C语言函数题库及答案

inta,b,c;intsum(intx1,intx2);total=sum((a,b),c);A.inta(floatx[],intn)B.inta(float*x,intn)C.inta(floatx[10],intn)D.inta(floatx,intn)fun1(a){printf("\n%d",a)；}是(D)A.swapa(intx,inty){inttemp；}B.swapb(int*x,int*y){inttemp；}C.swapc(int*x,int*y){inttemp；temp=*x；*x=*y；*y=temp；}D.swapd(int*x,int*y){int*temp；}sqofsina(x){floatx；return(sin(x)*sin(x))；}B.doublesqofsinb(x){floatx；return(sin((double)x)*sin((double)x))；}C.doublesqofsinc(x){return(((sin(x)*sin(x))；}D.sqofsind(x){floatx；return(double(sin(x)*sin(x)))；floatfun1(intx,inty){floatz；z=(float)x/y；return(z)；}A.printf("%f",fun1(a,b))；B.printf("%f",fun1(&a,&b))；C.printf("%f",fun1(*a,*b))；D.调用时发生错误a(s1,s2)chars1[],s2[]；{while(s2++=s1++)；}intd=1;fun(intp){intd=5;printf("%d",d);}{inta=3;fun(a);printf("%d",d);}1)#include2)longfun(intn)3){if(___1___)4)return(n*fun(___2___));5)elseif(___3___)6)return1;}行处填写n-1。又：1!=1故3，5行就好填了。因此答案是n>1n-1n==1。还有0!=1故，还可填写：n>0n-1n==01)longfun(intn)2){inti;3)longs;5)for(i=1;i<=n;i++)7)returns;10){longs;11)intk,n;12)scanf("%d",&n);14)for(k=1;k<=n;k++)16)printf("%ld\n",s);第四处：s+fun(k)1)intfun(intn){2)if(___1___)3)return0;4)elseif(___2___)5)return1;第三处：fun(n-1)+fun(n-2)1)#include2)#include3)___1___fun(intn)4){inta,b,c,k;6)s=0.0;9)for(k=1;k<=n;k++)16)returns;1)doublefun(doubleq)2){intn;5)s=2.0;8)s=s+(double)(n+1)/n;11)printf("n=%d\n",n);9.给定程序功能是计算S=f(-n)+f(-n+1)+floatf(doublex){if(x==0.0||x==2.0)elseif(x<0.0)return(x-1)/(x-2);return(x+1)/(x-2);}doublefun(intn){inti;doubles=0.0,y;for(i=-n;i<=___2___;i++){y=f(1.0*i);s+=y;}}{printf("%f\n",fun(5));}intfun(intscore[],intm,intbelow[]){inti,j=0;floataver=0.0;for(i=0;i<m;i++)aver+=score[i];aver/=(float)m;for(i=0;i<m;i++)if(score[i]<aver)below[j++]=___1___;returnj;}{inti,n,below[9];intscore[9]={10,20,30,40,50,60,70,80,90};n=fun(score,9,___2___);printf("\nBelowtheaveragescoreare:");for(i=0;i<n;i++)printf("%d",___3___);}第一处：score[i]第三处：below[i]voidfun(___1___,intn){inti=0;for(i=0;i<N;I++)<p>for(i=0;i<N;I++)<p>{if(i%5==0)printf("\n");printf("%d,",x[i]);}}第二处：sum+=x[i]intfun(intx){inti,s;s+=i;returns;}S=1+1/(1+2)+1/(1+2+3)+___1___fun(intn){inti,j;for(i=1;i<=n;i++){t=0.0;for(j=1;j<=i;j++)}}{intn,m;clrscr();printf("\nInputn,m\n");{}}{inta,b,c,max;clrscr();printf("\nInputthreenumbers:\n");printf("Thethreenumbersare:%d,%d,%d\n",a,b,c);if(a>b)printf("max=%d\n",max);}intfun(inta,intb,intc){intt;t=(a>b)(b>c?b:(a>c?c:___1___)):((a>c)c:___3_