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****CambridgeInternationalCambridgeInternationalAdvancedSubsidiaryandAdvanced Paper4Mechanics1 May/June1hour15Additional AnswerGraphListofFormulaeREADTHESEINSTRUCTIONSIfyouhavebeengivenanAnswerBooklet,followtheinstructionsonthefrontcoveroftheBooklet.WriteyourCentrenumber,candidatenumberandnameonalltheworkyouhandin.WriteindarkblueorblackYoumayuseanHBpencilforanydiagramsorgraphs.Donotusestaples,paperclips,glueorcorrectionfluid.DONOTWRITEINANYBARCODES.AnsweralltheGivenon-exactnumericalanswerscorrectto3significantfigures,or1decimalceinthecaseofanglesindegrees,unlessadifferentlevelofaccuracyisspecifiedinthequestion.Whereanumericalvaluefortheaccelerationduetogravityisneeded,use10ms−2.Theuseofanelectroniccalculatoripected,whereappropriate.YouareremindedoftheneedforclearpresentationinyourAtoftheexamination,fastenallyourworksecurelyThenumberofmarksisgiveninbrackets[]atofeachquestionorpartquestion.Thetotalnumberofmarksforthispaperis50.Questionscarryingsmallernumbersofmarksareprintedearlierinthepaper,andquestionscarryinglargernumbersofmarkslaterinthepaper.Thisconsistsof3printedpagesand1blankJC15©UCLES PAGEPAGE2©©UCLES1AblockBofmass2.7kgispulledatconstantspeedalongastraightlineonaroughhorizontalfloor.Thepullinghasmagnitude25Nandactsatanangleof!abovethehorizontal.ThenormalcomponentofthecontactactingonBhasmagnitude20N. Findtheworkdonebythepullinginmovingtheblockadistanceof5 2yF25xtan−1 xO63ThreehorizontalsofmagnitudesFN,63Nand25NactatO,theoriginofthex-axisandy-axis.Thesareinequilibrium.TheofmagnitudeFNmakesanangle!anticlockwisewiththepositivex-axis.Theofmagnitude63Nactsalongthenegativey-axis.Theofmagnitude25Nactsattan−10.75clockwisefromthenegativex-axis(seediagram).FindthevalueofFandthevalueoftan Ablockofweight6.1Nslidesdownaslopeinclinedattan−1!11"tothehorizontal.Thecoefficient4frictionbetweentheblockandtheslopeis1.Theblockpassesthroughapoint4

1withspeed2ms1FindhowfartheblockmovesfromAbeforeitcomesto Alorryofmass14000kgmovesalongaroadstartingfromrestatapointO.ItreachesapointA,andthencontinuestoapointBwhichitreacheswithaspeedof24ms−1.ThepartOAoftheroadisstraightandhorizontalandhaslength400m.ThepartABoftheroadisstraightandisinclineddownwardsatanangleof!#tothehorizontalandhaslength300m.ForthemotionfromOtoB,findthegaininkineticenergyofthelorryandexpressitslossinpotentialenergyintermsof Thetothemotionofthelorryis4800NandtheworkdonebythedrivingofthelorryfromOtoBis5000kJ.Findthevalueof Acyclistandherbicyclehaveatotalmassof84kg.SheworksonstantrateofPWwhilemovingonastraightroadwhichisinclinedtothehorizontalatanangle!,wheresin!=0.1.Whenmovinguphill,thecyclist’saccelerationis1.25ms−2ataninstantwhenherspeedis3ms−1.Whenmovingdownhill,thecyclist’saccelerationis1.25ms−2ataninstantwhenherspeedis10ms−1.Thetothecyclist’smotion,whetherthecyclistismovinguphillordownhill,isRN.FindthevaluesofPand TwoparticlesAandBstarttomoveatthesameinstantfromapointO.Theparticlesmoveinthesamedirectionalongthesamestraightline.TheaccelerationofAattimetsafterstartingtomoveisams−2,wherea=0.05−0.0002t.FindA’svelocitywhent=200andwhent= Bmoveswithconstantaccelerationforthefirst200sandhasthesamevelocityasAwhent=200.moveswithconstantretardationfromt=200tot=500andhasthesamevelocityasAwhent=FindthedistancebetweenAandBwhent= 7B0.5B0.5ParticlesAandB,ofmasses0.3kgand0.7kgrespectively,areattachedtosofalightinextensiblestring.ParticleAisheldatrestonaroughhorizontaltablewiththestringpassinerasmoothpulleyfixedattheedgeofthetable.ThecoefficientoffrictionbetweenAandthetableis0.2.ParticleBhangsverticallybelowthepulleyataheightof0.5mabovethefloor(seediagram).Thesystemisreleasedfromrestand0.25slaterthestringbreaks.Adoesnotreachthepulleyinthesubsequentmotion.FindthespeedofBimmediaybeforeithitsthe thetotaldistancetravelledby BLANKPermissiontoreproduceitemswherethird-partyownedmaterialprotectedbycopyrightisincludedhasbeensoughtandclearedwherepossible.Everyreasonableefforthasbeenmadebythepublisher(UCLES)totracecopyrightholders,butifanyitemsrequiringclearancehaveunwittinglybeenincluded,thepublisherwillbepleasedtomakeamendsattheearliestpossibleopportunity.Toavoidtheissueofdisclosureofanswer-relatedinformationtocandidates,allcopyrightacknowledgementsarereproducedonlineintheCambridgeInternationalExaminationsCopyrightAcknowledgementsBooklet.Thisisproducedforeachseriesofexaminationsandislyavailabletodownloadat theliveexaminationseries.CambridgeInternationalExaminationsispartoftheCambridgeAssessmentGroup.CambridgeAssessmentisthebrandnameofUniversityofCambridgeLocalExaminationsSyndicate(UCLES),whichisitselfadepartmentoftheUniversityofCambridge.国际考试国际高级附属和高级水*4力学1(M1)2015年5月/61.小时15分钟附加材料：答题册/纸方格纸列表首先阅读这些说明如果您收到了答题册，请按照该册子封面上的说明进行操作。在您提交的所有 编号、考生编号和。用深蓝色或黑色钢笔书写。您可以使用HB铅笔绘制 除非问题中指定了不同的精度级别，否则给出的非精确数字答案应正确至3度（以度为单位）1如果需要重力加速度的数值，请使用10ms.2。50本文档由3页印刷页和1页空白页组成。JC1506_9709_41/RP.UCLES翻212.7kgB25N，作用方向与水平面成一定角度。作用在B上的接触力的法向分量大小为20N。我证明sin=0.28。二求拉力将木块移动5m的距离所做的功。2FN、63N25NxyO为FN的力与x方向逆时针形成一个角度。大小为63N的力沿负y轴作用。力量的大小25N作用于从负x轴顺时针方向tan0.75处（见图）。求F的值和tan的值。1.3一块重量为6.1N的重物沿着与水平面成60°2ms.1A4求木块在静止之前从A移动了多远。4质量为14000kg的货车从O点开始沿道路行驶，到达A点，然后继续行驶至B24ms1.OA400mABα°300m。对于从O到B的运动，计算卡车动能的增益，并用表示其势能的损失。货车的运动阻力为4800N，货车从O到B的驱动力所做的功为5000kJ求的值。[3]UCLES20159709/41/M/J/1535自行车手和自行车的总质量为84公斤。她以PW的恒定速率工作，同时在与水平面倾斜一定角度的笔直道行驶，其中sin=0.1。上坡时，骑行者速度为3ms.1时，