单片机课程设计报告电子琴45

课程设计名称单片机原理课程设计（40346581）--1）根据应用系统的要求，初步掌握总体结构设计的方法和构思，从中选择一种--1）出勤20%；2）实验结果30%；3）报告20%；4）答辩30%。--低1DO#1DO#29463835#5SO##2RE#低3M#5SO#--#1DO##5SO#-59之间,用单片机播放音乐，或者弹奏电子12345671234567--DELAYDELAY125ms62ms187ms94ms250ms125ms本次采用12MHZ晶振，机器周期为1us，连接两个30pF的电容，连接到AT89C51的XATL1，XATL2--4）AT89C51AT89C51是一种带4K字节闪烁可编程可擦除只读存储器（FPEROM—Falsh--------设置行扫描初值N设置行扫描初值NN键码输出形成下一按扫描码NN--N是否有按键按下YYNYNYNYlowlow键按下YNY--节拍延时--NNYKEYBUFEQU30HSTH0EQU31HSTL0EQU32HDELYEQU33HNUMEQU34HORG0000HAJMPMAIN;跳转到主函数ORG000BHORG0040HMOVNUM,#01H；;num置1MOVR1,#00HANLTL0,#00HMOVA,P2;P2进入MOVDPTR,#TABLE1;低音键按下，进入低音表地址AJMPWAIT;跳转到音阶检测MOVDPTR,#TABLE2;中音键按下，进入中音表地址AJMPWAITMOVDPTR,#TABLE3;高音键按下，进入高音表地址AJMPWAITLCALLDELAY10MS;软件延时消抖MOVA,P2--MOVA,NUMMOVNUM,#00HMOVDPTR,#TABLE4AJMPWAIT1EXIT:CLRTR0MOVR1,#00HMOVNUM,#01HTEST4:MOVA,NUMCJNEA,#01H,WAIT2LJMPTESTWAIT2:LJMPWAIT1WAIT:CLRTR0MOVNUM,#01HSCAN1:MOVP3,#0F0HCLRTR0MOVA,P3;ANLA,#0F0HAJMPTESTTEE1:LCALLDELAY10MSAJMPTESTTEE2:MOVA,#0FEHSCAN2:MOVP3,AMOVA,P3MOVB,AANLA,#0F0HCJNEA,#0F0H,CARRYMOVA,BRLACJNEA,#0BFH,SCAN2LJMPSCAN1CARRY:ANLB,#0FHORLA,BCJNEA,#0EEH,KEY1MOVKEYBUF,#00HLJMPWAIMOVKEYBUF,#02HLJMPWAI--MOVKEYBUF,#04HLJMPWAIMOVKEYBUF,#06HLJMPWAIMOVKEYBUF,#08HLJMPWAIKEY5:CJNEA,#0DDH,KEY6MOVKEYBUF,#0AHLJMPWAIKEY6:CJNEA,#0DBH,KEY7MOVKEYBUF,#0CHLJMPWAIKEY7:CJNEA,#0D7H,SCAN1MOVKEYBUF,#0EHLJMPWAIWAI:MOVA,KEYBUFMOVCA,A+DPTRMOVSTH0,A-INCKEYBUFMOVA,KEYBUFMOVCA,A+DPTRMOVSTL0,AMOVTH0,STH0MOVTL0,STL0SETBTR0LCALLDELAY100MSLJMPSCAN1LOOP:MOVA,R1MOVCA,A+DPTRMOVSTH0,AMOVA,R1MOVCA,A+DPTRCJNEA,#0FEH,NEXT1MOVR1,#00HLJMPLOOP-NEXT1:MOVSTL0,AMOVA,R1MOVCA,A+DPTRMOVDELY,AMOVTH0,STH0MOVTL0,STL0SETBTR0NEXT2:LJMPDELAY187MS;节拍延时控制LJMPTESTNOKEY:LJMPTEST;重新检测DELAY10MS:MOVR6,#10;10ms延时D1:MOVR7,#248DELAY100MS:MOVR5,#06EH;100ms延时--DL0:MOVR4,#0CFHRETDELAY187MS:MOVR3,#187DL1:MOVR2,#248LJMPNEXT3MOVTL0,STL0RETI--