┃试卷合集4套┃2020年福建省泉州市数学高一(上)期末学业质量监测模拟试题_第1页
┃试卷合集4套┃2020年福建省泉州市数学高一(上)期末学业质量监测模拟试题_第2页
┃试卷合集4套┃2020年福建省泉州市数学高一(上)期末学业质量监测模拟试题_第3页
┃试卷合集4套┃2020年福建省泉州市数学高一(上)期末学业质量监测模拟试题_第4页
┃试卷合集4套┃2020年福建省泉州市数学高一(上)期末学业质量监测模拟试题_第5页
已阅读5页,还剩14页未读 继续免费阅读

下载本文档

版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领

文档简介

2019-2020学年高一数学上学期期末试卷一、选择题1.某几何体的三视图如图所示(单位:cm),则该几何体的体积(单位:SKIPIF1<0)是A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.若SKIPIF1<0,则SKIPIF1<0的值为SKIPIF1<0SKIPIF1<0A.SKIPIF1<0 B.SKIPIF1<0 C.2 D.33.已知函数SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的零点分别为SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,则SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的大小关系是SKIPIF1<0SKIPIF1<0A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<04.设角的终边经过点,那么()A. B. C. D.5.已知SKIPIF1<0为方程SKIPIF1<0的解,且SKIPIF1<0,则SKIPIF1<0SKIPIF1<0A.1 B.2 C.3 D.46.如图,在平面直角坐标系SKIPIF1<0中,角SKIPIF1<0以SKIPIF1<0为始边,终边与单位圆SKIPIF1<0相交于点SKIPIF1<0.过点SKIPIF1<0的圆SKIPIF1<0的切线交SKIPIF1<0轴于点SKIPIF1<0,点SKIPIF1<0的横坐标关于角SKIPIF1<0的函数记为SKIPIF1<0.则下列关于函数SKIPIF1<0的说法正确的()A.SKIPIF1<0的定义域是SKIPIF1<0B.SKIPIF1<0的图象的对称中心是SKIPIF1<0C.SKIPIF1<0的单调递增区间是SKIPIF1<0D.SKIPIF1<0对定义域内的SKIPIF1<0均满足SKIPIF1<07.已知实数SKIPIF1<0,SKIPIF1<0满足约束条件SKIPIF1<0,则目标函数SKIPIF1<0的最小值为()A.SKIPIF1<0 B.SKIPIF1<0 C.8 D.SKIPIF1<08.从1,2,3,…,9中任取两数,其中:①恰有一个偶数和恰有一个奇数;②至少有一个奇数和两个都是奇数;③至少有一个奇数和两个都是偶数;④至少有一个奇数和至少有一个偶数.在上述事件中,是对立事件的是().A.① B.②④ C.③ D.①③9.圆SKIPIF1<0的圆心到直线SKIPIF1<0的距离为1,则SKIPIF1<0()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.210.根据统计,一名工人组装第x件某产品所用的时间(单位:分钟)为f(x)=(A,c为常数).已知工人组装第4件产品用时30分钟,组装第A件产品用时15分钟,那么c和A的值分别是()A.75,25B.75,16C.60,25D.60,1611.一个三棱柱的底面是正三角形,侧棱垂直于底面,它的三视图及其尺寸如下(单位),则该三棱柱的表面积为()A.B.C.D.12.设SKIPIF1<0为定义在SKIPIF1<0上的函数,当SKIPIF1<0时,SKIPIF1<0,则SKIPIF1<0A.-3 B.-1 C.1 D.3二、填空题13.已知,则的最小值为____________。14.底面边长为1,棱长为SKIPIF1<0的正四棱柱,各顶点均为在同一球面上,则该球的体积为__________.15.已知角SKIPIF1<0终边上一点P的坐标为SKIPIF1<0,则SKIPIF1<0是第____象限角,SKIPIF1<0____·16.函数SKIPIF1<0的部分图象如图,其中SKIPIF1<0,SKIPIF1<0,SKIPIF1<0.则SKIPIF1<0____;SKIPIF1<0_____.三、解答题17.已知向量SKIPIF1<0,SKIPIF1<0,设函数SKIPIF1<0.SKIPIF1<0ⅠSKIPIF1<0求函数SKIPIF1<0的最小正周期和单调递增区间;SKIPIF1<0ⅡSKIPIF1<0求函数SKIPIF1<0在区间SKIPIF1<0的最大值和最小值.18.已知函数SKIPIF1<0SKIPIF1<0的图象如图所示.(1)求函数SKIPIF1<0的解析式;(2)求函数SKIPIF1<0的单调增区间;(3)当SKIPIF1<0时,求函数SKIPIF1<0的值域.19.是单位圆上的点,点是单位圆与轴正半轴的交点,点在第二象限,记,且.(1)求点的坐标;(2)求的值.20.如图,在四棱锥SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,平面SKIPIF1<0底面SKIPIF1<0,SKIPIF1<0,SKIPIF1<0和SKIPIF1<0分别是SKIPIF1<0和SKIPIF1<0的中点.求证:(1)SKIPIF1<0底面SKIPIF1<0;(2)SKIPIF1<0平面SKIPIF1<0;(3)平面SKIPIF1<0平面SKIPIF1<0.21.在平面直角坐标SKIPIF1<0中,圆SKIPIF1<0与圆SKIPIF1<0相交与SKIPIF1<0两点.(I)求线段SKIPIF1<0的长.(II)记圆SKIPIF1<0与SKIPIF1<0轴正半轴交于点SKIPIF1<0,点SKIPIF1<0在圆C上滑动,求SKIPIF1<0面积最大时的直线SKIPIF1<0的方程.22.如图,三棱柱SKIPIF1<0的侧面SKIPIF1<0是边长为SKIPIF1<0的菱形,SKIPIF1<0,且SKIPIF1<0.(1)求证:SKIPIF1<0;(2)若SKIPIF1<0,当二面角SKIPIF1<0为直二面角时,求三棱锥SKIPIF1<0的体积.【参考答案】***一、选择题题号123456789101112答案AAADBBCCADBA二、填空题13.414.SKIPIF1<015.四SKIPIF1<016.SKIPIF1<0三、解答题17.(Ⅰ)最小正周期是SKIPIF1<0,增区间为SKIPIF1<0,SKIPIF1<0;(Ⅱ)最大值为5,最小值为4.18.(1)SKIPIF1<0(2)SKIPIF1<0,SKIPIF1<0(3)SKIPIF1<019.(1);(2).20.(1)证明见解析.(2)证明见解析.(3)证明见解析.21.(I)SKIPIF1<0;(II)SKIPIF1<0或SKIPIF1<0.22.(1)略(2)SKIPIF1<0

2019-2020学年高一数学上学期期末试卷一、选择题1.设SKIPIF1<0是定义在SKIPIF1<0上恒不为零的函数,对任意实数SKIPIF1<0,都有SKIPIF1<0,若SKIPIF1<0,SKIPIF1<0,则数列SKIPIF1<0的前SKIPIF1<0项和SKIPIF1<0的取值范围是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.设是两条不同的直线,是两个不同的平面,则下列结论正确的是()A.若,,则 B.若,则C.若,则 D.若,则3.已知SKIPIF1<0、SKIPIF1<0是两条不同的直线,SKIPIF1<0、SKIPIF1<0是两个不同的平面,则下列命题正确的是()A.若SKIPIF1<0,SKIPIF1<0,则SKIPIF1<0 B.若SKIPIF1<0,SKIPIF1<0,则SKIPIF1<0C.若SKIPIF1<0,SKIPIF1<0,则SKIPIF1<0 D.若SKIPIF1<0,SKIPIF1<0,则SKIPIF1<04.函数SKIPIF1<0的部分图象如图所示,则()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<05.若SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,则SKIPIF1<0的最小值为()A.2 B.SKIPIF1<0 C.4 D.SKIPIF1<06.设SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,则SKIPIF1<0、SKIPIF1<0、SKIPIF1<0的大小关系为A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<07.动圆M与定圆SKIPIF1<0相外切,且与直线SKIPIF1<0相切,则动圆SKIPIF1<0的圆心SKIPIF1<0满足的方程为()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<08.设集合SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,则SKIPIF1<0A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<09.已知SKIPIF1<0且SKIPIF1<0,函数SKIPIF1<0,满足对任意实数SKIPIF1<0,都有SKIPIF1<0成立,则实数SKIPIF1<0的取值范围是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<010.容量为100的样本,其数据分布在SKIPIF1<0,将样本数据分为4组:SKIPIF1<0,得到频率分布直方图如图所示,则下列说法不正确的是()A.样本数据分布在SKIPIF1<0的频率为0.32 B.样本数据分布在SKIPIF1<0的频数为40C.样本数据分布在SKIPIF1<0的频数为40 D.估计总体数据大约有10%分布在SKIPIF1<011.执行如图的程序框图,如果输入的,则输出的值满足()A.B.C.D.12.执行如图所示的程序框图,输出的SKIPIF1<0值为()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.2二、填空题13.已知在SKIPIF1<0中,角SKIPIF1<0的大小依次成等差数列,最大边和最小边的长是方程SKIPIF1<0的两实根,则SKIPIF1<0__________.14.直三棱柱ABC-A1B1C1,内接于球O,且AB⊥BC,AB=3.BC=4.AA1=4,则球O的表面积______.15.如图,正方体SKIPIF1<0的棱长为1,线段SKIPIF1<0上有两个动点SKIPIF1<0,且SKIPIF1<0,现有如下四个结论:SKIPIF1<0;SKIPIF1<0平面SKIPIF1<0;SKIPIF1<0三棱锥SKIPIF1<0的体积为定值;SKIPIF1<0异面直线SKIPIF1<0所成的角为定值,其中正确结论的序号是______.16.已知函数SKIPIF1<0,SKIPIF1<0,若存在实数SKIPIF1<0,SKIPIF1<0,使得SKIPIF1<0,且SKIPIF1<0,则实数a的取值范围是_____.三、解答题17.已知数列SKIPIF1<0是公差不为0的等差数列,SKIPIF1<0成等比数列.(1)求SKIPIF1<0;(2)设SKIPIF1<0,数列SKIPIF1<0的前n项和为SKIPIF1<0,求SKIPIF1<018.已知函数SKIPIF1<0,SKIPIF1<0(1)求函数SKIPIF1<0的最小正周期;(2)设SKIPIF1<0的内角SKIPIF1<0的对边分别为SKIPIF1<0,且SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,求SKIPIF1<0的面积.19.已知函数SKIPIF1<0.SKIPIF1<0ⅠSKIPIF1<0若SKIPIF1<0,求SKIPIF1<0的值;SKIPIF1<0ⅡSKIPIF1<0设函数SKIPIF1<0,求函数SKIPIF1<0的值域.20.计算:。21.设二次函数SKIPIF1<0的图像过点SKIPIF1<0和SKIPIF1<0,且对于任意实数SKIPIF1<0,不等式SKIPIF1<0恒成立.(1)求SKIPIF1<0的表达式;(2)设SKIPIF1<0,若SKIPIF1<0在SKIPIF1<0上是增函数,求实数SKIPIF1<0的取值范围.22.已知是奇函数.求a的值并判断的单调性,无需证明;若对任意,不等式恒成立,求实数k的取值范围.【参考答案】***一、选择题题号123456789101112答案AAAACABCDDCD二、填空题13.SKIPIF1<014.SKIPIF1<015.SKIPIF1<016.SKIPIF1<0三、解答题17.(1)SKIPIF1<0(2)SKIPIF1<018.(1)SKIPIF1<0;(2)SKIPIF1<0.19.SKIPIF1<0ⅠSKIPIF1<0;(2)SKIPIF1<020.21.(Ⅰ);(Ⅱ).22.(1)在R上为增函数;(2)

2019-2020学年高一数学上学期期末试卷一、选择题1.在长为SKIPIF1<0的线段SKIPIF1<0上任取一点SKIPIF1<0.现作一矩形,邻边长分别等于线段SKIPIF1<0,SKIPIF1<0的长,则该矩形面积大于SKIPIF1<0的概率为()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.设,,是平面内共线的三个不同的点,点是,,所在直线外任意-点,且满足,若点在线段的延长线上,则()A., B., C. D.3.已知函数SKIPIF1<0在一个周期内的图象如图所示.则SKIPIF1<0的图象,可由函数SKIPIF1<0的图象怎样变换而来(纵坐标不变)()A.先把各点的横坐标缩短到原来的SKIPIF1<0倍,再向左平移SKIPIF1<0个单位B.先把各点的横坐标缩短到原来的SKIPIF1<0倍,再向右平移SKIPIF1<0个单位C.先把各点的横坐标伸长到原来的2倍,再向左平移SKIPIF1<0个单位D.先把各点的横坐标伸长到原来的2倍,再向右平移SKIPIF1<0个单位4.已知SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的对边分别是SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,且SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,则SKIPIF1<0边上的中线的长为()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0或SKIPIF1<0 D.SKIPIF1<0或SKIPIF1<05.已知函数f(x)=Asin(ωx+φ)(A>0,ω>0,|φ|<π)的图象经过点P(SKIPIF1<0,0)和相邻的最低点为Q(SKIPIF1<0,-2),则f(x)的解析式()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<06.下列函数中,值域是SKIPIF1<0的是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<07.已知边长为1的菱形SKIPIF1<0中,SKIPIF1<0,点SKIPIF1<0满足SKIPIF1<0,则SKIPIF1<0的值是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<08.设,若仅有一个常数,使得对于任意的,都有满足方程,则的取值集合为()A. B. C. D.9.若SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,则SKIPIF1<0的最小值为()A.2 B.SKIPIF1<0 C.4 D.SKIPIF1<010.已知函数SKIPIF1<0,若方程SKIPIF1<0有三个不同的实数根,则实数SKIPIF1<0的取值范围为()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<011.将进货单价为40元的商品按60元一个售出时,能卖出400个.已知该商品每个涨价1元,其销售量就减少10个,为了赚得最大利润,售价应定为A.每个70元B.每个85元C.每个80元D.每个75元12.如图,三棱柱中,侧棱底面,底面三角形是正三角形,是中点,则下列叙述正确的是()A.平面B.与是异面直线C.D.二、填空题13.如图,一热气球在海拔60m的高度飞行,在空中A处测得前下方河流两侧河岸SKIPIF1<0,SKIPIF1<0的俯角分别为75°,30°,则河流的宽度SKIPIF1<0等于_____m.14.已知SKIPIF1<0,若SKIPIF1<0,则a的取值范围是______.15.若函数是幂函数,则函数(其中,)的图象过定点的坐标为__________.16.一个三角形的三条边成等比数列,那么,公比q的取值范围是__________.三、解答题17.某市食品药品监督管理局开展2019年春季校园餐饮安全检查,对本市的8所中学食堂进行了原料采购加工标准和卫生标准的检查和评分,其评分情况如下表所示:中学编号12345678原料采购加工标准评分x10095938382757066卫生标准评分y8784838281797775(1)已知x与y之间具有线性相关关系,求y关于x的线性回归方程;(精确到0.1)(2)现从8个被检查的中学食堂中任意抽取两个组成一组,若两个中学食堂的原料采购加工标准和卫生标准的评分均超过80分,则组成“对比标兵食堂”,求该组被评为“对比标兵食堂”的概率.参考公式:SKIPIF1<0,SKIPIF1<0;参考数据:SKIPIF1<0,SKIPIF1<0.18.如图,已知以点SKIPIF1<0为圆心的圆与直线SKIPIF1<0相切.过点SKIPIF1<0的动直线SKIPIF1<0与圆A相交于M,N两点,Q是SKIPIF1<0的中点,直线SKIPIF1<0与SKIPIF1<0相交于点P.(1)求圆A的方程;(2)当SKIPIF1<0时,求直线SKIPIF1<0的方程.19.已知如图,在直三棱柱SKIPIF1<0中,SKIPIF1<0,且SKIPIF1<0,SKIPIF1<0是SKIPIF1<0的中点,SKIPIF1<0是SKIPIF1<0的中点,点SKIPIF1<0在直线SKIPIF1<0上.(1)若SKIPIF1<0为SKIPIF1<0中点,求证:SKIPIF1<0平面SKIPIF1<0;(2)证明:SKIPIF1<020.已知函数SKIPIF1<0(1)求函数SKIPIF1<0的最小正周期;(2)求函数SKIPIF1<0的单调递减区间;(3)求函数SKIPIF1<0在区间SKIPIF1<0上的最小值.21.已知函数SKIPIF1<0的定义域为SKIPIF1<0,且对任意实数SKIPIF1<0恒有SKIPIF1<0(SKIPIF1<0且SKIPIF1<0)成立.(1)求函数SKIPIF1<0的解析式;(2)讨论SKIPIF1<0在SKIPIF1<0上的单调性,并用定义加以证明.22.已知等差数列SKIPIF1<0的前3项和为6,前8项和为SKIPIF1<0.(1)求数列SKIPIF1<0的通项公式;(2)设SKIPIF1<0,求数列SKIPIF1<0的前SKIPIF1<0项和SKIPIF1<0【参考答案】***一、选择题题号123456789101112答案CABCBDACCAAD二、填空题13.SKIPIF1<014.SKIPIF1<015.(3,0)16.SKIPIF1<0三、解答题17.(1)SKIPIF1<0;(2)SKIPIF1<018.(1)SKIPIF1<0.(2)SKIPIF1<0或SKIPIF1<019.(1)略;(2)略20.(1)SKIPIF1<0;(2)SKIPIF1<0;(3)SKIPIF1<021.(1)SKIPIF1<0(2)当SKIPIF1<0时,SKIPIF1<0在SKIPIF1<0上为单调减函数;当SKIPIF1<0时,SKIPIF1<0在SKIPIF1<0上为单调增函数.22.(1)SKIPIF1<0(2)SKIPIF1<0

2019-2020学年高一数学上学期期末试卷一、选择题1.已知SKIPIF1<0是常数,那么“SKIPIF1<0”是“SKIPIF1<0等式对任意SKIPIF1<0恒成立”的()A.充分非必要条件 B.必要非充分条件C.充要条件 D.既不充分也不必要条件2.已知函数SKIPIF1<0,若函数SKIPIF1<0是周期为SKIPIF1<0的偶函数,则SKIPIF1<0可以是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<03.已知半圆C:SKIPIF1<0(SKIPIF1<0),A、B分别为半圆C与x轴的左、右交点,直线m过点B且与x轴垂直,点P在直线m上,纵坐标为t,若在半圆C上存在点Q使SKIPIF1<0,则t的取值范围是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<04.已知SKIPIF1<0,当m∈[0,1]时,SKIPIF1<0恒成立,则实数a的取值范围是()A.0≤a≤1 B.0<a<1 C.a≤0或a≥1 D.a<0或a>15.如图所示,平面内有三个向量SKIPIF1<0,其中SKIPIF1<0与SKIPIF1<0的夹角为SKIPIF1<0,SKIPIF1<0与SKIPIF1<0的夹角为SKIPIF1<0,且SKIPIF1<0,若SKIPIF1<0,则SKIPIF1<0SKIPIF1<0A.1 B.2 C.3 D.46.已知定义在SKIPIF1<0上的函数SKIPIF1<0的图象关于SKIPIF1<0轴对称,且函数SKIPIF1<0在SKIPIF1<0上单调递减,则不等式SKIPIF1<0的解集为()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<07.设函数f(x)=cos(x+SKIPIF1<0),则下列结论错误的是A.f(x)的一个周期为−2π B.y=f(x)的图像关于直线x=SKIPIF1<0对称C.f(x+π)的一个零点为x=SKIPIF1<0 D.f(x)在(SKIPIF1<0,π)单调递减8.已知集合SKIPIF1<0,则SKIPIF1<0()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<09.下列函数的最小值为SKIPIF1<0的是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<010.幂函数SKIPIF1<0在SKIPIF1<0时是减函数,则实数m的值为SKIPIF1<0SKIPIF1<0A.2或SKIPIF1<0 B.SKIPIF1<0 C.2 D.SKIPIF1<0或111.已知,,,则,,的大小关系为()A. B. C. D.12.下列函数中,在区间SKIPIF1<0上是增函数的是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0二、填空题13.对任意实数SKIPIF1<0,不等式SKIPIF1<0恒成立,则实数SKIPIF1<0的取值范围是____.14.已知SKIPIF1<0是SKIPIF1<0上的增函数,那么SKIPIF1<0的取值范围是______.15.已知x<0,且x-y=1,则SKIPIF1<0的最大值是____.16.已知数列SKIPIF1<0满足SKIPIF1<0,若SKIPIF1<0,则数列SKIPIF1<0的通项SKIPIF1<0______.三、解答题17.某快餐连锁店招聘外卖骑手,该快餐连锁店提供了两种日工资方案:方案(1)规定每日底薪50元,快递业务每完成一单提成3元;方案(2)规定每日底薪100元,快递业务的前44单没有提成,从第45单开始,每完成一单提成5元.该快餐连锁店记录了每天骑手的人均业务量.现随机抽取100天的数据,将样本数据分为[25,35),[35,45),[45,55),[55,65),[65,75),[75,85),[85,95]七组,整理得到如图所示的频率分布直方图。(1)随机选取一天,估计这一天该连锁店的骑手的人均日快递业务量不少于65单的概率;(2)若骑手甲、乙选择了日工资方案(1),丙、丁选择了日工资方案(2).现从上述4名骑手中随机选取2人,求至少有1名骑手选择方案(1)的概率;18.设圆SKIPIF1<0,圆SKIPIF1<0,(1)判断圆SKIPIF1<0与圆SKIPIF1<0的位置关系;(2)点SKIPIF1<0、SKIPIF1<0分别是圆SKIPIF1<0,SKIPIF1<0上的动点,SKIPIF1<0为直线SKIPIF1<0上的动点,求SKIPIF1<0的最小值。19.已知函数SKIPIF1<0,将SKIPIF1<0的图象向右平移SKIPIF1<0单位长度,再向下平移SKIPIF1<0个单位长度得到函数SKIPIF1<0的图象.(1)求函数SKIPIF1<0的递增区间;(2)当SKIPIF1<0时,求SKIPIF1<0的最小值以及取得最小值时SKIPIF1<0的集合.20.某市从高二年级随机选取1000名学生,统计他们选修物理、化学、生物、

温馨提示

  • 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
  • 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
  • 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
  • 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
  • 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
  • 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
  • 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。

最新文档

评论

0/150

提交评论