C语言上机练习题图文稿

文件管理序列号：[K8UY-K9IO69-O6M243-OL889-F88688]文件管理序列号：[K8UY-K9IO69-O6M243-OL889-F88688]C语言上机练习题输入一个不超过五位的正整数，输出其逆数。例如输入12345，输出应为54321。#include"stdio.h"main(){longn;intww,qw,bw,sw,gw;printf("Pleaseinput:\n");scanf("%ld",&n);while(n<=0||n>99999) { printf("\nThenumberistoolittleortoolarge.Retryplease!\n"); scanf("%ld",&n); }if(n>=10000&&n<=99999) { ww=n/10000; qw=n/1000%10; bw=n/100%10; sw=n/10%10; gw=n%10; printf("Theoldnumberis:%ld\n",n); printf("Thenewnumberis:%d%d%d%d%d\n",gw,sw,bw,qw,ww); }elseif(n>=1000&&n<=9999) { qw=n/1000; bw=n/100%10; sw=n/10%10; gw=n%10; printf("Theoldnumberis:%ld\n",n); printf("Thenewnumberis:%d%d%d%d\n",gw,sw,bw,qw); } elseif(n>=100&&n<=999) { bw=n/100; sw=n/10%10; gw=n%10; printf("Theoldnumberis:%ld\n",n); printf("Thenewnumberis:%d%d%d\n",gw,sw,bw); } elseif(n>=10&&n<=99) { sw=n/10; gw=n%10; printf("Theoldnumberis:%ld\n",n); printf("Thenewnumberis:%d%d\n",gw,sw); } elseprintf("Theoldnumberequalsthenewnumber:%ld",n);}计算1+2+3…+n的值，n是从键盘输入的自然数。/*Note:YourchoiceisCIDE*/#include"stdio.h"main(){intn,i;longsum=0;printf("1+2+3+....+n\n");printf("Pleaseinputn:\n");scanf("%d",&n);for(i=1;i<=n;i++){ sum+=i;}printf("sum=%ld",sum);}从终端（键盘）读入20个数据到数组中，统计其中正数的个数，并计算这些正数之和。、/*Note:YourchoiceisCIDE*/#include"stdio.h"#defineN20main(){ inta[N],i,sum=0,count=0; printf("Pleaseinputnumbers:\n"); for(i=0;i<N;i++) { scanf("%d",&a[i]); if(a[i]>0) { sum+=a[i]; count++; } } printf("count=%d,sum=%d",count,sum);}从终端（键盘）将5个整数输入到数组a中，然后将a逆序复制到数组b中，并输出b中各元素的值。/*Note:YourchoiceisCIDE*/#include"stdio.h"#defineN5main(){ inta[N],b[N],i; printf("Pleaseinputnumbers:\n"); for(i=0;i<N;i++) { scanf("%d",&a[i]); b[N-i-1]=a[i]; } printf("\nTheoldnumbersare:\n"); for(i=0;i<N;i++) printf("%-4d",a[i]); printf("\nThenewnumbersare:\n"); for(i=0;i<N;i++) printf("%-4d",b[i]);}要将五张100元的大钞票，换成等值的50元，20元，10元，5元一张的小钞票，每种面值至少1张，编程输出所有可能的换法，程序应适当考虑减少重复次数。/*Note:YourchoiceisCIDE*/#include"stdio.h"main(){ inti,j,k,n; for(i=1;i<=10;i++) for(j=1;j<=25;j++) for(k=1;k<=50;k++) for(n=1;n<=100;n++) if(i*50+j*20+k*10+n*5==500) printf("num50=%d,num20=%d,num10=%d,num5=%d\n",i,j,k,n);}求n以内（不包括n）同时能被3和7整除的所有自然数之和的平方根s，n从键盘输入。例如若n为1000时，函数值应为：s=153.909064。/*Note:YourchoiceisCIDE*/#include"stdio.h"#include"math.h"main(){ intn,s,i; floatsum=0; printf("Pleaseinputn:\n");scanf("%d",&n);while(n<=0) { printf("\nErrorinput.Retryplease:\n"); scanf("%d",&n); }for(i=1;i<n;i++) if(i%3==0&&i%7==0) sum+=i; printf("Thenumberis:%4.2f",sqrt(sum));}一辆卡车违反交通规则，撞人后逃跑。现场有三人目击事件，但都没有记住车号，只记下车号的一些特征。甲说：牌照的前两位数字是相同的；乙说：牌照的后两位数字是相同的，但与前两位不同；丙是数学家，他说：四位的车号刚好是一个整数的平方。请根据以上线索找出车号。/*Note:YourchoiceisCIDE*/#include"stdio.h"#include"math.h"main(){inti,qw,bw,sw,gw;for(i=1122;i<=9988;i++) { if(sqrt(i)!=(int)sqrt(i)) continue; qw=i/1000; bw=i/100%10; sw=i/10%10; gw=i%10; if(qw==bw&&sw==gw) { printf("\nThenumberis:%d\n",i); break; } }输入1~10之间的一个数字，输出它对应的英文单词。/*Note:YourchoiceisCIDE*/#include"stdio.h"main(){ intn; printf("Pleaseinputn:\n"); scanf("%d",&n); while(n<1||n>10) { printf("Errorinput!Retryplease:\n"); scanf("%d",&n); } switch(n) { case1:printf("One!");break; case2:printf("Two!");break; case3:printf("Three!");break; case4:printf("Four!");break; case5:printf("Five!");break; case6:printf("Six!");break; case7:printf("Seven!");break; case8:printf("Eight!");break; case9:printf("Nine!");break; case10:printf("Ten!");break; }}个位数为6且能被3整除但不能被5整除的三位自然数共有多少个，分别是哪些？/*Note:YourchoiceisCIDE*/#include"stdio.h"main(){inti,count=0;for(i=106;i<596;i=i+10){ if(i%3==0&&i%5!=0) { printf("%-4d",i); count++; }}printf("count=%-4d",count);}用自然语言描述程序逻辑如下，试写程序。① 设置环境；② 定义变量i、j、s，以及用于放置结果的变量sum，并令sum初值为0；③ i=1；④ 如果i≤100，则转⑤，否则转⑧；⑤ 令s=0，求前i个自然数之和，并放于变量s之中；⑥ sum=sum+s；⑦ i增加1，转④；输出和sum，结束。/*Note:YourchoiceisCIDE*/#include"stdio.h"main(){ inti,j;longs=0,sum=0;printf("1+1+2+1+2+3+1+2+3+4+....1+2+3+..+n\n");i=1;while(i<=3){ s+=i; sum+=s; i++;}printf("sum=%ld",sum);}用自然语言描述的程序逻辑为：① 设置环境；② 定义变量i、flag和password，并令flag=0，i=0；③ 用户回答口令，将其赋于password变量；④ 口令正确？如果是，则flag=1，转⑥。否则转⑤；⑤ 回答三次口令了吗？如果没有，计数器加1后（i++），转③，否则转⑥；根据flag之值输出相应信息。/*Note:YourchoiceisCIDE*/#include"stdio.h"#include"string.h"#defineN6main(){inti=0,flag=0;charpassword[N];printf("Thepasswordis:123456\n"); while(i<3){ gets(password); if(strlen(password)!=6) { printf("Thestringlengthiswrong!Retryplease!\n"); i++; continue; } if(strcmp("123456",password)==0) {flag=1;break;} else{printf("Wronginput!Retryplease!\n");i++;} }if(flag==1) printf("Rightpassword!\n");elseprintf("Wrongpassword!\n");}用自然语言描述的程序逻辑如下：① 设置环境；② 定义变量digit、x、y分别表示原始数、原始数的个位数和逆数；③ 输入原始正整数x；④ 从x中分解出个位数字digit；⑤ 合并个位digit至逆数y中；⑥ 原始数x缩小10倍：x=x/10；⑦ 如果x非零，则转④；输出逆数y，结束/*Note:YourchoiceisCIDE*/#include"stdio.h"main(){ longdigit,x,y;/*个位数、原始数、逆数*/ printf("Pleaseinputtheoldnumber:\n"); scanf("%ld",&x); digit=x%10; y=digit; while(x!=0) { x=x/10; digit=x%10; y=y*10+digit; } printf("x=%ld,y=%ld",x,y/10);}输入某三角形的三个边的长度，判断出这是个什么三角形（等腰、等边、任意，或不能构成）。/*Note:YourchoiceisCIDE*/#include"stdio.h"main(){floata,b,c,flag;/*flag=0不能，flag=1等边,flag=2等腰，flag=3任意*/printf("Pleaseinputangles:\n");scanf("%f,%f,%f",&a,&b,&c);if(a+b<=c||a+c<=b||b+c<=a) flag=0;elseif(a==b&&b==c) flag=1; elseif(a==b||b==c||c==a) flag=2; elseflag=3;if(flag==0)printf("\nCannot!\n");if(flag==1)printf("\nDengBian.\n");if(flag==2)printf("\nDengYao.\n");if(flag==3)printf("\nPutong.\n");}输入10个数，分别统计其中正数、负数、零的个数。#include"stdio.h"#defineN10main(){ inta[N]; inti,count1=0,count2=0,count3=0;/*count1记录正数个数，count2记录负数个数，count3记录0的个数*/ printf("Pleaseinputnumbers:\n"); for(i=0;i<N;i++) { scanf("%d",&a[i]); if(a[i]>0) count1++; if(a[i]<0) count2++; if(a[i]==0) count3++; }printf("count1=%-4d,count2=%-4d,count3=%-4d",count1,count2,count3);}先随机产生N个三位自然数输出，然后再输出其中同时是3、5、7倍数的数。（设N为100）/*Note:YourchoiceisCIDE*/#include"stdio.h"#defineN100#include<time.h>#include<stdlib.h>main(){ inta[N],i; printf("Pleaseinputnumbers:\n"); randomize(); for(i=0;i<N;i++){ a[i]=random(900)+100; printf("%-4d",a[i]);}printf("\n--------------------\n");printf("\n3,5,7:\n");for(i=0;i<N;i++) if(a[i]%3==0&&a[i]%5==0&&a[i]%7==0) printf("%-4d",a[i]);}用for编程找出100~200中的完全平方数。#include"stdio.h"#include"math.h"main(){inti;for(i=100;i<=200;i++) if(sqrt(i)==i%100) printf("%-4d",i);}从终端输入三个正实数，判断这三个数能否构成直角三角形。#include"stdio.h"main(){floata,b,c,flag;/*flag=0不能，flag=1能*/printf("Pleaseinputangles:\n");scanf("%f,%f,%f",&a,&b,&c);while(a<=0||b<=0||c<=0) { printf("Wronginput!Retryplease:\n"); scanf("%d,%d,%d",&a,&b,&c); }if(a+b<=c||b+c<=a||a+c<=b) flag=0; elseif(a*a==b*b+c*c||b*b==a*a+c*c||c*c==a*a+b*b) flag=1; elseflag=0;if(flag==1) printf("\nCan!"); elseprintf("\nCannot!");}输入一行字符，统计其中有多少个字母（包括大写字母和小写字母）。/*Note:YourchoiceisCIDE*/#include"stdio.h"#defineN10#include"stdlib.h"#include"ctype.h"#include"string.h"main(){charc[N];inti,count=0;gets(c);i=0;while(i!=strlen(c)){ if(isupper(c[i])||islower(c[i])) count++; i++;}printf("count=%-4d",count);getch();}输入一个字串，判断它是否是对称串。如”abcdcba”是对称串，””不是。/*Note:YourchoiceisCIDE*/#include"stdio.h"#include"string.h"#include"ctype.h"#include"stdlib.h"#defineN10main(){ chara[N],b[N],i; printf("Pleaseinputthestring:\n"); gets(a); if(strlen(a)>N) { printf("Wronginput!Retryplease!\n"); gets(a); } strcpy(b,a); strrev(a); if(strcmp(a,b)==0) printf("\nYes!\n"); elseprintf("\nNo!\n");}随机产生N个大写字母输出，然后统计其中共有多少个元音字符。（设N为200）/*Note:YourchoiceisCIDE*/#include"stdio.h"#include<stdlib.h>#include<time.h>#defineN200main(){intc[N],i,count=0;randomize();for(i=0;i<N;i++){c[i]=random(27)+65;printf("%c",c[i]);if(c[i]=='A'||c[i]=='E'||c[i]=='I'||c[i]=='O'||c[i]=='U')count++;}printf("\n----------------------\n");printf("\ncount=%-4d",count);}找出三位自然数中的所有素数，要求判断x素数用自定义函数data(x)实现。#include"stdio.h"intdata(intx);main(){inti,flag=0;/*1是，0否*/for(i=101;i<=999;i++){flag=data(i);if(flag==1)printf("%-4d",i);}} intdata(intx){inti;for(i=2;i<x/2;i++)if(x%i==0)return0;if(i==x/2)return1;elsereturn0;}输出n行由“#”组成的矩形，每行“#”的个数为m个，其中n、m由终端（键盘）输入。要求输出m个“#”功能由函数satr(m)函数实现。#include"stdio.h"voidsatr(intm);main(){ inti,n,m; printf("Pleaseinputn&m:\n"); printf("n="); scanf("%d",&n); printf("m="); scanf("%d",&m);printf("\n----------------\n");for(i=1;i<=n;i++) { satr(m); printf("\n"); }}voidsatr(intm){ inti; for(i=1;i<=m;i++) printf("#"); }若ax2+bx+c=0有实根，则求之。#include"stdio.h"#include"math.h"main(){inta,b,c;floatderta,x1,x2;printf("Pleaseinputa,b,c:\n");printf("a=");scanf("%d",&a); printf("b="); scanf("%d",&b); printf("c="); scanf("%d",&c); derta=b*b-4*a*c; if(derta<0) printf("NO!\n"); if(derta==0) { printf("One!\n"); x1=-b/(2*a); x2=x1; printf("x=%-4.2f",x1); } if(derta>0) { printf("Two!\n"); x1=(-b+sqrt(derta))/(2*a); x2=(-b-sqrt(derta))/(2*a); printf("x1=%-4.2f,x2=%-4.2f",x1,x2); }}从键盘输入两个字串，判断它们是否相同。#include"stdio.h"#include"string.h"#defineN20main(){ charc1[N],c2[N]; printf("Pleaseinputtwostringbelow:\n"); gets(c1); gets(c2); printf("--------------------\n"); printf("Theansweris:"); if(strcmp(c1,c2)==0) printf("Equal!\n"); elseprintf("Notequal!\n");}从键盘输入两个字串，输出其中较短的那个字串，并输出它的长度。#defineN20#include"stdio.h"#include"string.h"main(){ charc1[N],c2[N]; printf("Pleaseinputtwostringbelow:\n"); gets(c1); gets(c2); printf("--------------------\n"); printf("Theansweris:"); if(strlen(c1)==strlen(c2)) { puts(c1); puts(c2); printf("Thelengthis:%d\n",strlen(c1)); } if(strlen(c1)<strlen(c2)) { puts(c1); printf("Thelengthis:%d\n",strlen(c1)); } if(strlen(c1)>strlen(c2)) { puts(c2); printf("Thelengthis:%d\n",strlen(c2)); }从键盘输入长度不等的两个字串，将短串连接于长串之后输出。#include"stdio.h"#include"string.h"#defineN20main(){charc1[N],c2[N];printf("Pleaseinputtwostringbelow:\n");gets(c1);gets(c2);while(strlen(c1)==strlen(c2)){printf("Wronginput!Retryplease:\n");gets(c1);gets(c2);}printf("--------------------\n");printf("Theansweris:");if(strlen(c1)<strlen(c2))puts(strcat(c2,c1));if(strlen(c1)>strlen(c2))puts(strcat(c1,c2));}从键盘输入长度不等的两个字串，将长串连接于短串之后输出#include"stdio.h"#include"string.h"#defineN20main(){ charc1[N],c2[N]; printf("Pleaseinputtwostringbelow:\n"); gets(c1); gets(c2); while(strlen(c1)==strlen(c2)) { printf("Wronginput!Retryplease:\n"); gets(c1); gets(c2); } printf("--------------------\n"); printf("Theansweris:"); if(strlen(c1)<strlen(c2)) puts(strcat(c1,c2)); if(strlen(c1)>strlen(c2)) puts(strcat(c2,c1)); }随机产生N个两位自然数，降序排列后输出。（设N为20）#include"stdio.h"#include"stdlib.h"#include"time.h"#defineN20main(){ inta[N],i,j,temp; randomize(); for(i=0;i<N;i++) a[i]=random(900)+100; for(i=0;i<N-1;i++) for(j=i+1;j<N;j++) if(a[j]>a[i]) { temp=a[i]; a[i]=a[j]; a[j]=temp; } for(i=0;i<N;i++) printf("%-4d",a[i]);}从键盘输入两个字串，输出其中较长的那个字串，并输出它的长度。#defineN20#include"stdio.h"#include"string.h"main(){ charc1[N],c2[N]; printf("Pleaseinputtwostringbelow:\n"); gets(c1); gets(c2); printf("--------------------\n"); printf("Theansweris:"); if(strlen(c1)==strlen(c2)) { puts(c1); puts(c2); printf("Thelengthis:%d\n",strlen(c1)); } if(strlen(c2)<strlen(c1)) { puts(c1); printf("Thelengthis:%d\n",strlen(c1)); } if(strlen(c2)>strlen(c1)) { puts(c2); printf("Thelengthis:%d\n",strlen(c2)); } }从键盘输入10个战士的身高，输出平均身高，并找出哪些身高低于平均身高。#include"stdio.h"#defineN11main(){ floata[N],sum=0; inti; printf("Pleaseinputheigths:\n");for(i=0;i<N-1;i++) { scanf("%f",&a[i]); sum+=a[i]; }a[N-1]=sum/(N-1);printf("Theaverageis:%-6.2f\n",a[N-1]);printf("---------------------\n");printf("Theanswerare:\n");for(i=0;i<N-1;i++) if(a[i]<a[N-1]) printf("%-8.2f",a[i]);}从键盘输入10个战士的身高，输出平均身高，并找出哪些身高高于平均身高。#include"stdio.h"#defineN11main(){ floata[N],sum=0; inti; printf("Pleaseinputheigths:\n");for(i=0;i<N-1;i++) { scanf("%f",&a[i]); sum+=a[i]; }a[N-1]=sum/(N-1);printf("Theaverageis:%-6.2f\n",a[N-1]);printf("---------------------\n");printf("Theanswerare:\n");for(i=0;i<N-1;i++) if(a[i]>a[N-1]) printf("%-8.2f",a[i]);}从键盘输入10个战士的身高，输出最高、最低的身高#include"stdio.h"#defineN10main(){ floata[N],min=99999,max=-99999; inti; printf("Pleaseinputheigths:\n");for(i=0;i<N;i++) scanf("%f",&a[i]); printf("---------------------\n");for(i=0;i<N;i++){ if(a[i]>max) max=a[i]; if(a[i]<min) min=a[i];}printf("max=%-6.2f,min=%-6.2f",max,min);}。“百钱百鸡”问题。百钱买百鸡，鸡翁一值钱三，鸡母一值钱二，鸡雏三值钱一，问鸡翁、鸡母、鸡雏各几何？

#include"stdio.h"main(){ intjw,jm,jc; /*公鸡最多100/3=33只，母鸡最多100/2=50只,小鸡最多300只*/ for(jw=1;jw<=33;jw++) for(jm=1;jm<=50;jm++) for(jc=1;jc<=300;jc++) if(jw*3+jm*2+jc/3==100&&jw+jm+jc==100) printf("JW=%d,JM=%d,JC=%d\n",jw,jm,jc)