山东省临沂市2015年中考数学试题(含答案)

d格式-可编辑-感谢下载支持启前 A2015年临沂市初中学生学业考试试题学注意事项：1第共8分120间0分钟答用05考束试题回．2．第Ⅰ卷（选择题共42分）一、选择题（本大题共14小题，每小题3分，共42分）在每小题所给出的四个选项中，只有一项是符合题目要求的．11．2的绝对是111(A)2. (B)2. (C). (D)2.112．如图，直线a∥b，∠1=60，2=40则3等于(A)40.(B)60. a 1 2(C)80. 3b(D)100.3是 第2）(A)a2a22a4.(C)a2a3a6.

(B)(a2b)3a6b3.(D)a8a2a4.4．某市6下4 6 9 6 9 2 29据别是)29，29. )6. (C)2629. (D)2，3.d格式-可编辑-感谢下载支持5是) (B) (C) (D)第5）x 06．不等式组2x2≤6x 0321 0 1 2 321 0 1 2(A) (B)321 0 1 2 321 0 1 2(C) (D)7盖杯配.是113(A)4. (B)2. (C)4. (D).1138．如图，C是)°.(C)100.

O上的个，若C0则C于(B)80.(D)130. O9．多项式x2m与多项式x22x1的公因式是(A)x1. (B)x1.

A CB2(C)x21. (D)x. 第8题）210距20千米，汽间t）关于行驶速度v（单位：千米／小时）的函数关系式是vvv(A)t20v. (B)t20. )t20. (D)t10.vvv11．观察下列关于x的单项式，探究其规律：x，3x2，5x3，7x4，9x5，11x6，….按照上述规第205是(A)2015x2015. (B)4029x2014. )4029x2015. )4031x2015.Ed格式-可编辑-感谢下载支持12．如图，四边形AD为平行四长D到，．使D=接EDB.能使四．E是(A)BB.(C)AD=90.

)B⊥C.(D)C⊥DE.3线yx22x3线yx2是(A)移1个单移2个.(B)向移1移2.(C)向移1移2.(D)移1个单移2个.14线y=－＋2反数yx的图象有唯一公点.线11yxb与反比例数yx的图象有2个公共点则b的取值范围是 y1(A) ﹥2.(B)－﹤﹤2. 2(C) ﹥2或b－.(D) ﹤－. O 2 x第4题）第Ⅱ卷（非选择题共78分）注意事项：1．word格式-可编辑-感谢下载支持2用5题不分．二、填空题（本大题共5小题，每小题3分，共15分）15．小2______3（填“﹤，“＝，“﹥”.a46．计算：a2a22a___.a437在AD接B，DD,B4,nA4则AD的积是_.3AD CE DOA B B C第7） 第8）8AC中DE边CBD与E点O则___19．定义：给定关于x的函数y，对于该函数图象上任意两点（x1，y1），（x2，y2），当x1﹤x2，有y1﹤y该为.根据以数有________确.1①y=2； ②y=x＋；③y=x2(x＞； ④yx.1三、解答题（本大题共7小题，共63分）20．（本小题满分7）计算：(32(32).1．（本小题满分7）“责了214内该市若天的空气质量情作为样本进行统，绘制了如图所示条形统计图和扇统计图（部分信息未给）.信：d格式-可编辑-感谢下载支持（1）；（2）（5质到优“良”的；（3）优”的率.图 某图6 360482 1260优 良

轻微污染轻度污染% 中度污染良优 重度污染3 2 1轻微轻度 中度重度空气质污染污染 污染污染量类别第1）22．（本小题满分7）为3为60楼的水平为42，这楼多高？ BA αβ D第2题） Cd格式-可编辑-感谢下载支持23．（本小题满分9）如图点O为RtC边B上的以OAO与C切于点D与AC点，连接AD. C（1：D平∠C；ED（2）BC=60OA=留）.A O B第3题）4．（本小题满分9）.共3为0元／米2高0米的售低30元，已知该为0米2.者所商方：方案一价8送a；方案二价10%送.（1）请价y米2）层x（x≤2x取；（2算.word格式-可编辑-感谢下载支持25．（本小题满分1）图形AD的外侧，作两个等边三角形E和DC接，E.（1）请AF与BE量是 置是 ；（2）如图2，若将条件“两个等边三角形E和D”变为“两个等腰三角形E和F，且?；（3形AE和DF且AE=DF（？直你.B A B A B AE EC D C D C DFF图1 图2 图第5题）.分3）O为原点，直线y=－2x－1与y轴交于点A，与直线y=－x交点B,点B关于原点的对称点为点C.（1）求过ABC物式； y（P点为Q.形PC为点P的标； B②若点P的横坐标为t－1＜＜1当t为 O x何值形PBC理.A Cy2x1 yx第6题）d格式-可编辑-感谢下载支持参考答案及评分标准出有准分.一、题3分，共2）号 1 2 3 4 5 6答案 A C B A D C

7 8 9 10 11 12 13 14B D A B C B D C二、题3分，共5）5>；

6．a；a

7．37； 82； 9③.三解答题20．解：方法：(32(32)=[3(2)[3(2)]············································1分=(3)2(2)2······························································3分3(222)······························································5分32221································································6分22.············································································7分方法：(32(32)(3)2323123(2)221131211·········3分363622321··················································5分22.····························································································7分2：1确.······································································2分某市若干天空气质量情况条形统计图数36

3630241812 1260优 良

63 2 1轻微轻度中度重度空气质污染污染污染污染量类别d格式-可编辑-感谢下载支持（2）方（是60，∴该市2014（5天到优”、良总天数约：01236362天）.··········································································50方法二（是0，∴该市2014（5天到优”的天数：126036573（天.·················································································3分12该市2014年（365“良的为：6059）.···············································································46∴该市2014（5天到优”、良总天数约：73+21929）.···················································································5分（3）随取204年内某一天，量“优概率：2 105.··································································································7分2 12图α=30，β=60，D=.D D∵nD，nD， A α D∴D=D·tanα=42×°D D3=42×3=143.·····························3分3DDtan＝×t0°＝423.·········································6分 C∴CDCD＝143＋423＝563m.C因此，这栋为63m.········································································7分C2．1）证明：连接OD. E DA O Bd格式-可编辑-感谢下载支持∵COD为点，∴OD⊥C.···································1分∵AC⊥C，∴OD∥C，·································2分AD=CAD.··························3分又ODOA，∴AD=OD，··················································································4分∴C=A，即D∠BAC.··························································5分（2）方接OED. C∠BC=60，E=A， E DOAE边角，∴AO=60， A O B∴AD=30.1又∵D2C0，1∠AD=OA，∴DO，···································6分∴S△AED＝S△OED，32分积=S扇形ODE=043.·············································932方法二：同方法一，得ED∥O，·······························································6分∴四形AODE为平行四边，2∴S S 123.································································7分DD232又S扇形ODE－S△OED=0433.················································8分3222∴阴影部分的面积=S扇形ODE－S△OED)+S△D=3333.··················9分222当00－0＋00···············································2分d格式-可编辑-感谢下载支持当＝40＋0＝50370370为03600 数）.·······················4分当，一总：w1＝120（630）×%－＝48576－；·····································5分二总：w2＝120（60）×%＝475.·················································6分∴当w1＜w2即485760－a＜0，a＞0；当w1w2即48576－a＝47500时a＝10；当w1w2即48576－a＞47500时a＜15.于1060；于10元；于10元算.···································9分2：1A=，FBE.································································2分（2）立.························································································3分证明形AD，∴ADC∠D∠AC=90. B A在ED和FDC中， EEAFD, C DEDFC,FADDC,∴ED△F.E=FD.∴E+DA=FD∠CDAE∠F.······································4分在BE△F，d格式-可编辑-感谢下载支持BAAD,BEF,AEF,∴BE△.∴BE=F∠=.········································································6分∵DAF+BAF90，∴AE∠=°，∴FBE.······························································································9分（3）立.·················································································1分， 1.组， 1.∴点B（1，）.·········································································1分∵点C点B关，∴点C的1，1.·········································································2分又点A线与轴的交，∴点A的坐标为（，1）.·········································································3分为解 abc， a，∴abc，得b解 c1. c1.为·····································································5分（2）图点P在抛物线上，∴可点P的坐标为m，m2m1）.当四形PBQC是，O，∴QC，即点PQ线=上，∴m=m2m1，························································································7分解得m=1±2.·······················································································8分∴点P（+2，+2（-2，-2）.··································9分d格式-可编辑-感谢下载支持yyx2x1

yyx2x1B BQO xPA C

EDPF

QO xA Cy2x1 yx y2x1 yx图1 图2②法一：如图，设点P（t，2-t-1）.点P作PD∥y轴，交直线y=-x于点D，则D（，-）.分别点BC作BEPD，FD，垂足分别为点E，F.∴PD=-t(2-t)=-t2+1，BE+F=，·················································10分1 1∴S△C＝2D·BE+2D·1 11＝2D·BE+C）11＝2（-2+1×21＝-2+1.···································································