单招考试C语言技能题目

题目1：分别统计字符串中字母、数字、空格和其他字符出现的次数（字符长度小于80//全局变量，a用于保存字母个数、num用于保存数字个数//b用于保存空格个数、other用于保存其他字符字数inta=0,num=0,b=0,other=0;voidcount(charc[]){/**********Program**********//**********End**********/}voidmain(){//voidcount(charc[]);charch[80];printf("inputstring:");gets(ch);count(ch);printf("a=%dnum=%db=%dother=%d\n",a,num,b,other);wwjt();}wwjt(){FILE*IN,*OUT;inti;charsIN[80];IN=fopen("in.dat","r");if(IN==NULL){printf("PleaseVerifyTheCurrerntDir..ItMayBeChanged");}OUT=fopen("out.dat","w");if(OUT==NULL){printf("PleaseVerifyTheCurrentDir..ItMayBeChanged");}for(i=0;i<5;i++){a=0;num=0;b=0;other=0;fscanf(IN,"%s",&sIN);count(sIN);fprintf(OUT,"%d\n",a);fprintf(OUT,"%d\n",num);fprintf(OUT,"%d\n",b);fprintf(OUT,"%d\n",other);}fclose(IN);fclose(OUT);}答案：inti;for(i=0;c[i]!='\0';i++)if((c[i]>='A'&&c[i]<='Z')||(c[i]>='a'&&c[i]<='z'))a=a+1;elseif(c[i]>='0'&&c[i]<='9')num=num+1;elseif(c[i]=='')b=b+1;elseother=other+1;题目2：函数gcd()计算整型数组a中相邻两元素的最大公约数，最小公倍数，其中最大公约数存入数组b中，最小公倍数存入数组c中。注意：请勿改动主函数main()中的其他内容。#include<stdio.h>#include<conio.h>voidgcd(inta[],intn,intb[],intc[]){inti,x,y,z;/***********SPACE***********/for(i=0;i<【?】;i++){x=a[i];y=a[i+1];while(z=x%y){x=y;y=z;}b[i]=y;/***********SPACE***********/c[i]=a[i]*a[i+1]/【?】;}}intmain(){inta[5]={8,12,5,7,14};intb[4],c[4];inti;gcd(a,5,b,c);for(i=0;i<5;i++)printf("%d\t",a[i]);printf("\n");for(i=0;i<4;i++)printf("%d\t",b[i]);printf("\n");for(i=0;i<4;i++)prin