010000主排水228021126G5高爆PJG-10-20010000综采工作面2327.5140495G6高爆PJG-10-100100001#变压器G7高PJG-10-50010000联络1．两相短路电流计算公式1．两相短路电流计算公式1式中：Id(2)——两相短路电流，A1、——短路回路内一相电阻、电抗值的总和，Ω；——依据三相短路容量计算的系统电抗值，Ω；爆G8高爆PJG-10-10010000备用G9高爆PJG-10-10010000备用编名型号电压用途负载过载电流短路电流号称〔V)〔KW)〔A)〔A)G10高爆PJG-10-20010000轨道巷移变1351187G11高爆PJG-10-10010000主排水328021126G12高爆PJG-10-10010000备用G13高爆PJG-10-100100002#变压器3021855G14高爆PJG-10-50010000Ⅱ回总高爆3561167664、、——高压电缆的电阻、电抗值，Ω；——矿用变压器的变压比;、——矿用变压器的电阻、电抗值，Ω；、——低压电缆的电阻、电抗值，Ω；660V，Ue算。二.井下在用电缆、移变电阻、电抗工程162535507095电缆电阻电抗1.370.8700.6220.4350.3100.2290.0900.1200.1130.1070.1010.096变压器电阻、电抗变压器电阻、电抗工程500KVA800KVA1000KVA容量电阻0.00680.01350.0101电抗0.04270.10720.09311.井下变电所800KVA变压器二次出口短路电流计算：1〕高压电缆电阻、电抗：L=600m=0.6km查表得R=0.229Ω/km0X=O.O96Ω/km0此段高压电缆电阻R=0.6×0.229=0.1374Ω1电抗X=0.6×0.096=0.0576Ω1800KVA查表得：R=0.0135Ω/km X=O.1072Ω/kmb b50MVAX=O.O288Ω/kmX=0.1374/14.52+0.0135=0.0142Ω=0.0576/14.52+0.1072+0.0288=0.1363Ω两相短路电流：Id(2)=1

= =2517A4〕灵敏度系数校验：= =3.13>1.5 2.500KVA1〕高压电缆电阻、电抗：3×70mm2L=650m=0.65km查表得R=0.310Ω/km X=O.101Ω/km0 0此段高压电缆电阻R=0.65×0.310=0.2023Ω1电抗X=0.65×O.101=0.0657Ω1从井上至井下变电所高压电缆电阻、电抗已算：高压电缆总电阻R=0.1374+0.2023=0.3389Ωg总电抗X=0.0576+0.0657=0.1233Ωg500KVA查表得：R=0.0068Ω/km X=O.0427Ω/kmb bX=O.O288Ω/kmX=0.3389/14.52+0.0068=0.0084Ω=0.1233/14.52+0.0427+0.0288=0.0721Ω两相短路电流：Id(2)=1灵敏度系数校验：

= =4752A= =3>1.5 满足灵敏度要求。运输顺槽电气列车1000KVA移变二次出口短路电流计算：1〕高压电缆电阻、电抗：3×50mm2L=800m=0.8km查表得R=0.435Ω/km X=O.107Ω/km0 0此段高压电缆电阻R=0.8×0.435=0.348Ω1电抗X=0.8×O.107=0.0856Ω1从井上至500KVA高压电缆电阻、电抗已算：高压电缆总电阻R=0.3389+0.348=0.6869Ωg总电抗X=0.1233+0.0856=0.2089Ωg1000KVA查表得：R=0.0101Ω/km X=O.0931Ω/kmb bX=O.O288Ω/kmX=0.6869/8.32+0.0101=0.0201Ω=0.2089/8.32+0.0931+0.0288=0.1249Ω两相短路电流：Id(2)=1灵敏度系数校验：

= =4743A= =2.1>1.5 满足灵敏度要求。运输顺槽电气列车800KVA移变二次出口短路电流计算：1〕高压电缆电阻、电抗：抗已算：X=0.2089Ωg g800KVA查表得：R=0.0135Ω/km X=0.1072Ω/kmb bX=O.O288Ω/kmX=0.6869/8.32+0.0135=0.0234Ω=0.2089/8.32+0.1072+0.0288=0.1390Ω两相短路电流：Id(2)=1灵敏度系数校验：

= =4257A= =4.6>1.5 四．低压系统短路电流计算〔一〕井下变电所800KVAId(2)计算1低压电阻、电抗 L=50m=0.05km查表得R=0.870Ω/km X=O.120Ω/km0 0此段低压电缆电阻R=0.05×0.870=0.0435Ω1电抗X=0.05×0.120=0.0060Ω1=0.0142+0.0435=0.0577Ω=0.1363+0.0060=0.1423Ω两相短路电流：Id(2)=13)灵敏度系数校验：

= =2247A= =13.4>1.5 Id(2)计算1低压电阻、电抗 L=320m=0.32km查表得R=0.310Ω/km X=O.101Ω/km0 0此段低压电缆电阻R=0.32×0.310=0.0992Ω1电抗X=0.32×0.101=0.0323Ω1=0.0142+0.0992=0.1134Ω=0.1363+0.0323=0.1686Ω两相短路电流：Id(2)=13)灵敏度系数校验：

= =1698A= =2.65>1.5 满足灵敏度要求。Id(2)计算1低压电阻、电抗 L=470m=0.47km查表得R=0.870Ω/km X=O.120Ω/km0 0此段低压电缆电阻R=0.47×0.870=0.4089Ω1电抗X=0.47×0.120=0.0564Ω1=0.0142+0.4089=0.5509Ω=0.1363+0.0564=0.1927Ω两相短路电流：Id(2)=13)灵敏度系数校验：

= =591A= =4.02>1.5 Id(2)计算1低压电阻、电抗 L=80m=0.08km查表得R=0.870Ω/km X=O.120Ω/km0 0此段低压电缆电阻R=0.08×0.870=0.0696Ω1电抗X=0.08×0.120=0.0096Ω1=0.0142+0.0696=0.0838Ω=0.1363+0.0096=0.0013Ω两相短路电流：Id(2)=13)灵敏度系数校验：

= =4116A= =30.7>1.5 满足灵敏度要求。〔二〕500KVAId(2)计算1低压电阻、电抗 L=300m+10m=0.31km查表得R=0.435Ω/km X=O.107Ω/km0 0此段低压电缆电阻R=0.31×0.435=0.1349Ω1电抗X=0.31×0.107=0.0332Ω1=0.0084+0.1349=0.1433Ω=0.0721+0.0332=0.1053Ω两相短路电流：Id(2)=13)灵敏度系数校验：

= =1940A= =2.8>1.2 Id(2)计算1低压电阻、电抗 L=300m=0.3km查表得R=0.435Ω/km X=O.107Ω/km0 0此段低压电缆电阻R=0.3×0.435=0.1305Ω1电抗X=0.3×0.107=0.0321Ω1=0.0084+0.1305=0.1389Ω=0.0721+0.0321=0.1042Ω两相短路电流：Id(2)=13)灵敏度系数校验：

= =1987A= =45>1.2 Id(2)计算1低压电阻、电抗 L=40m=0.04km查表得R=1.37Ω/km X=O.090Ω/km0 0此段低压电缆电阻R=0.04×1.37=0.0548Ω1电抗X=0.04×0.090=0.0036Ω1=0.1389+0.0548=0.1937Ω=0.1042+0.0036=0.1078Ω两相短路电流：Id(2)=13)灵敏度系数校验：

= =1556A= =15>1.2 Id(2)计算1低压电阻、电抗 L=300m=0.3km查表得R=1.37Ω/km X=O.090Ω/km0 0此段低压电缆电阻R=0.3×1.370=0.4110Ω1电抗X=0.3×0.090=0.0270Ω1=0.1937+0.4110=0.6047Ω=0.1078+0.0270=0.1348Ω两相短路电流：Id(2)=13)灵敏度系数校验：

= =557A= =5.36>1.2 Id(2)计算1低压电阻、电抗 L=22m=0.022km查表得R=0.435Ω/km X=O.107Ω/km0 0此段低压电缆电阻R=0.022×0.435=0.0096Ω1电抗X=0.022×0.107=0.0024Ω1=0.0084+0.0096=0.0180Ω=0.0721+0.0024=0.0745Ω两相短路电流：Id(2)=13)灵敏度系数校验：

= =4501A= =2.7>1.2 Id(2)计算1低压电阻、电抗 L=355m=0.355km查表得R=1.37Ω/km X=O.090Ω/km0 0此段低压电缆电阻R=0.355×1.370=0.4864Ω1电抗X=0.355×0.090=0.0320Ω1=0.0084+0.4864=0.4948Ω=0.0721+0.0320=0.1041Ω两相短路电流：Id(2)=13)灵敏度系数校验：

= =682A= =5.7>1.2 Id(2)计算1低压电阻、电抗 L=50m=0.05km查表得R=1.37Ω/km X=O.090Ω/km0 0此段低压电缆电阻R=0.05×1.370=0.0685Ω1电抗X=0.05×0.090=0.0045Ω1=0.4948+0.0685=0.5633Ω=0.1041+0.0045=0.1086Ω两相短路电流：Id(2)=13)灵敏度系数校验：

= =601A= =5>1.2 Id(2)计算1低压电阻、电抗 L=100m=0.1km查表得R=1.37Ω/km X=O.090Ω/km0 0此段低压电缆电阻R=0.1×1.370=0.1370Ω1电抗X=0.1×0.090=0.0090Ω1=0.5633+0.1370=0.7003Ω=0.1086+0.0090=0.1176Ω两相短路电流：Id(2)=13)灵敏度系数校验：

= =486A= =3.6>1.2 满足灵敏度要求。Id(2)计算1低压电阻、电抗 L=80m=0.08km查表得R=1.37Ω/km X=O.090Ω/km0 0此段低压电缆电阻R=0.08×1.370=0.1096Ω1电抗X=0.08×0.090=0.0072Ω1=0.7003+0.1096=0.8099Ω=0.1176+0.0072=0.1248Ω两相短路电流：Id(2)=13)灵敏度系数校验：

= =421A= =2.5>1.2 10.3101Id(2)计算1低压电阻、电抗 L=400m=0.4km查表得R=0.870Ω/km X=O.120Ω/km0 0此段低压电缆电阻R=0.4×0.870=0.3480Ω1电抗X=0.4×0.120=0.0480Ω1=0.0084+0.3480=0.3564Ω=0.0721+0.0480=0.1201Ω两相短路电流：Id(2)=13)灵敏度系数校验：

= =917A= =2.3>1.5 满足灵敏度要求。〔三〕综采1000KVA移变分支线路各点短路电流计算Id(2)计算1低压电阻、电抗 L=330m=0.33km查表得R=0.229Ω/km X=O.096Ω/km0 0此段低压电缆电阻R=0.33×0.229=0.0756Ω1电抗X=0.33×0.096=0.0317Ω1=0.0201+0.0756=0.0957Ω=0.1249+0.0317=0.1566Ω两相短路电流：Id(2)=13)灵敏度系数校验：

= =3269A= =1.22>1.2 Id(2)计算1低